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If \(p(x)=x^2-ax+10\) and \(p(5)=0\), what is the value of \(a\)?
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Answer and explanation
Correct answer: 7
Substituting \(x=5\) in the given polynomial gives \(p(5)=25-5a+10=0\). Thus, \(35-5a=0\), so \(5a=35\) and \(a=7\). If \(a=10\), then \(p(5)=25-50+10=-15\), so that option is incorrect. Exam tip: substitute the given zero directly into the polynomial.
Frequently asked questions
What is the correct answer to this question?
7
Why is this the correct answer?
Substituting \(x=5\) in the given polynomial gives \(p(5)=25-5a+10=0\). Thus, \(35-5a=0\), so \(5a=35\) and \(a=7\). If \(a=10\), then \(p(5)=25-50+10=-15\), so that option is incorrect. Exam tip: substitute the given zero directly into the polynomial.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Polynomials in one variable.
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