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Assertion: In the equation \(x^2-2(a-b)x+(a+b)^2=0\), if \(ab<0\), its roots are real and distinct. Reason: The discriminant of this equation is \(D=-16ab\). Choose the correct option.

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Answer and explanation

Correct answer: Both the assertion and the reason are correct

Here, \(A=1\), \(B=-2(a-b)\), and \(C=(a+b)^2\). Therefore, \(D=B^2-4AC=4(a-b)^2-4(a+b)^2=-16ab\). Since \(ab<0\), we have \(-16ab>0\), so the discriminant is positive and the roots are real and distinct. Hence, both the assertion and the reason are correct, and the reason explains the assertion. Exam tip: For a quadratic equation, \(D>0\) indicates two real and distinct roots.

Related tags

Quadratic-EquationsNature-Of-RootsDiscriminantAssertion-ReasonParameter-Based

Frequently asked questions

What is the correct answer to this question?

Both the assertion and the reason are correct

Why is this the correct answer?

Here, \(A=1\), \(B=-2(a-b)\), and \(C=(a+b)^2\). Therefore, \(D=B^2-4AC=4(a-b)^2-4(a+b)^2=-16ab\). Since \(ab<0\), we have \(-16ab>0\), so the discriminant is positive and the roots are real and distinct. Hence, both the assertion and the reason are correct, and the reason explains the assertion. Exam tip: For a quadratic equation, \(D>0\) indicates two real and distinct roots.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Nature of Roots.

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