Concept-wise Practice

parameter MCQ Questions for Class 10

parameter se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

737 questions tagged with parameter.

यदि (p(x)=2x-2+bx+c), (p(0)=5) और (p(1)=1), तो (b) क्या है?

If (p(x)=2x-2+bx+c), (p(0)=5), and (p(1)=1), what is (b)?

Explanation opens after your attempt
Correct Answer

A. (-6)

Step 1

Concept

(p(0)=c=5) and (p(1)=2+b+5=1), so (b=-6). The constant term is found quickly from (x=0).

Step 2

Why this answer is correct

The correct answer is A. (-6). (p(0)=c=5) and (p(1)=2+b+5=1), so (b=-6). The constant term is found quickly from (x=0).

Step 3

Exam Tip

(p(0)=c=5) और (p(1)=2+b+5=1), इसलिए (b=-6)। (x=0) से अचर पद तुरंत मिलता है।

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किस मान के लिए ((m+1)x-2+(m-2)x+7) अचर बहुपद बन सकता है?

For what value of (m) can ((m+1)x-2+(m-2)x+7) become a constant polynomial?

Explanation opens after your attempt
Correct Answer

C. ऐसा कोई मान नहींNo such value

Step 1

Concept

For a constant polynomial, both (m+1=0) and (m-2=0) are needed, which is impossible together. All variable terms must vanish.

Step 2

Why this answer is correct

The correct answer is C. ऐसा कोई मान नहीं / No such value. For a constant polynomial, both (m+1=0) and (m-2=0) are needed, which is impossible together. All variable terms must vanish.

Step 3

Exam Tip

अचर बहुपद के लिए (m+1=0) और (m-2=0) दोनों चाहिए, जो साथ संभव नहीं हैं। सभी चर वाले पद हटने चाहिए।

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यदि (p(x)=x-3+rx-2+s), (p(0)=5) और (p(1)=9), तो (r) क्या है?

If (p(x)=x-3+rx-2+s), (p(0)=5), and (p(1)=9), what is (r)?

Explanation opens after your attempt
Correct Answer

C. (3)

Step 1

Concept

(p(0)=s=5) and (p(1)=1+r+5=9), so (r=3). First use (x=0) to find the constant term.

Step 2

Why this answer is correct

The correct answer is C. (3). (p(0)=s=5) and (p(1)=1+r+5=9), so (r=3). First use (x=0) to find the constant term.

Step 3

Exam Tip

(p(0)=s=5) और (p(1)=1+r+5=9), इसलिए (r=3)। पहले (x=0) से अचर पद निकालें।

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यदि (p(x)=x-3+px+q), (p(1)=4) और (p(-1)=-2), तो (p) का मान क्या है?

If (p(x)=x-3+px+q), (p(1)=4), and (p(-1)=-2), what is the value of (p)?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

The conditions give (1+p+q=4) and (-1-p+q=-2), so (p=2). Subtracting the two equations is quick.

Step 2

Why this answer is correct

The correct answer is B. (2). The conditions give (1+p+q=4) and (-1-p+q=-2), so (p=2). Subtracting the two equations is quick.

Step 3

Exam Tip

शर्तों से (1+p+q=4) और (-1-p+q=-2), इसलिए (p=2)। दो समीकरणों को घटाना तेज तरीका है।

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यदि बहुपद (p(x)=2x-3+kx-2-8x+3) में सभी गुणांकों का योग (0) है, तो (k) क्या है?

If the sum of all coefficients of (p(x)=2x-3+kx-2-8x+3) is (0), what is (k)?

Explanation opens after your attempt
Correct Answer

C. (3)

Step 1

Concept

The sum of coefficients is (2+k-8+3=k-3), so (k=3). The sum of coefficients can also be found by (p(1)).

Step 2

Why this answer is correct

The correct answer is C. (3). The sum of coefficients is (2+k-8+3=k-3), so (k=3). The sum of coefficients can also be found by (p(1)).

Step 3

Exam Tip

गुणांकों का योग (2+k-8+3=k-3) है, इसलिए (k=3)। गुणांकों का योग (p(1)) से भी मिलता है।

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यदि (p(x)=x-2+ax+b), (p(1)=0) और (p(2)=0), तो (a+b) क्या है?

If (p(x)=x-2+ax+b), (p(1)=0), and (p(2)=0), what is (a+b)?

Explanation opens after your attempt
Correct Answer

C. (1)

Step 1

Concept

The conditions give (1+a+b=0) and (4+2a+b=0), so (a=-3), (b=2), and (a+b=-1). The correct option is (-1).

Step 2

Why this answer is correct

The correct answer is C. (1). The conditions give (1+a+b=0) and (4+2a+b=0), so (a=-3), (b=2), and (a+b=-1). The correct option is (-1).

Step 3

Exam Tip

शर्तों से (1+a+b=0) और (4+2a+b=0), इसलिए (a=-3), (b=2) और (a+b=-1)। सही विकल्प (-1) है।

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किस मान के लिए (p(x)=x-3-4x-2+mx+6) में (p(1)=0) होगा?

For what value of (m) will (p(1)=0) in (p(x)=x-3-4x-2+mx+6)?

Explanation opens after your attempt
Correct Answer

A. (-3)

Step 1

Concept

(p(1)=1-4+m+6=m+3), so (m=-3). Substitute the given value and form a simple equation.

Step 2

Why this answer is correct

The correct answer is A. (-3). (p(1)=1-4+m+6=m+3), so (m=-3). Substitute the given value and form a simple equation.

Step 3

Exam Tip

(p(1)=1-4+m+6=m+3), इसलिए (m=-3)। दिए गए मान को रखकर सरल समीकरण बनाएं।

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यदि (x=3), बहुपद (p(x)=x-2-kx+12) का शून्य है, तो (k) क्या है?

If (x=3) is a zero of (p(x)=x-2-kx+12), what is (k)?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

(p(3)=9-3k+12=0), so (21=3k) and (k=7). For a zero, set the polynomial value equal to (0).

Step 2

Why this answer is correct

The correct answer is C. (7). (p(3)=9-3k+12=0), so (21=3k) and (k=7). For a zero, set the polynomial value equal to (0).

Step 3

Exam Tip

(p(3)=9-3k+12=0), इसलिए (21=3k) और (k=7)। शून्य की शर्त में बहुपद का मान (0) रखें।

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यदि (p(x)=kx-2-5x+6) और (p(-1)=14), तो (k) का मान क्या है?

If (p(x)=kx-2-5x+6) and (p(-1)=14), what is the value of (k)?

Explanation opens after your attempt
Correct Answer

C. (3)

Step 1

Concept

(p(-1)=k+5+6=14), so (k=3). Check signs carefully while substituting a negative value.

Step 2

Why this answer is correct

The correct answer is C. (3). (p(-1)=k+5+6=14), so (k=3). Check signs carefully while substituting a negative value.

Step 3

Exam Tip

(p(-1)=k+5+6=14), इसलिए (k=3)। ऋणात्मक मान रखते समय संकेत सावधानी से देखें।

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यदि (p(x)=(a-5)x-5+2x-3-7x+4) की घात (3) है, तो (a) क्या होगा?

If the degree of (p(x)=(a-5)x-5+2x-3-7x+4) is (3), what is (a)?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

For the degree to be (3), the coefficient of \(x^5\) must be (0), so (a-5=0). First make the highest-degree term vanish.

Step 2

Why this answer is correct

The correct answer is C. (5). For the degree to be (3), the coefficient of \(x^5\) must be (0), so (a-5=0). First make the highest-degree term vanish.

Step 3

Exam Tip

घात (3) होने के लिए \(x^5\) का गुणांक (0) होना चाहिए, इसलिए (a-5=0)। उच्चतम घात वाले पद को पहले शून्य करें।

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यदि (p(x)=ax-2+4x-12) और (x=2) इसका शून्य है, तो (a) क्या होगा?

If (p(x)=ax-2+4x-12) and (x=2) is its zero, what is (a)?

Explanation opens after your attempt
Correct Answer

A. (1)

Step 1

Concept

(p(2)=4a+8-12=0), so (4a=4) and (a=1). When a zero is given, set the polynomial value equal to (0).

Step 2

Why this answer is correct

The correct answer is A. (1). (p(2)=4a+8-12=0), so (4a=4) and (a=1). When a zero is given, set the polynomial value equal to (0).

Step 3

Exam Tip

(p(2)=4a+8-12=0), इसलिए (4a=4) और (a=1)। शून्य दिए होने पर बहुपद का मान (0) रखें।

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यदि (p(x)=2x-2-5x+c) और (p(4)=7), तो (c) का मान क्या है?

If (p(x)=2x-2-5x+c) and (p(4)=7), what is the value of (c)?

Explanation opens after your attempt
Correct Answer

A. (-5)

Step 1

Concept

(p(4)=32-20+c=7), so (12+c=7) and (c=-5). Substitute the given value to find the unknown constant term.

Step 2

Why this answer is correct

The correct answer is A. (-5). (p(4)=32-20+c=7), so (12+c=7) and (c=-5). Substitute the given value to find the unknown constant term.

Step 3

Exam Tip

(p(4)=32-20+c=7), इसलिए (12+c=7) और (c=-5)। दिए गए मान को रखकर अज्ञात अचर पद निकालें।

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यदि (p(x)=(k-4)x-4+3x-2-5x+2) की घात (2) है, तो (k) का मान क्या होगा?

If the degree of (p(x)=(k-4)x-4+3x-2-5x+2) is (2), what will be the value of (k)?

Explanation opens after your attempt
Correct Answer

C. (4)

Step 1

Concept

For the degree to be (2), the coefficient of \(x^4\) must be (0), so (k-4=0) and (k=4). Check the coefficient of the highest power first.

Step 2

Why this answer is correct

The correct answer is C. (4). For the degree to be (2), the coefficient of \(x^4\) must be (0), so (k-4=0) and (k=4). Check the coefficient of the highest power first.

Step 3

Exam Tip

घात (2) होने के लिए \(x^4\) का गुणांक (0) होना चाहिए, इसलिए (k-4=0) और (k=4)। सबसे बड़ी घात वाले पद का गुणांक पहले जांचें।

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यदि (p(x)=ax-3+bx-2+cx+d) और (p(0)=-7), तो (d) का मान क्या है?

If (p(x)=ax-3+bx-2+cx+d) and (p(0)=-7), what is the value of (d)?

Explanation opens after your attempt
Correct Answer

B. (-7)

Step 1

Concept

Putting (x=0) gives (p(0)=d). Therefore (d=-7).

Step 2

Why this answer is correct

The correct answer is B. (-7). Putting (x=0) gives (p(0)=d). Therefore (d=-7).

Step 3

Exam Tip

(x=0) रखने पर (p(0)=d) मिलता है। इसलिए (d=-7) है।

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किस मान के लिए \(x^2-6x+m\) में (x=2) शून्य होगा?

For what value of (m) will (x=2) be a zero of \(x^2-6x+m\)?

Explanation opens after your attempt
Correct Answer

B. (8)

Step 1

Concept

(4-12+m=0), so (m=8). When a zero is given, set the polynomial value equal to (0).

Step 2

Why this answer is correct

The correct answer is B. (8). (4-12+m=0), so (m=8). When a zero is given, set the polynomial value equal to (0).

Step 3

Exam Tip

(4-12+m=0), इसलिए (m=8)। शून्य दिए होने पर बहुपद का मान (0) रखें।

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यदि (p(x)=x-2-ax+18) और (p(3)=0), तो (a) का मान क्या है?

If (p(x)=x-2-ax+18) and (p(3)=0), what is the value of (a)?

Explanation opens after your attempt
Correct Answer

C. (9)

Step 1

Concept

(p(3)=9-3a+18=0), so (27=3a) and (a=9). After substitution, solve the simple linear equation.

Step 2

Why this answer is correct

The correct answer is C. (9). (p(3)=9-3a+18=0), so (27=3a) and (a=9). After substitution, solve the simple linear equation.

Step 3

Exam Tip

(p(3)=9-3a+18=0), इसलिए (27=3a) और (a=9)। मान रखने के बाद सरल रैखिक समीकरण हल करें।

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यदि (p(x)=x-2+kx-15) और (p(3)=0), तो (k) क्या है?

If (p(x)=x-2+kx-15) and (p(3)=0), what is (k)?

Explanation opens after your attempt
Correct Answer

A. (2)

Step 1

Concept

(p(3)=9+3k-15=0), so (3k=6) and (k=2). Use the zero condition to find the unknown.

Step 2

Why this answer is correct

The correct answer is A. (2). (p(3)=9+3k-15=0), so (3k=6) and (k=2). Use the zero condition to find the unknown.

Step 3

Exam Tip

(p(3)=9+3k-15=0), इसलिए (3k=6) और (k=2)। शून्य की शर्त लगाकर अज्ञात निकालें।

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यदि (p(x)=9x-2+cx-5) में (x) का गुणांक (-4) है, तो (c) क्या है?

If the coefficient of (x) in (p(x)=9x-2+cx-5) is (-4), what is (c)?

Explanation opens after your attempt
Correct Answer

C. (-4)

Step 1

Concept

In (cx), the coefficient of (x) is (c). It is given that (c=-4).

Step 2

Why this answer is correct

The correct answer is C. (-4). In (cx), the coefficient of (x) is (c). It is given that (c=-4).

Step 3

Exam Tip

(cx) में (x) का गुणांक (c) है। दिया है कि (c=-4)।

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यदि (p(x)=(a+3)x-2+5x-1) रैखिक बहुपद है, तो (a) क्या होगा?

If (p(x)=(a+3)x-2+5x-1) is a linear polynomial, what is (a)?

Explanation opens after your attempt
Correct Answer

A. (-3)

Step 1

Concept

For it to be linear, the coefficient of \(x^2\) must be (0). Hence (a+3=0) and (a=-3).

Step 2

Why this answer is correct

The correct answer is A. (-3). For it to be linear, the coefficient of \(x^2\) must be (0). Hence (a+3=0) and (a=-3).

Step 3

Exam Tip

रैखिक होने के लिए \(x^2\) का गुणांक (0) होना चाहिए। इसलिए (a+3=0) और (a=-3)।

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यदि (p(x)=x-2-ax+12) और (p(3)=0), तो (a) का मान क्या है?

If (p(x)=x-2-ax+12) and (p(3)=0), what is the value of (a)?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

(9-3a+12=0) gives (21-3a=0). Therefore (a=7).

Step 2

Why this answer is correct

The correct answer is C. (7). (9-3a+12=0) gives (21-3a=0). Therefore (a=7).

Step 3

Exam Tip

(9-3a+12=0) से (21-3a=0) मिलता है। इसलिए (a=7) है।

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यदि (p(x)=x-2+px+16) और (4) इसका शून्य है, तो (p) का मान क्या है?

If (4) is a zero of (p(x)=x-2+px+16), what is the value of (p)?

Explanation opens after your attempt
Correct Answer

A. (-8)

Step 1

Concept

\(4^2+4p+16=0\) gives (32+4p=0). Therefore (p=-8).

Step 2

Why this answer is correct

The correct answer is A. (-8). \(4^2+4p+16=0\) gives (32+4p=0). Therefore (p=-8).

Step 3

Exam Tip

\(4^2+4p+16=0\) से (32+4p=0) मिलता है। इसलिए (p=-8) है।

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यदि (p(x)=2x-2+bx-10) और (p(2)=4), तो (b) का मान क्या है?

If (p(x)=2x-2+bx-10) and (p(2)=4), what is the value of (b)?

Explanation opens after your attempt
Correct Answer

C. (3)

Step 1

Concept

(p(2)=8+2b-10=4) gives (2b-2=4). Therefore (b=3).

Step 2

Why this answer is correct

The correct answer is C. (3). (p(2)=8+2b-10=4) gives (2b-2=4). Therefore (b=3).

Step 3

Exam Tip

(p(2)=8+2b-10=4) से (2b-2=4) मिलता है। इसलिए (b=3) है।

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यदि (p(x)=x-3+ax-2+bx+1) में (a=0) और (b=-2), तो बहुपद क्या होगा?

If (a=0) and (b=-2) in (p(x)=x-3+ax-2+bx+1), what will the polynomial be?

Explanation opens after your attempt
Correct Answer

A. \(x^3-2x+1\)

Step 1

Concept

With (a=0), the \(x^2\) term vanishes, and with (b=-2), we get (-2x). So the polynomial is \(x^3-2x+1\).

Step 2

Why this answer is correct

The correct answer is A. \(x^3-2x+1\). With (a=0), the \(x^2\) term vanishes, and with (b=-2), we get (-2x). So the polynomial is \(x^3-2x+1\).

Step 3

Exam Tip

(a=0) से \(x^2\) पद हटता है और (b=-2) से (-2x) मिलता है। इसलिए बहुपद \(x^3-2x+1\) है।

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यदि \(x^3+2x^2+cx+5\) में (x) का गुणांक (6) है, तो (c+5) क्या होगा?

If the coefficient of (x) in \(x^3+2x^2+cx+5\) is (6), what will be (c+5)?

Explanation opens after your attempt
Correct Answer

C. (11)

Step 1

Concept

The coefficient of (x) is (c=6). Therefore (c+5=11).

Step 2

Why this answer is correct

The correct answer is C. (11). The coefficient of (x) is (c=6). Therefore (c+5=11).

Step 3

Exam Tip

(x) का गुणांक (c=6) है। इसलिए (c+5=11) होगा।

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यदि (p(x)=x-2+ax+a) और (p(1)=5), तो (a) का मान क्या है?

If (p(x)=x-2+ax+a) and (p(1)=5), what is the value of (a)?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

(p(1)=1+a+a=5) gives (1+2a=5). Therefore (a=2).

Step 2

Why this answer is correct

The correct answer is B. (2). (p(1)=1+a+a=5) gives (1+2a=5). Therefore (a=2).

Step 3

Exam Tip

(p(1)=1+a+a=5) से (1+2a=5) मिलता है। इसलिए (a=2) है।

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यदि (p(x)=kx+12) का शून्य (3) है, तो (k) का मान क्या है?

If (3) is a zero of (p(x)=kx+12), what is the value of (k)?

Explanation opens after your attempt
Correct Answer

B. (-4)

Step 1

Concept

From (p(3)=0), we get (3k+12=0). Therefore (k=-4).

Step 2

Why this answer is correct

The correct answer is B. (-4). From (p(3)=0), we get (3k+12=0). Therefore (k=-4).

Step 3

Exam Tip

(p(3)=0) से (3k+12=0) मिलता है। इसलिए (k=-4) है।

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किस मान के लिए (p(x)=(a-2)x-3+4x-2+1) की घात (2) हो जाएगी?

For which value will (p(x)=(a-2)x-3+4x-2+1) have degree (2)?

Explanation opens after your attempt
Correct Answer

C. (a=2)

Step 1

Concept

For degree (2), the coefficient of \(x^3\) must be (0). From (a-2=0), we get (a=2).

Step 2

Why this answer is correct

The correct answer is C. (a=2). For degree (2), the coefficient of \(x^3\) must be (0). From (a-2=0), we get (a=2).

Step 3

Exam Tip

घात (2) के लिए \(x^3\) का गुणांक (0) होना चाहिए। (a-2=0) से (a=2) मिलता है।

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यदि (p(x)=2x-3+mx-2-x+4) में \(x^2\) का गुणांक (-5) है, तो (m) क्या है?

If the coefficient of \(x^2\) in (p(x)=2x-3+mx-2-x+4) is (-5), what is (m)?

Explanation opens after your attempt
Correct Answer

B. (-5)

Step 1

Concept

The multiplier of \(x^2\) is (m). Given (m=-5), so the answer is (-5).

Step 2

Why this answer is correct

The correct answer is B. (-5). The multiplier of \(x^2\) is (m). Given (m=-5), so the answer is (-5).

Step 3

Exam Tip

\(x^2\) के साथ लगा गुणक (m) है। दिया है (m=-5), इसलिए उत्तर (-5) है।

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यदि (q(x)=x-2-kx+6) और (q(2)=0), तो (k) का मान क्या है?

If (q(x)=x-2-kx+6) and (q(2)=0), what is the value of (k)?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

(q(2)=4-2k+6=0) gives (10-2k=0). So (k=5).

Step 2

Why this answer is correct

The correct answer is C. (5). (q(2)=4-2k+6=0) gives (10-2k=0). So (k=5).

Step 3

Exam Tip

(q(2)=4-2k+6=0) से (10-2k=0) मिलता है। इसलिए (k=5) है।

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यदि (p(x)=ax-2+3x+5) की घात (1) है, तो (a) का मान क्या होगा?

If (p(x)=ax-2+3x+5) has degree (1), what will be the value of (a)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

For degree (1), the coefficient of \(x^2\) must be (0). Therefore (a=0).

Step 2

Why this answer is correct

The correct answer is A. (0). For degree (1), the coefficient of \(x^2\) must be (0). Therefore (a=0).

Step 3

Exam Tip

घात (1) होने के लिए \(x^2\) का गुणांक (0) होना चाहिए। इसलिए (a=0) है।

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