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If \(p(x)=x^2+kx-15\) and \(p(3)=0\), what is the value of \(k\)?यदि \(p(x)=x^2+kx-15\) तथा \(p(3)=0\), तो \(k\) का मान क्या है?
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Correct answer:सही उत्तर: 22
Since \(p(3)=0\), substitute \(x=3\) into the polynomial: \(p(3)=3^2+3k-15=0\). Thus, \(9+3k-15=0\), so \(3k=6\) and \(k=2\). The value 3 does not make the polynomial equal to zero. Exam tip: directly substitute the given zero of the polynomial for \(x\).चूँकि \(p(3)=0\), इसलिए \(p(3)=3^2+3k-15=0\)। अतः \(9+3k-15=0\), यानी \(3k=6\) और \(k=2\)। विकल्प 3 लेने पर समीकरण का मान शून्य नहीं आता। परीक्षा में किसी दिए गए शून्यक के लिए बहुपद में वही मान सीधे प्रतिस्थापित करें।
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