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If \(q(x)=x^2-kx+6\) satisfies \(q(2)=0\), what is the value of \(k\)?
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Answer and explanation
Correct answer: 5
Substituting \(x=2\) in the condition \(q(2)=0\) gives \(2^2-2k+6=0\), so \(10-2k=0\). Hence, \(2k=10\) and \(k=5\), making option C correct. Exam tip: If \(a\) is a zero of a polynomial, substitute \(x=a\) and set the polynomial equal to zero.
Frequently asked questions
What is the correct answer to this question?
5
Why is this the correct answer?
Substituting \(x=2\) in the condition \(q(2)=0\) gives \(2^2-2k+6=0\), so \(10-2k=0\). Hence, \(2k=10\) and \(k=5\), making option C correct. Exam tip: If \(a\) is a zero of a polynomial, substitute \(x=a\) and set the polynomial equal to zero.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Polynomials in one variable.
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