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If \(p(x)=x^2-ax+18\) and \(p(3)=0\), what is the value of \(a\)?यदि \(p(x)=x^2-ax+18\) और \(p(3)=0\), तो \(a\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 99
Substituting \(x=3\) in the condition \(p(3)=0\) gives \(3^2-3a+18=0\), or \(27-3a=0\). Hence, \(3a=27\) and \(a=9\). Exam tip: when the value of a polynomial is given, substitute the specified value of \(x\) directly and solve the resulting equation.\(p(3)=0\) में \(x=3\) रखने पर \(3^2-3a+18=0\), अर्थात \(27-3a=0\)। इसलिए \(3a=27\) और \(a=9\)। परीक्षा में बहुपद का मान दिया हो तो संबंधित \(x\) का मान सीधे प्रतिस्थापित करके समीकरण बनाइए।
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