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If \(p(x)=kx^2-5x+6\) and \(p(-1)=14\), what is the value of \(k\)?
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Answer and explanation
Correct answer: 3
Substituting \(x=-1\) gives \(p(-1)=k(-1)^2-5(-1)+6=k+5+6=k+11\). Thus, \(k+11=14\), so \(k=3\). For instance, taking \(k=2\) gives 13, not 14. In the exam, check both \((-1)^2\) and the sign in \(-5(-1)\) carefully.
Frequently asked questions
What is the correct answer to this question?
3
Why is this the correct answer?
Substituting \(x=-1\) gives \(p(-1)=k(-1)^2-5(-1)+6=k+5+6=k+11\). Thus, \(k+11=14\), so \(k=3\). For instance, taking \(k=2\) gives 13, not 14. In the exam, check both \((-1)^2\) and the sign in \(-5(-1)\) carefully.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Polynomials in one variable.
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