Class 9 Mathematics - Exploring Algebraic Identities - Quadratic expressions Hard Quiz

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द्विघात व्यंजक \(3x^2-5x+7\) में \(x^2\) का गुणांक क्या है?

What is the coefficient of \(x^2\) in the quadratic expression \(3x^2-5x+7\)?

Explanation opens after your attempt
Correct Answer

A. (3)coefficient of \(x^2\)

Step 1

Concept

The number attached to \(x^2\) is (3). In exams check the sign while finding coefficients.

Step 2

Why this answer is correct

The correct answer is A. (3) / coefficient of \(x^2\). The number attached to \(x^2\) is (3). In exams check the sign while finding coefficients.

Step 3

Exam Tip

\(x^2\) के साथ लगी संख्या (3) है। परीक्षा में गुणांक निकालते समय चिन्ह भी देखें।

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व्यंजक \(2y^2+9y-11\) में स्थिर पद कौन-सा है?

Which is the constant term in the expression \(2y^2+9y-11\)?

Explanation opens after your attempt
Correct Answer

C. (-11)constant term

Step 1

Concept

The term without a variable is the constant term. In exams write the constant term with its sign.

Step 2

Why this answer is correct

The correct answer is C. (-11) / constant term. The term without a variable is the constant term. In exams write the constant term with its sign.

Step 3

Exam Tip

जिस पद में चर नहीं होता वही स्थिर पद होता है। परीक्षा में चिन्ह सहित स्थिर पद लिखें।

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\(x^2+6x+9\) को पूर्ण वर्ग के रूप में लिखें।

Write \(x^2+6x+9\) as a perfect square.

Explanation opens after your attempt
Correct Answer

A. ((x+3)2)correct perfect square

Step 1

Concept

\(9=3^2\) and \(6x=2\cdot x\cdot3\). In exams take the square root of the last term and match the middle term.

Step 2

Why this answer is correct

The correct answer is A. ((x+3)2) / correct perfect square. \(9=3^2\) and \(6x=2\cdot x\cdot3\). In exams take the square root of the last term and match the middle term.

Step 3

Exam Tip

\(9=3^2\) और \(6x=2\cdot x\cdot3\) है। परीक्षा में अंतिम पद का वर्गमूल लेकर मध्य पद मिलाएं।

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\(a^2-10a+25\) किस पूर्ण वर्ग के बराबर है?

Which perfect square is equal to \(a^2-10a+25\)?

Explanation opens after your attempt
Correct Answer

B. ((a-5)2)correct square

Step 1

Concept

The middle term \(-10a=-2\cdot a\cdot5\), so the sign is negative. In exams the sign of the middle term is decisive.

Step 2

Why this answer is correct

The correct answer is B. ((a-5)2) / correct square. The middle term \(-10a=-2\cdot a\cdot5\), so the sign is negative. In exams the sign of the middle term is decisive.

Step 3

Exam Tip

मध्य पद \(-10a=-2\cdot a\cdot5\) है इसलिए चिन्ह ऋणात्मक होगा। परीक्षा में मध्य पद का चिन्ह निर्णायक होता है।

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\(x^2+8x+15\) के दो रैखिक गुणनखंड कौन-से हैं?

What are the two linear factors of \(x^2+8x+15\)?

Explanation opens after your attempt
Correct Answer

A. ((x+3)(x+5))correct factors

Step 1

Concept

(3+5=8) and \(3\cdot5=15\). In exams match the sum with the middle coefficient and the product with the constant term.

Step 2

Why this answer is correct

The correct answer is A. ((x+3)(x+5)) / correct factors. (3+5=8) and \(3\cdot5=15\). In exams match the sum with the middle coefficient and the product with the constant term.

Step 3

Exam Tip

(3+5=8) और \(3\cdot5=15\) है। परीक्षा में योग मध्य गुणांक और गुणनफल स्थिर पद से मिलाएं।

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\(x^2-7x+12\) का गुणनखंड रूप क्या है?

What is the factorised form of \(x^2-7x+12\)?

Explanation opens after your attempt
Correct Answer

B. ((x-3)(x-4))correct factors

Step 1

Concept

(-3+(-4)=-7) and ((-3)(-4)=12). In exams use two negative signs when the constant is positive and the middle term is negative.

Step 2

Why this answer is correct

The correct answer is B. ((x-3)(x-4)) / correct factors. (-3+(-4)=-7) and ((-3)(-4)=12). In exams use two negative signs when the constant is positive and the middle term is negative.

Step 3

Exam Tip

(-3+(-4)=-7) और ((-3)(-4)=12) है। परीक्षा में धनात्मक स्थिर पद और ऋणात्मक मध्य पद पर दोनों चिन्ह ऋणात्मक लें।

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\(x^2+x-20\) को गुणनखंडित करें।

Factorise \(x^2+x-20\).

Explanation opens after your attempt
Correct Answer

A. ((x+5)(x-4))correct factors

Step 1

Concept

(5+(-4)=1) and (5\cdot(-4)=-20). In exams look for opposite signs when the constant is negative.

Step 2

Why this answer is correct

The correct answer is A. ((x+5)(x-4)) / correct factors. (5+(-4)=1) and (5\cdot(-4)=-20). In exams look for opposite signs when the constant is negative.

Step 3

Exam Tip

(5+(-4)=1) और (5\cdot(-4)=-20) है। परीक्षा में ऋणात्मक स्थिर पद के लिए विपरीत चिन्ह खोजें।

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\(3x^2+10x+8\) का सही गुणनखंड रूप चुनें।

Choose the correct factorised form of \(3x^2+10x+8\).

Explanation opens after your attempt
Correct Answer

A. ((3x+4)(x+2))correct factors

Step 1

Concept

In ((3x+4)(x+2)), the cross terms are (6x) and (4x). In exams their sum should be the middle term.

Step 2

Why this answer is correct

The correct answer is A. ((3x+4)(x+2)) / correct factors. In ((3x+4)(x+2)), the cross terms are (6x) and (4x). In exams their sum should be the middle term.

Step 3

Exam Tip

((3x+4)(x+2)) में क्रॉस पद (6x) और (4x) हैं। परीक्षा में क्रॉस पदों का योग मध्य पद होना चाहिए।

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\(4x^2-9\) को द्विघात पहचान से लिखें।

Write \(4x^2-9\) using a quadratic identity.

Explanation opens after your attempt
Correct Answer

B. ((2x-3)(2x+3))difference of squares

Step 1

Concept

(4x-2=(2x)2) and \(9=3^2\). In exams write difference of squares as ((a-b)(a+b)).

Step 2

Why this answer is correct

The correct answer is B. ((2x-3)(2x+3)) / difference of squares. (4x-2=(2x)2) and \(9=3^2\). In exams write difference of squares as ((a-b)(a+b)).

Step 3

Exam Tip

(4x-2=(2x)2) और \(9=3^2\) है। परीक्षा में वर्गों के अंतर को ((a-b)(a+b)) लिखें।

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\(9y^2-24y+16\) किसके बराबर है?

What is \(9y^2-24y+16\) equal to?

Explanation opens after your attempt
Correct Answer

B. ((3y-4)2)correct perfect square

Step 1

Concept

(9y-2=(3y)2), \(16=4^2\), and the middle term is (-24y). In exams match both square terms and the middle term.

Step 2

Why this answer is correct

The correct answer is B. ((3y-4)2) / correct perfect square. (9y-2=(3y)2), \(16=4^2\), and the middle term is (-24y). In exams match both square terms and the middle term.

Step 3

Exam Tip

(9y-2=(3y)2), \(16=4^2\), और मध्य पद (-24y) है। परीक्षा में दोनों वर्ग पद और मध्य पद मिलाएं।

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(x=2) होने पर \(x^2-5x+6\) का मान क्या होगा?

What is the value of \(x^2-5x+6\) when (x=2)?

Explanation opens after your attempt
Correct Answer

A. (0)correct value

Step 1

Concept

Substitution gives \(2^2-5\cdot2+6=0\). In exams do powers first, then multiplication, then addition or subtraction.

Step 2

Why this answer is correct

The correct answer is A. (0) / correct value. Substitution gives \(2^2-5\cdot2+6=0\). In exams do powers first, then multiplication, then addition or subtraction.

Step 3

Exam Tip

मान रखने पर \(2^2-5\cdot2+6=0\) मिलता है। परीक्षा में पहले घात फिर गुणा और फिर जोड़-घटाव करें।

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(t=-1) पर \(2t^2+3t-5\) का मान क्या है?

What is the value of \(2t^2+3t-5\) at (t=-1)?

Explanation opens after your attempt
Correct Answer

A. (-6)correct value

Step 1

Concept

(2(-1)2+3(-1)-5=2-3-5=-6). In exams the square of a negative number is positive.

Step 2

Why this answer is correct

The correct answer is A. (-6) / correct value. (2(-1)2+3(-1)-5=2-3-5=-6). In exams the square of a negative number is positive.

Step 3

Exam Tip

(2(-1)2+3(-1)-5=2-3-5=-6) है। परीक्षा में ऋणात्मक संख्या का वर्ग धनात्मक होता है।

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\(x^2+kx+16\) पूर्ण वर्ग हो और (k) धनात्मक हो तो (k) का मान क्या है?

If \(x^2+kx+16\) is a perfect square and (k) is positive, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

B. (8)correct middle coefficient

Step 1

Concept

\(16=4^2\), and in a perfect square the middle term is \(2\cdot x\cdot4=8x\). In exams double the root of the constant term.

Step 2

Why this answer is correct

The correct answer is B. (8) / correct middle coefficient. \(16=4^2\), and in a perfect square the middle term is \(2\cdot x\cdot4=8x\). In exams double the root of the constant term.

Step 3

Exam Tip

\(16=4^2\) और पूर्ण वर्ग में मध्य पद \(2\cdot x\cdot4=8x\) होगा। परीक्षा में स्थिर पद की जड़ को दोगुना करें।

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\(x^2-14x+c\) पूर्ण वर्ग हो तो (c) क्या होगा?

If \(x^2-14x+c\) is a perfect square, what is (c)?

Explanation opens after your attempt
Correct Answer

C. (49)square of half coefficient

Step 1

Concept

\(-14x=-2\cdot x\cdot7\), so \(c=7^2=49\). In exams take half of the middle coefficient and square it.

Step 2

Why this answer is correct

The correct answer is C. (49) / square of half coefficient. \(-14x=-2\cdot x\cdot7\), so \(c=7^2=49\). In exams take half of the middle coefficient and square it.

Step 3

Exam Tip

\(-14x=-2\cdot x\cdot7\), इसलिए \(c=7^2=49\) है। परीक्षा में मध्य गुणांक का आधा लेकर उसका वर्ग करें।

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\(x^2+px+21\) के गुणनखंड ((x+3)(x+7)) हैं। (p) का मान क्या है?

The factors of \(x^2+px+21\) are ((x+3)(x+7)). What is the value of (p)?

Explanation opens after your attempt
Correct Answer

C. (10)sum of constants

Step 1

Concept

((x+3)(x+7)=x-2+10x+21), so (p=10). In exams the middle term comes from the sum of the constants.

Step 2

Why this answer is correct

The correct answer is C. (10) / sum of constants. ((x+3)(x+7)=x-2+10x+21), so (p=10). In exams the middle term comes from the sum of the constants.

Step 3

Exam Tip

((x+3)(x+7)=x-2+10x+21), इसलिए (p=10) है। परीक्षा में मध्य पद स्थिर संख्याओं के योग से बनता है।

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\(x^2-11x+30\) के शून्य बनाने वाले गुणनखंड कौन-से हैं?

Which factors make \(x^2-11x+30\) zero?

Explanation opens after your attempt
Correct Answer

A. ((x-5)(x-6))correct factors

Step 1

Concept

(-5+(-6)=-11) and ((-5)(-6)=30). In exams verify by expanding the factors.

Step 2

Why this answer is correct

The correct answer is A. ((x-5)(x-6)) / correct factors. (-5+(-6)=-11) and ((-5)(-6)=30). In exams verify by expanding the factors.

Step 3

Exam Tip

(-5+(-6)=-11) और ((-5)(-6)=30) है। परीक्षा में गुणनखंड फैलाकर सत्यापन करें।

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कौन-सा द्विघात व्यंजक ((x-4)(x+2)) से प्राप्त होता है?

Which quadratic expression is obtained from ((x-4)(x+2))?

Explanation opens after your attempt
Correct Answer

A. \(x^2-2x-8\)correct expansion

Step 1

Concept

The cross terms (2x) and (-4x) combine to (-2x). In exams add outer and inner terms.

Step 2

Why this answer is correct

The correct answer is A. \(x^2-2x-8\) / correct expansion. The cross terms (2x) and (-4x) combine to (-2x). In exams add outer and inner terms.

Step 3

Exam Tip

क्रॉस पद (2x) और (-4x) मिलकर (-2x) देते हैं। परीक्षा में बाहरी और अंदरूनी पद जोड़ें।

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((2x-3)(x+5)) का विस्तार क्या है?

What is the expansion of ((2x-3)(x+5))?

Explanation opens after your attempt
Correct Answer

A. \(2x^2+7x-15\)correct expansion

Step 1

Concept

\(2x\cdot5=10x\) and \(-3\cdot x=-3x\), so the middle term is (7x). In exams write all four products.

Step 2

Why this answer is correct

The correct answer is A. \(2x^2+7x-15\) / correct expansion. \(2x\cdot5=10x\) and \(-3\cdot x=-3x\), so the middle term is (7x). In exams write all four products.

Step 3

Exam Tip

\(2x\cdot5=10x\) और \(-3\cdot x=-3x\), इसलिए मध्य पद (7x) है। परीक्षा में चारों गुणनफल लिखें।

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\(5x^2-20x+20\) में समान गुणनखंड निकालने के बाद अंदर कौन-सा द्विघात व्यंजक बचेगा?

After taking the common factor from \(5x^2-20x+20\), which quadratic expression remains inside?

Explanation opens after your attempt
Correct Answer

A. \(x^2-4x+4\)correct inside expression

Step 1

Concept

Taking common (5) gives (5\(x^2-4x+4\)). In exams first take the common factor and then apply identities.

Step 2

Why this answer is correct

The correct answer is A. \(x^2-4x+4\) / correct inside expression. Taking common (5) gives (5\(x^2-4x+4\)). In exams first take the common factor and then apply identities.

Step 3

Exam Tip

समान गुणनखंड (5) निकालने पर (5\(x^2-4x+4\)) मिलता है। परीक्षा में पहले समान गुणनखंड निकालें फिर पहचान लगाएं।

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\(3x^2-27\) का पूर्ण गुणनखंड रूप क्या है?

What is the complete factorised form of \(3x^2-27\)?

Explanation opens after your attempt
Correct Answer

A. (3(x-3)(x+3))correct complete form

Step 1

Concept

First take out (3), and \(x^2-9\) is a difference of squares. In exams factorise the inside expression too.

Step 2

Why this answer is correct

The correct answer is A. (3(x-3)(x+3)) / correct complete form. First take out (3), and \(x^2-9\) is a difference of squares. In exams factorise the inside expression too.

Step 3

Exam Tip

पहले (3) निकालें और \(x^2-9\) वर्गों का अंतर है। परीक्षा में अंदर की अभिव्यक्ति को भी गुणनखंडित करें।

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\(4x^2+12x+k\) पूर्ण वर्ग हो तो (k) क्या होगा?

If \(4x^2+12x+k\) is a perfect square, what is (k)?

Explanation opens after your attempt
Correct Answer

B. (9)correct constant

Step 1

Concept

(4x-2=(2x)2) and \(12x=2\cdot2x\cdot3\), so (k=9). In exams identify the second part using (2ab).

Step 2

Why this answer is correct

The correct answer is B. (9) / correct constant. (4x-2=(2x)2) and \(12x=2\cdot2x\cdot3\), so (k=9). In exams identify the second part using (2ab).

Step 3

Exam Tip

(4x-2=(2x)2) और \(12x=2\cdot2x\cdot3\), इसलिए (k=9) है। परीक्षा में (2ab) से दूसरा भाग पहचानें।

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\(9x^2+kx+25\) पूर्ण वर्ग हो और (k) ऋणात्मक हो तो (k) क्या है?

If \(9x^2+kx+25\) is a perfect square and (k) is negative, what is (k)?

Explanation opens after your attempt
Correct Answer

B. (-30)correct middle

Step 1

Concept

(9x-2=(3x)2), \(25=5^2\), so the middle term is \(-2\cdot3x\cdot5=-30x\). In exams follow the given sign.

Step 2

Why this answer is correct

The correct answer is B. (-30) / correct middle. (9x-2=(3x)2), \(25=5^2\), so the middle term is \(-2\cdot3x\cdot5=-30x\). In exams follow the given sign.

Step 3

Exam Tip

(9x-2=(3x)2), \(25=5^2\), इसलिए मध्य पद \(-2\cdot3x\cdot5=-30x\) है। परीक्षा में दिए गए चिन्ह का पालन करें।

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\(x^2+2xy-15y^2\) का गुणनखंड रूप क्या है?

What is the factorised form of \(x^2+2xy-15y^2\)?

Explanation opens after your attempt
Correct Answer

A. ((x+5y)(x-3y))correct factors

Step 1

Concept

(5y+(-3y)=2y) and (5y\cdot(-3y)=-15y-2). In exams add the factors along with variables.

Step 2

Why this answer is correct

The correct answer is A. ((x+5y)(x-3y)) / correct factors. (5y+(-3y)=2y) and (5y\cdot(-3y)=-15y-2). In exams add the factors along with variables.

Step 3

Exam Tip

(5y+(-3y)=2y) और (5y\cdot(-3y)=-15y-2) है। परीक्षा में चर सहित गुणनखंडों का योग करें।

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\(2a^2+ab-6b^2\) के गुणनखंड कौन-से हैं?

What are the factors of \(2a^2+ab-6b^2\)?

Explanation opens after your attempt
Correct Answer

A. ((2a-3b)(a+2b))correct factors

Step 1

Concept

((2a-3b)(a+2b)=2a-2+ab-6b-2). In exams add cross terms to check the middle term.

Step 2

Why this answer is correct

The correct answer is A. ((2a-3b)(a+2b)) / correct factors. ((2a-3b)(a+2b)=2a-2+ab-6b-2). In exams add cross terms to check the middle term.

Step 3

Exam Tip

((2a-3b)(a+2b)=2a-2+ab-6b-2) है। परीक्षा में क्रॉस पदों को जोड़कर मध्य पद जांचें।

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\(6p^2+5pq-q^2\) का सही गुणनखंड रूप चुनें।

Choose the correct factorised form of \(6p^2+5pq-q^2\).

Explanation opens after your attempt
Correct Answer

A. ((3p-q)(2p+q))correct factors

Step 1

Concept

Actually ((3p-q)(2p+q)) gives \(6p^2+pq-q^2\). Check the cross terms carefully in exams.

Step 2

Why this answer is correct

The correct answer is A. ((3p-q)(2p+q)) / correct factors. Actually ((3p-q)(2p+q)) gives \(6p^2+pq-q^2\). Check the cross terms carefully in exams.

Step 3

Exam Tip

क्रॉस पद (3pq) और (-2pq) नहीं, सही रूप में \(3p\cdot q=3pq\) और \(-q\cdot2p=-2pq\) से (pq) मिलता है?

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\(6p^2+5pq-q^2\) का सही गुणनखंड रूप कौन-सा है?

Which is the correct factorised form of \(6p^2+5pq-q^2\)?

Explanation opens after your attempt
Correct Answer

A. ((6p-q)(p+q))correct factors

Step 1

Concept

((6p-q)(p+q)=6p-2+5pq-q-2). In exams always expand the option and check cross terms.

Step 2

Why this answer is correct

The correct answer is A. ((6p-q)(p+q)) / correct factors. ((6p-q)(p+q)=6p-2+5pq-q-2). In exams always expand the option and check cross terms.

Step 3

Exam Tip

((6p-q)(p+q)=6p-2+5pq-q-2) है। परीक्षा में विकल्प को फैलाकर क्रॉस पद जरूर जांचें।

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\(x^2+4x+4-y^2\) का पूर्ण गुणनखंड रूप क्या है?

What is the complete factorised form of \(x^2+4x+4-y^2\)?

Explanation opens after your attempt
Correct Answer

A. ((x+2-y)(x+2+y))correct form

Step 1

Concept

First (x-2+4x+4=(x+2)2), then apply difference of squares. In exams do not stop at the partial form.

Step 2

Why this answer is correct

The correct answer is A. ((x+2-y)(x+2+y)) / correct form. First (x-2+4x+4=(x+2)2), then apply difference of squares. In exams do not stop at the partial form.

Step 3

Exam Tip

पहले (x-2+4x+4=(x+2)2), फिर वर्गों का अंतर लगाएं। परीक्षा में आंशिक रूप पर न रुकें।

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\(x^2-6x+9-z^2\) को गुणनखंडित करें।

Factorise \(x^2-6x+9-z^2\).

Explanation opens after your attempt
Correct Answer

A. ((x-3-z)(x-3+z))correct form

Step 1

Concept

First (x-2-6x+9=(x-3)2), then use the \(a^2-b^2\) identity. In exams identify the perfect-square group.

Step 2

Why this answer is correct

The correct answer is A. ((x-3-z)(x-3+z)) / correct form. First (x-2-6x+9=(x-3)2), then use the \(a^2-b^2\) identity. In exams identify the perfect-square group.

Step 3

Exam Tip

पहले (x-2-6x+9=(x-3)2), फिर (\(a^2-b^2\)) पहचान लगती है। परीक्षा में पूर्ण वर्ग समूह पहचानें।

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\(x^2+ax+24\) का एक गुणनखंड (x+6) है। दूसरा गुणनखंड (x+4) हो तो (a) क्या है?

One factor of \(x^2+ax+24\) is (x+6). If the other factor is (x+4), what is (a)?

Explanation opens after your attempt
Correct Answer

A. (10)correct coefficient

Step 1

Concept

((x+6)(x+4)=x-2+10x+24), so (a=10). In exams add the constant parts of the factors.

Step 2

Why this answer is correct

The correct answer is A. (10) / correct coefficient. ((x+6)(x+4)=x-2+10x+24), so (a=10). In exams add the constant parts of the factors.

Step 3

Exam Tip

((x+6)(x+4)=x-2+10x+24), इसलिए (a=10) है। परीक्षा में गुणनखंडों के स्थिर भाग जोड़ें।

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\(x^2-bx+18\) के गुणनखंड ((x-3)(x-6)) हैं। (b) क्या है?

The factors of \(x^2-bx+18\) are ((x-3)(x-6)). What is (b)?

Explanation opens after your attempt
Correct Answer

C. (9)correct value

Step 1

Concept

((x-3)(x-6)=x-2-9x+18), so (b=9). In exams (b) remains positive because the expression has (-bx).

Step 2

Why this answer is correct

The correct answer is C. (9) / correct value. ((x-3)(x-6)=x-2-9x+18), so (b=9). In exams (b) remains positive because the expression has (-bx).

Step 3

Exam Tip

((x-3)(x-6)=x-2-9x+18), इसलिए (b=9) है। परीक्षा में ऋण चिन्ह के कारण (b) धनात्मक रहता है।

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\(2x^2+mx+10\) का गुणनखंड रूप ((2x+5)(x+2)) है। (m) क्या होगा?

The factorised form of \(2x^2+mx+10\) is ((2x+5)(x+2)). What is (m)?

Explanation opens after your attempt
Correct Answer

C. (9)correct middle coefficient

Step 1

Concept

The cross terms are (4x) and (5x), whose sum is (9x). In exams add both cross terms.

Step 2

Why this answer is correct

The correct answer is C. (9) / correct middle coefficient. The cross terms are (4x) and (5x), whose sum is (9x). In exams add both cross terms.

Step 3

Exam Tip

क्रॉस पद (4x) और (5x) हैं, जिनका योग (9x) है। परीक्षा में दोनों क्रॉस पद जोड़ें।

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कौन-सा (k), \(x^2+kx+81\) को पूर्ण वर्ग बनाएगा और (k) ऋणात्मक है?

Which (k) makes \(x^2+kx+81\) a perfect square and (k) is negative?

Explanation opens after your attempt
Correct Answer

B. (-18)correct middle

Step 1

Concept

\(81=9^2\), so the negative middle term is \(-2\cdot x\cdot9=-18x\). In exams do not forget the given sign.

Step 2

Why this answer is correct

The correct answer is B. (-18) / correct middle. \(81=9^2\), so the negative middle term is \(-2\cdot x\cdot9=-18x\). In exams do not forget the given sign.

Step 3

Exam Tip

\(81=9^2\), इसलिए ऋणात्मक मध्य पद \(-2\cdot x\cdot9=-18x\) होगा। परीक्षा में दिए गए चिन्ह को न भूलें।

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\(x^2-4x+5\) को पूर्ण वर्ग जोड़कर किस रूप में लिखा जा सकता है?

How can \(x^2-4x+5\) be written by completing the square?

Explanation opens after your attempt
Correct Answer

A. ((x-2)2+1)correct form

Step 1

Concept

(x-2-4x+4=(x-2)2), so write (5) as (4+1). In exams take half of the middle coefficient.

Step 2

Why this answer is correct

The correct answer is A. ((x-2)2+1) / correct form. (x-2-4x+4=(x-2)2), so write (5) as (4+1). In exams take half of the middle coefficient.

Step 3

Exam Tip

(x-2-4x+4=(x-2)2), इसलिए (5) को (4+1) लिखते हैं। परीक्षा में मध्य गुणांक का आधा लें।

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\(x^2+6x+11\) को पूर्ण वर्ग रूप में लिखें।

Write \(x^2+6x+11\) in completed square form.

Explanation opens after your attempt
Correct Answer

A. ((x+3)2+2)correct form

Step 1

Concept

(x-2+6x+9=(x+3)2), so (11=9+2). In exams form the needed square and keep the remainder separate.

Step 2

Why this answer is correct

The correct answer is A. ((x+3)2+2) / correct form. (x-2+6x+9=(x+3)2), so (11=9+2). In exams form the needed square and keep the remainder separate.

Step 3

Exam Tip

(x-2+6x+9=(x+3)2), इसलिए (11=9+2) है। परीक्षा में आवश्यक वर्ग जोड़कर शेष अलग रखें।

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\(x^2-8x+13\) का पूर्ण वर्ग रूप कौन-सा है?

Which is the completed square form of \(x^2-8x+13\)?

Explanation opens after your attempt
Correct Answer

A. ((x-4)2-3)correct form

Step 1

Concept

(x-2-8x+16=(x-4)2) and (13=16-3). In exams balance the square that was added.

Step 2

Why this answer is correct

The correct answer is A. ((x-4)2-3) / correct form. (x-2-8x+16=(x-4)2) and (13=16-3). In exams balance the square that was added.

Step 3

Exam Tip

(x-2-8x+16=(x-4)2) और (13=16-3) है। परीक्षा में जो वर्ग जोड़ा गया है उसे संतुलित करें।

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यदि (x+y=7) और (xy=10), तो \(x^2+y^2\) का मान क्या है?

If (x+y=7) and (xy=10), what is the value of \(x^2+y^2\)?

Explanation opens after your attempt
Correct Answer

A. (29)correct value

Step 1

Concept

(x-2+y-2=(x+y)2-2xy=49-20=29). In exams use the square of sum identity.

Step 2

Why this answer is correct

The correct answer is A. (29) / correct value. (x-2+y-2=(x+y)2-2xy=49-20=29). In exams use the square of sum identity.

Step 3

Exam Tip

(x-2+y-2=(x+y)2-2xy=49-20=29) है। परीक्षा में योग के वर्ग की पहचान उपयोग करें।

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यदि (a-b=5) और (ab=6), तो \(a^2+b^2\) क्या होगा?

If (a-b=5) and (ab=6), what is \(a^2+b^2\)?

Explanation opens after your attempt
Correct Answer

C. (37)correct value

Step 1

Concept

(a-2+b-2=(a-b)2+2ab=25+12=37). In exams add (2ab) when using the square of difference identity.

Step 2

Why this answer is correct

The correct answer is C. (37) / correct value. (a-2+b-2=(a-b)2+2ab=25+12=37). In exams add (2ab) when using the square of difference identity.

Step 3

Exam Tip

(a-2+b-2=(a-b)2+2ab=25+12=37) है। परीक्षा में अंतर के वर्ग की पहचान में (+2ab) जोड़ें।

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यदि (p+q=9) और \(p^2+q^2=41\), तो (pq) क्या है?

If (p+q=9) and \(p^2+q^2=41\), what is (pq)?

Explanation opens after your attempt
Correct Answer

A. (20)correct value

Step 1

Concept

((p+q)2=p-2+q-2+2pq), so (81=41+2pq) and (pq=20). In exams find (2pq) first.

Step 2

Why this answer is correct

The correct answer is A. (20) / correct value. ((p+q)2=p-2+q-2+2pq), so (81=41+2pq) and (pq=20). In exams find (2pq) first.

Step 3

Exam Tip

((p+q)2=p-2+q-2+2pq), इसलिए (81=41+2pq) और (pq=20) है। परीक्षा में (2pq) पहले निकालें।

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यदि (m-n=4) और \(m^2+n^2=34\), तो (mn) क्या है?

If (m-n=4) and \(m^2+n^2=34\), what is (mn)?

Explanation opens after your attempt
Correct Answer

A. (9)correct value

Step 1

Concept

((m-n)2=m-2+n-2-2mn), so (16=34-2mn) and (mn=9). In exams pay attention to the sign.

Step 2

Why this answer is correct

The correct answer is A. (9) / correct value. ((m-n)2=m-2+n-2-2mn), so (16=34-2mn) and (mn=9). In exams pay attention to the sign.

Step 3

Exam Tip

((m-n)2=m-2+n-2-2mn), इसलिए (16=34-2mn) और (mn=9) है। परीक्षा में चिन्ह पर ध्यान दें।

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\(2x^2-3x-2\) का गुणनखंड रूप क्या है?

What is the factorised form of \(2x^2-3x-2\)?

Explanation opens after your attempt
Correct Answer

A. ((2x+1)(x-2))correct factors

Step 1

Concept

((2x+1)(x-2)=2x-2-3x-2). In exams check opposite signs when the constant term is negative.

Step 2

Why this answer is correct

The correct answer is A. ((2x+1)(x-2)) / correct factors. ((2x+1)(x-2)=2x-2-3x-2). In exams check opposite signs when the constant term is negative.

Step 3

Exam Tip

((2x+1)(x-2)=2x-2-3x-2) है। परीक्षा में ऋणात्मक स्थिर पद पर विपरीत चिन्हों को जांचें।

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\(5x^2+13x+6\) के गुणनखंड कौन-से हैं?

What are the factors of \(5x^2+13x+6\)?

Explanation opens after your attempt
Correct Answer

A. ((5x+3)(x+2))correct factors

Step 1

Concept

The cross terms (10x) and (3x) combine to (13x). In exams check options using both leading coefficient and constant term.

Step 2

Why this answer is correct

The correct answer is A. ((5x+3)(x+2)) / correct factors. The cross terms (10x) and (3x) combine to (13x). In exams check options using both leading coefficient and constant term.

Step 3

Exam Tip

क्रॉस पद (10x) और (3x) मिलकर (13x) देते हैं। परीक्षा में अग्र गुणांक और स्थिर पद दोनों से विकल्प जांचें।

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\(6x^2-x-2\) का सही गुणनखंड रूप चुनें।

Choose the correct factorised form of \(6x^2-x-2\).

Explanation opens after your attempt
Correct Answer

A. ((3x-2)(2x+1))correct factors

Step 1

Concept

((3x-2)(2x+1)=6x-2-x-2). In exams add cross terms (3x) and (-4x).

Step 2

Why this answer is correct

The correct answer is A. ((3x-2)(2x+1)) / correct factors. ((3x-2)(2x+1)=6x-2-x-2). In exams add cross terms (3x) and (-4x).

Step 3

Exam Tip

((3x-2)(2x+1)=6x-2-x-2) है। परीक्षा में क्रॉस पद (3x) और (-4x) जोड़ें।

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\(12x^2+7x-12\) का गुणनखंड रूप क्या है?

What is the factorised form of \(12x^2+7x-12\)?

Explanation opens after your attempt
Correct Answer

A. ((3x+4)(4x-3))correct factors

Step 1

Concept

((3x+4)(4x-3)=12x-2+7x-12). In exams check that (16x-9x=7x).

Step 2

Why this answer is correct

The correct answer is A. ((3x+4)(4x-3)) / correct factors. ((3x+4)(4x-3)=12x-2+7x-12). In exams check that (16x-9x=7x).

Step 3

Exam Tip

((3x+4)(4x-3)=12x-2+7x-12) है। परीक्षा में (16x-9x=7x) जांचें।

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\(7-4x+2x^2\) को मानक द्विघात रूप में लिखें।

Write \(7-4x+2x^2\) in standard quadratic form.

Explanation opens after your attempt
Correct Answer

A. \(2x^2-4x+7\)correct standard form

Step 1

Concept

In standard form, the \(x^2\) term comes first, then the (x) term, then the constant term. In exams arrange terms in descending powers.

Step 2

Why this answer is correct

The correct answer is A. \(2x^2-4x+7\) / correct standard form. In standard form, the \(x^2\) term comes first, then the (x) term, then the constant term. In exams arrange terms in descending powers.

Step 3

Exam Tip

मानक रूप में \(x^2\) वाला पद पहले, फिर (x) वाला पद और फिर स्थिर पद आता है। परीक्षा में पदों को घात के घटते क्रम में रखें।

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\(x^2+10x+24\) को ((x+a)(x+b)) रूप में लिखने पर (a+b) क्या होगा?

When \(x^2+10x+24\) is written as ((x+a)(x+b)), what is (a+b)?

Explanation opens after your attempt
Correct Answer

A. (10)correct sum

Step 1

Concept

((x+a)(x+b)=x-2+(a+b)x+ab), so (a+b=10). In exams treat the middle coefficient as (a+b).

Step 2

Why this answer is correct

The correct answer is A. (10) / correct sum. ((x+a)(x+b)=x-2+(a+b)x+ab), so (a+b=10). In exams treat the middle coefficient as (a+b).

Step 3

Exam Tip

((x+a)(x+b)=x-2+(a+b)x+ab), इसलिए (a+b=10) है। परीक्षा में मध्य गुणांक को (a+b) मानें।

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यदि (x-2+sx+35=(x+5)(x+7)), तो (s) क्या है?

If (x-2+sx+35=(x+5)(x+7)), what is (s)?

Explanation opens after your attempt
Correct Answer

C. (12)correct sum

Step 1

Concept

((x+5)(x+7)=x-2+12x+35), so (s=12). In exams the sum of constant parts is the middle coefficient.

Step 2

Why this answer is correct

The correct answer is C. (12) / correct sum. ((x+5)(x+7)=x-2+12x+35), so (s=12). In exams the sum of constant parts is the middle coefficient.

Step 3

Exam Tip

((x+5)(x+7)=x-2+12x+35), इसलिए (s=12) है। परीक्षा में स्थिर भागों का योग मध्य गुणांक होता है।

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\(x^2-16x+64\) के लिए सही कथन कौन-सा है?

Which statement is correct for \(x^2-16x+64\)?

Explanation opens after your attempt
Correct Answer

A. यह ((x-8)2) हैit is ((x-8)2)

Step 1

Concept

\(64=8^2\) and \(-16x=-2\cdot x\cdot8\). In exams check both the last term and the middle term in a perfect square.

Step 2

Why this answer is correct

The correct answer is A. यह ((x-8)2) है / it is ((x-8)2). \(64=8^2\) and \(-16x=-2\cdot x\cdot8\). In exams check both the last term and the middle term in a perfect square.

Step 3

Exam Tip

\(64=8^2\) और \(-16x=-2\cdot x\cdot8\) है। परीक्षा में पूर्ण वर्ग में अंतिम पद और मध्य पद दोनों जांचें।

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\(3x^2+14x+8\) का सही गुणनखंड रूप क्या है?

What is the correct factorised form of \(3x^2+14x+8\)?

Explanation opens after your attempt
Correct Answer

A. ((3x+2)(x+4))सही गुणनखंड

Step 1

Concept

((3x+2)(x+4)=3x-2+14x+8). In exams check by adding the cross terms (12x) and (2x).

Step 2

Why this answer is correct

The correct answer is A. ((3x+2)(x+4)) / सही गुणनखंड. ((3x+2)(x+4)=3x-2+14x+8). In exams check by adding the cross terms (12x) and (2x).

Step 3

Exam Tip

((3x+2)(x+4)=3x-2+14x+8) है। परीक्षा में क्रॉस पदों (12x) और (2x) को जोड़कर जांचें।

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\(x^2-12x+20\) को पूर्ण वर्ग रूप में लिखें।

Write \(x^2-12x+20\) in completed square form.

Explanation opens after your attempt
Correct Answer

A. ((x-6)2-16)सही रूप

Step 1

Concept

(x-2-12x+36=(x-6)2) and (20=36-16). In exams take half of the middle coefficient and form its square.

Step 2

Why this answer is correct

The correct answer is A. ((x-6)2-16) / सही रूप. (x-2-12x+36=(x-6)2) and (20=36-16). In exams take half of the middle coefficient and form its square.

Step 3

Exam Tip

(x-2-12x+36=(x-6)2) और (20=36-16) है। परीक्षा में मध्य गुणांक का आधा लेकर उसका वर्ग बनाएं।

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यदि (u+v=11) और (uv=28), तो \(u^2+v^2\) का मान क्या होगा?

If (u+v=11) and (uv=28), what is the value of \(u^2+v^2\)?

Explanation opens after your attempt
Correct Answer

A. (65)सही मान

Step 1

Concept

(u-2+v-2=(u+v)2-2uv=121-56=65). In exams subtract (2uv) from the square of the sum.

Step 2

Why this answer is correct

The correct answer is A. (65) / सही मान. (u-2+v-2=(u+v)2-2uv=121-56=65). In exams subtract (2uv) from the square of the sum.

Step 3

Exam Tip

(u-2+v-2=(u+v)2-2uv=121-56=65) है। परीक्षा में योग के वर्ग से (2uv) घटाएं।

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FAQs

Class 9 Mathematics Quiz FAQs

How many questions are in this quiz?

This level is designed for 50 active questions. Currently 50 questions are available for the selected class and difficulty.

Is there a timer in this quiz?

Yes, the timer uses 30 seconds per question for Hard difficulty and shows the total remaining time on the page.

Can I open each question separately?

Yes, every question has its own SEO-friendly page with answer, explanation and related practice links.