\(x^2+px+21\) के गुणनखंड ((x+3)(x+7)) हैं। (p) का मान क्या है?
The factors of \(x^2+px+21\) are ((x+3)(x+7)). What is the value of (p)?
Explanation opens after your attempt
C. (10)sum of constants
Concept
((x+3)(x+7)=x-2+10x+21), so (p=10). In exams the middle term comes from the sum of the constants.
Why this answer is correct
The correct answer is C. (10) / sum of constants. ((x+3)(x+7)=x-2+10x+21), so (p=10). In exams the middle term comes from the sum of the constants.
Exam Tip
((x+3)(x+7)=x-2+10x+21), इसलिए (p=10) है। परीक्षा में मध्य पद स्थिर संख्याओं के योग से बनता है।
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