\(x^2-16x+64\) के लिए सही कथन कौन-सा है?

Which statement is correct for \(x^2-16x+64\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. यह ((x-8)2) हैit is ((x-8)2)

Step 1

Concept

\(64=8^2\) and \(-16x=-2\cdot x\cdot8\). In exams check both the last term and the middle term in a perfect square.

Step 2

Why this answer is correct

The correct answer is A. यह ((x-8)2) है / it is ((x-8)2). \(64=8^2\) and \(-16x=-2\cdot x\cdot8\). In exams check both the last term and the middle term in a perfect square.

Step 3

Exam Tip

\(64=8^2\) और \(-16x=-2\cdot x\cdot8\) है। परीक्षा में पूर्ण वर्ग में अंतिम पद और मध्य पद दोनों जांचें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

\(x^2-16x+64\) के लिए सही कथन कौन-सा है? / Which statement is correct for \(x^2-16x+64\)?

Correct Answer: A. यह ((x-8)2) है / it is ((x-8)2). Explanation: \(64=8^2\) और \(-16x=-2\cdot x\cdot8\) है। परीक्षा में पूर्ण वर्ग में अंतिम पद और मध्य पद दोनों जांचें। / \(64=8^2\) and \(-16x=-2\cdot x\cdot8\). In exams check both the last term and the middle term in a perfect square.

Which concept should I revise for this Mathematics MCQ?

\(64=8^2\) and \(-16x=-2\cdot x\cdot8\). In exams check both the last term and the middle term in a perfect square.

What exam hint can help solve this Mathematics question?

\(64=8^2\) और \(-16x=-2\cdot x\cdot8\) है। परीक्षा में पूर्ण वर्ग में अंतिम पद और मध्य पद दोनों जांचें।