\(5x^2-20x+20\) में समान गुणनखंड निकालने के बाद अंदर कौन-सा द्विघात व्यंजक बचेगा?
After taking the common factor from \(5x^2-20x+20\), which quadratic expression remains inside?
Explanation opens after your attempt
A. \(x^2-4x+4\)correct inside expression
Concept
Taking common (5) gives (5\(x^2-4x+4\)). In exams first take the common factor and then apply identities.
Why this answer is correct
The correct answer is A. \(x^2-4x+4\) / correct inside expression. Taking common (5) gives (5\(x^2-4x+4\)). In exams first take the common factor and then apply identities.
Exam Tip
समान गुणनखंड (5) निकालने पर (5\(x^2-4x+4\)) मिलता है। परीक्षा में पहले समान गुणनखंड निकालें फिर पहचान लगाएं।
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