\(5x^2-20x+20\) में समान गुणनखंड निकालने के बाद अंदर कौन-सा द्विघात व्यंजक बचेगा?

After taking the common factor from \(5x^2-20x+20\), which quadratic expression remains inside?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(x^2-4x+4\)correct inside expression

Step 1

Concept

Taking common (5) gives (5\(x^2-4x+4\)). In exams first take the common factor and then apply identities.

Step 2

Why this answer is correct

The correct answer is A. \(x^2-4x+4\) / correct inside expression. Taking common (5) gives (5\(x^2-4x+4\)). In exams first take the common factor and then apply identities.

Step 3

Exam Tip

समान गुणनखंड (5) निकालने पर (5\(x^2-4x+4\)) मिलता है। परीक्षा में पहले समान गुणनखंड निकालें फिर पहचान लगाएं।

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\(5x^2-20x+20\) में समान गुणनखंड निकालने के बाद अंदर कौन-सा द्विघात व्यंजक बचेगा? / After taking the common factor from \(5x^2-20x+20\), which quadratic expression remains inside?

Correct Answer: A. \(x^2-4x+4\) / correct inside expression. Explanation: समान गुणनखंड (5) निकालने पर (5\(x^2-4x+4\)) मिलता है। परीक्षा में पहले समान गुणनखंड निकालें फिर पहचान लगाएं। / Taking common (5) gives (5\(x^2-4x+4\)). In exams first take the common factor and then apply identities.

Which concept should I revise for this Mathematics MCQ?

Taking common (5) gives (5\(x^2-4x+4\)). In exams first take the common factor and then apply identities.

What exam hint can help solve this Mathematics question?

समान गुणनखंड (5) निकालने पर (5\(x^2-4x+4\)) मिलता है। परीक्षा में पहले समान गुणनखंड निकालें फिर पहचान लगाएं।