Class 11 Mathematics - Permutations And Combinations - Combinations Easy Quiz

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यदि (f(x)=2x+3) और (g(x)=x-5), तो ((f+g)(x)) क्या है?

If (f(x)=2x+3) and (g(x)=x-5), what is ((f+g)(x))?

Explanation opens after your attempt
Correct Answer

A. (3x-2)

Step 1

Concept

((f+g)(x)=(2x+3)+(x-5)=3x-2). While adding, combine only like terms.

Step 2

Why this answer is correct

The correct answer is A. (3x-2). ((f+g)(x)=(2x+3)+(x-5)=3x-2). While adding, combine only like terms.

Step 3

Exam Tip

((f+g)(x)=(2x+3)+(x-5)=3x-2)। जोड़ते समय समान पदों को ही जोड़ें।

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यदि (f(x)=7x-4) और (g(x)=2x+9), तो ((f-g)(x)) ज्ञात कीजिए।

If (f(x)=7x-4) and (g(x)=2x+9), find ((f-g)(x)).

Explanation opens after your attempt
Correct Answer

B. (5x-13)

Step 1

Concept

((f-g)(x)=(7x-4)-(2x+9)=5x-13). In subtraction, change all signs of the second bracket.

Step 2

Why this answer is correct

The correct answer is B. (5x-13). ((f-g)(x)=(7x-4)-(2x+9)=5x-13). In subtraction, change all signs of the second bracket.

Step 3

Exam Tip

((f-g)(x)=(7x-4)-(2x+9)=5x-13)। घटाने में दूसरे कोष्ठक के सभी चिह्न बदलें।

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यदि (f(x)=x+6) और (g(x)=x-2), तो ((fg)(x)) क्या होगा?

If (f(x)=x+6) and (g(x)=x-2), what will ((fg)(x)) be?

Explanation opens after your attempt
Correct Answer

A. \(x^2+4x-12\)

Step 1

Concept

((fg)(x)=(x+6)(x-2)=x-2+4x-12). In multiplication, multiply each term correctly.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+4x-12\). ((fg)(x)=(x+6)(x-2)=x-2+4x-12). In multiplication, multiply each term correctly.

Step 3

Exam Tip

((fg)(x)=(x+6)(x-2)=x-2+4x-12)। गुणन में हर पद को सही पद से गुणा करें।

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यदि (f(x)=4x-2+8x) और (g(x)=4x), तो (\left\(\frac{f}{g}\right\)(x)) क्या है, जहाँ \(x\neq0\)?

If (f(x)=4x-2+8x) and (g(x)=4x), what is (\left\(\frac{f}{g}\right\)(x)), where \(x\neq0\)?

Explanation opens after your attempt
Correct Answer

A. (x+2)

Step 1

Concept

(\frac{4x-2+8x}{4x}=\frac{4x(x+2)}{4x}=x+2), where \(x\neq0\). Check the denominator condition before cancellation.

Step 2

Why this answer is correct

The correct answer is A. (x+2). (\frac{4x-2+8x}{4x}=\frac{4x(x+2)}{4x}=x+2), where \(x\neq0\). Check the denominator condition before cancellation.

Step 3

Exam Tip

(\frac{4x-2+8x}{4x}=\frac{4x(x+2)}{4x}=x+2), जहाँ \(x\neq0\)। काटने से पहले हर की शर्त देखें।

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यदि (f(x)=x-2+2) और (g(x)=3x-1), तो ((f+g)(2)) का मान क्या है?

If (f(x)=x-2+2) and (g(x)=3x-1), what is the value of ((f+g)(2))?

Explanation opens after your attempt
Correct Answer

C. (11)

Step 1

Concept

((f+g)(2)=f(2)+g(2)=6+5=11). Add only after substituting the value.

Step 2

Why this answer is correct

The correct answer is C. (11). ((f+g)(2)=f(2)+g(2)=6+5=11). Add only after substituting the value.

Step 3

Exam Tip

((f+g)(2)=f(2)+g(2)=6+5=11)। मान रखने के बाद ही जोड़ करें।

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यदि (f(x)=5x+2) और (g(x)=x-2), तो ((f-g)(3)) का मान क्या होगा?

If (f(x)=5x+2) and (g(x)=x-2), what will be the value of ((f-g)(3))?

Explanation opens after your attempt
Correct Answer

A. (8)

Step 1

Concept

((f-g)(3)=f(3)-g(3)=17-9=8). Changing the order may change the answer.

Step 2

Why this answer is correct

The correct answer is A. (8). ((f-g)(3)=f(3)-g(3)=17-9=8). Changing the order may change the answer.

Step 3

Exam Tip

((f-g)(3)=f(3)-g(3)=17-9=8)। क्रम बदलने से उत्तर बदल सकता है।

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यदि (f(x)=2x-1) और (g(x)=x+4), तो ((fg)(2)) क्या है?

If (f(x)=2x-1) and (g(x)=x+4), what is ((fg)(2))?

Explanation opens after your attempt
Correct Answer

B. (18)

Step 1

Concept

((fg)(2)=f(2)g(2)=3\cdot6=18). In product, multiply the values of the functions.

Step 2

Why this answer is correct

The correct answer is B. (18). ((fg)(2)=f(2)g(2)=3\cdot6=18). In product, multiply the values of the functions.

Step 3

Exam Tip

((fg)(2)=f(2)g(2)=3\cdot6=18)। गुणन में फलनों के मानों का गुणा करें।

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यदि (f(x)=x-2-16) और (g(x)=x-4), तो (\left\(\frac{f}{g}\right\)(5)) का मान क्या है?

If (f(x)=x-2-16) and (g(x)=x-4), what is the value of (\left\(\frac{f}{g}\right\)(5))?

Explanation opens after your attempt
Correct Answer

C. (9)

Step 1

Concept

(\left\(\frac{f}{g}\right\)(5)=\frac{25-16}{5-4}=9). In division, the denominator value must not be zero.

Step 2

Why this answer is correct

The correct answer is C. (9). (\left\(\frac{f}{g}\right\)(5)=\frac{25-16}{5-4}=9). In division, the denominator value must not be zero.

Step 3

Exam Tip

(\left\(\frac{f}{g}\right\)(5)=\frac{25-16}{5-4}=9)। भाग में हर का मान शून्य नहीं होना चाहिए।

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यदि (f(x)=3x-2) और (g(x)=2x-2+1), तो ((f+g)(x)) किसके बराबर है?

If (f(x)=3x-2) and (g(x)=2x-2+1), then ((f+g)(x)) is equal to which expression?

Explanation opens after your attempt
Correct Answer

A. \(5x^2+1\)

Step 1

Concept

((f+g)(x)=3x-2+2x-2+1=5x-2+1). Add terms with the same power.

Step 2

Why this answer is correct

The correct answer is A. \(5x^2+1\). ((f+g)(x)=3x-2+2x-2+1=5x-2+1). Add terms with the same power.

Step 3

Exam Tip

((f+g)(x)=3x-2+2x-2+1=5x-2+1)। समान घात वाले पद जोड़ें।

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यदि (f(x)=9x-2) और (g(x)=4x-7), तो ((f-g)(x)) क्या होगा?

If (f(x)=9x-2) and (g(x)=4x-7), what is ((f-g)(x))?

Explanation opens after your attempt
Correct Answer

A. (5x+5)

Step 1

Concept

((f-g)(x)=9x-2-(4x-7)=5x+5). Write (-(-7)) as (+7).

Step 2

Why this answer is correct

The correct answer is A. (5x+5). ((f-g)(x)=9x-2-(4x-7)=5x+5). Write (-(-7)) as (+7).

Step 3

Exam Tip

((f-g)(x)=9x-2-(4x-7)=5x+5)। (-(-7)) को (+7) लिखें।

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यदि (f(x)=x-3) और (g(x)=2x), तो ((fg)(x)) क्या होगा?

If (f(x)=x-3) and (g(x)=2x), what will ((fg)(x)) be?

Explanation opens after your attempt
Correct Answer

C. \(2x^4\)

Step 1

Concept

((fg)(x)=x-3\cdot2x=2x-4). Add powers when multiplying the same base.

Step 2

Why this answer is correct

The correct answer is C. \(2x^4\). ((fg)(x)=x-3\cdot2x=2x-4). Add powers when multiplying the same base.

Step 3

Exam Tip

((fg)(x)=x-3\cdot2x=2x-4)। समान आधार में गुणा करते समय घातें जोड़ें।

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यदि (f(x)=10x-3) और (g(x)=5x), तो (\left\(\frac{f}{g}\right\)(x)) क्या है, जहाँ \(x\neq0\)?

If (f(x)=10x-3) and (g(x)=5x), what is (\left\(\frac{f}{g}\right\)(x)), where \(x\neq0\)?

Explanation opens after your attempt
Correct Answer

A. \(2x^2\)

Step 1

Concept

(\left\(\frac{f}{g}\right\)(x)=\frac{10x-3}{5x}=2x-2), where \(x\neq0\). In division, powers are subtracted.

Step 2

Why this answer is correct

The correct answer is A. \(2x^2\). (\left\(\frac{f}{g}\right\)(x)=\frac{10x-3}{5x}=2x-2), where \(x\neq0\). In division, powers are subtracted.

Step 3

Exam Tip

(\left\(\frac{f}{g}\right\)(x)=\frac{10x-3}{5x}=2x-2), जहाँ \(x\neq0\)। भाग में घातें घटती हैं।

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यदि (f(x)=x-8), तो ((3f)(x)) क्या है?

If (f(x)=x-8), what is ((3f)(x))?

Explanation opens after your attempt
Correct Answer

C. (3x-24)

Step 1

Concept

((3f)(x)=3(x-8)=3x-24). Multiply all terms by the scalar.

Step 2

Why this answer is correct

The correct answer is C. (3x-24). ((3f)(x)=3(x-8)=3x-24). Multiply all terms by the scalar.

Step 3

Exam Tip

((3f)(x)=3(x-8)=3x-24)। स्थिर गुणक को सभी पदों से गुणा करें।

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यदि (f(x)=4x+6), तो (\left\(\frac{1}{2}f\right\)(x)) क्या होगा?

If (f(x)=4x+6), what will (\left\(\frac{1}{2}f\right\)(x)) be?

Explanation opens after your attempt
Correct Answer

A. (2x+3)

Step 1

Concept

(\left\(\frac{1}{2}f\right\)(x)=\frac{1}{2}(4x+6)=2x+3). Apply the fractional multiplier to every term.

Step 2

Why this answer is correct

The correct answer is A. (2x+3). (\left\(\frac{1}{2}f\right\)(x)=\frac{1}{2}(4x+6)=2x+3). Apply the fractional multiplier to every term.

Step 3

Exam Tip

(\left\(\frac{1}{2}f\right\)(x)=\frac{1}{2}(4x+6)=2x+3)। भिन्न गुणक को हर पद पर लगाएँ।

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यदि (f(x)=2x-2-5), तो ((-f)(x)) किसके बराबर है?

If (f(x)=2x-2-5), what is ((-f)(x)) equal to?

Explanation opens after your attempt
Correct Answer

A. \(-2x^2+5\)

Step 1

Concept

((-f)(x)=-\(2x^2-5\)=-2x-2+5). The negative sign applies to the whole function.

Step 2

Why this answer is correct

The correct answer is A. \(-2x^2+5\). ((-f)(x)=-\(2x^2-5\)=-2x-2+5). The negative sign applies to the whole function.

Step 3

Exam Tip

((-f)(x)=-\(2x^2-5\)=-2x-2+5)। ऋण चिह्न पूरे फलन पर लगता है।

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यदि (f(x)=x-2+4x), तो ((f+f)(x)) क्या होगा?

If (f(x)=x-2+4x), what will ((f+f)(x)) be?

Explanation opens after your attempt
Correct Answer

B. \(2x^2+8x\)

Step 1

Concept

((f+f)(x)=2f(x)=2x-2+8x). Adding the same function equals (2f).

Step 2

Why this answer is correct

The correct answer is B. \(2x^2+8x\). ((f+f)(x)=2f(x)=2x-2+8x). Adding the same function equals (2f).

Step 3

Exam Tip

((f+f)(x)=2f(x)=2x-2+8x)। समान फलन जोड़ना (2f) के बराबर है।

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यदि (f(x)=x-3), तो ((ff)(x)) क्या है?

If (f(x)=x-3), what is ((ff)(x))?

Explanation opens after your attempt
Correct Answer

C. \(x^2-6x+9\)

Step 1

Concept

((ff)(x)=f(x)f(x)=(x-3)2=x-2-6x+9). Do not treat ((ff)(x)) as ((f+f)(x)).

Step 2

Why this answer is correct

The correct answer is C. \(x^2-6x+9\). ((ff)(x)=f(x)f(x)=(x-3)2=x-2-6x+9). Do not treat ((ff)(x)) as ((f+f)(x)).

Step 3

Exam Tip

((ff)(x)=f(x)f(x)=(x-3)2=x-2-6x+9)। ((ff)(x)) को ((f+f)(x)) न मानें।

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यदि (f(x)=2x+10) और (g(x)=2x+10), तो ((f-g)(x)) क्या है?

If (f(x)=2x+10) and (g(x)=2x+10), what is ((f-g)(x))?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

The difference of equal functions is (0), so ((f-g)(x)=0). In exams, first notice if both functions are equal.

Step 2

Why this answer is correct

The correct answer is A. (0). The difference of equal functions is (0), so ((f-g)(x)=0). In exams, first notice if both functions are equal.

Step 3

Exam Tip

समान फलनों का अंतर (0) होता है, इसलिए ((f-g)(x)=0)। परीक्षा में पहले पहचानें कि दोनों फलन समान हैं।

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यदि (f(x)=0) और (g(x)=3x-2-2), तो ((fg)(x)) क्या होगा?

If (f(x)=0) and (g(x)=3x-2-2), what will ((fg)(x)) be?

Explanation opens after your attempt
Correct Answer

B. (0)

Step 1

Concept

Multiplying by the zero function gives ((fg)(x)=0). In multiplication, (0) makes the whole product zero.

Step 2

Why this answer is correct

The correct answer is B. (0). Multiplying by the zero function gives ((fg)(x)=0). In multiplication, (0) makes the whole product zero.

Step 3

Exam Tip

शून्य फलन से गुणा करने पर ((fg)(x)=0) होता है। गुणन में (0) पूरे गुणनफल को शून्य कर देता है।

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यदि (f(x)=1) और (g(x)=5x-6), तो ((f+g)(x)) क्या है?

If (f(x)=1) and (g(x)=5x-6), what is ((f+g)(x))?

Explanation opens after your attempt
Correct Answer

A. (5x-5)

Step 1

Concept

((f+g)(x)=1+(5x-6)=5x-5). Add constant terms carefully.

Step 2

Why this answer is correct

The correct answer is A. (5x-5). ((f+g)(x)=1+(5x-6)=5x-5). Add constant terms carefully.

Step 3

Exam Tip

((f+g)(x)=1+(5x-6)=5x-5)। स्थिर पदों को ध्यान से जोड़ें।

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यदि (f(x)=x+9) और (g(x)=9-x), तो ((f+g)(x)) क्या होगा?

If (f(x)=x+9) and (g(x)=9-x), what will ((f+g)(x)) be?

Explanation opens after your attempt
Correct Answer

B. (18)

Step 1

Concept

((f+g)(x)=(x+9)+(9-x)=18). The terms (x) and (-x) cancel out.

Step 2

Why this answer is correct

The correct answer is B. (18). ((f+g)(x)=(x+9)+(9-x)=18). The terms (x) and (-x) cancel out.

Step 3

Exam Tip

((f+g)(x)=(x+9)+(9-x)=18)। (x) और (-x) कट जाते हैं।

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यदि (f(x)=x-2+5x) और (g(x)=x-2+2x), तो ((f-g)(x)) क्या है?

If (f(x)=x-2+5x) and (g(x)=x-2+2x), what is ((f-g)(x))?

Explanation opens after your attempt
Correct Answer

B. (3x)

Step 1

Concept

((f-g)(x)=x-2+5x-\(x^2+2x\)=3x). The like \(x^2\) terms cancel out.

Step 2

Why this answer is correct

The correct answer is B. (3x). ((f-g)(x)=x-2+5x-\(x^2+2x\)=3x). The like \(x^2\) terms cancel out.

Step 3

Exam Tip

((f-g)(x)=x-2+5x-\(x^2+2x\)=3x)। समान \(x^2\) पद कट जाते हैं।

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यदि (f(x)=x+7) और (g(x)=3x-2), तो ((fg)(1)) का मान क्या है?

If (f(x)=x+7) and (g(x)=3x-2), what is the value of ((fg)(1))?

Explanation opens after your attempt
Correct Answer

A. (8)

Step 1

Concept

((fg)(1)=f(1)g(1)=8\cdot1=8). First find both values.

Step 2

Why this answer is correct

The correct answer is A. (8). ((fg)(1)=f(1)g(1)=8\cdot1=8). First find both values.

Step 3

Exam Tip

((fg)(1)=f(1)g(1)=8\cdot1=8)। पहले दोनों मान निकालें।

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यदि (f(x)=x-2+10) और (g(x)=x-2+4), तो ((f-g)(1)) क्या है?

If (f(x)=x-2+10) and (g(x)=x-2+4), what is ((f-g)(1))?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

((f-g)(1)=f(1)-g(1)=11-5=6). Here the \(x^2\) terms effectively cancel.

Step 2

Why this answer is correct

The correct answer is C. (6). ((f-g)(1)=f(1)-g(1)=11-5=6). Here the \(x^2\) terms effectively cancel.

Step 3

Exam Tip

((f-g)(1)=f(1)-g(1)=11-5=6)। यहाँ \(x^2\) पद प्रभावी रूप से कट जाते हैं।

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यदि (f(x)=6x+1) और (g(x)=2x+3), तो (\left\(\frac{f}{g}\right\)(0)) क्या होगा?

If (f(x)=6x+1) and (g(x)=2x+3), what will (\left\(\frac{f}{g}\right\)(0)) be?

Explanation opens after your attempt
Correct Answer

A. \(\frac{1}{3}\)

Step 1

Concept

(\left\(\frac{f}{g}\right\)(0)=\frac{1}{3}). The denominator is (3), so the quotient is valid.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{1}{3}\). (\left\(\frac{f}{g}\right\)(0)=\frac{1}{3}). The denominator is (3), so the quotient is valid.

Step 3

Exam Tip

(\left\(\frac{f}{g}\right\)(0)=\frac{1}{3})। हर (3) है, इसलिए भाग मान्य है।

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यदि (f(x)=\sqrt{x+5}) और (g(x)=x), तो ((f+g)(4)) का मान क्या है?

If (f(x)=\sqrt{x+5}) and (g(x)=x), what is the value of ((f+g)(4))?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

((f+g)(4)=\sqrt{9}+4=3+4=7). For a radical term, first find the inside value.

Step 2

Why this answer is correct

The correct answer is C. (7). ((f+g)(4)=\sqrt{9}+4=3+4=7). For a radical term, first find the inside value.

Step 3

Exam Tip

((f+g)(4)=\sqrt{9}+4=3+4=7)। मूल वाले पद में पहले अंदर का मान निकालें।

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यदि (f(x)=x-2+1) और (g(x)=\sqrt{x}), तो ((fg)(4)) क्या होगा?

If (f(x)=x-2+1) and (g(x)=\sqrt{x}), what will ((fg)(4)) be?

Explanation opens after your attempt
Correct Answer

B. (34)

Step 1

Concept

((fg)(4)=f(4)g(4)=17\cdot2=34). Finding separate values is the safest method.

Step 2

Why this answer is correct

The correct answer is B. (34). ((fg)(4)=f(4)g(4)=17\cdot2=34). Finding separate values is the safest method.

Step 3

Exam Tip

((fg)(4)=f(4)g(4)=17\cdot2=34)। अलग-अलग मान निकालना सबसे सुरक्षित तरीका है।

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यदि (f(x)=\frac{2}{x}) और (g(x)=x-2), तो ((fg)(3)) का मान क्या है?

If (f(x)=\frac{2}{x}) and (g(x)=x-2), what is the value of ((fg)(3))?

Explanation opens after your attempt
Correct Answer

A. (6)

Step 1

Concept

((fg)(3)=\frac{2}{3}\cdot9=6). A reciprocal-type function keeps the condition \(x\neq0\).

Step 2

Why this answer is correct

The correct answer is A. (6). ((fg)(3)=\frac{2}{3}\cdot9=6). A reciprocal-type function keeps the condition \(x\neq0\).

Step 3

Exam Tip

((fg)(3)=\frac{2}{3}\cdot9=6)। भिन्न फलन में \(x\neq0\) शर्त रहती है।

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यदि (f(x)=x+12) और (g(x)=x+3), तो (\left\(\frac{f}{g}\right\)(3)) क्या है?

If (f(x)=x+12) and (g(x)=x+3), what is (\left\(\frac{f}{g}\right\)(3))?

Explanation opens after your attempt
Correct Answer

A. \(\frac{5}{2}\)

Step 1

Concept

(\left\(\frac{f}{g}\right\)(3)=\frac{15}{6}=\frac{5}{2}). Write the final answer in simplest fraction form.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{5}{2}\). (\left\(\frac{f}{g}\right\)(3)=\frac{15}{6}=\frac{5}{2}). Write the final answer in simplest fraction form.

Step 3

Exam Tip

(\left\(\frac{f}{g}\right\)(3)=\frac{15}{6}=\frac{5}{2})। अंतिम उत्तर को सरल भिन्न में लिखें।

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यदि (f(x)=x+4) और (g(x)=x-4), तो ((fg)(x)) को सरल करने के लिए कौन-सी पहचान उपयोगी है?

If (f(x)=x+4) and (g(x)=x-4), which identity is useful to simplify ((fg)(x))?

Explanation opens after your attempt
Correct Answer

A. \(a^2-b^2\)

Step 1

Concept

((x+4)(x-4)) uses \(a^2-b^2\). It gives the answer \(x^2-16\).

Step 2

Why this answer is correct

The correct answer is A. \(a^2-b^2\). ((x+4)(x-4)) uses \(a^2-b^2\). It gives the answer \(x^2-16\).

Step 3

Exam Tip

((x+4)(x-4)) में \(a^2-b^2\) लगता है। इससे उत्तर \(x^2-16\) मिलता है।

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यदि (f(x)=2x-2+3) और (g(x)=x+5), तो ((f+g)(1)) क्या है?

If (f(x)=2x-2+3) and (g(x)=x+5), what is ((f+g)(1))?

Explanation opens after your attempt
Correct Answer

C. (11)

Step 1

Concept

((f+g)(1)=f(1)+g(1)=5+6=11). First put (x=1), then add.

Step 2

Why this answer is correct

The correct answer is C. (11). ((f+g)(1)=f(1)+g(1)=5+6=11). First put (x=1), then add.

Step 3

Exam Tip

((f+g)(1)=f(1)+g(1)=5+6=11)। पहले (x=1) रखें, फिर जोड़ें।

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यदि (f(x)=5x-2+2) और (g(x)=2x-2-7), तो ((f-g)(x)) क्या होगा?

If (f(x)=5x-2+2) and (g(x)=2x-2-7), what will ((f-g)(x)) be?

Explanation opens after your attempt
Correct Answer

C. \(3x^2+9\)

Step 1

Concept

((f-g)(x)=5x-2+2-\(2x^2-7\)=3x-2+9). Applying the minus to (-7) gives (+7).

Step 2

Why this answer is correct

The correct answer is C. \(3x^2+9\). ((f-g)(x)=5x-2+2-\(2x^2-7\)=3x-2+9). Applying the minus to (-7) gives (+7).

Step 3

Exam Tip

((f-g)(x)=5x-2+2-\(2x^2-7\)=3x-2+9)। ऋण को (-7) पर लगाने से (+7) आता है।

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यदि (f(x)=x-6) और (g(x)=x), तो ((fg)(x)) क्या है?

If (f(x)=x-6) and (g(x)=x), what is ((fg)(x))?

Explanation opens after your attempt
Correct Answer

A. \(x^2-6x\)

Step 1

Concept

((fg)(x)=(x-6)x=x-2-6x). Multiply (x) with both terms.

Step 2

Why this answer is correct

The correct answer is A. \(x^2-6x\). ((fg)(x)=(x-6)x=x-2-6x). Multiply (x) with both terms.

Step 3

Exam Tip

((fg)(x)=(x-6)x=x-2-6x)। (x) को दोनों पदों से गुणा करें।

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यदि (f(x)=4x+11) और (g(x)=x-6), तो ((f+g)(x)) क्या है?

If (f(x)=4x+11) and (g(x)=x-6), what is ((f+g)(x))?

Explanation opens after your attempt
Correct Answer

A. (5x+5)

Step 1

Concept

((f+g)(x)=4x+11+x-6=5x+5). Add (x)-terms and constant terms separately.

Step 2

Why this answer is correct

The correct answer is A. (5x+5). ((f+g)(x)=4x+11+x-6=5x+5). Add (x)-terms and constant terms separately.

Step 3

Exam Tip

((f+g)(x)=4x+11+x-6=5x+5)। (x) पद और स्थिर पद अलग-अलग जोड़ें।

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यदि (f(x)=8) और (g(x)=x-2-3x), तो ((f-g)(x)) क्या है?

If (f(x)=8) and (g(x)=x-2-3x), what is ((f-g)(x))?

Explanation opens after your attempt
Correct Answer

B. \(8-x^2+3x\)

Step 1

Concept

((f-g)(x)=8-\(x^2-3x\)=8-x-2+3x). In subtraction, signs of the whole (g(x)) change.

Step 2

Why this answer is correct

The correct answer is B. \(8-x^2+3x\). ((f-g)(x)=8-\(x^2-3x\)=8-x-2+3x). In subtraction, signs of the whole (g(x)) change.

Step 3

Exam Tip

((f-g)(x)=8-\(x^2-3x\)=8-x-2+3x)। घटाने में पूरे (g(x)) के चिह्न बदलते हैं।

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यदि (f(x)=x-2-25) और (g(x)=x+5), तो (\left\(\frac{f}{g}\right\)(x)) का सरल रूप क्या है, जहाँ \(x\neq-5\)?

If (f(x)=x-2-25) and (g(x)=x+5), what is the simplified form of (\left\(\frac{f}{g}\right\)(x)), where \(x\neq-5\)?

Explanation opens after your attempt
Correct Answer

A. (x-5)

Step 1

Concept

(\frac{x-2-25}{x+5}=\frac{(x-5)(x+5)}{x+5}=x-5). Keep the condition \(x\neq-5\).

Step 2

Why this answer is correct

The correct answer is A. (x-5). (\frac{x-2-25}{x+5}=\frac{(x-5)(x+5)}{x+5}=x-5). Keep the condition \(x\neq-5\).

Step 3

Exam Tip

(\frac{x-2-25}{x+5}=\frac{(x-5)(x+5)}{x+5}=x-5)। शर्त \(x\neq-5\) साथ रखें।

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यदि (f(x)=x-2-4x+4) और (g(x)=x-2), तो (\left\(\frac{f}{g}\right\)(x)) क्या है, जहाँ \(x\neq2\)?

If (f(x)=x-2-4x+4) and (g(x)=x-2), what is (\left\(\frac{f}{g}\right\)(x)), where \(x\neq2\)?

Explanation opens after your attempt
Correct Answer

B. (x-2)

Step 1

Concept

Since (x-2-4x+4=(x-2)2), the quotient is (x-2). Remove (x=2) from the domain.

Step 2

Why this answer is correct

The correct answer is B. (x-2). Since (x-2-4x+4=(x-2)2), the quotient is (x-2). Remove (x=2) from the domain.

Step 3

Exam Tip

क्योंकि (x-2-4x+4=(x-2)2), इसलिए भागफल (x-2) है। (x=2) को डोमेन से हटाएँ।

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यदि (f(x)=x-1) और (g(x)=x+10), तो ((f+g)(1)) क्या होगा?

If (f(x)=x-1) and (g(x)=x+10), what will ((f+g)(1)) be?

Explanation opens after your attempt
Correct Answer

B. (11)

Step 1

Concept

((f+g)(1)=f(1)+g(1)=0+11=11). Include the zero value in the sum.

Step 2

Why this answer is correct

The correct answer is B. (11). ((f+g)(1)=f(1)+g(1)=0+11=11). Include the zero value in the sum.

Step 3

Exam Tip

((f+g)(1)=f(1)+g(1)=0+11=11)। शून्य मान को जोड़ में शामिल करें।

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यदि (f(x)=5x) और (g(x)=x+1), तो ((fg)(3)) का मान क्या है?

If (f(x)=5x) and (g(x)=x+1), what is the value of ((fg)(3))?

Explanation opens after your attempt
Correct Answer

B. (60)

Step 1

Concept

((fg)(3)=f(3)g(3)=15\cdot4=60). (fg) means product of functions.

Step 2

Why this answer is correct

The correct answer is B. (60). ((fg)(3)=f(3)g(3)=15\cdot4=60). (fg) means product of functions.

Step 3

Exam Tip

((fg)(3)=f(3)g(3)=15\cdot4=60)। (fg) का अर्थ फलनों का गुणन है।

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यदि (f(x)=x-2-4) और (g(x)=x-2+4), तो ((f+g)(x)) क्या है?

If (f(x)=x-2-4) and (g(x)=x-2+4), what is ((f+g)(x))?

Explanation opens after your attempt
Correct Answer

A. \(2x^2\)

Step 1

Concept

((f+g)(x)=x-2-4+x-2+4=2x-2). Opposite constant terms cancel out.

Step 2

Why this answer is correct

The correct answer is A. \(2x^2\). ((f+g)(x)=x-2-4+x-2+4=2x-2). Opposite constant terms cancel out.

Step 3

Exam Tip

((f+g)(x)=x-2-4+x-2+4=2x-2)। विपरीत स्थिर पद कट जाते हैं।

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यदि (f(x)=4x-2-3) और (g(x)=x-2+8), तो ((f-g)(x)) क्या होगा?

If (f(x)=4x-2-3) and (g(x)=x-2+8), what will ((f-g)(x)) be?

Explanation opens after your attempt
Correct Answer

B. \(3x^2-11\)

Step 1

Concept

((f-g)(x)=4x-2-3-\(x^2+8\)=3x-2-11). Pay attention to constant terms after brackets.

Step 2

Why this answer is correct

The correct answer is B. \(3x^2-11\). ((f-g)(x)=4x-2-3-\(x^2+8\)=3x-2-11). Pay attention to constant terms after brackets.

Step 3

Exam Tip

((f-g)(x)=4x-2-3-\(x^2+8\)=3x-2-11)। कोष्ठक के बाद स्थिर पदों पर ध्यान दें।

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यदि (f(x)=x-5) और (g(x)=3), तो ((fg)(x)) क्या है?

If (f(x)=x-5) and (g(x)=3), what is ((fg)(x))?

Explanation opens after your attempt
Correct Answer

A. (3x-15)

Step 1

Concept

((fg)(x)=(x-5)\cdot3=3x-15). Multiplication by a constant function multiplies all terms.

Step 2

Why this answer is correct

The correct answer is A. (3x-15). ((fg)(x)=(x-5)\cdot3=3x-15). Multiplication by a constant function multiplies all terms.

Step 3

Exam Tip

((fg)(x)=(x-5)\cdot3=3x-15)। स्थिर फलन से गुणा में सभी पद गुणित होते हैं।

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यदि (f(x)=12x-6) और (g(x)=6), तो (\left\(\frac{f}{g}\right\)(x)) क्या है?

If (f(x)=12x-6) and (g(x)=6), what is (\left\(\frac{f}{g}\right\)(x))?

Explanation opens after your attempt
Correct Answer

A. (2x-1)

Step 1

Concept

(\left\(\frac{f}{g}\right\)(x)=\frac{12x-6}{6}=2x-1). Divide every numerator term by (6).

Step 2

Why this answer is correct

The correct answer is A. (2x-1). (\left\(\frac{f}{g}\right\)(x)=\frac{12x-6}{6}=2x-1). Divide every numerator term by (6).

Step 3

Exam Tip

(\left\(\frac{f}{g}\right\)(x)=\frac{12x-6}{6}=2x-1)। अंश के हर पद को (6) से भाग दें।

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यदि (f(x)=2x-11) और (g(x)=11-2x), तो ((f+g)(x)) क्या होगा?

If (f(x)=2x-11) and (g(x)=11-2x), what will ((f+g)(x)) be?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

((f+g)(x)=(2x-11)+(11-2x)=0). These two functions are additive inverses.

Step 2

Why this answer is correct

The correct answer is A. (0). ((f+g)(x)=(2x-11)+(11-2x)=0). These two functions are additive inverses.

Step 3

Exam Tip

((f+g)(x)=(2x-11)+(11-2x)=0)। ये दोनों फलन योगात्मक प्रतिलोम हैं।

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यदि (f(x)=3x+8) और (g(x)=3x-8), तो ((f-g)(x)) क्या है?

If (f(x)=3x+8) and (g(x)=3x-8), what is ((f-g)(x))?

Explanation opens after your attempt
Correct Answer

B. (16)

Step 1

Concept

((f-g)(x)=3x+8-(3x-8)=16). The (3x) terms cancel out.

Step 2

Why this answer is correct

The correct answer is B. (16). ((f-g)(x)=3x+8-(3x-8)=16). The (3x) terms cancel out.

Step 3

Exam Tip

((f-g)(x)=3x+8-(3x-8)=16)। (3x) पद कट जाते हैं।

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यदि (f(x)=x-5) और (g(x)=x-2), तो ((fg)(x)) क्या है?

If (f(x)=x-5) and (g(x)=x-2), what is ((fg)(x))?

Explanation opens after your attempt
Correct Answer

A. \(x^7\)

Step 1

Concept

((fg)(x)=x-5\cdot x-2=x-7). Add powers while multiplying the same base.

Step 2

Why this answer is correct

The correct answer is A. \(x^7\). ((fg)(x)=x-5\cdot x-2=x-7). Add powers while multiplying the same base.

Step 3

Exam Tip

((fg)(x)=x-5\cdot x-2=x-7)। समान आधार में गुणा करते समय घातों को जोड़ें।

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यदि (f(x)=x-6) और (g(x)=x-3), तो (\left\(\frac{f}{g}\right\)(x)) क्या होगा, जहाँ \(x\neq0\)?

If (f(x)=x-6) and (g(x)=x-3), what will (\left\(\frac{f}{g}\right\)(x)) be, where \(x\neq0\)?

Explanation opens after your attempt
Correct Answer

B. \(x^3\)

Step 1

Concept

(\left\(\frac{f}{g}\right\)(x)=\frac{x-6}{x-3}=x-3), where \(x\neq0\). In division, subtract powers of the same base.

Step 2

Why this answer is correct

The correct answer is B. \(x^3\). (\left\(\frac{f}{g}\right\)(x)=\frac{x-6}{x-3}=x-3), where \(x\neq0\). In division, subtract powers of the same base.

Step 3

Exam Tip

(\left\(\frac{f}{g}\right\)(x)=\frac{x-6}{x-3}=x-3), जहाँ \(x\neq0\)। भाग में समान आधार की घातें घटाएँ।

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यदि (f(x)=2x+1) और (g(x)=x-2+3), दोनों का डोमेन \(\mathbb{R}\) है, तो ((fg)(x)) का डोमेन क्या है?

If (f(x)=2x+1) and (g(x)=x-2+3), both have domain \(\mathbb{R}\), what is the domain of ((fg)(x))?

Explanation opens after your attempt
Correct Answer

A. \(\mathbb{R}\)

Step 1

Concept

Both polynomials are defined on all \(\mathbb{R}\), so the product domain is \(\mathbb{R}\). The domain is the set of common allowed values.

Step 2

Why this answer is correct

The correct answer is A. \(\mathbb{R}\). Both polynomials are defined on all \(\mathbb{R}\), so the product domain is \(\mathbb{R}\). The domain is the set of common allowed values.

Step 3

Exam Tip

दोनों बहुपद पूरे \(\mathbb{R}\) पर परिभाषित हैं, इसलिए गुणनफल का डोमेन \(\mathbb{R}\) है। डोमेन सामान्य मानों का समुच्चय होता है।

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यदि (f(x)=\sqrt{x}) और (g(x)=x+2), तो ((f+g)(x)) का डोमेन क्या है?

If (f(x)=\sqrt{x}) and (g(x)=x+2), what is the domain of ((f+g)(x))?

Explanation opens after your attempt
Correct Answer

A. \([0,\infty\))

Step 1

Concept

For \(\sqrt{x}\), we need \(x\geq0\), so the domain of the sum is \([0,\infty\)). Take the common domain.

Step 2

Why this answer is correct

The correct answer is A. \([0,\infty\)). For \(\sqrt{x}\), we need \(x\geq0\), so the domain of the sum is \([0,\infty\)). Take the common domain.

Step 3

Exam Tip

\(\sqrt{x}\) के लिए \(x\geq0\) चाहिए, इसलिए योग का डोमेन \([0,\infty\)) है। साझा डोमेन लें।

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यदि (f(x)=x+4) और (g(x)=x-2-9), तो (\left\(\frac{f}{g}\right\)(x)) का डोमेन क्या है?

If (f(x)=x+4) and (g(x)=x-2-9), what is the domain of (\left\(\frac{f}{g}\right\)(x))?

Explanation opens after your attempt
Correct Answer

A. \(\mathbb{R}-{-3,3}\)

Step 1

Concept

In division, (g(x)\neq0) is needed, and \(x^2-9=0\) gives \(x=\pm3\). So the domain is \(\mathbb{R}-{-3,3}\).

Step 2

Why this answer is correct

The correct answer is A. \(\mathbb{R}-{-3,3}\). In division, (g(x)\neq0) is needed, and \(x^2-9=0\) gives \(x=\pm3\). So the domain is \(\mathbb{R}-{-3,3}\).

Step 3

Exam Tip

भाग में (g(x)\neq0) चाहिए, और \(x^2-9=0\) से \(x=\pm3\) मिलता है। इसलिए डोमेन \(\mathbb{R}-{-3,3}\) है।

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FAQs

Class 11 Mathematics Quiz FAQs

How many questions are in this quiz?

This level is designed for 50 active questions. Currently 50 questions are available for the selected class and difficulty.

Is there a timer in this quiz?

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Can I open each question separately?

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