यदि (f(x)=2x+3) और (g(x)=x-5), तो ((f+g)(x)) क्या है?
If (f(x)=2x+3) and (g(x)=x-5), what is ((f+g)(x))?
#algebra
#real functions
#function addition
#easy
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A (3x-2)
B (x+8)
C (3x+8)
D \(2x^2-10x+3\)
Explanation opens after your attempt
Step 1
Concept
((f+g)(x)=(2x+3)+(x-5)=3x-2). While adding, combine only like terms.
Step 2
Why this answer is correct
The correct answer is A. (3x-2). ((f+g)(x)=(2x+3)+(x-5)=3x-2). While adding, combine only like terms.
Step 3
Exam Tip
((f+g)(x)=(2x+3)+(x-5)=3x-2)। जोड़ते समय समान पदों को ही जोड़ें।
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यदि (f(x)=7x-4) और (g(x)=2x+9), तो ((f-g)(x)) ज्ञात कीजिए।
If (f(x)=7x-4) and (g(x)=2x+9), find ((f-g)(x)).
#algebra
#real functions
#function subtraction
#sign rule
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A (5x+5)
B (5x-13)
C (9x+5)
D (9x-13)
Explanation opens after your attempt
Correct Answer
B. (5x-13)
Step 1
Concept
((f-g)(x)=(7x-4)-(2x+9)=5x-13). In subtraction, change all signs of the second bracket.
Step 2
Why this answer is correct
The correct answer is B. (5x-13). ((f-g)(x)=(7x-4)-(2x+9)=5x-13). In subtraction, change all signs of the second bracket.
Step 3
Exam Tip
((f-g)(x)=(7x-4)-(2x+9)=5x-13)। घटाने में दूसरे कोष्ठक के सभी चिह्न बदलें।
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यदि (f(x)=x+6) और (g(x)=x-2), तो ((fg)(x)) क्या होगा?
If (f(x)=x+6) and (g(x)=x-2), what will ((fg)(x)) be?
#algebra
#real functions
#function product
#linear product
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A \(x^2+4x-12\)
B (2x+4)
C \(x^2+8x-12\)
D \(x^2-4x-12\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+4x-12\)
Step 1
Concept
((fg)(x)=(x+6)(x-2)=x-2 +4x-12). In multiplication, multiply each term correctly.
Step 2
Why this answer is correct
The correct answer is A. \(x^2+4x-12\). ((fg)(x)=(x+6)(x-2)=x-2 +4x-12). In multiplication, multiply each term correctly.
Step 3
Exam Tip
((fg)(x)=(x+6)(x-2)=x-2 +4x-12)। गुणन में हर पद को सही पद से गुणा करें।
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यदि (f(x)=4x-2 +8x) और (g(x)=4x), तो (\left\(\frac{f}{g}\right\)(x)) क्या है, जहाँ \(x\neq0\)?
If (f(x)=4x-2 +8x) and (g(x)=4x), what is (\left\(\frac{f}{g}\right\)(x)), where \(x\neq0\)?
#algebra
#real functions
#function quotient
#domain
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A (x+2)
B (4x+8)
C \(x^2+2x\)
D (2x+1)
Explanation opens after your attempt
Step 1
Concept
(\frac{4x-2 +8x}{4x}=\frac{4x(x+2)}{4x}=x+2), where \(x\neq0\). Check the denominator condition before cancellation.
Step 2
Why this answer is correct
The correct answer is A. (x+2). (\frac{4x-2 +8x}{4x}=\frac{4x(x+2)}{4x}=x+2), where \(x\neq0\). Check the denominator condition before cancellation.
Step 3
Exam Tip
(\frac{4x-2 +8x}{4x}=\frac{4x(x+2)}{4x}=x+2), जहाँ \(x\neq0\)। काटने से पहले हर की शर्त देखें।
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यदि (f(x)=x-2 +2) और (g(x)=3x-1), तो ((f+g)(2)) का मान क्या है?
If (f(x)=x-2 +2) and (g(x)=3x-1), what is the value of ((f+g)(2))?
#algebra
#real functions
#value based
#function addition
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A (9)
B (10)
C (11)
D (13)
Explanation opens after your attempt
Step 1
Concept
((f+g)(2)=f(2)+g(2)=6+5=11). Add only after substituting the value.
Step 2
Why this answer is correct
The correct answer is C. (11). ((f+g)(2)=f(2)+g(2)=6+5=11). Add only after substituting the value.
Step 3
Exam Tip
((f+g)(2)=f(2)+g(2)=6+5=11)। मान रखने के बाद ही जोड़ करें।
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यदि (f(x)=5x+2) और (g(x)=x-2 ), तो ((f-g)(3)) का मान क्या होगा?
If (f(x)=5x+2) and (g(x)=x-2 ), what will be the value of ((f-g)(3))?
#algebra
#real functions
#function subtraction
#value
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A (8)
B (17)
C (26)
D (-8)
Explanation opens after your attempt
Step 1
Concept
((f-g)(3)=f(3)-g(3)=17-9=8). Changing the order may change the answer.
Step 2
Why this answer is correct
The correct answer is A. (8). ((f-g)(3)=f(3)-g(3)=17-9=8). Changing the order may change the answer.
Step 3
Exam Tip
((f-g)(3)=f(3)-g(3)=17-9=8)। क्रम बदलने से उत्तर बदल सकता है।
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यदि (f(x)=2x-1) और (g(x)=x+4), तो ((fg)(2)) क्या है?
If (f(x)=2x-1) and (g(x)=x+4), what is ((fg)(2))?
#algebra
#real functions
#function product
#value based
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A (9)
B (18)
C (21)
D (24)
Explanation opens after your attempt
Step 1
Concept
((fg)(2)=f(2)g(2)=3\cdot6=18). In product, multiply the values of the functions.
Step 2
Why this answer is correct
The correct answer is B. (18). ((fg)(2)=f(2)g(2)=3\cdot6=18). In product, multiply the values of the functions.
Step 3
Exam Tip
((fg)(2)=f(2)g(2)=3\cdot6=18)। गुणन में फलनों के मानों का गुणा करें।
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यदि (f(x)=x-2 -16) और (g(x)=x-4), तो (\left\(\frac{f}{g}\right\)(5)) का मान क्या है?
If (f(x)=x-2 -16) and (g(x)=x-4), what is the value of (\left\(\frac{f}{g}\right\)(5))?
#algebra
#real functions
#quotient
#value
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A (5)
B (7)
C (9)
D (11)
Explanation opens after your attempt
Step 1
Concept
(\left\(\frac{f}{g}\right\)(5)=\frac{25-16}{5-4}=9). In division, the denominator value must not be zero.
Step 2
Why this answer is correct
The correct answer is C. (9). (\left\(\frac{f}{g}\right\)(5)=\frac{25-16}{5-4}=9). In division, the denominator value must not be zero.
Step 3
Exam Tip
(\left\(\frac{f}{g}\right\)(5)=\frac{25-16}{5-4}=9)। भाग में हर का मान शून्य नहीं होना चाहिए।
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यदि (f(x)=3x-2 ) और (g(x)=2x-2 +1), तो ((f+g)(x)) किसके बराबर है?
If (f(x)=3x-2 ) and (g(x)=2x-2 +1), then ((f+g)(x)) is equal to which expression?
#algebra
#real functions
#polynomial addition
#class 11
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A \(5x^2+1\)
B \(6x^4+1\)
C \(x^2+1\)
D \(5x^4\)
Explanation opens after your attempt
Correct Answer
A. \(5x^2+1\)
Step 1
Concept
((f+g)(x)=3x-2 +2x-2 +1=5x-2 +1). Add terms with the same power.
Step 2
Why this answer is correct
The correct answer is A. \(5x^2+1\). ((f+g)(x)=3x-2 +2x-2 +1=5x-2 +1). Add terms with the same power.
Step 3
Exam Tip
((f+g)(x)=3x-2 +2x-2 +1=5x-2 +1)। समान घात वाले पद जोड़ें।
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यदि (f(x)=9x-2) और (g(x)=4x-7), तो ((f-g)(x)) क्या होगा?
If (f(x)=9x-2) and (g(x)=4x-7), what is ((f-g)(x))?
#algebra
#real functions
#linear subtraction
#signs
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A (5x+5)
B (13x-9)
C (5x-9)
D (13x+5)
Explanation opens after your attempt
Step 1
Concept
((f-g)(x)=9x-2-(4x-7)=5x+5). Write (-(-7)) as (+7).
Step 2
Why this answer is correct
The correct answer is A. (5x+5). ((f-g)(x)=9x-2-(4x-7)=5x+5). Write (-(-7)) as (+7).
Step 3
Exam Tip
((f-g)(x)=9x-2-(4x-7)=5x+5)। (-(-7)) को (+7) लिखें।
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यदि (f(x)=x-3 ) और (g(x)=2x), तो ((fg)(x)) क्या होगा?
If (f(x)=x-3 ) and (g(x)=2x), what will ((fg)(x)) be?
#algebra
#real functions
#product
#exponents
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A \(2x^3\)
B \(x^4\)
C \(2x^4\)
D \(3x^4\)
Explanation opens after your attempt
Correct Answer
C. \(2x^4\)
Step 1
Concept
((fg)(x)=x-3 \cdot2x=2x-4 ). Add powers when multiplying the same base.
Step 2
Why this answer is correct
The correct answer is C. \(2x^4\). ((fg)(x)=x-3 \cdot2x=2x-4 ). Add powers when multiplying the same base.
Step 3
Exam Tip
((fg)(x)=x-3 \cdot2x=2x-4 )। समान आधार में गुणा करते समय घातें जोड़ें।
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यदि (f(x)=10x-3 ) और (g(x)=5x), तो (\left\(\frac{f}{g}\right\)(x)) क्या है, जहाँ \(x\neq0\)?
If (f(x)=10x-3 ) and (g(x)=5x), what is (\left\(\frac{f}{g}\right\)(x)), where \(x\neq0\)?
#algebra
#real functions
#quotient
#exponents
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A \(2x^2\)
B \(5x^2\)
C \(2x^3\)
D \(15x^4\)
Explanation opens after your attempt
Correct Answer
A. \(2x^2\)
Step 1
Concept
(\left\(\frac{f}{g}\right\)(x)=\frac{10x-3 }{5x}=2x-2 ), where \(x\neq0\). In division, powers are subtracted.
Step 2
Why this answer is correct
The correct answer is A. \(2x^2\). (\left\(\frac{f}{g}\right\)(x)=\frac{10x-3 }{5x}=2x-2 ), where \(x\neq0\). In division, powers are subtracted.
Step 3
Exam Tip
(\left\(\frac{f}{g}\right\)(x)=\frac{10x-3 }{5x}=2x-2 ), जहाँ \(x\neq0\)। भाग में घातें घटती हैं।
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यदि (f(x)=x-8), तो ((3f)(x)) क्या है?
If (f(x)=x-8), what is ((3f)(x))?
#algebra
#real functions
#scalar multiplication
#easy
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A (3x-8)
B (x-24)
C (3x-24)
D (x-5)
Explanation opens after your attempt
Correct Answer
C. (3x-24)
Step 1
Concept
((3f)(x)=3(x-8)=3x-24). Multiply all terms by the scalar.
Step 2
Why this answer is correct
The correct answer is C. (3x-24). ((3f)(x)=3(x-8)=3x-24). Multiply all terms by the scalar.
Step 3
Exam Tip
((3f)(x)=3(x-8)=3x-24)। स्थिर गुणक को सभी पदों से गुणा करें।
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यदि (f(x)=4x+6), तो (\left\(\frac{1}{2}f\right\)(x)) क्या होगा?
If (f(x)=4x+6), what will (\left\(\frac{1}{2}f\right\)(x)) be?
#algebra
#real functions
#scalar multiplication
#fraction
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A (2x+3)
B (4x+3)
C (2x+6)
D (8x+12)
Explanation opens after your attempt
Step 1
Concept
(\left\(\frac{1}{2}f\right\)(x)=\frac{1}{2}(4x+6)=2x+3). Apply the fractional multiplier to every term.
Step 2
Why this answer is correct
The correct answer is A. (2x+3). (\left\(\frac{1}{2}f\right\)(x)=\frac{1}{2}(4x+6)=2x+3). Apply the fractional multiplier to every term.
Step 3
Exam Tip
(\left\(\frac{1}{2}f\right\)(x)=\frac{1}{2}(4x+6)=2x+3)। भिन्न गुणक को हर पद पर लगाएँ।
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यदि (f(x)=2x-2 -5), तो ((-f)(x)) किसके बराबर है?
If (f(x)=2x-2 -5), what is ((-f)(x)) equal to?
#algebra
#real functions
#negative function
#sign rule
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A \(-2x^2+5\)
B \(2x^2+5\)
C \(-2x^2-5\)
D (5-2x)
Explanation opens after your attempt
Correct Answer
A. \(-2x^2+5\)
Step 1
Concept
((-f)(x)=-\(2x^2-5\)=-2x-2 +5). The negative sign applies to the whole function.
Step 2
Why this answer is correct
The correct answer is A. \(-2x^2+5\). ((-f)(x)=-\(2x^2-5\)=-2x-2 +5). The negative sign applies to the whole function.
Step 3
Exam Tip
((-f)(x)=-\(2x^2-5\)=-2x-2 +5)। ऋण चिह्न पूरे फलन पर लगता है।
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यदि (f(x)=x-2 +4x), तो ((f+f)(x)) क्या होगा?
If (f(x)=x-2 +4x), what will ((f+f)(x)) be?
#algebra
#real functions
#function addition
#common mistake
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A \(x^4+16x^2\)
B \(2x^2+8x\)
C \(x^2+8x\)
D \(2x^2+4x\)
Explanation opens after your attempt
Correct Answer
B. \(2x^2+8x\)
Step 1
Concept
((f+f)(x)=2f(x)=2x-2 +8x). Adding the same function equals (2f).
Step 2
Why this answer is correct
The correct answer is B. \(2x^2+8x\). ((f+f)(x)=2f(x)=2x-2 +8x). Adding the same function equals (2f).
Step 3
Exam Tip
((f+f)(x)=2f(x)=2x-2 +8x)। समान फलन जोड़ना (2f) के बराबर है।
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यदि (f(x)=x-3), तो ((ff)(x)) क्या है?
If (f(x)=x-3), what is ((ff)(x))?
#algebra
#real functions
#function product
#common mistake
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A (2x-6)
B \(x^2-3\)
C \(x^2-6x+9\)
D \(x^2+6x+9\)
Explanation opens after your attempt
Correct Answer
C. \(x^2-6x+9\)
Step 1
Concept
((ff)(x)=f(x)f(x)=(x-3)2 =x-2 -6x+9). Do not treat ((ff)(x)) as ((f+f)(x)).
Step 2
Why this answer is correct
The correct answer is C. \(x^2-6x+9\). ((ff)(x)=f(x)f(x)=(x-3)2 =x-2 -6x+9). Do not treat ((ff)(x)) as ((f+f)(x)).
Step 3
Exam Tip
((ff)(x)=f(x)f(x)=(x-3)2 =x-2 -6x+9)। ((ff)(x)) को ((f+f)(x)) न मानें।
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यदि (f(x)=2x+10) और (g(x)=2x+10), तो ((f-g)(x)) क्या है?
If (f(x)=2x+10) and (g(x)=2x+10), what is ((f-g)(x))?
#algebra
#real functions
#equal functions
#subtraction
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A (0)
B (4x+20)
C (1)
D (2x+10)
Explanation opens after your attempt
Step 1
Concept
The difference of equal functions is (0), so ((f-g)(x)=0). In exams, first notice if both functions are equal.
Step 2
Why this answer is correct
The correct answer is A. (0). The difference of equal functions is (0), so ((f-g)(x)=0). In exams, first notice if both functions are equal.
Step 3
Exam Tip
समान फलनों का अंतर (0) होता है, इसलिए ((f-g)(x)=0)। परीक्षा में पहले पहचानें कि दोनों फलन समान हैं।
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यदि (f(x)=0) और (g(x)=3x-2 -2), तो ((fg)(x)) क्या होगा?
If (f(x)=0) and (g(x)=3x-2 -2), what will ((fg)(x)) be?
#algebra
#real functions
#zero function
#product
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A \(3x^2-2\)
B (0)
C \(3x^2\)
D (2)
Explanation opens after your attempt
Step 1
Concept
Multiplying by the zero function gives ((fg)(x)=0). In multiplication, (0) makes the whole product zero.
Step 2
Why this answer is correct
The correct answer is B. (0). Multiplying by the zero function gives ((fg)(x)=0). In multiplication, (0) makes the whole product zero.
Step 3
Exam Tip
शून्य फलन से गुणा करने पर ((fg)(x)=0) होता है। गुणन में (0) पूरे गुणनफल को शून्य कर देता है।
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यदि (f(x)=1) और (g(x)=5x-6), तो ((f+g)(x)) क्या है?
If (f(x)=1) and (g(x)=5x-6), what is ((f+g)(x))?
#algebra
#real functions
#constant function
#addition
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A (5x-5)
B (5x-6)
C (5x-7)
D (5x)
Explanation opens after your attempt
Step 1
Concept
((f+g)(x)=1+(5x-6)=5x-5). Add constant terms carefully.
Step 2
Why this answer is correct
The correct answer is A. (5x-5). ((f+g)(x)=1+(5x-6)=5x-5). Add constant terms carefully.
Step 3
Exam Tip
((f+g)(x)=1+(5x-6)=5x-5)। स्थिर पदों को ध्यान से जोड़ें।
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यदि (f(x)=x+9) और (g(x)=9-x), तो ((f+g)(x)) क्या होगा?
If (f(x)=x+9) and (g(x)=9-x), what will ((f+g)(x)) be?
#algebra
#real functions
#function addition
#cancellation
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A (2x)
B (18)
C \(x^2-81\)
D (0)
Explanation opens after your attempt
Step 1
Concept
((f+g)(x)=(x+9)+(9-x)=18). The terms (x) and (-x) cancel out.
Step 2
Why this answer is correct
The correct answer is B. (18). ((f+g)(x)=(x+9)+(9-x)=18). The terms (x) and (-x) cancel out.
Step 3
Exam Tip
((f+g)(x)=(x+9)+(9-x)=18)। (x) और (-x) कट जाते हैं।
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यदि (f(x)=x-2 +5x) और (g(x)=x-2 +2x), तो ((f-g)(x)) क्या है?
If (f(x)=x-2 +5x) and (g(x)=x-2 +2x), what is ((f-g)(x))?
#algebra
#real functions
#polynomial subtraction
#easy
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A \(2x^2+7x\)
B (3x)
C (7x)
D \(x^2+3x\)
Explanation opens after your attempt
Step 1
Concept
((f-g)(x)=x-2 +5x-\(x^2+2x\)=3x). The like \(x^2\) terms cancel out.
Step 2
Why this answer is correct
The correct answer is B. (3x). ((f-g)(x)=x-2 +5x-\(x^2+2x\)=3x). The like \(x^2\) terms cancel out.
Step 3
Exam Tip
((f-g)(x)=x-2 +5x-\(x^2+2x\)=3x)। समान \(x^2\) पद कट जाते हैं।
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यदि (f(x)=x+7) और (g(x)=3x-2), तो ((fg)(1)) का मान क्या है?
If (f(x)=x+7) and (g(x)=3x-2), what is the value of ((fg)(1))?
#algebra
#real functions
#product
#value
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A (8)
B (6)
C (1)
D (14)
Explanation opens after your attempt
Step 1
Concept
((fg)(1)=f(1)g(1)=8\cdot1=8). First find both values.
Step 2
Why this answer is correct
The correct answer is A. (8). ((fg)(1)=f(1)g(1)=8\cdot1=8). First find both values.
Step 3
Exam Tip
((fg)(1)=f(1)g(1)=8\cdot1=8)। पहले दोनों मान निकालें।
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यदि (f(x)=x-2 +10) और (g(x)=x-2 +4), तो ((f-g)(1)) क्या है?
If (f(x)=x-2 +10) and (g(x)=x-2 +4), what is ((f-g)(1))?
#algebra
#real functions
#value based
#subtraction
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A (4)
B (5)
C (6)
D (16)
Explanation opens after your attempt
Step 1
Concept
((f-g)(1)=f(1)-g(1)=11-5=6). Here the \(x^2\) terms effectively cancel.
Step 2
Why this answer is correct
The correct answer is C. (6). ((f-g)(1)=f(1)-g(1)=11-5=6). Here the \(x^2\) terms effectively cancel.
Step 3
Exam Tip
((f-g)(1)=f(1)-g(1)=11-5=6)। यहाँ \(x^2\) पद प्रभावी रूप से कट जाते हैं।
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यदि (f(x)=6x+1) और (g(x)=2x+3), तो (\left\(\frac{f}{g}\right\)(0)) क्या होगा?
If (f(x)=6x+1) and (g(x)=2x+3), what will (\left\(\frac{f}{g}\right\)(0)) be?
#algebra
#real functions
#quotient
#value based
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A \(\frac{1}{3}\)
B (3)
C \(\frac{3}{1}\)
D (0)
Explanation opens after your attempt
Correct Answer
A. \(\frac{1}{3}\)
Step 1
Concept
(\left\(\frac{f}{g}\right\)(0)=\frac{1}{3}). The denominator is (3), so the quotient is valid.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{1}{3}\). (\left\(\frac{f}{g}\right\)(0)=\frac{1}{3}). The denominator is (3), so the quotient is valid.
Step 3
Exam Tip
(\left\(\frac{f}{g}\right\)(0)=\frac{1}{3})। हर (3) है, इसलिए भाग मान्य है।
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यदि (f(x)=\sqrt{x+5}) और (g(x)=x), तो ((f+g)(4)) का मान क्या है?
If (f(x)=\sqrt{x+5}) and (g(x)=x), what is the value of ((f+g)(4))?
#algebra
#real functions
#radical function
#value
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A (5)
B (6)
C (7)
D (9)
Explanation opens after your attempt
Step 1
Concept
((f+g)(4)=\sqrt{9}+4=3+4=7). For a radical term, first find the inside value.
Step 2
Why this answer is correct
The correct answer is C. (7). ((f+g)(4)=\sqrt{9}+4=3+4=7). For a radical term, first find the inside value.
Step 3
Exam Tip
((f+g)(4)=\sqrt{9}+4=3+4=7)। मूल वाले पद में पहले अंदर का मान निकालें।
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यदि (f(x)=x-2 +1) और (g(x)=\sqrt{x}), तो ((fg)(4)) क्या होगा?
If (f(x)=x-2 +1) and (g(x)=\sqrt{x}), what will ((fg)(4)) be?
#algebra
#real functions
#product
#radical function
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A (17)
B (34)
C (18)
D (68)
Explanation opens after your attempt
Step 1
Concept
((fg)(4)=f(4)g(4)=17\cdot2=34). Finding separate values is the safest method.
Step 2
Why this answer is correct
The correct answer is B. (34). ((fg)(4)=f(4)g(4)=17\cdot2=34). Finding separate values is the safest method.
Step 3
Exam Tip
((fg)(4)=f(4)g(4)=17\cdot2=34)। अलग-अलग मान निकालना सबसे सुरक्षित तरीका है।
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यदि (f(x)=\frac{2}{x}) और (g(x)=x-2 ), तो ((fg)(3)) का मान क्या है?
If (f(x)=\frac{2}{x}) and (g(x)=x-2 ), what is the value of ((fg)(3))?
#algebra
#real functions
#reciprocal function
#product
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A (6)
B (9)
C \(\frac{2}{3}\)
D (18)
Explanation opens after your attempt
Step 1
Concept
((fg)(3)=\frac{2}{3}\cdot9=6). A reciprocal-type function keeps the condition \(x\neq0\).
Step 2
Why this answer is correct
The correct answer is A. (6). ((fg)(3)=\frac{2}{3}\cdot9=6). A reciprocal-type function keeps the condition \(x\neq0\).
Step 3
Exam Tip
((fg)(3)=\frac{2}{3}\cdot9=6)। भिन्न फलन में \(x\neq0\) शर्त रहती है।
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यदि (f(x)=x+12) और (g(x)=x+3), तो (\left\(\frac{f}{g}\right\)(3)) क्या है?
If (f(x)=x+12) and (g(x)=x+3), what is (\left\(\frac{f}{g}\right\)(3))?
#algebra
#real functions
#quotient
#simplification
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A \(\frac{5}{2}\)
B (5)
C \(\frac{2}{5}\)
D (3)
Explanation opens after your attempt
Correct Answer
A. \(\frac{5}{2}\)
Step 1
Concept
(\left\(\frac{f}{g}\right\)(3)=\frac{15}{6}=\frac{5}{2}). Write the final answer in simplest fraction form.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{5}{2}\). (\left\(\frac{f}{g}\right\)(3)=\frac{15}{6}=\frac{5}{2}). Write the final answer in simplest fraction form.
Step 3
Exam Tip
(\left\(\frac{f}{g}\right\)(3)=\frac{15}{6}=\frac{5}{2})। अंतिम उत्तर को सरल भिन्न में लिखें।
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यदि (f(x)=x+4) और (g(x)=x-4), तो ((fg)(x)) को सरल करने के लिए कौन-सी पहचान उपयोगी है?
If (f(x)=x+4) and (g(x)=x-4), which identity is useful to simplify ((fg)(x))?
#algebra
#real functions
#identity
#product
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A \(a^2-b^2\)
B \(a^2+2ab+b^2\)
C \(a^2-2ab+b^2\)
D \(a^3-b^3\)
Explanation opens after your attempt
Correct Answer
A. \(a^2-b^2\)
Step 1
Concept
((x+4)(x-4)) uses \(a^2-b^2\). It gives the answer \(x^2-16\).
Step 2
Why this answer is correct
The correct answer is A. \(a^2-b^2\). ((x+4)(x-4)) uses \(a^2-b^2\). It gives the answer \(x^2-16\).
Step 3
Exam Tip
((x+4)(x-4)) में \(a^2-b^2\) लगता है। इससे उत्तर \(x^2-16\) मिलता है।
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यदि (f(x)=2x-2 +3) और (g(x)=x+5), तो ((f+g)(1)) क्या है?
If (f(x)=2x-2 +3) and (g(x)=x+5), what is ((f+g)(1))?
#algebra
#real functions
#value
#function addition
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A (6)
B (9)
C (11)
D (12)
Explanation opens after your attempt
Step 1
Concept
((f+g)(1)=f(1)+g(1)=5+6=11). First put (x=1), then add.
Step 2
Why this answer is correct
The correct answer is C. (11). ((f+g)(1)=f(1)+g(1)=5+6=11). First put (x=1), then add.
Step 3
Exam Tip
((f+g)(1)=f(1)+g(1)=5+6=11)। पहले (x=1) रखें, फिर जोड़ें।
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यदि (f(x)=5x-2 +2) और (g(x)=2x-2 -7), तो ((f-g)(x)) क्या होगा?
If (f(x)=5x-2 +2) and (g(x)=2x-2 -7), what will ((f-g)(x)) be?
#algebra
#real functions
#polynomial subtraction
#signs
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A \(3x^2-5\)
B \(7x^2-5\)
C \(3x^2+9\)
D \(7x^2+9\)
Explanation opens after your attempt
Correct Answer
C. \(3x^2+9\)
Step 1
Concept
((f-g)(x)=5x-2 +2-\(2x^2-7\)=3x-2 +9). Applying the minus to (-7) gives (+7).
Step 2
Why this answer is correct
The correct answer is C. \(3x^2+9\). ((f-g)(x)=5x-2 +2-\(2x^2-7\)=3x-2 +9). Applying the minus to (-7) gives (+7).
Step 3
Exam Tip
((f-g)(x)=5x-2 +2-\(2x^2-7\)=3x-2 +9)। ऋण को (-7) पर लगाने से (+7) आता है।
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यदि (f(x)=x-6) और (g(x)=x), तो ((fg)(x)) क्या है?
If (f(x)=x-6) and (g(x)=x), what is ((fg)(x))?
#algebra
#real functions
#product
#distributive law
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A \(x^2-6x\)
B (2x-6)
C \(x^2-6\)
D \(6x^2\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-6x\)
Step 1
Concept
((fg)(x)=(x-6)x=x-2 -6x). Multiply (x) with both terms.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-6x\). ((fg)(x)=(x-6)x=x-2 -6x). Multiply (x) with both terms.
Step 3
Exam Tip
((fg)(x)=(x-6)x=x-2 -6x)। (x) को दोनों पदों से गुणा करें।
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यदि (f(x)=4x+11) और (g(x)=x-6), तो ((f+g)(x)) क्या है?
If (f(x)=4x+11) and (g(x)=x-6), what is ((f+g)(x))?
#algebra
#real functions
#linear functions
#addition
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A (5x+5)
B (3x+17)
C (5x+17)
D \(4x^2-13x-66\)
Explanation opens after your attempt
Step 1
Concept
((f+g)(x)=4x+11+x-6=5x+5). Add (x)-terms and constant terms separately.
Step 2
Why this answer is correct
The correct answer is A. (5x+5). ((f+g)(x)=4x+11+x-6=5x+5). Add (x)-terms and constant terms separately.
Step 3
Exam Tip
((f+g)(x)=4x+11+x-6=5x+5)। (x) पद और स्थिर पद अलग-अलग जोड़ें।
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यदि (f(x)=8) और (g(x)=x-2 -3x), तो ((f-g)(x)) क्या है?
If (f(x)=8) and (g(x)=x-2 -3x), what is ((f-g)(x))?
#algebra
#real functions
#constant function
#subtraction
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A \(x^2-3x-8\)
B \(8-x^2+3x\)
C \(8x^2-24x\)
D \(x^2+3x+8\)
Explanation opens after your attempt
Correct Answer
B. \(8-x^2+3x\)
Step 1
Concept
((f-g)(x)=8-\(x^2-3x\)=8-x-2 +3x). In subtraction, signs of the whole (g(x)) change.
Step 2
Why this answer is correct
The correct answer is B. \(8-x^2+3x\). ((f-g)(x)=8-\(x^2-3x\)=8-x-2 +3x). In subtraction, signs of the whole (g(x)) change.
Step 3
Exam Tip
((f-g)(x)=8-\(x^2-3x\)=8-x-2 +3x)। घटाने में पूरे (g(x)) के चिह्न बदलते हैं।
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यदि (f(x)=x-2 -25) और (g(x)=x+5), तो (\left\(\frac{f}{g}\right\)(x)) का सरल रूप क्या है, जहाँ \(x\neq-5\)?
If (f(x)=x-2 -25) and (g(x)=x+5), what is the simplified form of (\left\(\frac{f}{g}\right\)(x)), where \(x\neq-5\)?
#algebra
#real functions
#quotient
#factorization
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A (x-5)
B (x+5)
C \(x^2-5\)
D (x-25)
Explanation opens after your attempt
Step 1
Concept
(\frac{x-2 -25}{x+5}=\frac{(x-5)(x+5)}{x+5}=x-5). Keep the condition \(x\neq-5\).
Step 2
Why this answer is correct
The correct answer is A. (x-5). (\frac{x-2 -25}{x+5}=\frac{(x-5)(x+5)}{x+5}=x-5). Keep the condition \(x\neq-5\).
Step 3
Exam Tip
(\frac{x-2 -25}{x+5}=\frac{(x-5)(x+5)}{x+5}=x-5)। शर्त \(x\neq-5\) साथ रखें।
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यदि (f(x)=x-2 -4x+4) और (g(x)=x-2), तो (\left\(\frac{f}{g}\right\)(x)) क्या है, जहाँ \(x\neq2\)?
If (f(x)=x-2 -4x+4) and (g(x)=x-2), what is (\left\(\frac{f}{g}\right\)(x)), where \(x\neq2\)?
#algebra
#real functions
#quotient
#perfect square
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A (x+2)
B (x-2)
C \(x^2-2\)
D (2x-4)
Explanation opens after your attempt
Step 1
Concept
Since (x-2 -4x+4=(x-2)2 ), the quotient is (x-2). Remove (x=2) from the domain.
Step 2
Why this answer is correct
The correct answer is B. (x-2). Since (x-2 -4x+4=(x-2)2 ), the quotient is (x-2). Remove (x=2) from the domain.
Step 3
Exam Tip
क्योंकि (x-2 -4x+4=(x-2)2 ), इसलिए भागफल (x-2) है। (x=2) को डोमेन से हटाएँ।
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यदि (f(x)=x-1) और (g(x)=x+10), तो ((f+g)(1)) क्या होगा?
If (f(x)=x-1) and (g(x)=x+10), what will ((f+g)(1)) be?
#algebra
#real functions
#value
#addition
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A (10)
B (11)
C (12)
D (0)
Explanation opens after your attempt
Step 1
Concept
((f+g)(1)=f(1)+g(1)=0+11=11). Include the zero value in the sum.
Step 2
Why this answer is correct
The correct answer is B. (11). ((f+g)(1)=f(1)+g(1)=0+11=11). Include the zero value in the sum.
Step 3
Exam Tip
((f+g)(1)=f(1)+g(1)=0+11=11)। शून्य मान को जोड़ में शामिल करें।
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यदि (f(x)=5x) और (g(x)=x+1), तो ((fg)(3)) का मान क्या है?
If (f(x)=5x) and (g(x)=x+1), what is the value of ((fg)(3))?
#algebra
#real functions
#product
#value
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A (45)
B (60)
C (15)
D (20)
Explanation opens after your attempt
Step 1
Concept
((fg)(3)=f(3)g(3)=15\cdot4=60). (fg) means product of functions.
Step 2
Why this answer is correct
The correct answer is B. (60). ((fg)(3)=f(3)g(3)=15\cdot4=60). (fg) means product of functions.
Step 3
Exam Tip
((fg)(3)=f(3)g(3)=15\cdot4=60)। (fg) का अर्थ फलनों का गुणन है।
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यदि (f(x)=x-2 -4) और (g(x)=x-2 +4), तो ((f+g)(x)) क्या है?
If (f(x)=x-2 -4) and (g(x)=x-2 +4), what is ((f+g)(x))?
#algebra
#real functions
#polynomial addition
#cancellation
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A \(2x^2\)
B (8)
C \(x^4-16\)
D \(2x^2+8\)
Explanation opens after your attempt
Correct Answer
A. \(2x^2\)
Step 1
Concept
((f+g)(x)=x-2 -4+x-2 +4=2x-2 ). Opposite constant terms cancel out.
Step 2
Why this answer is correct
The correct answer is A. \(2x^2\). ((f+g)(x)=x-2 -4+x-2 +4=2x-2 ). Opposite constant terms cancel out.
Step 3
Exam Tip
((f+g)(x)=x-2 -4+x-2 +4=2x-2 )। विपरीत स्थिर पद कट जाते हैं।
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यदि (f(x)=4x-2 -3) और (g(x)=x-2 +8), तो ((f-g)(x)) क्या होगा?
If (f(x)=4x-2 -3) and (g(x)=x-2 +8), what will ((f-g)(x)) be?
#algebra
#real functions
#subtraction
#polynomial
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A \(5x^2+5\)
B \(3x^2-11\)
C \(3x^2+5\)
D \(5x^2-11\)
Explanation opens after your attempt
Correct Answer
B. \(3x^2-11\)
Step 1
Concept
((f-g)(x)=4x-2 -3-\(x^2+8\)=3x-2 -11). Pay attention to constant terms after brackets.
Step 2
Why this answer is correct
The correct answer is B. \(3x^2-11\). ((f-g)(x)=4x-2 -3-\(x^2+8\)=3x-2 -11). Pay attention to constant terms after brackets.
Step 3
Exam Tip
((f-g)(x)=4x-2 -3-\(x^2+8\)=3x-2 -11)। कोष्ठक के बाद स्थिर पदों पर ध्यान दें।
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यदि (f(x)=x-5) और (g(x)=3), तो ((fg)(x)) क्या है?
If (f(x)=x-5) and (g(x)=3), what is ((fg)(x))?
#algebra
#real functions
#constant function
#product
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A (3x-15)
B (x-2)
C (3x-5)
D \(x^2-15\)
Explanation opens after your attempt
Correct Answer
A. (3x-15)
Step 1
Concept
((fg)(x)=(x-5)\cdot3=3x-15). Multiplication by a constant function multiplies all terms.
Step 2
Why this answer is correct
The correct answer is A. (3x-15). ((fg)(x)=(x-5)\cdot3=3x-15). Multiplication by a constant function multiplies all terms.
Step 3
Exam Tip
((fg)(x)=(x-5)\cdot3=3x-15)। स्थिर फलन से गुणा में सभी पद गुणित होते हैं।
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यदि (f(x)=12x-6) और (g(x)=6), तो (\left\(\frac{f}{g}\right\)(x)) क्या है?
If (f(x)=12x-6) and (g(x)=6), what is (\left\(\frac{f}{g}\right\)(x))?
#algebra
#real functions
#quotient
#constant denominator
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A (2x-1)
B (12x-1)
C (2x-6)
D (72x-36)
Explanation opens after your attempt
Step 1
Concept
(\left\(\frac{f}{g}\right\)(x)=\frac{12x-6}{6}=2x-1). Divide every numerator term by (6).
Step 2
Why this answer is correct
The correct answer is A. (2x-1). (\left\(\frac{f}{g}\right\)(x)=\frac{12x-6}{6}=2x-1). Divide every numerator term by (6).
Step 3
Exam Tip
(\left\(\frac{f}{g}\right\)(x)=\frac{12x-6}{6}=2x-1)। अंश के हर पद को (6) से भाग दें।
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यदि (f(x)=2x-11) और (g(x)=11-2x), तो ((f+g)(x)) क्या होगा?
If (f(x)=2x-11) and (g(x)=11-2x), what will ((f+g)(x)) be?
#algebra
#real functions
#additive inverse
#addition
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A (0)
B (4x-22)
C (22)
D (2x)
Explanation opens after your attempt
Step 1
Concept
((f+g)(x)=(2x-11)+(11-2x)=0). These two functions are additive inverses.
Step 2
Why this answer is correct
The correct answer is A. (0). ((f+g)(x)=(2x-11)+(11-2x)=0). These two functions are additive inverses.
Step 3
Exam Tip
((f+g)(x)=(2x-11)+(11-2x)=0)। ये दोनों फलन योगात्मक प्रतिलोम हैं।
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यदि (f(x)=3x+8) और (g(x)=3x-8), तो ((f-g)(x)) क्या है?
If (f(x)=3x+8) and (g(x)=3x-8), what is ((f-g)(x))?
#algebra
#real functions
#subtraction
#linear functions
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A (6x)
B (16)
C (6x+16)
D (0)
Explanation opens after your attempt
Step 1
Concept
((f-g)(x)=3x+8-(3x-8)=16). The (3x) terms cancel out.
Step 2
Why this answer is correct
The correct answer is B. (16). ((f-g)(x)=3x+8-(3x-8)=16). The (3x) terms cancel out.
Step 3
Exam Tip
((f-g)(x)=3x+8-(3x-8)=16)। (3x) पद कट जाते हैं।
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यदि (f(x)=x-5 ) और (g(x)=x-2 ), तो ((fg)(x)) क्या है?
If (f(x)=x-5 ) and (g(x)=x-2 ), what is ((fg)(x))?
#algebra
#real functions
#product
#exponents
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A \(x^7\)
B \(x^{10}\)
C \(2x^5\)
D \(x^3\)
Explanation opens after your attempt
Correct Answer
A. \(x^7\)
Step 1
Concept
((fg)(x)=x-5 \cdot x-2 =x-7 ). Add powers while multiplying the same base.
Step 2
Why this answer is correct
The correct answer is A. \(x^7\). ((fg)(x)=x-5 \cdot x-2 =x-7 ). Add powers while multiplying the same base.
Step 3
Exam Tip
((fg)(x)=x-5 \cdot x-2 =x-7 )। समान आधार में गुणा करते समय घातों को जोड़ें।
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यदि (f(x)=x-6 ) और (g(x)=x-3 ), तो (\left\(\frac{f}{g}\right\)(x)) क्या होगा, जहाँ \(x\neq0\)?
If (f(x)=x-6 ) and (g(x)=x-3 ), what will (\left\(\frac{f}{g}\right\)(x)) be, where \(x\neq0\)?
#algebra
#real functions
#quotient
#exponents
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A \(x^9\)
B \(x^3\)
C \(x^2\)
D (1)
Explanation opens after your attempt
Correct Answer
B. \(x^3\)
Step 1
Concept
(\left\(\frac{f}{g}\right\)(x)=\frac{x-6 }{x-3 }=x-3 ), where \(x\neq0\). In division, subtract powers of the same base.
Step 2
Why this answer is correct
The correct answer is B. \(x^3\). (\left\(\frac{f}{g}\right\)(x)=\frac{x-6 }{x-3 }=x-3 ), where \(x\neq0\). In division, subtract powers of the same base.
Step 3
Exam Tip
(\left\(\frac{f}{g}\right\)(x)=\frac{x-6 }{x-3 }=x-3 ), जहाँ \(x\neq0\)। भाग में समान आधार की घातें घटाएँ।
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यदि (f(x)=2x+1) और (g(x)=x-2 +3), दोनों का डोमेन \(\mathbb{R}\) है, तो ((fg)(x)) का डोमेन क्या है?
If (f(x)=2x+1) and (g(x)=x-2 +3), both have domain \(\mathbb{R}\), what is the domain of ((fg)(x))?
#algebra
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#domain
#product
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A \(\mathbb{R}\)
B \(\mathbb{R}-{0}\)
C ({1,3})
D \(\emptyset\)
Explanation opens after your attempt
Correct Answer
A. \(\mathbb{R}\)
Step 1
Concept
Both polynomials are defined on all \(\mathbb{R}\), so the product domain is \(\mathbb{R}\). The domain is the set of common allowed values.
Step 2
Why this answer is correct
The correct answer is A. \(\mathbb{R}\). Both polynomials are defined on all \(\mathbb{R}\), so the product domain is \(\mathbb{R}\). The domain is the set of common allowed values.
Step 3
Exam Tip
दोनों बहुपद पूरे \(\mathbb{R}\) पर परिभाषित हैं, इसलिए गुणनफल का डोमेन \(\mathbb{R}\) है। डोमेन सामान्य मानों का समुच्चय होता है।
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यदि (f(x)=\sqrt{x}) और (g(x)=x+2), तो ((f+g)(x)) का डोमेन क्या है?
If (f(x)=\sqrt{x}) and (g(x)=x+2), what is the domain of ((f+g)(x))?
#algebra
#real functions
#domain
#radical function
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A \([0,\infty\))
B \(\mathbb{R}\)
C (\(-\infty,0]\)
D \(\mathbb{R}-{0}\)
Explanation opens after your attempt
Correct Answer
A. \([0,\infty\))
Step 1
Concept
For \(\sqrt{x}\), we need \(x\geq0\), so the domain of the sum is \([0,\infty\)). Take the common domain.
Step 2
Why this answer is correct
The correct answer is A. \([0,\infty\)). For \(\sqrt{x}\), we need \(x\geq0\), so the domain of the sum is \([0,\infty\)). Take the common domain.
Step 3
Exam Tip
\(\sqrt{x}\) के लिए \(x\geq0\) चाहिए, इसलिए योग का डोमेन \([0,\infty\)) है। साझा डोमेन लें।
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यदि (f(x)=x+4) और (g(x)=x-2 -9), तो (\left\(\frac{f}{g}\right\)(x)) का डोमेन क्या है?
If (f(x)=x+4) and (g(x)=x-2 -9), what is the domain of (\left\(\frac{f}{g}\right\)(x))?
#algebra
#real functions
#domain
#quotient
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A \(\mathbb{R}-{-3,3}\)
B \(\mathbb{R}\)
C \(\mathbb{R}-{4}\)
D ((-3,3))
Explanation opens after your attempt
Correct Answer
A. \(\mathbb{R}-{-3,3}\)
Step 1
Concept
In division, (g(x)\neq0) is needed, and \(x^2-9=0\) gives \(x=\pm3\). So the domain is \(\mathbb{R}-{-3,3}\).
Step 2
Why this answer is correct
The correct answer is A. \(\mathbb{R}-{-3,3}\). In division, (g(x)\neq0) is needed, and \(x^2-9=0\) gives \(x=\pm3\). So the domain is \(\mathbb{R}-{-3,3}\).
Step 3
Exam Tip
भाग में (g(x)\neq0) चाहिए, और \(x^2-9=0\) से \(x=\pm3\) मिलता है। इसलिए डोमेन \(\mathbb{R}-{-3,3}\) है।
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