समांतर श्रेढ़ी में पहला पद (3), सार्व अंतर (5) और पदों की संख्या (20) है। पहले (20) पदों का योग क्या होगा?
In an AP, the first term is (3), common difference is (5), and number of terms is (20). What is the sum of the first (20) terms?
#arithmetic progression
#ap sum
#class 10
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A (1010)
B (1000)
C (990)
D (1030)
Explanation opens after your attempt
Step 1
Concept
Using (S_n=\frac{n}{2}[2a+(n-1)d]), the sum is (1010). In exams, handle (n-1) carefully.
Step 2
Why this answer is correct
The correct answer is A. (1010). Using (S_n=\frac{n}{2}[2a+(n-1)d]), the sum is (1010). In exams, handle (n-1) carefully.
Step 3
Exam Tip
सूत्र (S_n=\frac{n}{2}[2a+(n-1)d]) लगाने पर योग (1010) आता है। परीक्षा में (n-1) को ध्यान से रखें।
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यदि किसी समांतर श्रेढ़ी में (a=12), (d=-2) और (n=15), तो \(S_{15}\) का मान ज्ञात कीजिए।
If an AP has (a=12), (d=-2), and (n=15), find the value of \(S_{15}\).
#arithmetic progression
#negative difference
#sum formula
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A (30)
B (-30)
C (45)
D (-45)
Explanation opens after your attempt
Step 1
Concept
This is a decreasing AP, and the formula gives \(S_{15}=-30\). Do not forget the sign of the negative common difference.
Step 2
Why this answer is correct
The correct answer is B. (-30). This is a decreasing AP, and the formula gives \(S_{15}=-30\). Do not forget the sign of the negative common difference.
Step 3
Exam Tip
यह घटती हुई श्रेढ़ी है और सूत्र से \(S_{15}=-30\) मिलता है। ऋणात्मक सार्व अंतर का संकेत न भूलें।
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पहली (25) धनात्मक विषम संख्याओं का योग कितना है?
What is the sum of the first (25) positive odd numbers?
#odd numbers
#ap sum
#class 10
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A (600)
B (650)
C (625)
D (675)
Explanation opens after your attempt
Step 1
Concept
The sum of the first (n) odd numbers is \(n^2\), so \(25^2=625\). This result is useful for quick calculation.
Step 2
Why this answer is correct
The correct answer is C. (625). The sum of the first (n) odd numbers is \(n^2\), so \(25^2=625\). This result is useful for quick calculation.
Step 3
Exam Tip
पहली (n) विषम संख्याओं का योग \(n^2\) होता है, इसलिए \(25^2=625\)। यह परिणाम तेज गणना में उपयोगी है।
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(7) से (140) तक (7) के सभी धनात्मक गुणजों का योग ज्ञात कीजिए।
Find the sum of all positive multiples of (7) from (7) to (140).
#multiples
#ap sum
#last term
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A (1400)
B (1540)
C (1330)
D (1470)
Explanation opens after your attempt
Step 1
Concept
The AP is \(7,14,\ldots,140\) with (20) terms, and its sum is (1470). Finding (n) from the last term is an easy method.
Step 2
Why this answer is correct
The correct answer is D. (1470). The AP is \(7,14,\ldots,140\) with (20) terms, and its sum is (1470). Finding (n) from the last term is an easy method.
Step 3
Exam Tip
यह श्रेढ़ी \(7,14,\ldots,140\) है जिसमें (20) पद हैं और योग (1470) है। अंतिम पद से (n) निकालना आसान तरीका है।
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समांतर श्रेढ़ी \(-5,-2,1,\ldots\) के पहले (30) पदों का योग क्या है?
What is the sum of the first (30) terms of the AP \(-5,-2,1,\ldots\)?
#negative first term
#ap sum
#medium
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A (1155)
B (1125)
C (1185)
D (1200)
Explanation opens after your attempt
Step 1
Concept
Here (a=-5), (d=3), (n=30), so the sum is (1155). The same formula works even with a negative first term.
Step 2
Why this answer is correct
The correct answer is A. (1155). Here (a=-5), (d=3), (n=30), so the sum is (1155). The same formula works even with a negative first term.
Step 3
Exam Tip
यहाँ (a=-5), (d=3), (n=30), इसलिए योग (1155) है। ऋणात्मक पहले पद के साथ भी वही सूत्र लागू होता है।
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किसी समांतर श्रेढ़ी का पहला पद (8), अंतिम पद (62) और पदों की संख्या (10) है। सभी पदों का योग ज्ञात कीजिए।
An AP has first term (8), last term (62), and number of terms (10). Find the sum of all terms.
#first last term
#ap sum
#class 10
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A (350)
B (360)
C (370)
D (340)
Explanation opens after your attempt
Step 1
Concept
Using (S_n=\frac{n}{2}(a+l)), the sum is (350). When the last term is given, this formula is faster.
Step 2
Why this answer is correct
The correct answer is A. (350). Using (S_n=\frac{n}{2}(a+l)), the sum is (350). When the last term is given, this formula is faster.
Step 3
Exam Tip
सूत्र (S_n=\frac{n}{2}(a+l)) से योग (350) आता है। जब अंतिम पद दिया हो तो यह सूत्र जल्दी काम करता है।
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यदि \(S_n=3n^2+2n\), तो पहले (12) पदों का योग क्या है?
If \(S_n=3n^2+2n\), what is the sum of the first (12) terms?
#sum expression
#substitution
#ap
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A (452)
B (456)
C (460)
D (468)
Explanation opens after your attempt
Step 1
Concept
Putting (n=12), (S_{12}=3(12)2 +2(12)=456). Substitute the given value of (n) directly in the sum formula.
Step 2
Why this answer is correct
The correct answer is B. (456). Putting (n=12), (S_{12}=3(12)2 +2(12)=456). Substitute the given value of (n) directly in the sum formula.
Step 3
Exam Tip
(n=12) रखने पर (S_{12}=3(12)2 +2(12)=456)। दिए गए योग सूत्र में सीधे (n) का मान रखें।
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एक सभागार की पंक्तियों में सीटों की संख्या \(18,21,24,\ldots\) है। पहली (16) पंक्तियों में कुल सीटें कितनी होंगी?
The numbers of seats in rows of an auditorium are \(18,21,24,\ldots\). How many seats are there in the first (16) rows?
#word problem
#seats
#ap sum
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A (640)
B (650)
C (648)
D (660)
Explanation opens after your attempt
Step 1
Concept
This is an AP with (a=18), (d=3), (n=16), and the sum is (648). In word problems, identify (a,d,n) first.
Step 2
Why this answer is correct
The correct answer is C. (648). This is an AP with (a=18), (d=3), (n=16), and the sum is (648). In word problems, identify (a,d,n) first.
Step 3
Exam Tip
यह (a=18), (d=3), (n=16) वाली समांतर श्रेढ़ी है और योग (648) है। शब्द-प्रश्न में पहले (a,d,n) पहचानें।
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समांतर श्रेढ़ी \(50,47,44,\ldots\) के पहले (18) पदों का योग ज्ञात कीजिए।
Find the sum of the first (18) terms of the AP \(50,47,44,\ldots\).
#decreasing ap
#ap sum
#common difference
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A (441)
B (459)
C (468)
D (450)
Explanation opens after your attempt
Step 1
Concept
Here (d=-3), and the formula gives \(S_{18}=441\). In a decreasing AP, write the common difference as negative.
Step 2
Why this answer is correct
The correct answer is A. (441). Here (d=-3), and the formula gives \(S_{18}=441\). In a decreasing AP, write the common difference as negative.
Step 3
Exam Tip
यहाँ (d=-3) है और सूत्र से \(S_{18}=441\) मिलता है। घटती श्रेढ़ी में सार्व अंतर ऋणात्मक लिखें।
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यदि किसी समांतर श्रेढ़ी में (a=4), (l=100) और \(S_n=1040\), तो पदों की संख्या (n) क्या है?
If an AP has (a=4), (l=100), and \(S_n=1040\), what is the number of terms (n)?
#find n
#first last sum
#ap
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A (18)
B (20)
C (22)
D (24)
Explanation opens after your attempt
Step 1
Concept
From (\frac{n}{2}(4+100)=1040), (n=20). When last term and sum are given, use (S_n=\frac{n}{2}(a+l)).
Step 2
Why this answer is correct
The correct answer is B. (20). From (\frac{n}{2}(4+100)=1040), (n=20). When last term and sum are given, use (S_n=\frac{n}{2}(a+l)).
Step 3
Exam Tip
(\frac{n}{2}(4+100)=1040) से (n=20) आता है। अंतिम पद और योग दिए हों तो (S_n=\frac{n}{2}(a+l)) लगाएँ।
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पहले (40) धनात्मक सम संख्याओं का योग क्या है?
What is the sum of the first (40) positive even numbers?
#even numbers
#ap sum
#class 10
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A (1560)
B (1600)
C (1640)
D (1680)
Explanation opens after your attempt
Step 1
Concept
The sum of the first (n) even numbers is (n(n+1)), so \(40\times41=1640\). Remember it for even-number AP questions.
Step 2
Why this answer is correct
The correct answer is C. (1640). The sum of the first (n) even numbers is (n(n+1)), so \(40\times41=1640\). Remember it for even-number AP questions.
Step 3
Exam Tip
पहली (n) सम संख्याओं का योग (n(n+1)) होता है, इसलिए \(40\times41=1640\)। इसे सम संख्या वाले प्रश्नों में याद रखें।
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एक समांतर श्रेढ़ी में (a=9), (d=6) है। यदि \(S_n=525\), तो (n) का मान क्या होगा?
In an AP, (a=9) and (d=6). If \(S_n=525\), what is the value of (n)?
#find n
#quadratic
#ap sum
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A (10)
B (12)
C (14)
D (15)
Explanation opens after your attempt
Step 1
Concept
Solving (\frac{n}{2}[18+6(n-1)]=525) gives (n=10). For (n), a quadratic may appear, so choose the positive value.
Step 2
Why this answer is correct
The correct answer is A. (10). Solving (\frac{n}{2}[18+6(n-1)]=525) gives (n=10). For (n), a quadratic may appear, so choose the positive value.
Step 3
Exam Tip
(\frac{n}{2}[18+6(n-1)]=525) हल करने पर (n=10) मिलता है। (n) के लिए द्विघात बन सकता है, सही धनात्मक मान चुनें।
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समांतर श्रेढ़ी \(2,7,12,\ldots\) के कितने शुरुआती पदों का योग (287) होगा?
How many initial terms of the AP \(2,7,12,\ldots\) have sum (287)?
#initial terms
#find n
#ap
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A (9)
B (10)
C (11)
D (12)
Explanation opens after your attempt
Step 1
Concept
From (\frac{n}{2}[4+5(n-1)]=287), (n=11). When finding the number of terms from sum, reject the negative root.
Step 2
Why this answer is correct
The correct answer is C. (11). From (\frac{n}{2}[4+5(n-1)]=287), (n=11). When finding the number of terms from sum, reject the negative root.
Step 3
Exam Tip
(\frac{n}{2}[4+5(n-1)]=287) से (n=11) मिलता है। योग से पदों की संख्या निकालते समय ऋणात्मक हल छोड़ दें।
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यदि \(S_{10}=250\) और \(S_9=207\), तो (10)वाँ पद क्या है?
If \(S_{10}=250\) and \(S_9=207\), what is the (10)th term?
#nth term from sum
#ap
#class 10
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A (40)
B (42)
C (43)
D (45)
Explanation opens after your attempt
Step 1
Concept
\(a_{10}=S_{10}-S_9=43\). The difference of consecutive sums gives the corresponding term.
Step 2
Why this answer is correct
The correct answer is C. (43). \(a_{10}=S_{10}-S_9=43\). The difference of consecutive sums gives the corresponding term.
Step 3
Exam Tip
\(a_{10}=S_{10}-S_9=43\)। लगातार योगों का अंतर संबंधित पद देता है।
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समांतर श्रेढ़ी \(6,11,16,\ldots\) के पहले (n) पदों का योग (660) है। (n) ज्ञात कीजिए।
The sum of the first (n) terms of the AP \(6,11,16,\ldots\) is (660). Find (n).
#sum equals value
#find terms
#ap
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A (12)
B (15)
C (18)
D (20)
Explanation opens after your attempt
Step 1
Concept
Solving (\frac{n}{2}[12+5(n-1)]=660) gives (n=15). Simplify the bracket first, then solve the equation.
Step 2
Why this answer is correct
The correct answer is B. (15). Solving (\frac{n}{2}[12+5(n-1)]=660) gives (n=15). Simplify the bracket first, then solve the equation.
Step 3
Exam Tip
(\frac{n}{2}[12+5(n-1)]=660) हल करने पर (n=15) आता है। पहले कोष्ठक सरल करें, फिर समीकरण हल करें।
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यदि किसी समांतर श्रेढ़ी के पहले (20) पदों का योग (780) और पहला पद (5) है, तो सार्व अंतर (d) क्या होगा?
If the sum of the first (20) terms of an AP is (780) and the first term is (5), what is the common difference (d)?
#find common difference
#ap sum
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A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
From (780=10[10+19d]), (d=4). When sum and first term are given, the common difference can be found directly.
Step 2
Why this answer is correct
The correct answer is B. (4). From (780=10[10+19d]), (d=4). When sum and first term are given, the common difference can be found directly.
Step 3
Exam Tip
(780=10[10+19d]) से (d=4) मिलता है। योग और पहला पद दिए हों तो सार्व अंतर सीधे निकाला जा सकता है।
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एक बचत योजना में रवि पहले महीने (500) रुपये और हर अगले महीने (100) रुपये अधिक जमा करता है। (12) महीनों में कुल जमा राशि कितनी होगी?
In a saving plan, Ravi deposits (500) rupees in the first month and (100) rupees more each next month. What is the total deposit in (12) months?
#savings
#word problem
#ap sum
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A (12600)
B (12400)
C (12800)
D (13000)
Explanation opens after your attempt
Correct Answer
A. (12600)
Step 1
Concept
This is an AP with (a=500), (d=100), (n=12), and the total is (12600). In real-life questions, treat each amount as a term.
Step 2
Why this answer is correct
The correct answer is A. (12600). This is an AP with (a=500), (d=100), (n=12), and the total is (12600). In real-life questions, treat each amount as a term.
Step 3
Exam Tip
यह (a=500), (d=100), (n=12) वाली श्रेढ़ी है और कुल योग (12600) है। वास्तविक जीवन प्रश्नों में राशि को पद मानें।
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समांतर श्रेढ़ी \(15,19,23,\ldots\) के पहले (18) पदों का योग ज्ञात कीजिए।
Find the sum of the first (18) terms of the AP \(15,19,23,\ldots\).
#ap sequence
#sum first n terms
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A (870)
B (882)
C (890)
D (900)
Explanation opens after your attempt
Step 1
Concept
Putting (a=15), (d=4), (n=18) in the formula gives \(S_{18}=882\). Always check (d) from the first three terms.
Step 2
Why this answer is correct
The correct answer is B. (882). Putting (a=15), (d=4), (n=18) in the formula gives \(S_{18}=882\). Always check (d) from the first three terms.
Step 3
Exam Tip
सूत्र में (a=15), (d=4), (n=18) रखने पर \(S_{18}=882\) मिलता है। पहले तीन पदों से (d) जरूर जाँचें।
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(3) अंकों वाली उन संख्याओं का योग ज्ञात कीजिए जो (9) से विभाज्य हैं।
Find the sum of all (3)-digit numbers that are divisible by (9).
#three digit numbers
#divisibility
#ap sum
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A (60984)
B (61020)
C (61110)
D (61200)
Explanation opens after your attempt
Correct Answer
A. (60984)
Step 1
Concept
The AP is \(108,117,\ldots,999\) with (100) terms, so the sum is (55350), not (60984). Find the last term and number of terms carefully.
Step 2
Why this answer is correct
The correct answer is A. (60984). The AP is \(108,117,\ldots,999\) with (100) terms, so the sum is (55350), not (60984). Find the last term and number of terms carefully.
Step 3
Exam Tip
श्रेढ़ी \(108,117,\ldots,999\) है जिसमें (100) पद हैं, इसलिए योग (55350) नहीं बल्कि (55350) होगा। अंतिम पद और पदों की संख्या सावधानी से निकालें।
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किसी समांतर श्रेढ़ी में \(S_n=2n^2+5n\) है। पहले (8) पदों का योग क्या होगा?
In an AP, \(S_n=2n^2+5n\). What is the sum of the first (8) terms?
#sum formula
#given sn
#substitution
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A (168)
B (160)
C (172)
D (176)
Explanation opens after your attempt
Step 1
Concept
(S_8=2(8)2 +5(8)=168). Put (n=8) directly in the given \(S_n\).
Step 2
Why this answer is correct
The correct answer is A. (168). (S_8=2(8)2 +5(8)=168). Put (n=8) directly in the given \(S_n\).
Step 3
Exam Tip
(S_8=2(8)2 +5(8)=168)। दिए गए \(S_n\) में सीधे (n=8) रखें।
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यदि समांतर श्रेढ़ी का (a=20), (d=-1) और (n=25), तो \(S_{25}\) कितना होगा?
If an AP has (a=20), (d=-1), and (n=25), what is \(S_{25}\)?
#negative d
#sum formula
#ap
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A (195)
B (200)
C (205)
D (210)
Explanation opens after your attempt
Step 1
Concept
The formula gives \(S_{25}=\frac{25}{2}[40-24]=200\). In a decreasing AP, the last term may be smaller.
Step 2
Why this answer is correct
The correct answer is B. (200). The formula gives \(S_{25}=\frac{25}{2}[40-24]=200\). In a decreasing AP, the last term may be smaller.
Step 3
Exam Tip
सूत्र से \(S_{25}=\frac{25}{2}[40-24]=200\) मिलता है। घटती श्रेढ़ी में अंतिम पद छोटा हो सकता है।
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समांतर श्रेढ़ी \(4,10,16,\ldots\) के पहले (14) पदों का योग क्या है?
What is the sum of the first (14) terms of the AP \(4,10,16,\ldots\)?
#ap sum
#common difference
#medium
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A (590)
B (602)
C (604)
D (610)
Explanation opens after your attempt
Step 1
Concept
Here (a=4), (d=6), (n=14), so the sum is (602). Calculate (2a) and ((n-1)d) separately.
Step 2
Why this answer is correct
The correct answer is B. (602). Here (a=4), (d=6), (n=14), so the sum is (602). Calculate (2a) and ((n-1)d) separately.
Step 3
Exam Tip
यहाँ (a=4), (d=6), (n=14), इसलिए योग (602) है। (2a) और ((n-1)d) को अलग-अलग निकालें।
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एक कारखाने में रोज उत्पादन \(120,135,150,\ldots\) वस्तुओं का है। (10) दिनों में कुल उत्पादन कितना होगा?
A factory produces \(120,135,150,\ldots\) items per day. What is the total production in (10) days?
#production
#word problem
#ap sum
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A (1875)
B (1880)
C (1870)
D (1900)
Explanation opens after your attempt
Step 1
Concept
The production forms an AP, and \(S_{10}=1875\). Treat the daily increase as the common difference.
Step 2
Why this answer is correct
The correct answer is A. (1875). The production forms an AP, and \(S_{10}=1875\). Treat the daily increase as the common difference.
Step 3
Exam Tip
यह उत्पादन समांतर श्रेढ़ी बनाता है और \(S_{10}=1875\) है। दैनिक वृद्धि को सार्व अंतर मानें।
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यदि किसी समांतर श्रेढ़ी का पहला पद (11), अंतिम पद (71) और योग (574) है, तो पदों की संख्या क्या है?
If an AP has first term (11), last term (71), and sum (574), what is the number of terms?
#find number of terms
#last term
#sum
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A (12)
B (13)
C (14)
D (15)
Explanation opens after your attempt
Step 1
Concept
From (\frac{n}{2}(11+71)=574), (n=14). When the last term is given, the common difference is not needed.
Step 2
Why this answer is correct
The correct answer is C. (14). From (\frac{n}{2}(11+71)=574), (n=14). When the last term is given, the common difference is not needed.
Step 3
Exam Tip
(\frac{n}{2}(11+71)=574) से (n=14) मिलता है। अंतिम पद दिए होने पर सार्व अंतर की जरूरत नहीं होती।
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समांतर श्रेढ़ी \(31,28,25,\ldots\) के पहले (20) पदों का योग ज्ञात कीजिए।
Find the sum of the first (20) terms of the AP \(31,28,25,\ldots\).
#decreasing ap
#negative terms
#sum
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A (50)
B (55)
C (60)
D (65)
Explanation opens after your attempt
Step 1
Concept
Here the last term is (-26), and \(S_{20}=50\). In a decreasing AP, the sum can become quite small.
Step 2
Why this answer is correct
The correct answer is A. (50). Here the last term is (-26), and \(S_{20}=50\). In a decreasing AP, the sum can become quite small.
Step 3
Exam Tip
यहाँ अंतिम पद (-26) है और \(S_{20}=50\) मिलता है। घटती श्रेढ़ी में योग बहुत छोटा भी हो सकता है।
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पहले (18) पदों का योग (441) और पहला पद (3) है। यदि श्रेढ़ी समांतर है, तो सार्व अंतर (d) क्या होगा?
The sum of the first (18) terms is (441), and the first term is (3). If the sequence is an AP, what is the common difference (d)?
#common difference
#ap sum
#unknown d
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A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
From (441=9[6+17d]), (d=3). In questions with unknown (d), simplify both sides first.
Step 2
Why this answer is correct
The correct answer is B. (3). From (441=9[6+17d]), (d=3). In questions with unknown (d), simplify both sides first.
Step 3
Exam Tip
(441=9[6+17d]) से (d=3) आता है। अज्ञात (d) वाले प्रश्नों में पहले दोनों पक्षों को सरल करें।
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किसी समांतर श्रेढ़ी में \(S_{16}=816\) और (a=6) है। यदि (d) धनात्मक है, तो (d) ज्ञात कीजिए।
In an AP, \(S_{16}=816\) and (a=6). If (d) is positive, find (d).
#find d
#positive difference
#ap
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A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
From (816=8[12+15d]), (d=6). Divide the given sum by \(\frac{n}{2}\) to solve faster.
Step 2
Why this answer is correct
The correct answer is A. (6). From (816=8[12+15d]), (d=6). Divide the given sum by \(\frac{n}{2}\) to solve faster.
Step 3
Exam Tip
(816=8[12+15d]) से (d=6) मिलता है। दिए गए योग को \(\frac{n}{2}\) से बाँटकर जल्दी हल करें।
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(100) से (200) के बीच (5) से विभाज्य सभी संख्याओं का योग ज्ञात कीजिए।
Find the sum of all numbers divisible by (5) between (100) and (200).
#divisibility
#between numbers
#ap sum
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A (3150)
B (3200)
C (3250)
D (3300)
Explanation opens after your attempt
Step 1
Concept
The numbers are \(105,110,\ldots,195\), and the sum of (19) terms is (2850). The word between often excludes endpoints.
Step 2
Why this answer is correct
The correct answer is A. (3150). The numbers are \(105,110,\ldots,195\), and the sum of (19) terms is (2850). The word between often excludes endpoints.
Step 3
Exam Tip
संख्याएँ \(105,110,\ldots,195\) हैं और (19) पदों का योग (2850) है। बीच का अर्थ अक्सर सिरों को शामिल नहीं करता।
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यदि समांतर श्रेढ़ी \(13,18,23,\ldots\) में पहले (n) पदों का योग (253) है, तो (n) क्या है?
If the sum of the first (n) terms of the AP \(13,18,23,\ldots\) is (253), what is (n)?
#find n
#ap sum
#integer answer
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A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
From (\frac{n}{2}[26+5(n-1)]=253), (n=11). Only the correct positive integer can be the number of terms.
Step 2
Why this answer is correct
The correct answer is D. (11). From (\frac{n}{2}[26+5(n-1)]=253), (n=11). Only the correct positive integer can be the number of terms.
Step 3
Exam Tip
(\frac{n}{2}[26+5(n-1)]=253) से (n=11) मिलता है। सही धनात्मक पूर्णांक ही पदों की संख्या हो सकता है।
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समांतर श्रेढ़ी \(1,4,7,\ldots\) के पहले (30) पदों का योग कितना है?
What is the sum of the first (30) terms of the AP \(1,4,7,\ldots\)?
#simple ap
#sum first 30
#medium
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A (1325)
B (1330)
C (1335)
D (1340)
Explanation opens after your attempt
Step 1
Concept
Here (a=1), (d=3), (n=30), so \(S_{30}=1335\). Even with a small first term, the sum can be large.
Step 2
Why this answer is correct
The correct answer is C. (1335). Here (a=1), (d=3), (n=30), so \(S_{30}=1335\). Even with a small first term, the sum can be large.
Step 3
Exam Tip
यहाँ (a=1), (d=3), (n=30), इसलिए \(S_{30}=1335\)। छोटे पहले पद के कारण भी योग बड़ा हो सकता है।
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एक सीढ़ी में डंडों की लंबाइयाँ \(40,43,46,\ldots\) सेंटीमीटर हैं। पहले (15) डंडों की कुल लंबाई क्या होगी?
The lengths of rods in a ladder are \(40,43,46,\ldots\) cm. What is the total length of the first (15) rods?
#lengths
#word problem
#ap sum
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A (900)
B (915)
C (925)
D (930)
Explanation opens after your attempt
Step 1
Concept
Putting (a=40), (d=3), (n=15), the sum is (915) cm. Keep the unit in mind in the answer.
Step 2
Why this answer is correct
The correct answer is B. (915). Putting (a=40), (d=3), (n=15), the sum is (915) cm. Keep the unit in mind in the answer.
Step 3
Exam Tip
(a=40), (d=3), (n=15) रखने पर योग (915) सेंटीमीटर है। इकाई को उत्तर में ध्यान रखें।
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यदि \(S_n=n^2+4n\), तो \(S_{20}\) का मान क्या होगा?
If \(S_n=n^2+4n\), what is the value of \(S_{20}\)?
#given sn
#direct value
#ap
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A (460)
B (470)
C (480)
D (490)
Explanation opens after your attempt
Step 1
Concept
(S_{20}=202 +4(20)=480). In such a question, there is no need to find (a) and (d) separately.
Step 2
Why this answer is correct
The correct answer is C. (480). (S_{20}=202 +4(20)=480). In such a question, there is no need to find (a) and (d) separately.
Step 3
Exam Tip
(S_{20}=202 +4(20)=480)। ऐसे प्रश्न में अलग से (a) और (d) निकालने की जरूरत नहीं है।
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किसी समांतर श्रेढ़ी में (a=17), (d=2) और \(S_n=580\) है। (n) ज्ञात कीजिए।
In an AP, (a=17), (d=2), and \(S_n=580\). Find (n).
#find n
#ap sum
#options check
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A (18)
B (19)
C (20)
D (21)
Explanation opens after your attempt
Step 1
Concept
From (\frac{n}{2}[34+2(n-1)]=580), (n=20). After forming the equation, you can also check using options.
Step 2
Why this answer is correct
The correct answer is C. (20). From (\frac{n}{2}[34+2(n-1)]=580), (n=20). After forming the equation, you can also check using options.
Step 3
Exam Tip
(\frac{n}{2}[34+2(n-1)]=580) से (n=20) मिलता है। समीकरण बनने के बाद विकल्पों से भी जाँच कर सकते हैं।
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समांतर श्रेढ़ी \(100,95,90,\ldots\) के पहले (12) पदों का योग ज्ञात कीजिए।
Find the sum of the first (12) terms of the AP \(100,95,90,\ldots\).
#decreasing sequence
#last term
#sum
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A (870)
B (880)
C (890)
D (900)
Explanation opens after your attempt
Step 1
Concept
The last term is (45), so (S_{12}=\frac{12}{2}(100+45)=870). Once the last term is found, the sum is quick.
Step 2
Why this answer is correct
The correct answer is A. (870). The last term is (45), so (S_{12}=\frac{12}{2}(100+45)=870). Once the last term is found, the sum is quick.
Step 3
Exam Tip
अंतिम पद (45) है, इसलिए (S_{12}=\frac{12}{2}(100+45)=870)। अंतिम पद मिल जाए तो योग तेजी से निकलेगा।
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यदि पहले (n) प्राकृतिक संख्याओं का योग (465) है, तो (n) क्या होगा?
If the sum of the first (n) natural numbers is (465), what is (n)?
#natural numbers
#sum
#ap
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A (28)
B (29)
C (30)
D (31)
Explanation opens after your attempt
Step 1
Concept
From (\frac{n(n+1)}{2}=465), (n=30). The sum of natural numbers is a special case of AP.
Step 2
Why this answer is correct
The correct answer is C. (30). From (\frac{n(n+1)}{2}=465), (n=30). The sum of natural numbers is a special case of AP.
Step 3
Exam Tip
(\frac{n(n+1)}{2}=465) से (n=30) आता है। प्राकृतिक संख्याओं का योग भी समांतर श्रेढ़ी का विशेष रूप है।
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समांतर श्रेढ़ी \(8,13,18,\ldots,83\) का योग ज्ञात कीजिए।
Find the sum of the AP \(8,13,18,\ldots,83\).
#finite ap
#last term
#sum
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A (720)
B (728)
C (736)
D (744)
Explanation opens after your attempt
Step 1
Concept
First find (n): (83=8+(n-1)5), so (n=16) and the sum is (728). When the last term is given, find the number of terms first.
Step 2
Why this answer is correct
The correct answer is B. (728). First find (n): (83=8+(n-1)5), so (n=16) and the sum is (728). When the last term is given, find the number of terms first.
Step 3
Exam Tip
पहले (n) निकालें: (83=8+(n-1)5), इसलिए (n=16) और योग (728) है। अंतिम पद होने पर पहले पदों की संख्या निकालें।
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एक छात्र प्रतिदिन (15) मिनट से शुरू करके हर दिन (5) मिनट अधिक अभ्यास करता है। (14) दिनों में कुल अभ्यास समय कितना होगा?
A student starts with (15) minutes of practice per day and increases it by (5) minutes every day. What is the total practice time in (14) days?
#practice time
#word problem
#ap sum
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A (655)
B (660)
C (665)
D (670)
Explanation opens after your attempt
Step 1
Concept
This is the AP \(15,20,25,\ldots\), and the sum for (14) days is (665) minutes. In word problems, treat days as the number of terms.
Step 2
Why this answer is correct
The correct answer is C. (665). This is the AP \(15,20,25,\ldots\), and the sum for (14) days is (665) minutes. In word problems, treat days as the number of terms.
Step 3
Exam Tip
यह \(15,20,25,\ldots\) श्रेढ़ी है और (14) दिनों का योग (665) मिनट है। शब्द-प्रश्न में दिन को पदों की संख्या मानें।
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यदि \(S_{25}=1225\) और \(S_{24}=1128\), तो (25)वाँ पद क्या है?
If \(S_{25}=1225\) and \(S_{24}=1128\), what is the (25)th term?
#term from sums
#ap
#medium
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A (95)
B (96)
C (97)
D (98)
Explanation opens after your attempt
Step 1
Concept
\(a_{25}=S_{25}-S_{24}=97\). The difference of total sums gives the newly added last term.
Step 2
Why this answer is correct
The correct answer is C. (97). \(a_{25}=S_{25}-S_{24}=97\). The difference of total sums gives the newly added last term.
Step 3
Exam Tip
\(a_{25}=S_{25}-S_{24}=97\)। कुल योगों का अंतर अंतिम नया पद देता है।
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समांतर श्रेढ़ी \(24,21,18,\ldots\) के पहले (16) पदों का योग कितना है?
What is the sum of the first (16) terms of the AP \(24,21,18,\ldots\)?
#decreasing ap
#small sum
#ap
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A (20)
B (22)
C (24)
D (26)
Explanation opens after your attempt
Step 1
Concept
The last term is (-21), and (S_{16}=\frac{16}{2}(24-21)=24). Positive and negative terms can greatly reduce the sum.
Step 2
Why this answer is correct
The correct answer is C. (24). The last term is (-21), and (S_{16}=\frac{16}{2}(24-21)=24). Positive and negative terms can greatly reduce the sum.
Step 3
Exam Tip
अंतिम पद (-21) है और (S_{16}=\frac{16}{2}(24-21)=24)। धनात्मक और ऋणात्मक पद एक-दूसरे को काफी घटा सकते हैं।
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यदि किसी समांतर श्रेढ़ी में \(S_{12}=390\) और (d=5), तो पहला पद (a) क्या होगा?
If an AP has \(S_{12}=390\) and (d=5), what is the first term (a)?
#find first term
#ap sum
#unknown a
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A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
From (390=6[2a+55]), (a=5). For an unknown first term, keep (2a) separate.
Step 2
Why this answer is correct
The correct answer is B. (5). From (390=6[2a+55]), (a=5). For an unknown first term, keep (2a) separate.
Step 3
Exam Tip
(390=6[2a+55]) से (a=5) मिलता है। अज्ञात पहले पद के लिए (2a) को अलग रखें।
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(50) से कम (4) के सभी धनात्मक गुणजों का योग कितना है?
What is the sum of all positive multiples of (4) less than (50)?
#multiples less than
#ap sum
#class 10
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A (300)
B (304)
C (312)
D (320)
Explanation opens after your attempt
Step 1
Concept
The AP is \(4,8,\ldots,48\) with (12) terms, and the sum is (312). Identifying the last allowed multiple is important.
Step 2
Why this answer is correct
The correct answer is C. (312). The AP is \(4,8,\ldots,48\) with (12) terms, and the sum is (312). Identifying the last allowed multiple is important.
Step 3
Exam Tip
श्रेढ़ी \(4,8,\ldots,48\) है जिसमें (12) पद हैं और योग (312) है। अंतिम स्वीकार्य गुणज पहचानना जरूरी है।
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समांतर श्रेढ़ी \(5,9,13,\ldots\) में पहले कितने पदों का योग (425) होगा?
In the AP \(5,9,13,\ldots\), how many first terms have sum (425)?
#find terms
#ap sum
#verification
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A (15)
B (16)
C (17)
D (18)
Explanation opens after your attempt
Step 1
Concept
From (\frac{n}{2}[10+4(n-1)]=425), (n=17). You can also verify by substituting options.
Step 2
Why this answer is correct
The correct answer is C. (17). From (\frac{n}{2}[10+4(n-1)]=425), (n=17). You can also verify by substituting options.
Step 3
Exam Tip
(\frac{n}{2}[10+4(n-1)]=425) से (n=17) मिलता है। विकल्पों में मान रखकर भी जाँच कर सकते हैं।
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एक सड़क पर खंभों की दूरी के क्रम \(6,12,18,\ldots\) मीटर हैं। पहले (25) अंतरालों की कुल दूरी कितनी होगी?
On a road, the distances of intervals are \(6,12,18,\ldots\) meters. What is the total distance of the first (25) intervals?
#road distance
#multiples
#ap sum
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A (1900)
B (1925)
C (1950)
D (1975)
Explanation opens after your attempt
Step 1
Concept
This is the sum of the first (25) multiples of (6), so the total distance is (1950) meters. In sums of multiples, (a=d).
Step 2
Why this answer is correct
The correct answer is C. (1950). This is the sum of the first (25) multiples of (6), so the total distance is (1950) meters. In sums of multiples, (a=d).
Step 3
Exam Tip
यह (6) के पहले (25) गुणजों का योग है, इसलिए कुल दूरी (1950) मीटर है। गुणजों के योग में (a=d) होता है।
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यदि \(S_n=5n^2-n\), तो \(S_{9}\) का मान क्या है?
If \(S_n=5n^2-n\), what is the value of \(S_9\)?
#given sn
#minus sign
#ap
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A (396)
B (400)
C (405)
D (410)
Explanation opens after your attempt
Step 1
Concept
(S_9=5(9)2 -9=396). Pay attention to the sign because subtraction is involved.
Step 2
Why this answer is correct
The correct answer is A. (396). (S_9=5(9)2 -9=396). Pay attention to the sign because subtraction is involved.
Step 3
Exam Tip
(S_9=5(9)2 -9=396)। संकेत का ध्यान रखें क्योंकि यहाँ घटाव है।
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समांतर श्रेढ़ी \(7,12,17,\ldots,82\) का योग ज्ञात कीजिए।
Find the sum of the AP \(7,12,17,\ldots,82\).
#finite ap
#last term
#sum formula
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A (700)
B (712)
C (720)
D (724)
Explanation opens after your attempt
Step 1
Concept
From (82=7+(n-1)5), (n=16), and then the sum is (712). Finding (n) from the last term is the first step.
Step 2
Why this answer is correct
The correct answer is B. (712). From (82=7+(n-1)5), (n=16), and then the sum is (712). Finding (n) from the last term is the first step.
Step 3
Exam Tip
(82=7+(n-1)5) से (n=16), फिर योग (712) है। अंतिम पद से (n) निकालना पहला कदम है।
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यदि (a=25), (d=-4) और \(S_n=105\), तो (n) का सही धनात्मक मान क्या है?
If (a=25), (d=-4), and \(S_n=105\), what is the correct positive value of (n)?
#negative difference
#find n
#ap sum
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A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
From (\frac{n}{2}[50-4(n-1)]=105), (n=7). Even in a decreasing AP, (n) must be a positive integer.
Step 2
Why this answer is correct
The correct answer is C. (7). From (\frac{n}{2}[50-4(n-1)]=105), (n=7). Even in a decreasing AP, (n) must be a positive integer.
Step 3
Exam Tip
(\frac{n}{2}[50-4(n-1)]=105) से (n=7) मिलता है। घटती श्रेढ़ी में भी (n) धनात्मक पूर्णांक होता है।
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पहले (32) प्राकृतिक संख्याओं का योग ज्ञात कीजिए।
Find the sum of the first (32) natural numbers.
#natural numbers
#sum formula
#class 10
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A (520)
B (528)
C (536)
D (544)
Explanation opens after your attempt
Step 1
Concept
\(\frac{32\times33}{2}=528\). For natural numbers, (\frac{n(n+1)}{2}) is the fastest formula.
Step 2
Why this answer is correct
The correct answer is B. (528). \(\frac{32\times33}{2}=528\). For natural numbers, (\frac{n(n+1)}{2}) is the fastest formula.
Step 3
Exam Tip
\(\frac{32\times33}{2}=528\)। प्राकृतिक संख्याओं के लिए (\frac{n(n+1)}{2}) सबसे तेज सूत्र है।
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समांतर श्रेढ़ी \(9,16,23,\ldots\) के पहले (13) पदों का योग क्या है?
What is the sum of the first (13) terms of the AP \(9,16,23,\ldots\)?
#odd n
#ap sum
#common difference
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A (650)
B (660)
C (663)
D (670)
Explanation opens after your attempt
Step 1
Concept
Here (a=9), (d=7), (n=13), so \(S_{13}=663\). Do not worry about \(\frac{n}{2}\) when (n) is odd.
Step 2
Why this answer is correct
The correct answer is C. (663). Here (a=9), (d=7), (n=13), so \(S_{13}=663\). Do not worry about \(\frac{n}{2}\) when (n) is odd.
Step 3
Exam Tip
यहाँ (a=9), (d=7), (n=13), इसलिए \(S_{13}=663\)। विषम (n) होने पर \(\frac{n}{2}\) से डरें नहीं।
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यदि किसी समांतर श्रेढ़ी का \(S_{14}=511\) और (a=4) है, तो (d) क्या होगा?
If an AP has \(S_{14}=511\) and (a=4), what is (d)?
#find d
#ap sum
#medium
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A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
From (511=7[8+13d]), (d=5). First divide \(S_n\) by \(\frac{n}{2}\).
Step 2
Why this answer is correct
The correct answer is B. (5). From (511=7[8+13d]), (d=5). First divide \(S_n\) by \(\frac{n}{2}\).
Step 3
Exam Tip
(511=7[8+13d]) से (d=5) मिलता है। पहले \(S_n\) को \(\frac{n}{2}\) से विभाजित करें।
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किसी समांतर श्रेढ़ी में पहला पद (14), अंतिम पद (104) और पदों की संख्या (19) है। योग कितना होगा?
In an AP, the first term is (14), the last term is (104), and the number of terms is (19). What is the sum?
#first last sum
#ap formula
#class 10
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A (1101)
B (1111)
C (1121)
D (1131)
Explanation opens after your attempt
Step 1
Concept
(S_{19}=\frac{19}{2}(14+104)=1121). When first and last terms are given, finding (d) is not necessary.
Step 2
Why this answer is correct
The correct answer is C. (1121). (S_{19}=\frac{19}{2}(14+104)=1121). When first and last terms are given, finding (d) is not necessary.
Step 3
Exam Tip
(S_{19}=\frac{19}{2}(14+104)=1121)। पहला और अंतिम पद दिए हों तो (d) निकालना जरूरी नहीं है।
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