प्रतिस्थापन विधि से (2x+y=11) और (x-y=1) को हल करें।
Solve (2x+y=11) and (x-y=1) by substitution.
#linear equations
#substitution
#medium
#class 10
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A ( (3,5) )
B ( (4,3) )
C ( (5,1) )
D ( (2,7) )
Explanation opens after your attempt
Correct Answer
B. ( (4,3) )
Step 1
Concept
From (x-y=1), (y=x-1), so (2x+x-1=11) and the solution is ( (4,3) ). In exams, isolate the easier variable first.
Step 2
Why this answer is correct
The correct answer is B. ( (4,3) ). From (x-y=1), (y=x-1), so (2x+x-1=11) and the solution is ( (4,3) ). In exams, isolate the easier variable first.
Step 3
Exam Tip
(x-y=1) से (y=x-1), इसलिए (2x+x-1=11) और हल ( (4,3) ) है। परीक्षा में पहले आसान चर अलग करें।
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समीकरण (2x+3y=19) और (x-y=2) का हल क्या है?
What is the solution of (2x+3y=19) and (x-y=2)?
#linear equations
#substitution
#two variables
#medium
#class 10
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A ( (4,5) )
B ( (6,2) )
C ( (5,3) )
D ( (3,5) )
Explanation opens after your attempt
Correct Answer
C. ( (5,3) )
Step 1
Concept
From (x-y=2), (x=y+2), so (2(y+2)+3y=19) and (y=3). Then (x=5).
Step 2
Why this answer is correct
The correct answer is C. ( (5,3) ). From (x-y=2), (x=y+2), so (2(y+2)+3y=19) and (y=3). Then (x=5).
Step 3
Exam Tip
(x-y=2) से (x=y+2), इसलिए (2(y+2)+3y=19) और (y=3)। फिर (x=5) मिलेगा।
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विलोपन विधि से (3x+2y=23) और (3x-y=11) को हल करें।
Solve (3x+2y=23) and (3x-y=11) by elimination.
#linear equations
#elimination
#equal coefficient
#medium
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A ( (5,4) )
B ( (4,5) )
C ( (6,3) )
D ( (3,6) )
Explanation opens after your attempt
Correct Answer
A. ( (5,4) )
Step 1
Concept
Subtracting the second equation from the first gives (3y=12), so (y=4) and (x=5). Equal (x)-coefficients make elimination faster.
Step 2
Why this answer is correct
The correct answer is A. ( (5,4) ). Subtracting the second equation from the first gives (3y=12), so (y=4) and (x=5). Equal (x)-coefficients make elimination faster.
Step 3
Exam Tip
पहले समीकरण से दूसरे को घटाने पर (3y=12), इसलिए (y=4) और (x=5)। समान (x) गुणांक दिखें तो विलोपन तेज होता है।
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दो संख्याओं का योग (14) और अंतर (4) है। बड़ी संख्या और छोटी संख्या क्या हैं?
The sum of two numbers is (14) and their difference is (4). What are the greater and smaller numbers?
#linear equations
#word problem
#elimination
#medium
#class 10
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A ( (8,6) )
B ( (10,4) )
C ( (7,7) )
D ( (9,5) )
Explanation opens after your attempt
Correct Answer
D. ( (9,5) )
Step 1
Concept
Adding (x+y=14) and (x-y=4) gives (2x=18), so (x=9) and (y=5). In word problems, form equations first.
Step 2
Why this answer is correct
The correct answer is D. ( (9,5) ). Adding (x+y=14) and (x-y=4) gives (2x=18), so (x=9) and (y=5). In word problems, form equations first.
Step 3
Exam Tip
समीकरण (x+y=14) और (x-y=4) जोड़ने पर (2x=18), इसलिए (x=9) और (y=5)। शब्द-प्रश्न में पहले समीकरण बनाएं।
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समीकरण (2x+3y=13) और (4x-y=5) का हल चुनें।
Choose the solution of (2x+3y=13) and (4x-y=5).
#linear equations
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#medium
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A ( (1,4) )
B ( (2,3) )
C ( (3,2) )
D ( (4,1) )
Explanation opens after your attempt
Correct Answer
B. ( (2,3) )
Step 1
Concept
From (4x-y=5), (y=4x-5), so (2x+3(4x-5)=13) and (x=2). Then (y=3).
Step 2
Why this answer is correct
The correct answer is B. ( (2,3) ). From (4x-y=5), (y=4x-5), so (2x+3(4x-5)=13) and (x=2). Then (y=3).
Step 3
Exam Tip
(4x-y=5) से (y=4x-5), इसलिए (2x+3(4x-5)=13) और (x=2)। फिर (y=3) मिलेगा।
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विलोपन विधि से (5x+2y=34) और (3x+2y=22) का हल क्या है?
What is the solution of (5x+2y=34) and (3x+2y=22) by elimination?
#linear equations
#elimination
#medium
#class 10
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A ( (4,7) )
B ( (5,4) )
C ( (6,2) )
D ( (7,1) )
Explanation opens after your attempt
Correct Answer
C. ( (6,2) )
Step 1
Concept
Subtracting gives (2x=12), so (x=6) and (y=2). When (y)-coefficients are equal, subtraction is easy.
Step 2
Why this answer is correct
The correct answer is C. ( (6,2) ). Subtracting gives (2x=12), so (x=6) and (y=2). When (y)-coefficients are equal, subtraction is easy.
Step 3
Exam Tip
घटाने पर (2x=12), इसलिए (x=6) और (y=2)। समान (y) गुणांक होने पर समीकरण घटाना आसान है।
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समीकरण \(\frac{x}{2}+y=7\) और (x-y=2) को हल करें।
Solve \(\frac{x}{2}+y=7\) and (x-y=2).
#linear equations
#substitution
#fraction
#medium
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A ( (6,4) )
B ( (4,6) )
C ( (8,3) )
D ( (5,5) )
Explanation opens after your attempt
Correct Answer
A. ( (6,4) )
Step 1
Concept
From (x-y=2), (x=y+2), so \(\frac{y+2}{2}+y=7\) and (y=4). In fraction questions, try to clear denominators first.
Step 2
Why this answer is correct
The correct answer is A. ( (6,4) ). From (x-y=2), (x=y+2), so \(\frac{y+2}{2}+y=7\) and (y=4). In fraction questions, try to clear denominators first.
Step 3
Exam Tip
(x-y=2) से (x=y+2), इसलिए \(\frac{y+2}{2}+y=7\) और (y=4)। भिन्न वाले प्रश्न में पहले हर हटाने की कोशिश करें।
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यदि (x+y=10) और (3x+2y=24), तो (x) और (y) के मान क्या हैं?
If (x+y=10) and (3x+2y=24), what are the values of (x) and (y)?
#linear equations
#substitution
#medium
#class 10
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A ( (6,4) )
B ( (5,5) )
C ( (4,6) )
D ( (3,7) )
Explanation opens after your attempt
Correct Answer
C. ( (4,6) )
Step 1
Concept
Putting (x=10-y) gives (3(10-y)+2y=24), so (y=6) and (x=4). A sum equation makes substitution easier.
Step 2
Why this answer is correct
The correct answer is C. ( (4,6) ). Putting (x=10-y) gives (3(10-y)+2y=24), so (y=6) and (x=4). A sum equation makes substitution easier.
Step 3
Exam Tip
(x=10-y) रखने पर (3(10-y)+2y=24), इसलिए (y=6) और (x=4)। योग वाले समीकरण से प्रतिस्थापन आसान बनता है।
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विलोपन विधि से (2x+5y=26) और (3x+5y=29) का हल निकालें।
Find the solution of (2x+5y=26) and (3x+5y=29) by elimination.
#linear equations
#elimination
#back substitution
#medium
#class 10
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A ( (2,5) )
B ( (4,3) )
C ( (5,2) )
D ( (3,4) )
Explanation opens after your attempt
Correct Answer
D. ( (3,4) )
Step 1
Concept
Subtracting the first equation from the second gives (x=3), then (2x+5y=26) gives (y=4). Substitute back after elimination.
Step 2
Why this answer is correct
The correct answer is D. ( (3,4) ). Subtracting the first equation from the second gives (x=3), then (2x+5y=26) gives (y=4). Substitute back after elimination.
Step 3
Exam Tip
दूसरे समीकरण से पहला घटाने पर (x=3), फिर (2x+5y=26) से (y=4)। विलोपन के बाद मान वापस रखें।
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समीकरण (x+2y=11) और (3x+2y=25) का हल क्या है?
What is the solution of (x+2y=11) and (3x+2y=25)?
#linear equations
#elimination
#medium
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A ( (7,2) )
B ( (5,3) )
C ( (3,4) )
D ( (6,1) )
Explanation opens after your attempt
Correct Answer
A. ( (7,2) )
Step 1
Concept
Subtracting gives (2x=14), so (x=7) and (y=2). Removing equal (2y) terms gives a quick solution.
Step 2
Why this answer is correct
The correct answer is A. ( (7,2) ). Subtracting gives (2x=14), so (x=7) and (y=2). Removing equal (2y) terms gives a quick solution.
Step 3
Exam Tip
घटाने पर (2x=14), इसलिए (x=7) और (y=2)। समान (2y) पदों को हटाकर हल जल्दी मिलता है।
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प्रतिस्थापन विधि से (y=2x+1) और (x+y=10) को हल करें।
Solve (y=2x+1) and (x+y=10) by substitution.
#linear equations
#substitution
#direct expression
#medium
#class 10
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A ( (2,8) )
B ( (4,6) )
C ( (3,7) )
D ( (5,5) )
Explanation opens after your attempt
Correct Answer
C. ( (3,7) )
Step 1
Concept
Putting (y=2x+1) gives (3x+1=10), so (x=3) and (y=7). If (y=) form is given, substitute directly.
Step 2
Why this answer is correct
The correct answer is C. ( (3,7) ). Putting (y=2x+1) gives (3x+1=10), so (x=3) and (y=7). If (y=) form is given, substitute directly.
Step 3
Exam Tip
(y=2x+1) रखने पर (3x+1=10), इसलिए (x=3) और (y=7)। दिए गए रूप (y=) में हो तो सीधे रखें।
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यदि (x=3y-1) और (x+y=11), तो ((x,y)) क्या है?
If (x=3y-1) and (x+y=11), what is ((x,y))?
#linear equations
#substitution
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#class 10
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A ( (6,5) )
B ( (7,4) )
C ( (8,3) )
D ( (9,2) )
Explanation opens after your attempt
Correct Answer
C. ( (8,3) )
Step 1
Concept
From (3y-1+y=11), (4y=12), so (y=3) and (x=8). Keeping the expression in brackets is safer.
Step 2
Why this answer is correct
The correct answer is C. ( (8,3) ). From (3y-1+y=11), (4y=12), so (y=3) and (x=8). Keeping the expression in brackets is safer.
Step 3
Exam Tip
(3y-1+y=11) से (4y=12), इसलिए (y=3) और (x=8)। अभिव्यक्ति को पूरी तरह कोष्ठक में रखना सुरक्षित है।
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एक प्रश्न में (x+y=13) और (2x+3y=34) बनते हैं। हल क्या होगा?
In a problem, the equations formed are (x+y=13) and (2x+3y=34). What is the solution?
#linear equations
#word problem
#substitution
#medium
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A ( (5,8) )
B ( (8,5) )
C ( (6,7) )
D ( (7,6) )
Explanation opens after your attempt
Correct Answer
A. ( (5,8) )
Step 1
Concept
Putting (x=13-y) gives (2(13-y)+3y=34), so (y=8) and (x=5). Keep the formed equations organized.
Step 2
Why this answer is correct
The correct answer is A. ( (5,8) ). Putting (x=13-y) gives (2(13-y)+3y=34), so (y=8) and (x=5). Keep the formed equations organized.
Step 3
Exam Tip
(x=13-y) रखने पर (2(13-y)+3y=34), इसलिए (y=8) और (x=5)। बने हुए समीकरणों को व्यवस्थित रखें।
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समीकरण (4x+2y=30) और (2x-y=9) को हल करें।
Solve (4x+2y=30) and (2x-y=9).
#linear equations
#substitution
#medium
#class 10
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A ( (3,9) )
B ( (6,3) )
C ( (5,5) )
D ( (4,7) )
Explanation opens after your attempt
Correct Answer
B. ( (6,3) )
Step 1
Concept
From the second equation, (y=2x-9), so (4x+2(2x-9)=30) and (x=6). Then (y=3).
Step 2
Why this answer is correct
The correct answer is B. ( (6,3) ). From the second equation, (y=2x-9), so (4x+2(2x-9)=30) and (x=6). Then (y=3).
Step 3
Exam Tip
दूसरे समीकरण से (y=2x-9), इसलिए (4x+2(2x-9)=30) और (x=6)। फिर (y=3) है।
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विलोपन विधि से (7x-2y=41) और (7x+2y=57) को हल करें।
Solve (7x-2y=41) and (7x+2y=57) by elimination.
#linear equations
#elimination
#opposite terms
#medium
#class 10
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A ( (5,6) )
B ( (6,5) )
C ( (7,4) )
D ( (8,3) )
Explanation opens after your attempt
Correct Answer
C. ( (7,4) )
Step 1
Concept
Adding both equations gives (14x=98), so (x=7) and (y=4). Add opposite (y) terms to eliminate them.
Step 2
Why this answer is correct
The correct answer is C. ( (7,4) ). Adding both equations gives (14x=98), so (x=7) and (y=4). Add opposite (y) terms to eliminate them.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (14x=98), इसलिए (x=7) और (y=4)। विपरीत (y) पदों को जोड़कर हटाएँ।
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समीकरण (2x+3y=12) और (4x+6y=24) के लिए सही निष्कर्ष क्या है?
What is the correct conclusion for (2x+3y=12) and (4x+6y=24)?
#linear equations
#dependent equations
#elimination
#medium
#class 10
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A कोई हल नहीं / No solution
B अनंत हल / Infinitely many solutions
C केवल एक हल / Exactly one solution
D दो अलग हल / Two different solutions
Explanation opens after your attempt
Correct Answer
B. अनंत हल / Infinitely many solutions
Step 1
Concept
The second equation is (2) times the first, so both represent the same line. Such a pair has infinitely many solutions.
Step 2
Why this answer is correct
The correct answer is B. अनंत हल / Infinitely many solutions. The second equation is (2) times the first, so both represent the same line. Such a pair has infinitely many solutions.
Step 3
Exam Tip
दूसरा समीकरण पहले का (2) गुना है, इसलिए दोनों एक ही रेखा हैं। ऐसे युग्म के अनंत हल होते हैं।
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समीकरण (3x-2y=8) और (6x-4y=20) के लिए कौन-सा कथन सही है?
Which statement is correct for (3x-2y=8) and (6x-4y=20)?
#linear equations
#inconsistent equations
#medium
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A एक हल है / It has one solution
B अनंत हल हैं / It has infinitely many solutions
C कोई हल नहीं है / It has no solution
D हल ( (2,1) ) है / The solution is ( (2,1) )
Explanation opens after your attempt
Correct Answer
C. कोई हल नहीं है / It has no solution
Step 1
Concept
Multiplying the first equation by (2) gives the same left side but constant (16). Since it conflicts with (20), there is no solution.
Step 2
Why this answer is correct
The correct answer is C. कोई हल नहीं है / It has no solution. Multiplying the first equation by (2) gives the same left side but constant (16). Since it conflicts with (20), there is no solution.
Step 3
Exam Tip
पहले समीकरण को (2) से गुणा करने पर बायाँ पक्ष समान बनता है लेकिन स्थिर पद (16) होता है। (20) से विरोधाभास होने के कारण कोई हल नहीं है।
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विलोपन विधि से (2x+3y=20) और (5x+3y=32) का हल क्या है?
What is the solution of (2x+3y=20) and (5x+3y=32) by elimination?
#linear equations
#elimination
#medium
#class 10
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A ( (4,4) )
B ( (3,5) )
C ( (5,3) )
D ( (6,2) )
Explanation opens after your attempt
Correct Answer
A. ( (4,4) )
Step 1
Concept
Subtracting the first from the second gives (3x=12), so (x=4) and (y=4). After elimination, substitute into any original equation.
Step 2
Why this answer is correct
The correct answer is A. ( (4,4) ). Subtracting the first from the second gives (3x=12), so (x=4) and (y=4). After elimination, substitute into any original equation.
Step 3
Exam Tip
दूसरे से पहला घटाने पर (3x=12), इसलिए (x=4) और (y=4)। विलोपन के बाद किसी भी मूल समीकरण में मान रखें।
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यदि (x=2y+1) और (3x-y=18), तो (x) और (y) क्या हैं?
If (x=2y+1) and (3x-y=18), what are (x) and (y)?
#linear equations
#substitution
#brackets
#medium
#class 10
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A ( (5,2) )
B ( (6,4) )
C ( (7,3) )
D ( (8,2) )
Explanation opens after your attempt
Correct Answer
C. ( (7,3) )
Step 1
Concept
Substituting (x=2y+1) gives (3(2y+1)-y=18), so (y=3) and (x=7). Use brackets while multiplying.
Step 2
Why this answer is correct
The correct answer is C. ( (7,3) ). Substituting (x=2y+1) gives (3(2y+1)-y=18), so (y=3) and (x=7). Use brackets while multiplying.
Step 3
Exam Tip
(x=2y+1) रखने पर (3(2y+1)-y=18), इसलिए (y=3) और (x=7)। कोष्ठक लगाकर गुणा करें।
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समीकरण (y=3x-5) और (2x+y=20) का हल चुनें।
Choose the solution of (y=3x-5) and (2x+y=20).
#linear equations
#substitution
#expression
#medium
#class 10
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A ( (4,7) )
B ( (5,10) )
C ( (6,13) )
D ( (3,4) )
Explanation opens after your attempt
Correct Answer
B. ( (5,10) )
Step 1
Concept
Putting (3x-5) in place of (y) gives (5x-5=20), so (x=5) and (y=10). Replace the entire expression carefully.
Step 2
Why this answer is correct
The correct answer is B. ( (5,10) ). Putting (3x-5) in place of (y) gives (5x-5=20), so (x=5) and (y=10). Replace the entire expression carefully.
Step 3
Exam Tip
(3x-5) को (y) की जगह रखने पर (5x-5=20), इसलिए (x=5) और (y=10)। अभिव्यक्ति रखते समय पूरा पद बदलें।
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पिता और पुत्र की आयु का योग (50) है। पिता की आयु पुत्र की आयु की (4) गुनी है। आयु क्या है?
The sum of the ages of a father and son is (50). The father's age is (4) times the son's age. What are the ages?
#linear equations
#word problem
#age
#medium
#class 10
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A (40) और (10) / (40) and (10)
B (35) और (15) / (35) and (15)
C (30) और (20) / (30) and (20)
D (45) और (5) / (45) and (5)
Explanation opens after your attempt
Correct Answer
A. (40) और (10) / (40) and (10)
Step 1
Concept
If the father's age is (x) and the son's age is (y), then (x+y=50) and (x=4y). This gives (5y=50), so the ages are (40) and (10).
Step 2
Why this answer is correct
The correct answer is A. (40) और (10) / (40) and (10). If the father's age is (x) and the son's age is (y), then (x+y=50) and (x=4y). This gives (5y=50), so the ages are (40) and (10).
Step 3
Exam Tip
यदि पिता की आयु (x) और पुत्र की (y) है, तो (x+y=50) और (x=4y)। इससे (5y=50), इसलिए आयु (40) और (10) हैं।
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किसी मेले में वयस्क टिकटों की संख्या (x) और बच्चों के टिकटों की संख्या (y) है। यदि (x+y=12) और (50x+30y=500), तो (x) और (y) क्या हैं?
At a fair, the number of adult tickets is (x) and child tickets is (y). If (x+y=12) and (50x+30y=500), what are (x) and (y)?
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#word problem
#tickets
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A ( (6,6) )
B ( (8,4) )
C ( (7,5) )
D ( (5,7) )
Explanation opens after your attempt
Correct Answer
C. ( (7,5) )
Step 1
Concept
Dividing (50x+30y=500) by (10) gives (5x+3y=50). Solving with (x+y=12) gives (x=7) and (y=5).
Step 2
Why this answer is correct
The correct answer is C. ( (7,5) ). Dividing (50x+30y=500) by (10) gives (5x+3y=50). Solving with (x+y=12) gives (x=7) and (y=5).
Step 3
Exam Tip
(50x+30y=500) को (10) से भाग देने पर (5x+3y=50) मिलता है। (x+y=12) के साथ हल करने पर (x=7) और (y=5)।
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विलोपन विधि से (x+2y=13) और (3x-2y=23) का हल निकालें।
Find the solution of (x+2y=13) and (3x-2y=23) by elimination.
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#elimination
#opposite coefficients
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A ( (6,4) )
B ( (8,3) )
C ( (9,2) )
D ( (7,3) )
Explanation opens after your attempt
Correct Answer
C. ( (9,2) )
Step 1
Concept
Adding both equations gives (4x=36), so (x=9) and (y=2). Identify opposite (2y) terms.
Step 2
Why this answer is correct
The correct answer is C. ( (9,2) ). Adding both equations gives (4x=36), so (x=9) and (y=2). Identify opposite (2y) terms.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (4x=36), इसलिए (x=9) और (y=2)। विपरीत (2y) पदों को पहचानें।
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समीकरण (2x+y=13) और (x+3y=19) को हल करें।
Solve (2x+y=13) and (x+3y=19).
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A ( (4,5) )
B ( (5,4) )
C ( (3,6) )
D ( (6,3) )
Explanation opens after your attempt
Correct Answer
A. ( (4,5) )
Step 1
Concept
From the first equation, (y=13-2x), so (x+3(13-2x)=19). This gives (x=4) and (y=5).
Step 2
Why this answer is correct
The correct answer is A. ( (4,5) ). From the first equation, (y=13-2x), so (x+3(13-2x)=19). This gives (x=4) and (y=5).
Step 3
Exam Tip
पहले समीकरण से (y=13-2x), इसलिए (x+3(13-2x)=19)। इससे (x=4) और (y=5)।
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समीकरण \(\frac{x}{3}+y=6\) और (x-y=6) का हल क्या है?
What is the solution of \(\frac{x}{3}+y=6\) and (x-y=6)?
#linear equations
#substitution
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A ( (6,0) )
B ( (9,3) )
C ( (12,6) )
D ( (3,9) )
Explanation opens after your attempt
Correct Answer
B. ( (9,3) )
Step 1
Concept
Putting (x=y+6) gives \(\frac{y+6}{3}+y=6\), so (y=3) and (x=9). Matching denominators reduces mistakes in fractions.
Step 2
Why this answer is correct
The correct answer is B. ( (9,3) ). Putting (x=y+6) gives \(\frac{y+6}{3}+y=6\), so (y=3) and (x=9). Matching denominators reduces mistakes in fractions.
Step 3
Exam Tip
(x=y+6) रखने पर \(\frac{y+6}{3}+y=6\), इसलिए (y=3) और (x=9)। भिन्न में हर समान करने से गलती कम होती है।
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यदि (2x-y=7) और (x+2y=16), तो हल क्या है?
If (2x-y=7) and (x+2y=16), what is the solution?
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A ( (4,7) )
B ( (5,6) )
C ( (6,5) )
D ( (7,4) )
Explanation opens after your attempt
Correct Answer
C. ( (6,5) )
Step 1
Concept
From (2x-y=7), (y=2x-7), so (x+2(2x-7)=16) and (x=6). Then (y=5).
Step 2
Why this answer is correct
The correct answer is C. ( (6,5) ). From (2x-y=7), (y=2x-7), so (x+2(2x-7)=16) and (x=6). Then (y=5).
Step 3
Exam Tip
(2x-y=7) से (y=2x-7), इसलिए (x+2(2x-7)=16) और (x=6)। फिर (y=5) मिलेगा।
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समीकरण (3x+y=25) और (x-y=7) को हल करें।
Solve (3x+y=25) and (x-y=7).
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A ( (7,4) )
B ( (8,1) )
C ( (6,7) )
D ( (9,2) )
Explanation opens after your attempt
Correct Answer
B. ( (8,1) )
Step 1
Concept
From (x-y=7), (y=x-7), so (3x+x-7=25) and (x=8). Then (y=1).
Step 2
Why this answer is correct
The correct answer is B. ( (8,1) ). From (x-y=7), (y=x-7), so (3x+x-7=25) and (x=8). Then (y=1).
Step 3
Exam Tip
(x-y=7) से (y=x-7), इसलिए (3x+x-7=25) और (x=8)। फिर (y=1) है।
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समीकरण (x+4y=13) और (2x-y=8) से (x) और (y) क्या मिलेंगे?
From (x+4y=13) and (2x-y=8), what are (x) and (y)?
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A ( (5,2) )
B ( (4,3) )
C ( (6,1) )
D ( (3,4) )
Explanation opens after your attempt
Correct Answer
A. ( (5,2) )
Step 1
Concept
From (2x-y=8), (y=2x-8), so (x+4(2x-8)=13). This gives (x=5) and (y=2).
Step 2
Why this answer is correct
The correct answer is A. ( (5,2) ). From (2x-y=8), (y=2x-8), so (x+4(2x-8)=13). This gives (x=5) and (y=2).
Step 3
Exam Tip
(2x-y=8) से (y=2x-8), इसलिए (x+4(2x-8)=13)। इससे (x=5) और (y=2)।
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विलोपन विधि से (5x-y=38) और (x+y=10) का हल क्या होगा?
What will be the solution of (5x-y=38) and (x+y=10) by elimination?
#linear equations
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A ( (6,4) )
B ( (7,3) )
C ( (8,2) )
D ( (9,1) )
Explanation opens after your attempt
Correct Answer
C. ( (8,2) )
Step 1
Concept
Adding both equations gives (6x=48), so (x=8) and (y=2). Add opposite (y) terms to eliminate quickly.
Step 2
Why this answer is correct
The correct answer is C. ( (8,2) ). Adding both equations gives (6x=48), so (x=8) and (y=2). Add opposite (y) terms to eliminate quickly.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (6x=48), इसलिए (x=8) और (y=2)। विपरीत (y) पदों को जोड़कर तुरंत हटाएँ।
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समीकरण (4x+3y=42) और (2x-y=6) को हल करें।
Solve (4x+3y=42) and (2x-y=6).
#linear equations
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A ( (6,6) )
B ( (7,4) )
C ( (8,2) )
D ( (5,8) )
Explanation opens after your attempt
Correct Answer
A. ( (6,6) )
Step 1
Concept
From (2x-y=6), (y=2x-6), so (4x+3(2x-6)=42) and (x=6). Then (y=6).
Step 2
Why this answer is correct
The correct answer is A. ( (6,6) ). From (2x-y=6), (y=2x-6), so (4x+3(2x-6)=42) and (x=6). Then (y=6).
Step 3
Exam Tip
(2x-y=6) से (y=2x-6), इसलिए (4x+3(2x-6)=42) और (x=6)। फिर (y=6) मिलेगा।
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विलोपन विधि में (3x+2y=16) और (x+4y=14) से (x) हटाने के लिए दूसरे समीकरण को किससे गुणा करना चाहिए?
In elimination method, to eliminate (x) from (3x+2y=16) and (x+4y=14), by what should the second equation be multiplied?
#linear equations
#elimination
#method
#medium
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A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
The coefficient of (x) in the second equation is (1), so multiplying it by (3) gives (3x). In elimination, first make coefficients equal.
Step 2
Why this answer is correct
The correct answer is B. (3). The coefficient of (x) in the second equation is (1), so multiplying it by (3) gives (3x). In elimination, first make coefficients equal.
Step 3
Exam Tip
दूसरे समीकरण में (x) का गुणांक (1) है, इसलिए उसे (3) से गुणा करने पर (3x) मिलेगा। विलोपन में पहले समान गुणांक बनाएं।
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यदि (x-y=5) और (2x+3y=30), तो हल क्या है?
If (x-y=5) and (2x+3y=30), what is the solution?
#linear equations
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A ( (8,3) )
B ( (9,4) )
C ( (7,2) )
D ( (10,5) )
Explanation opens after your attempt
Correct Answer
B. ( (9,4) )
Step 1
Concept
Putting (x=y+5) gives (2(y+5)+3y=30), so (y=4) and (x=9). Combine like terms after substitution.
Step 2
Why this answer is correct
The correct answer is B. ( (9,4) ). Putting (x=y+5) gives (2(y+5)+3y=30), so (y=4) and (x=9). Combine like terms after substitution.
Step 3
Exam Tip
(x=y+5) रखने पर (2(y+5)+3y=30), इसलिए (y=4) और (x=9)। प्रतिस्थापन के बाद समान पद जोड़ें।
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समीकरण (3x-4y=17) और (x+y=8) का हल चुनें।
Choose the solution of (3x-4y=17) and (x+y=8).
#linear equations
#substitution
#negative terms
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A ( (6,2) )
B ( (5,3) )
C ( (7,1) )
D ( (4,4) )
Explanation opens after your attempt
Correct Answer
C. ( (7,1) )
Step 1
Concept
Putting (x=8-y) gives (3(8-y)-4y=17), so (y=1) and (x=7). Be careful while combining negative terms.
Step 2
Why this answer is correct
The correct answer is C. ( (7,1) ). Putting (x=8-y) gives (3(8-y)-4y=17), so (y=1) and (x=7). Be careful while combining negative terms.
Step 3
Exam Tip
(x=8-y) रखने पर (3(8-y)-4y=17), इसलिए (y=1) और (x=7)। ऋण पदों को जोड़ते समय ध्यान रखें।
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समीकरण (6x+2y=64) और (3x-y=28) को हल करें।
Solve (6x+2y=64) and (3x-y=28).
#linear equations
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A ( (9,5) )
B ( (8,4) )
C ( (10,2) )
D ( (7,7) )
Explanation opens after your attempt
Correct Answer
C. ( (10,2) )
Step 1
Concept
From the second equation, (y=3x-28), so (6x+2(3x-28)=64). This gives (x=10) and (y=2).
Step 2
Why this answer is correct
The correct answer is C. ( (10,2) ). From the second equation, (y=3x-28), so (6x+2(3x-28)=64). This gives (x=10) and (y=2).
Step 3
Exam Tip
दूसरे समीकरण से (y=3x-28), इसलिए (6x+2(3x-28)=64)। इससे (x=10) और (y=2)।
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विलोपन विधि से (2x+7y=41) और (2x+3y=29) का हल ज्ञात करें।
Find the solution of (2x+7y=41) and (2x+3y=29) by elimination.
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A ( (8,5) )
B ( (9,4) )
C ( (7,6) )
D ( (10,3) )
Explanation opens after your attempt
Correct Answer
D. ( (10,3) )
Step 1
Concept
Subtracting the second from the first gives (4y=12), so (y=3) and (x=10). Removing equal (2x) terms shortens the calculation.
Step 2
Why this answer is correct
The correct answer is D. ( (10,3) ). Subtracting the second from the first gives (4y=12), so (y=3) and (x=10). Removing equal (2x) terms shortens the calculation.
Step 3
Exam Tip
पहले से दूसरे को घटाने पर (4y=12), इसलिए (y=3) और (x=10)। समान (2x) पद हटाने से गणना छोटी हो जाती है।
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समीकरण (4x-y=14) और (2x+y=16) का हल क्या है?
What is the solution of (4x-y=14) and (2x+y=16)?
#linear equations
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A ( (5,6) )
B ( (6,5) )
C ( (4,7) )
D ( (7,4) )
Explanation opens after your attempt
Correct Answer
A. ( (5,6) )
Step 1
Concept
Adding both equations gives (6x=30), so (x=5) and (y=6). Opposite (y) terms cancel when added.
Step 2
Why this answer is correct
The correct answer is A. ( (5,6) ). Adding both equations gives (6x=30), so (x=5) and (y=6). Opposite (y) terms cancel when added.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (6x=30), इसलिए (x=5) और (y=6)। विपरीत (y) पद जोड़ने पर कट जाते हैं।
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विलोपन विधि से (3x+5y=36) और (3x+2y=18) को हल करें।
Solve (3x+5y=36) and (3x+2y=18) by elimination.
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A ( (4,5) )
B ( (2,6) )
C ( (6,2) )
D ( (3,7) )
Explanation opens after your attempt
Correct Answer
B. ( (2,6) )
Step 1
Concept
Subtracting gives (3y=18), so (y=6) and (x=2). Eliminate equal (3x) terms to find (y) first.
Step 2
Why this answer is correct
The correct answer is B. ( (2,6) ). Subtracting gives (3y=18), so (y=6) and (x=2). Eliminate equal (3x) terms to find (y) first.
Step 3
Exam Tip
घटाने पर (3y=18), इसलिए (y=6) और (x=2)। समान (3x) को हटाकर पहले (y) निकालें।
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यदि (x=2y-3) और (2x+y=24), तो ((x,y)) क्या है?
If (x=2y-3) and (2x+y=24), what is ((x,y))?
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A ( (6,9) )
B ( (8,7) )
C ( (9,6) )
D ( (10,5) )
Explanation opens after your attempt
Correct Answer
C. ( (9,6) )
Step 1
Concept
Putting (x=2y-3) gives (2(2y-3)+y=24), so (y=6) and (x=9). Correct brackets prevent sign errors.
Step 2
Why this answer is correct
The correct answer is C. ( (9,6) ). Putting (x=2y-3) gives (2(2y-3)+y=24), so (y=6) and (x=9). Correct brackets prevent sign errors.
Step 3
Exam Tip
(x=2y-3) रखने पर (2(2y-3)+y=24), इसलिए (y=6) और (x=9)। कोष्ठक सही लगाने से चिह्न की गलती नहीं होती।
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समीकरण (y=15-2x) और (x-y=6) का हल चुनें।
Choose the solution of (y=15-2x) and (x-y=6).
#linear equations
#substitution
#signs
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A ( (6,3) )
B ( (8,2) )
C ( (5,5) )
D ( (7,1) )
Explanation opens after your attempt
Correct Answer
D. ( (7,1) )
Step 1
Concept
Putting (15-2x) in place of (y) gives (x-(15-2x)=6), so (x=7) and (y=1). Always use brackets with a minus sign.
Step 2
Why this answer is correct
The correct answer is D. ( (7,1) ). Putting (15-2x) in place of (y) gives (x-(15-2x)=6), so (x=7) and (y=1). Always use brackets with a minus sign.
Step 3
Exam Tip
(15-2x) को (y) की जगह रखने पर (x-(15-2x)=6), इसलिए (x=7) और (y=1)। ऋण के साथ कोष्ठक जरूर लगाएँ।
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समीकरण \(\frac{x}{2}+\frac{y}{4}=5\) और (x-y=4) को हल करें।
Solve \(\frac{x}{2}+\frac{y}{4}=5\) and (x-y=4).
#linear equations
#fraction
#elimination
#medium
#class 10
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A ( (8,4) )
B ( (6,2) )
C ( (10,6) )
D ( (4,8) )
Explanation opens after your attempt
Correct Answer
A. ( (8,4) )
Step 1
Concept
Multiplying the first equation by (4) gives (2x+y=20). Solving it with (x-y=4) gives (x=8) and (y=4).
Step 2
Why this answer is correct
The correct answer is A. ( (8,4) ). Multiplying the first equation by (4) gives (2x+y=20). Solving it with (x-y=4) gives (x=8) and (y=4).
Step 3
Exam Tip
पहले समीकरण को (4) से गुणा करने पर (2x+y=20) मिलता है। इसे (x-y=4) के साथ हल करने पर (x=8) और (y=4)।
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एक आयत की लंबाई (l) और चौड़ाई (b) है। यदि (2l+2b=34) और (l-b=5), तो (l) और (b) क्या हैं?
A rectangle has length (l) and breadth (b). If (2l+2b=34) and (l-b=5), what are (l) and (b)?
#linear equations
#word problem
#rectangle
#medium
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A ( (10,7) )
B ( (11,6) )
C ( (12,5) )
D ( (9,8) )
Explanation opens after your attempt
Correct Answer
B. ( (11,6) )
Step 1
Concept
From (2l+2b=34), (l+b=17), and (l-b=5). Adding gives (2l=22), so (l=11) and (b=6).
Step 2
Why this answer is correct
The correct answer is B. ( (11,6) ). From (2l+2b=34), (l+b=17), and (l-b=5). Adding gives (2l=22), so (l=11) and (b=6).
Step 3
Exam Tip
(2l+2b=34) से (l+b=17), और (l-b=5)। जोड़ने पर (2l=22), इसलिए (l=11) और (b=6)।
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दो अंकों वाली संख्या में दहाई का अंक (x) और इकाई का अंक (y) है। यदि (x+y=13) और (x-y=3), तो अंक क्या हैं?
In a two-digit number, the tens digit is (x) and the units digit is (y). If (x+y=13) and (x-y=3), what are the digits?
#linear equations
#word problem
#digits
#medium
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A (8) और (5) / (8) and (5)
B (7) और (6) / (7) and (6)
C (9) और (4) / (9) and (4)
D (6) और (7) / (6) and (7)
Explanation opens after your attempt
Correct Answer
A. (8) और (5) / (8) and (5)
Step 1
Concept
Adding both equations gives (2x=16), so (x=8) and (y=5). In digit problems, do not interchange tens and units.
Step 2
Why this answer is correct
The correct answer is A. (8) और (5) / (8) and (5). Adding both equations gives (2x=16), so (x=8) and (y=5). In digit problems, do not interchange tens and units.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (2x=16), इसलिए (x=8) और (y=5)। अंकों के प्रश्न में दहाई और इकाई का क्रम न बदलें।
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समीकरण (3x+2y=12) और (6x+4y=25) के लिए सही निष्कर्ष क्या है?
What is the correct conclusion for (3x+2y=12) and (6x+4y=25)?
#linear equations
#inconsistent pair
#medium
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A अनंत हल / Infinitely many solutions
B कोई हल नहीं / No solution
C एक हल / One solution
D हल ( (2,3) ) / Solution ( (2,3) )
Explanation opens after your attempt
Correct Answer
B. कोई हल नहीं / No solution
Step 1
Concept
Multiplying the first equation by (2) should give left side (6x+4y) and right side (24). But the second right side is (25), so there is no solution.
Step 2
Why this answer is correct
The correct answer is B. कोई हल नहीं / No solution. Multiplying the first equation by (2) should give left side (6x+4y) and right side (24). But the second right side is (25), so there is no solution.
Step 3
Exam Tip
पहले समीकरण को (2) से गुणा करने पर बायाँ पक्ष (6x+4y) और दायाँ पक्ष (24) होना चाहिए। लेकिन दूसरा दायाँ पक्ष (25) है, इसलिए कोई हल नहीं।
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समीकरण (4x-5y=2) और (x+y=5) का हल क्या है?
What is the solution of (4x-5y=2) and (x+y=5)?
#linear equations
#substitution
#medium
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A ( (4,1) )
B ( (2,3) )
C ( (5,0) )
D ( (3,2) )
Explanation opens after your attempt
Correct Answer
D. ( (3,2) )
Step 1
Concept
Putting (x=5-y) gives (4(5-y)-5y=2), so (y=2) and (x=3). Be careful while combining negative terms.
Step 2
Why this answer is correct
The correct answer is D. ( (3,2) ). Putting (x=5-y) gives (4(5-y)-5y=2), so (y=2) and (x=3). Be careful while combining negative terms.
Step 3
Exam Tip
(x=5-y) रखने पर (4(5-y)-5y=2), इसलिए (y=2) और (x=3)। ऋण वाले पदों को जोड़ते समय सावधानी रखें।
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विलोपन विधि से (5x+4y=60) और (5x-y=35) को हल करें।
Solve (5x+4y=60) and (5x-y=35) by elimination.
#linear equations
#elimination
#medium
#class 10
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A ( (8,5) )
B ( (7,6) )
C ( (9,4) )
D ( (6,7) )
Explanation opens after your attempt
Correct Answer
A. ( (8,5) )
Step 1
Concept
Subtracting the second equation from the first gives (5y=25), so (y=5) and (x=8). Eliminating equal (5x) terms is the right step.
Step 2
Why this answer is correct
The correct answer is A. ( (8,5) ). Subtracting the second equation from the first gives (5y=25), so (y=5) and (x=8). Eliminating equal (5x) terms is the right step.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (5y=25), इसलिए (y=5) और (x=8)। समान (5x) पदों को हटाना सही कदम है।
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यदि (2x+3y=33) और (4x-y=3), तो हल क्या होगा?
If (2x+3y=33) and (4x-y=3), what will be the solution?
#linear equations
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A ( (4,7) )
B ( (5,6) )
C ( (3,9) )
D ( (6,5) )
Explanation opens after your attempt
Correct Answer
C. ( (3,9) )
Step 1
Concept
From (4x-y=3), (y=4x-3), so (2x+3(4x-3)=33). This gives (x=3) and (y=9).
Step 2
Why this answer is correct
The correct answer is C. ( (3,9) ). From (4x-y=3), (y=4x-3), so (2x+3(4x-3)=33). This gives (x=3) and (y=9).
Step 3
Exam Tip
(4x-y=3) से (y=4x-3), इसलिए (2x+3(4x-3)=33)। इससे (x=3) और (y=9)।
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समीकरण (x+5y=37) और (3x-y=15) का हल चुनें।
Choose the solution of (x+5y=37) and (3x-y=15).
#linear equations
#substitution
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A ( (8,5) )
B ( (7,6) )
C ( (6,7) )
D ( (9,4) )
Explanation opens after your attempt
Correct Answer
B. ( (7,6) )
Step 1
Concept
From (3x-y=15), (y=3x-15), so (x+5(3x-15)=37). This gives (x=7) and (y=6).
Step 2
Why this answer is correct
The correct answer is B. ( (7,6) ). From (3x-y=15), (y=3x-15), so (x+5(3x-15)=37). This gives (x=7) and (y=6).
Step 3
Exam Tip
(3x-y=15) से (y=3x-15), इसलिए (x+5(3x-15)=37)। इससे (x=7) और (y=6)।
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विलोपन विधि से (7x+2y=42) और (7x-2y=14) का हल क्या है?
What is the solution of (7x+2y=42) and (7x-2y=14) by elimination?
#linear equations
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A ( (5,4) )
B ( (6,3) )
C ( (4,7) )
D ( (3,8) )
Explanation opens after your attempt
Correct Answer
C. ( (4,7) )
Step 1
Concept
Adding both equations gives (14x=56), so (x=4) and (y=7). Add opposite (2y) terms to eliminate them.
Step 2
Why this answer is correct
The correct answer is C. ( (4,7) ). Adding both equations gives (14x=56), so (x=4) and (y=7). Add opposite (2y) terms to eliminate them.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (14x=56), इसलिए (x=4) और (y=7)। विपरीत (2y) पदों को जोड़कर हटाएँ।
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समीकरण (2x-y=8) और (3x+2y=47) को हल करें।
Solve (2x-y=8) and (3x+2y=47).
#linear equations
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A ( (7,6) )
B ( (8,8) )
C ( (10,7) )
D ( (9,10) )
Explanation opens after your attempt
Correct Answer
D. ( (9,10) )
Step 1
Concept
From (2x-y=8), (y=2x-8), so (3x+2(2x-8)=47). This gives (x=9) and (y=10).
Step 2
Why this answer is correct
The correct answer is D. ( (9,10) ). From (2x-y=8), (y=2x-8), so (3x+2(2x-8)=47). This gives (x=9) and (y=10).
Step 3
Exam Tip
(2x-y=8) से (y=2x-8), इसलिए (3x+2(2x-8)=47)। इससे (x=9) और (y=10)।
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विलोपन विधि से (5x+3y=60) और (2x+3y=33) का हल ज्ञात करें।
Find the solution of (5x+3y=60) and (2x+3y=33) by elimination.
#linear equations
#elimination
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A ( (7,8) )
B ( (8,6) )
C ( (9,5) )
D ( (10,4) )
Explanation opens after your attempt
Correct Answer
C. ( (9,5) )
Step 1
Concept
Subtracting the second from the first gives (3x=27), so (x=9) and (y=5). Remove equal (3y) terms to solve quickly.
Step 2
Why this answer is correct
The correct answer is C. ( (9,5) ). Subtracting the second from the first gives (3x=27), so (x=9) and (y=5). Remove equal (3y) terms to solve quickly.
Step 3
Exam Tip
पहले से दूसरे को घटाने पर (3x=27), इसलिए (x=9) और (y=5)। समान (3y) पदों को हटाकर जल्दी हल करें।
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