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A rectangle has length (l) and breadth (b). If (2l+2b=34) and (l-b=5), what are (l) and (b)?

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Answer and explanation

Correct answer: \(l=11,\ b=6\)

Divide the first equation \(2l+2b=34\) by 2 to get \(l+b=17\). Adding this to \(l-b=5\) gives \(2l=22\), so \(l=11\). Substituting into \(l-b=5\), we get \(11-b=5\), hence \(b=6\). Option C is not correct because its difference is 7, not 5. Exam tip: Simplify coefficients first, then use addition or subtraction to eliminate one variable.

Related tags

Pair Of Linear EquationsElimination MethodSubstitution MethodRectangleWord ProblemClass 10

Frequently asked questions

What is the correct answer to this question?

\(l=11,\ b=6\)

Why is this the correct answer?

Divide the first equation \(2l+2b=34\) by 2 to get \(l+b=17\). Adding this to \(l-b=5\) gives \(2l=22\), so \(l=11\). Substituting into \(l-b=5\), we get \(11-b=5\), hence \(b=6\). Option C is not correct because its difference is 7, not 5. Exam tip: Simplify coefficients first, then use addition or subtraction to eliminate one variable.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Pair of Linear Equations in Two Variables. Topic: Algebraic methods: Substitution method and Elimination method..

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