Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 101-110 of 600 questions.
If (p(a)=0) for a number (a), what is (a) called for (p(x)=0)?
A. मूलRoot
(p(a)=0) होने पर (a) समीकरण को संतुष्ट करता है। इसलिए (a) उसका मूल है। / If (p(a)=0), then (a) satisfies the equation. Therefore (a) is its root.
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Is (x=2) a root of \(x^2-4x+4=0\)?
A. हाँYes
(x=2) रखने पर (4-8+4=0) मिलता है। इसलिए (2) इसका मूल है। / Putting (x=2) gives (4-8+4=0). Therefore (2) is a root.
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Is (x=-1) a root of \(2x^2+x-1=0\)?
A. हाँYes
(x=-1) रखने पर (2-1-1=0) मिलता है। ऋणात्मक मूल में चिन्हों की जांच जरूरी है। / Putting (x=-1) gives (2-1-1=0). Sign checking is important with a negative root.
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What are the roots of \(x^2-36=0\)?
A. (6) और (-6)(6) and (-6)
(x-2-36=(x-6)(x+6)) है। इसलिए मूल (6) और (-6) हैं। / (x-2-36=(x-6)(x+6)). Therefore the roots are (6) and (-6).
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What are the roots of \(x^2-8x+15=0\)?
A. (3) और (5)(3) and (5)
(x-2-8x+15=(x-3)(x-5)) है। इसलिए मूल (3) और (5) हैं। / (x-2-8x+15=(x-3)(x-5)). Therefore the roots are (3) and (5).
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What are the roots of \(x^2+10x+21=0\)?
A. (-3) और (-7)(-3) and (-7)
(x-2+10x+21=(x+3)(x+7)) है। इसलिए मूल (-3) और (-7) हैं। / (x-2+10x+21=(x+3)(x+7)). Therefore the roots are (-3) and (-7).
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Which equation has roots (0) and (8)?
A. \(x^2-8x=0\)
मूल (0) और (8) होने पर समीकरण (x(x-8)=0) होगा। इसे खोलने पर \(x^2-8x=0\) मिलता है। / With roots (0) and (8), the equation is (x(x-8)=0). Expanding it gives \(x^2-8x=0\).
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If (3) is a root of \(x^2+sx-12=0\), what is the value of (s)?
A. (1)
(x=3) रखने पर (9+3s-12=0) इसलिए (s=1)। दिए गए मूल को सीधे समीकरण में रखें। / Putting (x=3) gives (9+3s-12=0), so (s=1). Substitute the given root directly into the equation.
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What is the sum of roots of \(2x^2+3x-5=0\)?
A. \(-\frac{3}{2}\)
मूलों का योग \(-\frac{b}{a}\) होता है। यहां योग \(-\frac{3}{2}\) है। / The sum of roots is \(-\frac{b}{a}\). Here the sum is \(-\frac{3}{2}\).
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What is the product of roots of \(6x^2-x-2=0\)?
A. \(-\frac{1}{3}\)
मूलों का गुणनफल \(\frac{c}{a}\) होता है। यहां \(\frac{-2}{6}=-\frac{1}{3}\) सही है। / The product of roots is \(\frac{c}{a}\). Here \(\frac{-2}{6}=-\frac{1}{3}\) is correct.
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