Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 81-90 of 600 questions.
If (-1) is a root of \(x^2+rx-12=0\), what is the value of (r)?
A. (-11)
(x=-1) रखने पर (1-r-12=0) इसलिए (r=-11)। ऋणात्मक मूल रखते समय प्रत्येक पद का चिन्ह देखें। / Putting (x=-1) gives (1-r-12=0), so (r=-11). Check the sign of each term while using a negative root.
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What are the roots of \(x^2+12x+36=0\)?
B. (-6) और (-6)(-6) and (-6)
(x-2+12x+36=(x+6)2) है। इसलिए दोनों मूल (-6) हैं। / (x-2+12x+36=(x+6)2). Therefore both roots are (-6).
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What are the roots of \(2x^2-10x=0\)?
A. (0) और (5)(0) and (5)
(2x-2-10x=2x(x-5)) है। इसलिए मूल (0) और (5) हैं। / (2x-2-10x=2x(x-5)). Therefore the roots are (0) and (5).
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Which is the root of \(x^2+14x+49=0\)?
B. (-7) दो बार(-7) twice
(x-2+14x+49=(x+7)2) है। इसलिए दोहराया मूल (-7) है। / (x-2+14x+49=(x+7)2). Therefore the repeated root is (-7).
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Which of the following values is not a root of \(x^2-64=0\)?
C. (0)
\(x^2-64=0\) के मूल (8) और (-8) हैं। (0) रखने पर समीकरण सत्य नहीं होता। / The roots of \(x^2-64=0\) are (8) and (-8). Substituting (0) does not make the equation true.
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If ((x+1)(x-8)=0), what are the roots?
B. (-1) और (8)(-1) and (8)
शून्य गुणनफल नियम से (x+1=0) या (x-8=0) होगा। इसलिए मूल (-1) और (8) हैं। / By the zero product rule, (x+1=0) or (x-8=0). Therefore the roots are (-1) and (8).
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If the roots of an equation are (2) and (-5), what is their sum?
B. (-3)
योग (2+(-5)=-3) है। ऋणात्मक मूल जोड़ते समय चिन्ह न भूलें। / The sum is (2+(-5)=-3). Do not forget the sign while adding a negative root.
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Which monic quadratic equation has sum of roots (-9) and product of roots (20)?
A. \(x^2+9x+20=0\)
\(मोनिक समीकरण (x^2-(\)योग)x+गुणनफल=0) होता है। इसलिए \(x^2+9x+20=0\) सही है। \(/ A monic equation is (x^2-(\)sum)x+product\(=0). Therefore (x^2+9x+20=0) is correct.\)
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If (2) is a root of \(3x^2-8x+n=0\), what is the value of (n)?
B. (4)
(x=2) रखने पर (12-16+n=0) इसलिए (n=4)। ऐसे प्रश्नों में गणना धीरे और सही करें। / Putting (x=2) gives (12-16+n=0), so (n=4). In such questions calculate slowly and correctly.
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What are the roots of \(x^2-5x+6=0\)?
A. (2) और (3)(2) and (3)
(x-2-5x+6=(x-2)(x-3)) है। इसलिए मूल (2) और (3) हैं। / (x-2-5x+6=(x-2)(x-3)). Therefore the roots are (2) and (3).
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