Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 91-100 of 600 questions.
If (-3) is a root of a quadratic polynomial, which factor is certain?
B. (x+3)
मूल (r) होने पर गुणनखंड (x-r) होता है। (r=-3) के लिए गुणनखंड (x+3) होगा। / If the root is (r), the factor is (x-r). For (r=-3), the factor is (x+3).
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How many real roots does \(x^2+16=0\) have?
C. (0)
वास्तविक संख्या के लिए \(x^2\ge0\) होता है। इसलिए \(x^2+16=0\) का कोई वास्तविक मूल नहीं है। / For a real number, \(x^2\ge0\). Therefore \(x^2+16=0\) has no real root.
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What are the roots of \(x^2-3x-10=0\)?
A. (5) और (-2)(5) and (-2)
(x-2-3x-10=(x-5)(x+2)) है। इसलिए मूल (5) और (-2) हैं। / (x-2-3x-10=(x-5)(x+2)). Therefore the roots are (5) and (-2).
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What are the roots of \(x^2=49\)?
A. (7) और (-7)(7) and (-7)
\(x^2=49\) से \(x=\pm7\) मिलता है। वर्गमूल लेते समय दोनों चिन्ह लें। / From \(x^2=49\), we get \(x=\pm7\). Take both signs while finding square roots.
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If one root is (5) and the product of roots is (35), what is the other root?
B. (7)
दूसरा मूल \(\frac{35}{5}=7\) होगा। गुणनफल में दिए हुए मूल से भाग करें। / The other root is \(\frac{35}{5}=7\). Divide the product by the given root.
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If the sum of roots is (8) and one root is (3), what is the other root?
B. (5)
दूसरा मूल (8-3=5) है। योग में से दिया हुआ मूल घटाएं। / The other root is (8-3=5). Subtract the given root from the sum.
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If the roots of a quadratic equation are (r) and (-r), what is their sum?
C. (0)
(r+(-r)=0) होता है। विपरीत मूलों का योग हमेशा (0) होता है। / (r+(-r)=0). The sum of opposite roots is always (0).
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What are the roots of \(3x^2-10x+3=0\)?
A. (3) और \(\frac{1}{3}\)(3) and \(\frac{1}{3}\)
(3x-2-10x+3=(3x-1)(x-3)) है। इसलिए मूल \(\frac{1}{3}\) और (3) हैं। / (3x-2-10x+3=(3x-1)(x-3)). Therefore the roots are \(\frac{1}{3}\) and (3).
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If both roots of a monic quadratic equation are (-4) and (-4), which equation is it?
A. \(x^2+8x+16=0\)
दोनों मूल (-4) हों तो समीकरण ((x+4)2=0) होगा। इसे खोलने पर \(x^2+8x+16=0\) मिलता है। / If both roots are (-4), the equation is ((x+4)2=0). Expanding it gives \(x^2+8x+16=0\).
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If \(x=\frac{1}{2}\) is a root of \(4x^2+px-3=0\), what is the value of (p)?
B. (4)
\(x=\frac{1}{2}\) रखने पर \(1+\frac{p}{2}-3=0\) इसलिए (p=4)। भिन्न मूल रखते समय हर पद सावधानी से हल करें। / Putting \(x=\frac{1}{2}\) gives \(1+\frac{p}{2}-3=0\), so (p=4). When substituting a fractional root, solve each term carefully.
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