Concept-wise Practice

number_of_roots MCQ Questions for Class 10

number_of_roots se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

All Tags Search Similar

Practice Questions

3 questions tagged with number_of_roots.

Question 1/3 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

समीकरण \(x^2+36=0\) के वास्तविक मूलों की संख्या कितनी है?

How many real roots does \(x^2+36=0\) have?

Explanation opens after your attempt
Correct Answer

C. (0)

Step 1

Concept

For a real number, \(x^2\ge0\). Therefore \(x^2+36=0\) has no real root.

Step 2

Why this answer is correct

The correct answer is C. (0). For a real number, \(x^2\ge0\). Therefore \(x^2+36=0\) has no real root.

Step 3

Exam Tip

वास्तविक संख्या के लिए \(x^2\ge0\) होता है। इसलिए \(x^2+36=0\) का कोई वास्तविक मूल नहीं है।

Open Question Page
Ask Friends
Question 2/3 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

समीकरण \(x^2+16=0\) के वास्तविक मूलों की संख्या कितनी है?

How many real roots does \(x^2+16=0\) have?

Explanation opens after your attempt
Correct Answer

C. (0)

Step 1

Concept

For a real number, \(x^2\ge0\). Therefore \(x^2+16=0\) has no real root.

Step 2

Why this answer is correct

The correct answer is C. (0). For a real number, \(x^2\ge0\). Therefore \(x^2+16=0\) has no real root.

Step 3

Exam Tip

वास्तविक संख्या के लिए \(x^2\ge0\) होता है। इसलिए \(x^2+16=0\) का कोई वास्तविक मूल नहीं है।

Open Question Page
Ask Friends
Question 3/3 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

समीकरण \(x^2+4=0\) के वास्तविक मूलों की संख्या कितनी है?

How many real roots does \(x^2+4=0\) have?

Explanation opens after your attempt
Correct Answer

C. (0)

Step 1

Concept

Because \(x^2\ge 0\) so \(x^2+4\) never becomes (0). Therefore it has no real root.

Step 2

Why this answer is correct

The correct answer is C. (0). Because \(x^2\ge 0\) so \(x^2+4\) never becomes (0). Therefore it has no real root.

Step 3

Exam Tip

क्योंकि \(x^2\ge 0\) होता है इसलिए \(x^2+4\) कभी (0) नहीं बनता। इसलिए कोई वास्तविक मूल नहीं है।

Open Question Page
Ask Friends

number_of_roots Revision Links

All MCQ Tags

Browse concept directory

All Subjects

Subject-wise practice

Search number_of_roots

More keyword results