100 results found for "ap-sum-last-term" in Class 10.
यदि किसी समांतर श्रेढ़ी का पहला पद (11), अंतिम पद (71) और योग (574) है, तो पदों की संख्या क्या है?
If an AP has first term (11), last term (71), and sum (574), what is the number of terms?
#find number of terms
#last term
#sum
A (12)
B (13)
C (14)
D (15)
Explanation opens after your attempt
Step 1
Concept
From (\frac{n}{2}(11+71)=574), (n=14). When the last term is given, the common difference is not needed.
Step 2
Why this answer is correct
The correct answer is C. (14). From (\frac{n}{2}(11+71)=574), (n=14). When the last term is given, the common difference is not needed.
Step 3
Exam Tip
(\frac{n}{2}(11+71)=574) से (n=14) मिलता है। अंतिम पद दिए होने पर सार्व अंतर की जरूरत नहीं होती।
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किसी समांतर श्रेढ़ी का पहला पद (8), अंतिम पद (62) और पदों की संख्या (10) है। सभी पदों का योग ज्ञात कीजिए।
An AP has first term (8), last term (62), and number of terms (10). Find the sum of all terms.
#first last term
#ap sum
#class 10
A (350)
B (360)
C (370)
D (340)
Explanation opens after your attempt
Step 1
Concept
Using (S_n=\frac{n}{2}(a+l)), the sum is (350). When the last term is given, this formula is faster.
Step 2
Why this answer is correct
The correct answer is A. (350). Using (S_n=\frac{n}{2}(a+l)), the sum is (350). When the last term is given, this formula is faster.
Step 3
Exam Tip
सूत्र (S_n=\frac{n}{2}(a+l)) से योग (350) आता है। जब अंतिम पद दिया हो तो यह सूत्र जल्दी काम करता है।
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एक AP में पहला पद (12), अंतिम पद (72) और कुल पद (11) हैं। योग क्या होगा?
In an AP, the first term is (12), the last term is (72), and total terms are (11). What is the sum?
#ap-sum-given-last
A (442)
B (452)
C (462)
D (472)
Explanation opens after your attempt
Step 1
Concept
Using (S_n=\frac{n}{2}(a+l)), (S_{11}=\frac{11}{2}(12+72)=462).
Step 2
Why this answer is correct
The correct answer is C. (462). Using (S_n=\frac{n}{2}(a+l)), (S_{11}=\frac{11}{2}(12+72)=462).
Step 3
Exam Tip
(S_n=\frac{n}{2}(a+l)) से (S_{11}=\frac{11}{2}(12+72)=462)।
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किसी समांतर श्रेढ़ी में पहले और अंतिम पद का योग (420) है तथा कुल योग (7350) है। पदों की संख्या ज्ञात कीजिए।
In an AP, the sum of the first and last terms is (420), and the total sum is (7350). Find the number of terms.
#first last sum
#find n
#ap
A (33)
B (34)
C (35)
D (36)
Explanation opens after your attempt
Step 1
Concept
From \(7350=\frac{n}{2}\times420\), (n=35). If (a+l) is given, finding (d) is not needed.
Step 2
Why this answer is correct
The correct answer is C. (35). From \(7350=\frac{n}{2}\times420\), (n=35). If (a+l) is given, finding (d) is not needed.
Step 3
Exam Tip
\(7350=\frac{n}{2}\times420\) से (n=35) मिलता है। (a+l) दिया हो तो (d) निकालने की जरूरत नहीं है।
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किसी समांतर श्रेढ़ी में पहले और अंतिम पद का योग (340) है तथा कुल योग (5780) है। पदों की संख्या ज्ञात कीजिए।
In an AP, the sum of the first and last terms is (340), and the total sum is (5780). Find the number of terms.
#first last sum
#find n
#ap
A (32)
B (34)
C (36)
D (38)
Explanation opens after your attempt
Step 1
Concept
From \(5780=\frac{n}{2}\times340\), (n=34). If (a+l) is given, finding (d) is not needed.
Step 2
Why this answer is correct
The correct answer is B. (34). From \(5780=\frac{n}{2}\times340\), (n=34). If (a+l) is given, finding (d) is not needed.
Step 3
Exam Tip
\(5780=\frac{n}{2}\times340\) से (n=34) मिलता है। (a+l) दिया हो तो (d) निकालने की जरूरत नहीं होती।
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किसी समांतर श्रेढ़ी में पहले और अंतिम पद का योग (260) है तथा कुल योग (4160) है। पदों की संख्या ज्ञात कीजिए।
In an AP, the sum of the first and last terms is (260), and the total sum is (4160). Find the number of terms.
#first last sum
#find n
#ap
A (28)
B (30)
C (34)
D (32)
Explanation opens after your attempt
Step 1
Concept
From \(4160=\frac{n}{2}\times260\), (n=32). If (a+l) is given, finding (d) is not needed.
Step 2
Why this answer is correct
The correct answer is D. (32). From \(4160=\frac{n}{2}\times260\), (n=32). If (a+l) is given, finding (d) is not needed.
Step 3
Exam Tip
\(4160=\frac{n}{2}\times260\) से (n=32) मिलता है। (a+l) दिया हो तो (d) निकालने की जरूरत नहीं होती।
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किसी समांतर श्रेढ़ी में पहले और अंतिम पद का योग (150) है तथा कुल योग (1800) है। पदों की संख्या ज्ञात कीजिए।
In an AP, the sum of the first and last terms is (150), and the total sum is (1800). Find the number of terms.
#first last sum
#find n
#ap
A (20)
B (22)
C (26)
D (24)
Explanation opens after your attempt
Step 1
Concept
From \(1800=\frac{n}{2}\times150\), (n=24). If (a+l) is given, finding (d) is not needed.
Step 2
Why this answer is correct
The correct answer is D. (24). From \(1800=\frac{n}{2}\times150\), (n=24). If (a+l) is given, finding (d) is not needed.
Step 3
Exam Tip
\(1800=\frac{n}{2}\times150\) से (n=24) मिलता है। (a+l) दिया हो तो (d) निकालने की जरूरत नहीं है।
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किसी समांतर श्रेढ़ी में पहला पद (14), अंतिम पद (104) और पदों की संख्या (19) है। योग कितना होगा?
In an AP, the first term is (14), the last term is (104), and the number of terms is (19). What is the sum?
#first last sum
#ap formula
#class 10
A (1101)
B (1111)
C (1121)
D (1131)
Explanation opens after your attempt
Step 1
Concept
(S_{19}=\frac{19}{2}(14+104)=1121). When first and last terms are given, finding (d) is not necessary.
Step 2
Why this answer is correct
The correct answer is C. (1121). (S_{19}=\frac{19}{2}(14+104)=1121). When first and last terms are given, finding (d) is not necessary.
Step 3
Exam Tip
(S_{19}=\frac{19}{2}(14+104)=1121)। पहला और अंतिम पद दिए हों तो (d) निकालना जरूरी नहीं है।
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यदि किसी AP का पहला पद (5), अंतिम पद (45) और पदों की संख्या (9) है तो योग क्या है?
If the first term of an AP is (5), the last term is (45), and the number of terms is (9), what is the sum?
#ap-sum-first-last
A (215)
B (225)
C (235)
D (245)
Explanation opens after your attempt
Step 1
Concept
When first and last terms are given use (S_n=\frac{n}{2}(a+l)). (S_9=\frac{9}{2}(5+45)=225).
Step 2
Why this answer is correct
The correct answer is B. (225). When first and last terms are given use (S_n=\frac{n}{2}(a+l)). (S_9=\frac{9}{2}(5+45)=225).
Step 3
Exam Tip
जब पहला और अंतिम पद दिए हों तो (S_n=\frac{n}{2}(a+l))। (S_9=\frac{9}{2}(5+45)=225)।
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यदि किसी समान्तर श्रेणी के पहले (18) पदों का योग (999) और प्रथम पद (13) है तो अंतिम पद क्या होगा?
If the sum of the first (18) terms of an arithmetic progression is (999) and the first term is (13), what is the last term?
#ap
#last-term
#sum-formula
#expert
A (92)
B (96)
C (98)
D (101)
Explanation opens after your attempt
Step 1
Concept
From (999=9(13+l)), (l=98). Exam tip: (S_n=\frac{n}{2}(a+l)) is the shortest method here.
Step 2
Why this answer is correct
The correct answer is C. (98). From (999=9(13+l)), (l=98). Exam tip: (S_n=\frac{n}{2}(a+l)) is the shortest method here.
Step 3
Exam Tip
(999=9(13+l)) से (l=98) मिलता है। परीक्षा में (S_n=\frac{n}{2}(a+l)) सबसे छोटा तरीका है।
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एक समांतर श्रेढ़ी का प्रथम पद (6), अंतिम पद (60) और कुल पद (10) हैं। उसका योग कितना है?
An arithmetic progression has first term (6), last term (60), and (10) terms. What is its sum?
#ap
#sum
#first_last
A (320)
B (330)
C (340)
D (350)
Explanation opens after your attempt
Step 1
Concept
Using (S_n=\frac{n}{2}(a+l)), \(S_{10}=330\). If the last term is given, finding (d) is not necessary.
Step 2
Why this answer is correct
The correct answer is B. (330). Using (S_n=\frac{n}{2}(a+l)), \(S_{10}=330\). If the last term is given, finding (d) is not necessary.
Step 3
Exam Tip
(S_n=\frac{n}{2}(a+l)) से \(S_{10}=330\)। अंतिम पद मिले तो (d) निकालना जरूरी नहीं।
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किसी समांतर श्रेढ़ी में पहले (20) पदों का योग (740) है और (20)वाँ पद (60) है। पहला पद ज्ञात कीजिए।
In an AP, the sum of the first (20) terms is (740), and the (20)th term is (60). Find the first term.
#first term
#last term
#sum
#ap
A (10)
B (14)
C (18)
D (22)
Explanation opens after your attempt
Step 1
Concept
From (740=10(a+60)), (a=14). When the (n)th term is given, use it as the last term for the first (n) terms.
Step 2
Why this answer is correct
The correct answer is B. (14). From (740=10(a+60)), (a=14). When the (n)th term is given, use it as the last term for the first (n) terms.
Step 3
Exam Tip
(740=10(a+60)) से (a=14) मिलता है। जब (n)वाँ पद दिया हो तो उसे अंतिम पद की तरह इस्तेमाल करें।
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किसी समांतर श्रेढ़ी के पहले पद और (60)वें पद का योग (300) है। (21)वें पद से (40)वें पद तक का योग ज्ञात कीजिए।
The sum of the first term and the (60)th term of an AP is (300). Find the sum from the (21)st term to the (40)th term.
#symmetric terms
#range sum
#ap
A (2900)
B (2950)
C (3000)
D (3050)
Explanation opens after your attempt
Step 1
Concept
\(a_{21}+a_{40}=a_1+a_{60}=300\), so the sum of (20) terms is (3000). Sums of symmetric terms are equal in an AP.
Step 2
Why this answer is correct
The correct answer is C. (3000). \(a_{21}+a_{40}=a_1+a_{60}=300\), so the sum of (20) terms is (3000). Sums of symmetric terms are equal in an AP.
Step 3
Exam Tip
\(a_{21}+a_{40}=a_1+a_{60}=300\), इसलिए (20) पदों का योग (3000) है। सममित पदों का योग बराबर होता है।
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किसी समांतर श्रेढ़ी के पहले पद और (40)वें पद का योग (210) है। (11)वें पद से (30)वें पद तक का योग ज्ञात कीजिए।
The sum of the first term and the (40)th term of an AP is (210). Find the sum from the (11)th term to the (30)th term.
#symmetric terms
#range sum
#ap
A (2000)
B (2100)
C (2200)
D (2300)
Explanation opens after your attempt
Step 1
Concept
\(a_{11}+a_{30}=a_1+a_{40}=210\), so the sum of (20) terms is (2100). Sums of symmetric terms are equal in an AP.
Step 2
Why this answer is correct
The correct answer is B. (2100). \(a_{11}+a_{30}=a_1+a_{40}=210\), so the sum of (20) terms is (2100). Sums of symmetric terms are equal in an AP.
Step 3
Exam Tip
\(a_{11}+a_{30}=a_1+a_{40}=210\), इसलिए (20) पदों का योग (2100) है। सममित पदों का योग बराबर होता है।
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एक समान्तर श्रेणी का प्रथम पद (8) और अंतिम पद (176) है। यदि कुल योग (2208) है तो पदों की संख्या कितनी होगी?
The first term of an arithmetic progression is (8) and the last term is (176). If the total sum is (2208), how many terms are there?
#ap
#number-of-terms
#expert
A (20)
B (22)
C (23)
D (24)
Explanation opens after your attempt
Step 1
Concept
From (2208=\frac{n}{2}(8+176)), (n=24). Exam tip: use the (a+l) form when first and last terms are known.
Step 2
Why this answer is correct
The correct answer is D. (24). From (2208=\frac{n}{2}(8+176)), (n=24). Exam tip: use the (a+l) form when first and last terms are known.
Step 3
Exam Tip
(2208=\frac{n}{2}(8+176)) से (n=24) है। परीक्षा में प्रथम और अंतिम पद हों तो (a+l) वाला सूत्र लगाएं।
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एक समान्तर श्रेणी का प्रथम पद (7) और अंतिम पद (151) है। यदि कुल योग (1264) है तो पदों की संख्या कितनी होगी?
The first term of an arithmetic progression is (7) and the last term is (151). If the total sum is (1264), how many terms are there?
#ap
#number-of-terms
#expert
A (16)
B (18)
C (20)
D (22)
Explanation opens after your attempt
Step 1
Concept
From (1264=\frac{n}{2}(7+151)), (n=16). Exam tip: use the (a+l) form when first and last terms are known.
Step 2
Why this answer is correct
The correct answer is A. (16). From (1264=\frac{n}{2}(7+151)), (n=16). Exam tip: use the (a+l) form when first and last terms are known.
Step 3
Exam Tip
(1264=\frac{n}{2}(7+151)) से (n=16) है। परीक्षा में प्रथम और अंतिम पद हों तो (a+l) वाला सूत्र लगाएं।
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एक समान्तर श्रेणी का प्रथम पद (3) है और अंतिम पद (103) है। यदि योग (901) है तो पदों की संख्या कितनी है?
The first term of an arithmetic progression is (3) and the last term is (103). If the sum is (901), how many terms are there?
#ap
#number-of-terms
#expert
A (15)
B (17)
C (19)
D (21)
Explanation opens after your attempt
Step 1
Concept
From (901=\frac{n}{2}(3+103)), (n=17). Exam tip: when first and last terms are known, use (S_n=\frac{n}{2}(a+l)).
Step 2
Why this answer is correct
The correct answer is B. (17). From (901=\frac{n}{2}(3+103)), (n=17). Exam tip: when first and last terms are known, use (S_n=\frac{n}{2}(a+l)).
Step 3
Exam Tip
(901=\frac{n}{2}(3+103)) से (n=17) है। परीक्षा में प्रथम और अंतिम पद मिलें तो (S_n=\frac{n}{2}(a+l)) लगाएं।
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पहले (15) पदों का योग (975) है और अंतिम पद (97) है। पहला पद कितना होगा?
The sum of the first (15) terms is (975), and the last term is (97). What is the first term?
#reverse_formula
#first_term
#ap_sum
A (31)
B (33)
C (35)
D (37)
Explanation opens after your attempt
Step 1
Concept
From (975=\frac{15}{2}(a+97)), (a=33). First find the value of (a+l).
Step 2
Why this answer is correct
The correct answer is B. (33). From (975=\frac{15}{2}(a+97)), (a=33). First find the value of (a+l).
Step 3
Exam Tip
(975=\frac{15}{2}(a+97)) से (a=33)। पहले (a+l) का मान निकालें।
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पहले (12) पदों का योग (912) है और पहला पद (18) है। अंतिम पद (l) कितना होगा?
The sum of the first (12) terms is (912), and the first term is (18). What will be the last term (l)?
#reverse_formula
#last_term
#ap_sum
A (134)
B (136)
C (138)
D (140)
Explanation opens after your attempt
Step 1
Concept
From (912=\frac{12}{2}(18+l)), (l=134). Using the sum formula in reverse also appears in exams.
Step 2
Why this answer is correct
The correct answer is A. (134). From (912=\frac{12}{2}(18+l)), (l=134). Using the sum formula in reverse also appears in exams.
Step 3
Exam Tip
(912=\frac{12}{2}(18+l)) से (l=134)। योग सूत्र को उल्टा लगाना भी परीक्षा में आता है।
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पहले (12) पदों का योग (456) है और पहला पद (8) है। यदि अंतिम पद (l) है, तो (l) कितना होगा?
The sum of the first (12) terms is (456), and the first term is (8). If the last term is (l), what is (l)?
#reverse_formula
#last_term
#ap_sum
A (66)
B (68)
C (70)
D (72)
Explanation opens after your attempt
Step 1
Concept
From (456=\frac{12}{2}(8+l)), (l=68). Using the sum formula in reverse is also an important skill.
Step 2
Why this answer is correct
The correct answer is B. (68). From (456=\frac{12}{2}(8+l)), (l=68). Using the sum formula in reverse is also an important skill.
Step 3
Exam Tip
(456=\frac{12}{2}(8+l)) से (l=68)। योग सूत्र को उल्टा लगाना भी जरूरी कौशल है।
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यदि किसी समांतर श्रेढ़ी में पहला पद (2), अंतिम पद (50) और पदों की संख्या (13) है, तो योग कितना है?
If an arithmetic progression has first term (2), last term (50), and (13) terms, what is the sum?
#ap_sum
#first_last
#formula
A (328)
B (338)
C (348)
D (358)
Explanation opens after your attempt
Step 1
Concept
(S_{13}=\frac{13}{2}(2+50)=338). Add the first and last terms and multiply by half the number of terms.
Step 2
Why this answer is correct
The correct answer is B. (338). (S_{13}=\frac{13}{2}(2+50)=338). Add the first and last terms and multiply by half the number of terms.
Step 3
Exam Tip
(S_{13}=\frac{13}{2}(2+50)=338)। पहला और अंतिम पद जोड़कर आधे पदों से गुणा करें।
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यदि किसी समांतर श्रेढ़ी का पहला पद (7), अंतिम पद (43) और कुल पद (10) हैं, तो योग क्या होगा?
If the first term of an arithmetic progression is (7), the last term is (43), and there are (10) terms, what is the sum?
#ap
#sum
#last_term
A (240)
B (250)
C (260)
D (270)
Explanation opens after your attempt
Step 1
Concept
Using (S_n=\frac{n}{2}(a+l)), we get \(S_{10}=250\). When the last term is given, this formula is faster.
Step 2
Why this answer is correct
The correct answer is B. (250). Using (S_n=\frac{n}{2}(a+l)), we get \(S_{10}=250\). When the last term is given, this formula is faster.
Step 3
Exam Tip
सूत्र (S_n=\frac{n}{2}(a+l)) से \(S_{10}=250\) आता है। जब अंतिम पद दिया हो तो यह सूत्र तेज है।
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किसी समांतर श्रेढ़ी में पहले (30) पदों का योग (3000) है और (30)वाँ पद (150) है। पहला पद ज्ञात कीजिए।
In an AP, the sum of the first (30) terms is (3000), and the (30)th term is (150). Find the first term.
#first term
#last term
#sum
#ap
A (45)
B (50)
C (55)
D (60)
Explanation opens after your attempt
Step 1
Concept
From (3000=15(a+150)), (a=50). Treat the (n)th term as the last term of the first (n) terms.
Step 2
Why this answer is correct
The correct answer is B. (50). From (3000=15(a+150)), (a=50). Treat the (n)th term as the last term of the first (n) terms.
Step 3
Exam Tip
(3000=15(a+150)) से (a=50) मिलता है। (n)वें पद को पहले (n) पदों का अंतिम पद मानें।
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किसी समांतर श्रेढ़ी में पहले (25) पदों का योग (1625) है और (25)वाँ पद (113) है। पहला पद ज्ञात कीजिए।
In an AP, the sum of the first (25) terms is (1625), and the (25)th term is (113). Find the first term.
#first term
#last term
#sum
#ap
A (17)
B (15)
C (19)
D (21)
Explanation opens after your attempt
Step 1
Concept
From (1625=\frac{25}{2}(a+113)), (a=17). Treat the (n)th term as the last term of the first (n) terms.
Step 2
Why this answer is correct
The correct answer is A. (17). From (1625=\frac{25}{2}(a+113)), (a=17). Treat the (n)th term as the last term of the first (n) terms.
Step 3
Exam Tip
(1625=\frac{25}{2}(a+113)) से (a=17) मिलता है। (n)वें पद को पहले (n) पदों का अंतिम पद मानें।
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(600) से कम (13) के धनात्मक गुणजों में अंतिम पद क्या है?
What is the last term among the positive multiples of (13) less than (600)?
#ap multiples last-term nth-term
A (585)
B (598)
C (611)
D (624)
Explanation opens after your attempt
Step 1
Concept
In (13n<600), the greatest (n=46) so the term is \(13\times46=598\). Take the greatest integer below the limit.
Step 2
Why this answer is correct
The correct answer is B. (598). In (13n<600), the greatest (n=46) so the term is \(13\times46=598\). Take the greatest integer below the limit.
Step 3
Exam Tip
(13n<600) में सबसे बड़ा (n=46) है इसलिए पद \(13\times46=598\)। सीमा से कम सबसे बड़ा पूर्णांक लें।
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समान्तर श्रेणी \(7,12,17,\ldots\) में (180) से कम अंतिम पद क्या है?
In the AP \(7,12,17,\ldots\), what is the last term less than (180)?
#ap last-term-less-than nth-term class10
A (172)
B (175)
C (177)
D (179)
Explanation opens after your attempt
Step 1
Concept
The terms are (7+5(n-1)). The last term less than (180) is (177) because the next term will be (182).
Step 2
Why this answer is correct
The correct answer is C. (177). The terms are (7+5(n-1)). The last term less than (180) is (177) because the next term will be (182).
Step 3
Exam Tip
पद (7+5(n-1)) हैं। (180) से कम अंतिम पद (177) है क्योंकि अगला पद (182) होगा।
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(500) से कम (11) के धनात्मक गुणजों में अंतिम पद क्या है?
What is the last term among the positive multiples of (11) less than (500)?
#ap
#multiples
#last-term
#nth-term
A (484)
B (495)
C (506)
D (517)
Explanation opens after your attempt
Step 1
Concept
In (11n<500), the greatest (n=45), so the term is \(11\times45=495\). Take the greatest integer below the limit.
Step 2
Why this answer is correct
The correct answer is B. (495). In (11n<500), the greatest (n=45), so the term is \(11\times45=495\). Take the greatest integer below the limit.
Step 3
Exam Tip
(11n<500) में सबसे बड़ा (n=45) है इसलिए पद \(11\times45=495\)। सीमा से कम सबसे बड़ा पूर्णांक लें।
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समान्तर श्रेणी \(2,6,10,\ldots\) में (75) से कम अंतिम पद क्या है?
In the AP \(2,6,10,\ldots\), what is the last term less than (75)?
#ap
#last-term-less-than
#nth-term
#class10
A (74)
B (70)
C (72)
D (76)
Explanation opens after your attempt
Step 1
Concept
The terms of this sequence are (2+4(n-1)). The last term less than (75) is (74).
Step 2
Why this answer is correct
The correct answer is A. (74). The terms of this sequence are (2+4(n-1)). The last term less than (75) is (74).
Step 3
Exam Tip
इस श्रेणी के पद (2+4(n-1)) हैं। (75) से कम अंतिम पद (74) है।
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यदि समान्तर श्रेणी \(5,9,13,\ldots\) के पहले (n) पदों का योग (425) है तो अंतिम पद क्या होगा?
If the sum of the first (n) terms of the arithmetic progression \(5,9,13,\ldots\) is (425), what is the last term?
#ap
#last-term-from-sum
#expert
A (49)
B (53)
C (57)
D (61)
Explanation opens after your attempt
Step 1
Concept
Solving gives (n=13), so the last term is (5+12(4)=53). Exam tip: verify both the sum and the last term after finding (n).
Step 2
Why this answer is correct
The correct answer is C. (57). Solving gives (n=13), so the last term is (5+12(4)=53). Exam tip: verify both the sum and the last term after finding (n).
Step 3
Exam Tip
पहले (n=13) मिलता है और अंतिम पद (5+12(4)=53) नहीं बल्कि \(S_n\) की जांच से (n=17) तथा अंतिम पद (69) नहीं आता इसलिए विकल्पों में सही गणना (n=13) पर (53) है। परीक्षा में योग और अंतिम पद दोनों की दोबारा जांच करें।
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यदि किसी समांतर श्रेणी के पहले (10) पदों का योग (310) है और अंतिम पद (49) है, तो पहला पद कितना होगा?
If the sum of the first (10) terms of an arithmetic progression is (310), and the last term is (49), what is the first term?
#reverse_formula
#first_term
#ap_sum
A (11)
B (12)
C (13)
D (14)
Explanation opens after your attempt
Step 1
Concept
From (310=\frac{10}{2}(a+49)), (a=13). Using the sum formula in reverse also appears in exams.
Step 2
Why this answer is correct
The correct answer is C. (13). From (310=\frac{10}{2}(a+49)), (a=13). Using the sum formula in reverse also appears in exams.
Step 3
Exam Tip
(310=\frac{10}{2}(a+49)) से (a=13)। योग सूत्र को उल्टा लगाना भी परीक्षा में आता है।
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किसी समांतर श्रेढ़ी का (8)वाँ पद (57) है और पहले (8) पदों का योग (260) है। पहले (16) पदों का योग ज्ञात कीजिए।
The (8)th term of an AP is (57), and the sum of the first (8) terms is (260). Find the sum of the first (16) terms.
#given term and sum
#find sum
#ap
A (936)
B (952)
C (968)
D (984)
Explanation opens after your attempt
Step 1
Concept
The conditions give (a=8) and (d=7), so \(S_{16}=968\). Convert the given term and sum into two equations.
Step 2
Why this answer is correct
The correct answer is C. (968). The conditions give (a=8) and (d=7), so \(S_{16}=968\). Convert the given term and sum into two equations.
Step 3
Exam Tip
शर्तों से (a=8) और (d=7) मिलते हैं, इसलिए \(S_{16}=968\) है। दिए गए पद और योग को दो समीकरणों में बदलें।
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किसी समांतर श्रेढ़ी का (7)वाँ पद (48) है और पहले (7) पदों का योग (231) है। पहले (14) पदों का योग ज्ञात कीजिए।
The (7)th term of an AP is (48), and the sum of the first (7) terms is (231). Find the sum of the first (14) terms.
#given term and sum
#find sum
#ap
A (679)
B (693)
C (707)
D (721)
Explanation opens after your attempt
Step 1
Concept
The conditions give (a=18) and (d=5), so \(S_{14}=707\). Convert the given term and sum into two equations.
Step 2
Why this answer is correct
The correct answer is C. (707). The conditions give (a=18) and (d=5), so \(S_{14}=707\). Convert the given term and sum into two equations.
Step 3
Exam Tip
शर्तों से (a=18) और (d=5) मिलते हैं, इसलिए \(S_{14}=707\) है। दिए गए पद और योग को दो समीकरणों में बदलें।
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किसी समांतर श्रेढ़ी का (6)वाँ पद (31) है और पहले (6) पदों का योग (111) है। पहले (12) पदों का योग ज्ञात कीजिए।
The (6)th term of an AP is (31), and the sum of the first (6) terms is (111). Find the sum of the first (12) terms.
#given term and sum
#find sum
#ap
A (372)
B (386)
C (402)
D (418)
Explanation opens after your attempt
Step 1
Concept
The conditions give (a=6) and (d=5), so \(S_{12}=402\). Convert the given term and sum into two equations.
Step 2
Why this answer is correct
The correct answer is C. (402). The conditions give (a=6) and (d=5), so \(S_{12}=402\). Convert the given term and sum into two equations.
Step 3
Exam Tip
शर्तों से (a=6) और (d=5) मिलते हैं, इसलिए \(S_{12}=402\)। दिए गए पद और योग को दो समीकरणों में बदलें।
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एक समांतर श्रेढ़ी का पहला पद (6) है और उसका (14)वाँ पद उसके (4)वें पद का (3) गुना है। पहले (30) पदों का योग क्या होगा?
The first term of an AP is (6), and its (14)th term is (3) times its (4)th term. What is the sum of the first (30) terms?
#term condition
#ap sum
#expert
A (1425)
B (1485)
C (1545)
D (1605)
Explanation opens after your attempt
Step 1
Concept
The condition gives (6+13d=3(6+3d)), so (d=3) and \(S_{30}=1485\). Convert the term condition into an equation first.
Step 2
Why this answer is correct
The correct answer is B. (1485). The condition gives (6+13d=3(6+3d)), so (d=3) and \(S_{30}=1485\). Convert the term condition into an equation first.
Step 3
Exam Tip
शर्त से (6+13d=3(6+3d)), इसलिए (d=3) और \(S_{30}=1485\) है। पदों की शर्त को पहले समीकरण में बदलें।
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एक समांतर श्रेढ़ी का पहला पद (5) है और उसका (12)वाँ पद उसके (3)वें पद का (4) गुना है। पहले (20) पदों का योग क्या होगा?
The first term of an AP is (5), and its (12)th term is (4) times its (3)rd term. What is the sum of the first (20) terms?
#term condition
#ap sum
#hard
A (1050)
B (1025)
C (1075)
D (1100)
Explanation opens after your attempt
Step 1
Concept
The condition gives (5+11d=4(5+2d)), so (d=5) and \(S_{20}=1050\). Convert the term condition into an equation first.
Step 2
Why this answer is correct
The correct answer is A. (1050). The condition gives (5+11d=4(5+2d)), so (d=5) and \(S_{20}=1050\). Convert the term condition into an equation first.
Step 3
Exam Tip
शर्त से (5+11d=4(5+2d)), इसलिए (d=5) और \(S_{20}=1050\) है। पदों की शर्त को पहले समीकरण में बदलें।
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एक समांतर श्रेढ़ी का पहला पद (6) है और उसका (9)वाँ पद उसके (4)वें पद का (2) गुना है। पहले (25) पदों का योग क्या होगा?
The first term of an AP is (6), and its (9)th term is (2) times its (4)th term. What is the sum of the first (25) terms?
#term condition
#ap sum
#hard
A (1000)
B (1025)
C (1050)
D (1075)
Explanation opens after your attempt
Step 1
Concept
The condition gives (6+8d=2(6+3d)), so (d=3) and \(S_{25}=1050\). Convert the term condition into an equation first.
Step 2
Why this answer is correct
The correct answer is C. (1050). The condition gives (6+8d=2(6+3d)), so (d=3) and \(S_{25}=1050\). Convert the term condition into an equation first.
Step 3
Exam Tip
शर्त से (6+8d=2(6+3d)), इसलिए (d=3) और \(S_{25}=1050\) है। पदों की शर्त को पहले समीकरण में बदलें।
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एक समांतर श्रेढ़ी का पहला पद (4) है और उसका (8)वाँ पद उसके (3)वें पद का (3) गुना है। पहले (12) पदों का योग क्या होगा?
The first term of an AP is (4), and its (8)th term is (3) times its (3)rd term. What is the sum of the first (12) terms?
#term condition
#ap sum
#hard
A (528)
B (552)
C (576)
D (600)
Explanation opens after your attempt
Step 1
Concept
The condition gives (4+7d=3(4+2d)), so (d=8) and \(S_{12}=576\). Convert the term condition into an equation first.
Step 2
Why this answer is correct
The correct answer is C. (576). The condition gives (4+7d=3(4+2d)), so (d=8) and \(S_{12}=576\). Convert the term condition into an equation first.
Step 3
Exam Tip
शर्त से (4+7d=3(4+2d)), इसलिए (d=8) और \(S_{12}=576\)। पदों की शर्त को पहले समीकरण में बदलें।
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यदि समांतर श्रेणी का पहला पद (85), अंतिम पद (0) और पदों की संख्या (18) है, तो योग कितना है?
If the first term of an arithmetic progression is (85), the last term is (0), and the number of terms is (18), what is the sum?
#first_last
#zero_last
#ap_sum
A (745)
B (765)
C (785)
D (805)
Explanation opens after your attempt
Step 1
Concept
(S_{18}=\frac{18}{2}(85+0)=765). The formula remains the same even when the last term is zero.
Step 2
Why this answer is correct
The correct answer is B. (765). (S_{18}=\frac{18}{2}(85+0)=765). The formula remains the same even when the last term is zero.
Step 3
Exam Tip
(S_{18}=\frac{18}{2}(85+0)=765)। अंतिम पद शून्य हो तब भी सूत्र वही रहता है।
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समांतर श्रेणी का पहला पद (9), अंतिम पद (147) और पदों की संख्या (24) है। योग ज्ञात कीजिए।
The first term of an arithmetic progression is (9), the last term is (147), and the number of terms is (24). Find the sum.
#first_last
#ap_sum
#average
A (1812)
B (1832)
C (1852)
D (1872)
Explanation opens after your attempt
Step 1
Concept
(S_{24}=\frac{24}{2}(9+147)=1872). In the average method, multiply \(\frac{a+l}{2}\) by (n).
Step 2
Why this answer is correct
The correct answer is D. (1872). (S_{24}=\frac{24}{2}(9+147)=1872). In the average method, multiply \(\frac{a+l}{2}\) by (n).
Step 3
Exam Tip
(S_{24}=\frac{24}{2}(9+147)=1872)। औसत विधि में \(\frac{a+l}{2}\) को (n) से गुणा करें।
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यदि किसी समांतर श्रेणी का पहला पद (18), अंतिम पद (126) और कुल पद (19) हैं, तो योग कितना होगा?
If the first term of an arithmetic progression is (18), the last term is (126), and there are (19) terms, what is the sum?
#first_last
#ap_sum
#formula
A (1348)
B (1368)
C (1388)
D (1408)
Explanation opens after your attempt
Step 1
Concept
(S_{19}=\frac{19}{2}(18+126)=1368). If the first and last terms are given, use the shorter formula.
Step 2
Why this answer is correct
The correct answer is B. (1368). (S_{19}=\frac{19}{2}(18+126)=1368). If the first and last terms are given, use the shorter formula.
Step 3
Exam Tip
(S_{19}=\frac{19}{2}(18+126)=1368)। पहला और अंतिम पद दिए हों तो छोटा सूत्र लगाएँ।
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यदि समांतर श्रेणी का पहला पद (11), अंतिम पद (83) और कुल पद (13) हैं, तो योग कितना होगा?
If the first term of an arithmetic progression is (11), the last term is (83), and there are (13) terms, what is the sum?
#first_last
#ap_sum
#medium
A (591)
B (601)
C (611)
D (621)
Explanation opens after your attempt
Step 1
Concept
(S_{13}=\frac{13}{2}(11+83)=611). When the last term is given, (S_n=\frac{n}{2}(a+l)) is faster.
Step 2
Why this answer is correct
The correct answer is C. (611). (S_{13}=\frac{13}{2}(11+83)=611). When the last term is given, (S_n=\frac{n}{2}(a+l)) is faster.
Step 3
Exam Tip
(S_{13}=\frac{13}{2}(11+83)=611)। जब अंतिम पद दिया हो तो (S_n=\frac{n}{2}(a+l)) तेज रहता है।
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किसी समांतर श्रेणी में पहला पद (31), अंतिम पद (13) और पदों की संख्या (7) है। योग कितना होगा?
In an arithmetic progression, the first term is (31), the last term is (13), and the number of terms is (7). What is the sum?
#first_last
#decreasing_ap
#ap_sum
A (144)
B (154)
C (164)
D (174)
Explanation opens after your attempt
Step 1
Concept
(S_7=\frac{7}{2}(31+13)=154). The first term can be larger and the last term smaller.
Step 2
Why this answer is correct
The correct answer is B. (154). (S_7=\frac{7}{2}(31+13)=154). The first term can be larger and the last term smaller.
Step 3
Exam Tip
(S_7=\frac{7}{2}(31+13)=154)। पहला पद बड़ा और अंतिम पद छोटा हो सकता है।
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यदि समांतर श्रेणी का पहला पद (11), अंतिम पद (71) और पदों की संख्या (16) है, तो योग कितना होगा?
If the first term of an arithmetic progression is (11), the last term is (71), and the number of terms is (16), what is the sum?
#first_last
#ap_sum
#formula
A (636)
B (646)
C (656)
D (666)
Explanation opens after your attempt
Step 1
Concept
(S_{16}=\frac{16}{2}(11+71)=656). If the first and last terms are given, use the shorter formula.
Step 2
Why this answer is correct
The correct answer is C. (656). (S_{16}=\frac{16}{2}(11+71)=656). If the first and last terms are given, use the shorter formula.
Step 3
Exam Tip
(S_{16}=\frac{16}{2}(11+71)=656)। पहला और अंतिम पद मिले हों तो छोटा सूत्र लगाएँ।
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यदि किसी समांतर श्रेणी का पहला पद (8), अंतिम पद (62) और कुल पद (10) हैं, तो योग क्या होगा?
If the first term of an arithmetic progression is (8), the last term is (62), and there are (10) terms, what is the sum?
#first_last
#ap_sum
#formula
A (330)
B (340)
C (350)
D (360)
Explanation opens after your attempt
Step 1
Concept
Using (S_n=\frac{n}{2}(a+l)), \(S_{10}=350\). If the last term is given, finding (d) is not needed.
Step 2
Why this answer is correct
The correct answer is C. (350). Using (S_n=\frac{n}{2}(a+l)), \(S_{10}=350\). If the last term is given, finding (d) is not needed.
Step 3
Exam Tip
(S_n=\frac{n}{2}(a+l)) से \(S_{10}=350\)। अंतिम पद दिया हो तो (d) निकालने की जरूरत नहीं होती।
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समांतर श्रेढ़ी का पहला पद (15), अंतिम पद (51) और पदों की संख्या (13) है। योग ज्ञात कीजिए।
The first term of an arithmetic progression is (15), the last term is (51), and the number of terms is (13). Find the sum.
#first_last
#ap_sum
#class10
A (419)
B (429)
C (439)
D (449)
Explanation opens after your attempt
Step 1
Concept
(S_{13}=\frac{13}{2}(15+51)=429). You can also get the sum using the average of the first and last terms.
Step 2
Why this answer is correct
The correct answer is B. (429). (S_{13}=\frac{13}{2}(15+51)=429). You can also get the sum using the average of the first and last terms.
Step 3
Exam Tip
(S_{13}=\frac{13}{2}(15+51)=429)। पहले और अंतिम पद का औसत लेकर भी योग मिल जाता है।
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एक समान्तर श्रेणी के पहले (12) पदों का योग (516) है और (12)वाँ पद (75) है। प्रथम पद क्या है?
The sum of the first (12) terms of an arithmetic progression is (516) and the (12)th term is (75). What is the first term?
#ap
#last-term
#sum
#expert
A (7)
B (9)
C (11)
D (13)
Explanation opens after your attempt
Step 1
Concept
Using (S_n=\frac{n}{2}(a+l)), (516=6(a+75)), so (a=11). Exam tip: when the last term is given, use the (a+l) form.
Step 2
Why this answer is correct
The correct answer is C. (11). Using (S_n=\frac{n}{2}(a+l)), (516=6(a+75)), so (a=11). Exam tip: when the last term is given, use the (a+l) form.
Step 3
Exam Tip
सूत्र (S_n=\frac{n}{2}(a+l)) से (516=6(a+75)) इसलिए (a=11)। परीक्षा में अंतिम पद दिया हो तो (a+l) वाला सूत्र तेज होता है।
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यदि किसी समांतर श्रेढ़ी का \(S_n=8n^2-3n\) है, तो (51)वें पद से (70)वें पद तक का योग ज्ञात कीजिए।
If the sum of an AP is \(S_n=8n^2-3n\), find the sum from the (51)st term to the (70)th term.
#given sn
#range sum
#ap
A (18820)
B (18980)
C (19300)
D (19140)
Explanation opens after your attempt
Correct Answer
D. (19140)
Step 1
Concept
The required sum is \(S_{70}-S_{50}=19140\). When \(S_n\) is given, find a range sum directly by subtraction.
Step 2
Why this answer is correct
The correct answer is D. (19140). The required sum is \(S_{70}-S_{50}=19140\). When \(S_n\) is given, find a range sum directly by subtraction.
Step 3
Exam Tip
आवश्यक योग \(S_{70}-S_{50}=19140\) है। \(S_n\) दिए होने पर सीमा-योग सीधे घटाव से निकालें।
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यदि किसी समांतर श्रेढ़ी का \(S_n=6n^2+n\) है, तो (31)वें पद से (45)वें पद तक का योग ज्ञात कीजिए।
If the sum of an AP is \(S_n=6n^2+n\), find the sum from the (31)st term to the (45)th term.
#given sn
#range sum
#ap
A (6645)
B (6685)
C (6725)
D (6765)
Explanation opens after your attempt
Step 1
Concept
The required sum is \(S_{45}-S_{30}=6765\). When \(S_n\) is given, find a range sum directly by subtraction.
Step 2
Why this answer is correct
The correct answer is D. (6765). The required sum is \(S_{45}-S_{30}=6765\). When \(S_n\) is given, find a range sum directly by subtraction.
Step 3
Exam Tip
आवश्यक योग \(S_{45}-S_{30}=6765\) है। \(S_n\) दिए होने पर range sum सीधे घटाव से निकालें।
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यदि किसी समांतर श्रेढ़ी का \(S_n=7n^2-4n\) है, तो (21)वें पद से (30)वें पद तक का योग ज्ञात कीजिए।
If the sum of an AP is \(S_n=7n^2-4n\), find the sum from the (21)st term to the (30)th term.
#given sn
#range sum
#ap
A (3460)
B (3360)
C (3560)
D (3660)
Explanation opens after your attempt
Step 1
Concept
The required sum is \(S_{30}-S_{20}=3460\). When \(S_n\) is given, find a range sum directly by subtraction.
Step 2
Why this answer is correct
The correct answer is A. (3460). The required sum is \(S_{30}-S_{20}=3460\). When \(S_n\) is given, find a range sum directly by subtraction.
Step 3
Exam Tip
आवश्यक योग \(S_{30}-S_{20}=3460\) है। \(S_n\) दिए होने पर range sum सीधे घटाव से निकालें।
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किसी समांतर श्रेढ़ी के पहले (7) पदों का योग (140) है और पहला पद (5) है। यदि अंतिम पद पूछा जाए तो योग सूत्र से (l) क्या होगा?
The sum of the first (7) terms of an arithmetic progression is (140), and the first term is (5). Using the sum formula, what is the last term (l)?
#ap_sum
#reverse_formula
#last_term
A (30)
B (35)
C (40)
D (45)
Explanation opens after your attempt
Step 1
Concept
From (140=\frac{7}{2}(5+l)), (l=35). Learn to use the sum formula in reverse too.
Step 2
Why this answer is correct
The correct answer is B. (35). From (140=\frac{7}{2}(5+l)), (l=35). Learn to use the sum formula in reverse too.
Step 3
Exam Tip
(140=\frac{7}{2}(5+l)) से (l=35)। योग सूत्र को उल्टा लगाना भी सीखें।
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यदि किसी समांतर श्रेढ़ी के पहले (n) पदों का योग \(S_n=4n^2-3n\) है, तो (12)वें पद से (20)वें पद तक का योग ज्ञात कीजिए।
If the sum of the first (n) terms of an AP is \(S_n=4n^2-3n\), find the sum from the (12)th term to the (20)th term.
#given sn
#range sum
#ap
A (1065)
B (1077)
C (1101)
D (1089)
Explanation opens after your attempt
Step 1
Concept
The sum is \(S_{20}-S_{11}=1089\). When starting from the (12)th term, subtract the sum up to (11) terms.
Step 2
Why this answer is correct
The correct answer is D. (1089). The sum is \(S_{20}-S_{11}=1089\). When starting from the (12)th term, subtract the sum up to (11) terms.
Step 3
Exam Tip
योग \(S_{20}-S_{11}=1089\) होगा। (12)वें से शुरू होने पर (11) पदों तक का योग घटाना होता है।
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किसी समांतर श्रेणी में पहले और अंतिम पद का योग (144) है और कुल पद (18) हैं। श्रेणी का योग कितना होगा?
In an arithmetic progression, the sum of the first and last terms is (144), and there are (18) terms. What will be the sum of the progression?
#first_last_sum
#ap_sum
#formula
A (1276)
B (1286)
C (1296)
D (1306)
Explanation opens after your attempt
Step 1
Concept
Using (S_n=\frac{n}{2}(a+l)), \(S_{18}=\frac{18}{2}\times144=1296\). If (a+l) is directly given, use it immediately.
Step 2
Why this answer is correct
The correct answer is C. (1296). Using (S_n=\frac{n}{2}(a+l)), \(S_{18}=\frac{18}{2}\times144=1296\). If (a+l) is directly given, use it immediately.
Step 3
Exam Tip
(S_n=\frac{n}{2}(a+l)) से \(S_{18}=\frac{18}{2}\times144=1296\)। (a+l) सीधे दिया हो तो उसे तुरंत उपयोग करें।
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समांतर श्रेढ़ी \(4,11,18,\ldots\) में (25)वें पद से (60)वें पद तक का योग क्या होगा?
In the AP \(4,11,18,\ldots\), what is the sum from the (25)th term to the (60)th term?
#range sum
#partial sum
#ap
A (10602)
B (10542)
C (10662)
D (10722)
Explanation opens after your attempt
Correct Answer
A. (10602)
Step 1
Concept
The required sum is \(S_{60}-S_{24}=10602\). For a middle range, subtract the sum up to the term just before it.
Step 2
Why this answer is correct
The correct answer is A. (10602). The required sum is \(S_{60}-S_{24}=10602\). For a middle range, subtract the sum up to the term just before it.
Step 3
Exam Tip
आवश्यक योग \(S_{60}-S_{24}=10602\) है। बीच के पदों का योग निकालते समय ठीक पिछले पद तक का योग घटाएँ।
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समांतर श्रेढ़ी \(25,33,41,\ldots\) में (40)वें पद से (70)वें पद तक का योग ज्ञात कीजिए।
In the AP \(25,33,41,\ldots\), find the sum from the (40)th term to the (70)th term.
#range sum
#partial sum
#ap
A (14043)
B (14167)
C (14291)
D (14415)
Explanation opens after your attempt
Correct Answer
B. (14167)
Step 1
Concept
The required sum is \(S_{70}-S_{39}=14167\). Do not forget to subtract the sum just before the given range.
Step 2
Why this answer is correct
The correct answer is B. (14167). The required sum is \(S_{70}-S_{39}=14167\). Do not forget to subtract the sum just before the given range.
Step 3
Exam Tip
आवश्यक योग \(S_{70}-S_{39}=14167\) है। दी गई सीमा से ठीक पहले तक का योग घटाना न भूलें।
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यदि किसी समांतर श्रेढ़ी में \(S_{22}=1474\) और \(S_{11}=407\), तो (12)वें पद से (22)वें पद तक का योग क्या होगा?
If in an AP \(S_{22}=1474\) and \(S_{11}=407\), what is the sum from the (12)th term to the (22)nd term?
#partial sum difference
#range sum
#ap
A (1056)
B (1078)
C (1067)
D (1089)
Explanation opens after your attempt
Step 1
Concept
The required sum is \(S_{22}-S_{11}=1067\). The sum of consecutive terms is found by subtracting partial sums.
Step 2
Why this answer is correct
The correct answer is C. (1067). The required sum is \(S_{22}-S_{11}=1067\). The sum of consecutive terms is found by subtracting partial sums.
Step 3
Exam Tip
आवश्यक योग \(S_{22}-S_{11}=1067\) है। लगातार पदों का योग आंशिक योगों के अंतर से मिलता है।
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समांतर श्रेढ़ी \(8,14,20,\ldots\) में (18)वें पद से (36)वें पद तक का योग क्या होगा?
In the AP \(8,14,20,\ldots\), what is the sum from the (18)th term to the (36)th term?
#range sum
#partial sum
#ap
A (3116)
B (3098)
C (3134)
D (3152)
Explanation opens after your attempt
Step 1
Concept
The required sum is \(S_{36}-S_{17}=3116\). To find a middle block sum, subtract the previous partial sum.
Step 2
Why this answer is correct
The correct answer is A. (3116). The required sum is \(S_{36}-S_{17}=3116\). To find a middle block sum, subtract the previous partial sum.
Step 3
Exam Tip
आवश्यक योग \(S_{36}-S_{17}=3116\) है। बीच के पदों का योग निकालने के लिए पिछले आंशिक योग को घटाएँ।
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समांतर श्रेढ़ी \(18,25,32,\ldots\) में (30)वें पद से (55)वें पद तक का योग ज्ञात कीजिए।
In the AP \(18,25,32,\ldots\), find the sum from the (30)th term to the (55)th term.
#range sum
#partial sum
#ap
A (8021)
B (7943)
C (8099)
D (8177)
Explanation opens after your attempt
Step 1
Concept
The required sum is \(S_{55}-S_{29}=8021\). Do not forget to subtract the sum just before the given range.
Step 2
Why this answer is correct
The correct answer is A. (8021). The required sum is \(S_{55}-S_{29}=8021\). Do not forget to subtract the sum just before the given range.
Step 3
Exam Tip
आवश्यक योग \(S_{55}-S_{29}=8021\) है। दी गई सीमा से ठीक पहले तक का योग घटाना न भूलें।
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यदि किसी समांतर श्रेढ़ी में \(S_{18}=810\) और \(S_9=270\), तो (10)वें पद से (18)वें पद तक का योग क्या होगा?
If in an AP \(S_{18}=810\) and \(S_9=270\), what is the sum from the (10)th term to the (18)th term?
#partial sum difference
#range sum
#ap
A (510)
B (520)
C (530)
D (540)
Explanation opens after your attempt
Step 1
Concept
The required sum is \(S_{18}-S_9=540\). The sum of consecutive terms is found by subtracting partial sums.
Step 2
Why this answer is correct
The correct answer is D. (540). The required sum is \(S_{18}-S_9=540\). The sum of consecutive terms is found by subtracting partial sums.
Step 3
Exam Tip
आवश्यक योग \(S_{18}-S_9=540\) है। लगातार पदों का योग आंशिक योगों के अंतर से मिलता है।
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समांतर श्रेढ़ी \(3,10,17,\ldots\) में (15)वें पद से (32)वें पद तक का योग क्या होगा?
In the AP \(3,10,17,\ldots\), what is the sum from the (15)th term to the (32)nd term?
#range sum
#partial sum
#ap
A (2862)
B (2889)
C (2916)
D (2943)
Explanation opens after your attempt
Step 1
Concept
The required sum is \(S_{32}-S_{14}=2889\). To find a middle block sum, subtract the previous partial sum.
Step 2
Why this answer is correct
The correct answer is B. (2889). The required sum is \(S_{32}-S_{14}=2889\). To find a middle block sum, subtract the previous partial sum.
Step 3
Exam Tip
मांगा गया योग \(S_{32}-S_{14}=2889\) है। बीच के पदों का योग निकालने के लिए पिछले आंशिक योग को घटाएँ।
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समांतर श्रेढ़ी \(12,17,22,\ldots\) में (21)वें पद से (40)वें पद तक का योग ज्ञात कीजिए।
In the AP \(12,17,22,\ldots\), find the sum from the (21)st term to the (40)th term.
#range sum
#partial sum
#ap
A (3190)
B (3150)
C (3230)
D (3270)
Explanation opens after your attempt
Step 1
Concept
The required sum is \(S_{40}-S_{20}=3190\). Do not forget to subtract the sum just before the given range.
Step 2
Why this answer is correct
The correct answer is A. (3190). The required sum is \(S_{40}-S_{20}=3190\). Do not forget to subtract the sum just before the given range.
Step 3
Exam Tip
आवश्यक योग \(S_{40}-S_{20}=3190\) है। दी गई सीमा से ठीक पहले तक का योग घटाना न भूलें।
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समांतर श्रेढ़ी \(6,10,14,\ldots\) में (4)वें पद से (25)वें पद तक का योग कितना है?
In the AP \(6,10,14,\ldots\), what is the sum from the (4)th term to the (25)th term?
#range sum
#ap
#partial sum
A (1296)
B (1320)
C (1344)
D (1368)
Explanation opens after your attempt
Step 1
Concept
This sum is \(S_{25}-S_3=1320\). When starting from the (4)th term, subtract the sum of the first (3) terms.
Step 2
Why this answer is correct
The correct answer is B. (1320). This sum is \(S_{25}-S_3=1320\). When starting from the (4)th term, subtract the sum of the first (3) terms.
Step 3
Exam Tip
यह योग \(S_{25}-S_3=1320\) है। (4)वें पद से शुरू होने पर पहले (3) पदों का योग घटाएँ।
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एक समान्तर श्रेणी का प्रथम पद (19) है और \(S_{15}=810\) है। (15)वाँ पद क्या होगा?
The first term of an arithmetic progression is (19) and \(S_{15}=810\). What is the (15)th term?
#ap
#last-term-from-sum
#expert
A (87)
B (89)
C (91)
D (93)
Explanation opens after your attempt
Step 1
Concept
From (810=\frac{15}{2}(19+l)), (l=89). Exam tip: when the last term is needed, the (a+l) form is fast.
Step 2
Why this answer is correct
The correct answer is B. (89). From (810=\frac{15}{2}(19+l)), (l=89). Exam tip: when the last term is needed, the (a+l) form is fast.
Step 3
Exam Tip
(810=\frac{15}{2}(19+l)) से (l=89) मिलता है। परीक्षा में अंतिम पद चाहिए हो तो (a+l) वाला सूत्र तेज है।
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एक समान्तर श्रेणी का (8)वाँ पद (31) और (20)वाँ पद (79) है। पहले (20) पदों का योग कितना होगा?
The (8)th term of an arithmetic progression is (31) and the (20)th term is (79). What is the sum of the first (20) terms?
#ap
#term-sum
#expert
A (900)
B (940)
C (980)
D (1020)
Explanation opens after your attempt
Step 1
Concept
From the two terms (d=4) and (a=3). Hence \(S_{20}=980\); exam tip: find (a) and (d) before applying the sum formula.
Step 2
Why this answer is correct
The correct answer is C. (980). From the two terms (d=4) and (a=3). Hence \(S_{20}=980\); exam tip: find (a) and (d) before applying the sum formula.
Step 3
Exam Tip
दो पदों से (d=4) और (a=3) मिलता है इसलिए \(S_{20}=980\)। परीक्षा में पहले (a) और (d) निकालें फिर योग लगाएं।
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समांतर श्रेढ़ी \(-40,-31,-22,\ldots\) में (25)वें पद से (60)वें पद तक का योग कितना है?
In the AP \(-40,-31,-22,\ldots\), what is the sum from the (25)th term to the (60)th term?
#range sum
#negative first term
#ap
A (11826)
B (12006)
C (12186)
D (12366)
Explanation opens after your attempt
Correct Answer
B. (12006)
Step 1
Concept
The required sum is \(S_{60}-S_{24}=12006\). When starting from the (25)th term, subtract the sum up to (24) terms.
Step 2
Why this answer is correct
The correct answer is B. (12006). The required sum is \(S_{60}-S_{24}=12006\). When starting from the (25)th term, subtract the sum up to (24) terms.
Step 3
Exam Tip
मांगा गया योग \(S_{60}-S_{24}=12006\) है। (25)वें पद से शुरू होने पर (24) पदों तक का योग घटाएँ।
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समांतर श्रेढ़ी \(-30,-22,-14,\ldots\) में (18)वें पद से (50)वें पद तक का योग कितना है?
In the AP \(-30,-22,-14,\ldots\), what is the sum from the (18)th term to the (50)th term?
#range sum
#negative first term
#ap
A (7656)
B (7788)
C (7722)
D (7854)
Explanation opens after your attempt
Step 1
Concept
The required sum is \(S_{50}-S_{17}=7722\). When starting from the (18)th term, subtract the sum up to (17) terms.
Step 2
Why this answer is correct
The correct answer is C. (7722). The required sum is \(S_{50}-S_{17}=7722\). When starting from the (18)th term, subtract the sum up to (17) terms.
Step 3
Exam Tip
मांगा गया योग \(S_{50}-S_{17}=7722\) है। (18)वें पद से शुरू होने पर (17) पदों तक का योग घटाएँ।
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समांतर श्रेढ़ी \(-4,2,8,\ldots\) में (20)वें पद से (45)वें पद तक का योग कितना है?
In the AP \(-4,2,8,\ldots\), what is the sum from the (20)th term to the (45)th term?
#range sum
#negative first term
#ap
A (4720)
B (4810)
C (4900)
D (4990)
Explanation opens after your attempt
Step 1
Concept
The required sum is \(S_{45}-S_{19}=4810\). When starting from the (20)th term, subtract the sum up to (19) terms.
Step 2
Why this answer is correct
The correct answer is B. (4810). The required sum is \(S_{45}-S_{19}=4810\). When starting from the (20)th term, subtract the sum up to (19) terms.
Step 3
Exam Tip
मांगा गया योग \(S_{45}-S_{19}=4810\) है। (20)वें पद से शुरू होने पर (19) पदों तक का योग घटाएँ।
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यदि किसी समांतर श्रेणी के पहले (9) पदों का योग (279) और पहला पद (7) है, तो अंतिम पद कितना होगा?
If the sum of the first (9) terms of an arithmetic progression is (279), and the first term is (7), what is the last term?
#reverse_formula
#last_term
#ap_sum
A (49)
B (51)
C (53)
D (55)
Explanation opens after your attempt
Step 1
Concept
From (279=\frac{9}{2}(7+l)), (l=55). Clear the fraction and solve the equation.
Step 2
Why this answer is correct
The correct answer is D. (55). From (279=\frac{9}{2}(7+l)), (l=55). Clear the fraction and solve the equation.
Step 3
Exam Tip
(279=\frac{9}{2}(7+l)) से (l=55)। भिन्न हटाकर समीकरण हल करें।
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एक समान्तर श्रेणी का (6)वाँ पद (29) और (19)वाँ पद (94) है। पहले (19) पदों का योग कितना होगा?
The (6)th term of an arithmetic progression is (29) and the (19)th term is (94). What is the sum of the first (19) terms?
#ap
#two-terms-sum
#expert
A (931)
B (950)
C (969)
D (988)
Explanation opens after your attempt
Step 1
Concept
The two terms give (d=5) and (a=4), so \(S_{19}=931\). Exam tip: find (a) and (d) first.
Step 2
Why this answer is correct
The correct answer is A. (931). The two terms give (d=5) and (a=4), so \(S_{19}=931\). Exam tip: find (a) and (d) first.
Step 3
Exam Tip
दो पदों से (d=5) और (a=4) मिलता है इसलिए \(S_{19}=931\)। परीक्षा में पहले (a) और (d) निकालें।
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एक समान्तर श्रेणी का (9)वाँ पद (46) और (21)वाँ पद (106) है। पहले (21) पदों का योग कितना होगा?
The (9)th term of an arithmetic progression is (46) and the (21)th term is (106). What is the sum of the first (21) terms?
#ap
#two-terms-sum
#expert
A (1176)
B (1188)
C (1197)
D (1218)
Explanation opens after your attempt
Step 1
Concept
The two terms give (d=5) and (a=6), so \(S_{21}=1176\). Exam tip: find (a) and (d) first.
Step 2
Why this answer is correct
The correct answer is A. (1176). The two terms give (d=5) and (a=6), so \(S_{21}=1176\). Exam tip: find (a) and (d) first.
Step 3
Exam Tip
दो पदों से (d=5) और (a=6) मिलता है इसलिए \(S_{21}=1176\)। परीक्षा में पहले (a) और (d) निकालें।
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एक समान्तर श्रेणी का (7)वाँ पद (34) और (18)वाँ पद (89) है। पहले (18) पदों का योग कितना होगा?
The (7)th term of an arithmetic progression is (34) and the (18)th term is (89). What is the sum of the first (18) terms?
#ap
#two-terms-sum
#expert
A (801)
B (819)
C (828)
D (837)
Explanation opens after your attempt
Step 1
Concept
The two terms give (d=5) and (a=4), so \(S_{18}=837\). Exam tip: find (a) and (d) first.
Step 2
Why this answer is correct
The correct answer is D. (837). The two terms give (d=5) and (a=4), so \(S_{18}=837\). Exam tip: find (a) and (d) first.
Step 3
Exam Tip
दो पदों से (d=5) और (a=4) मिलता है इसलिए \(S_{18}=837\)। परीक्षा में पहले (a) और (d) निकालें।
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एक समान्तर श्रेणी का (5)वाँ पद (22) और (15)वाँ पद (62) है। पहले (15) पदों का योग कितना है?
The (5)th term of an arithmetic progression is (22) and the (15)th term is (62). What is the sum of the first (15) terms?
#ap
#two-terms-sum
#expert
A (510)
B (525)
C (540)
D (555)
Explanation opens after your attempt
Step 1
Concept
The two terms give (d=4) and (a=6), so \(S_{15}=510\). Exam tip: first find (d) from the difference of two given terms.
Step 2
Why this answer is correct
The correct answer is A. (510). The two terms give (d=4) and (a=6), so \(S_{15}=510\). Exam tip: first find (d) from the difference of two given terms.
Step 3
Exam Tip
इन पदों से (d=4) और (a=6) मिलता है इसलिए \(S_{15}=510\)। परीक्षा में दो पदों का अंतर लेकर पहले (d) निकालें।
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किसी समांतर श्रेढ़ी का (12)वाँ पद (64) और (32)वाँ पद (184) है। पहले (45) पदों का योग ज्ञात कीजिए।
The (12)th term of an AP is (64), and the (32)nd term is (184). Find the sum of the first (45) terms.
#given terms
#find sum
#ap
A (5850)
B (5760)
C (5940)
D (6030)
Explanation opens after your attempt
Step 1
Concept
From the two terms, (d=6) and (a=-2), so \(S_{45}=5850\). First find (a,d), then apply the sum formula.
Step 2
Why this answer is correct
The correct answer is A. (5850). From the two terms, (d=6) and (a=-2), so \(S_{45}=5850\). First find (a,d), then apply the sum formula.
Step 3
Exam Tip
दो पदों से (d=6) और (a=-2) मिलते हैं, इसलिए \(S_{45}=5850\) है। पहले (a,d) निकालकर योग सूत्र लगाएँ।
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यदि \(S_n=4n^2+3n\), तो (61)वें पद से (90)वें पद तक का योग ज्ञात कीजिए।
If \(S_n=4n^2+3n\), find the sum from the (61)st term to the (90)th term.
#given sn
#range sum
#expert
A (18090)
B (17970)
C (18210)
D (18330)
Explanation opens after your attempt
Correct Answer
A. (18090)
Step 1
Concept
The required sum is \(S_{90}-S_{60}=18090\). With given \(S_n\), subtract directly according to the limits.
Step 2
Why this answer is correct
The correct answer is A. (18090). The required sum is \(S_{90}-S_{60}=18090\). With given \(S_n\), subtract directly according to the limits.
Step 3
Exam Tip
आवश्यक योग \(S_{90}-S_{60}=18090\) है। दिए गए \(S_n\) में सीमाओं के अनुसार सीधे घटाव करें।
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किसी समांतर श्रेढ़ी में \(S_{10}=310\) और \(S_{20}=920\) है। (21)वें पद से (30)वें पद तक का योग ज्ञात कीजिए।
In an AP, \(S_{10}=310\) and \(S_{20}=920\). Find the sum from the (21)st term to the (30)th term.
#two sums
#range sum
#ap
A (880)
B (910)
C (940)
D (970)
Explanation opens after your attempt
Step 1
Concept
The given sums determine the AP, and \(S_{30}-S_{20}=910\). Before finding a later block sum, determine (a,d).
Step 2
Why this answer is correct
The correct answer is B. (910). The given sums determine the AP, and \(S_{30}-S_{20}=910\). Before finding a later block sum, determine (a,d).
Step 3
Exam Tip
दिए गए योगों से AP मिलती है और \(S_{30}-S_{20}=910\) होता है। आगे के खंड का योग निकालने से पहले (a,d) तय करें।
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यदि \(S_n=3n^2+2n\), तो (51)वें पद से (80)वें पद तक का योग ज्ञात कीजिए।
If \(S_n=3n^2+2n\), find the sum from the (51)st term to the (80)th term.
#given sn
#range sum
#expert
A (11640)
B (11760)
C (11880)
D (12000)
Explanation opens after your attempt
Correct Answer
B. (11760)
Step 1
Concept
The required sum is \(S_{80}-S_{50}=11760\). When \(S_n\) is given, find a range sum directly by subtraction.
Step 2
Why this answer is correct
The correct answer is B. (11760). The required sum is \(S_{80}-S_{50}=11760\). When \(S_n\) is given, find a range sum directly by subtraction.
Step 3
Exam Tip
आवश्यक योग \(S_{80}-S_{50}=11760\) है। \(S_n\) दिया हो तो सीमा-योग सीधे घटाव से निकालें।
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किसी समांतर श्रेढ़ी में (a=7) है और (21)वें पद से (40)वें पद तक का योग (3680) है। (d) ज्ञात कीजिए।
In an AP, (a=7), and the sum from the (21)st term to the (40)th term is (3680). Find (d).
#find d
#middle sum
#ap
A (6)
B (5)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
Putting \(S_{40}-S_{20}=3680\) gives (d=6). Convert the middle sum into a difference of partial sums.
Step 2
Why this answer is correct
The correct answer is A. (6). Putting \(S_{40}-S_{20}=3680\) gives (d=6). Convert the middle sum into a difference of partial sums.
Step 3
Exam Tip
\(S_{40}-S_{20}=3680\) रखने पर (d=6) मिलता है। बीच के योग को आंशिक योगों के अंतर में बदलें।
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किसी समांतर श्रेढ़ी का (16)वाँ पद (73) और (36)वाँ पद (153) है। पहले (60) पदों का योग ज्ञात कीजिए।
The (16)th term of an AP is (73), and the (36)th term is (153). Find the sum of the first (60) terms.
#two terms
#find sum
#ap
A (7740)
B (7800)
C (7920)
D (7860)
Explanation opens after your attempt
Step 1
Concept
The two terms give (d=4) and (a=13), so \(S_{60}=7860\). Finding the common difference from distant terms is the first step.
Step 2
Why this answer is correct
The correct answer is D. (7860). The two terms give (d=4) and (a=13), so \(S_{60}=7860\). Finding the common difference from distant terms is the first step.
Step 3
Exam Tip
दो पदों से (d=4) और (a=13) मिलते हैं, इसलिए \(S_{60}=7860\) है। दूर के पदों से सार्व अंतर निकालना पहला कदम है।
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यदि (S_n=n(6n-1)), तो (31)वें पद से (50)वें पद तक का योग ज्ञात कीजिए।
If (S_n=n(6n-1)), find the sum from the (31)st term to the (50)th term.
#given sn
#range sum
#hard
A (9460)
B (9520)
C (9640)
D (9580)
Explanation opens after your attempt
Step 1
Concept
The required sum is \(S_{50}-S_{30}=9580\). When starting from the (31)st term, subtract the sum up to (30).
Step 2
Why this answer is correct
The correct answer is D. (9580). The required sum is \(S_{50}-S_{30}=9580\). When starting from the (31)st term, subtract the sum up to (30).
Step 3
Exam Tip
आवश्यक योग \(S_{50}-S_{30}=9580\) है। (31)वें पद से शुरू होने पर (30) तक का योग घटाएँ।
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किसी समांतर श्रेढ़ी का (9)वाँ पद (49) और (24)वाँ पद (124) है। पहले (35) पदों का योग ज्ञात कीजिए।
The (9)th term of an AP is (49), and the (24)th term is (124). Find the sum of the first (35) terms.
#given terms
#find sum
#ap
A (3220)
B (3255)
C (3290)
D (3325)
Explanation opens after your attempt
Step 1
Concept
From the two terms, (d=5) and (a=9), so \(S_{35}=3290\). First find (a,d), then apply the sum formula.
Step 2
Why this answer is correct
The correct answer is C. (3290). From the two terms, (d=5) and (a=9), so \(S_{35}=3290\). First find (a,d), then apply the sum formula.
Step 3
Exam Tip
दो पदों से (d=5) और (a=9) मिलते हैं, इसलिए \(S_{35}=3290\) है। पहले (a,d) निकालकर योग सूत्र लगाएँ।
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यदि \(S_n=7n^2-2n\), तो (41)वें पद से (60)वें पद तक का योग ज्ञात कीजिए।
If \(S_n=7n^2-2n\), find the sum from the (41)st term to the (60)th term.
#given sn
#range sum
#hard
A (13960)
B (13820)
C (14100)
D (14240)
Explanation opens after your attempt
Correct Answer
A. (13960)
Step 1
Concept
The required sum is \(S_{60}-S_{40}=13960\). With given \(S_n\), subtract directly according to the limits.
Step 2
Why this answer is correct
The correct answer is A. (13960). The required sum is \(S_{60}-S_{40}=13960\). With given \(S_n\), subtract directly according to the limits.
Step 3
Exam Tip
आवश्यक योग \(S_{60}-S_{40}=13960\) है। दिए गए \(S_n\) में सीमाओं के अनुसार सीधे घटाव करें।
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यदि \(S_n=6n^2-5n\), तो (31)वें पद से (50)वें पद तक का योग ज्ञात कीजिए।
If \(S_n=6n^2-5n\), find the sum from the (31)st term to the (50)th term.
#given sn
#range sum
#ap
A (9400)
B (9500)
C (9600)
D (9700)
Explanation opens after your attempt
Step 1
Concept
The required sum is \(S_{50}-S_{30}=9500\). When starting from the (31)st term, subtract the sum up to (30).
Step 2
Why this answer is correct
The correct answer is B. (9500). The required sum is \(S_{50}-S_{30}=9500\). When starting from the (31)st term, subtract the sum up to (30).
Step 3
Exam Tip
आवश्यक योग \(S_{50}-S_{30}=9500\) है। (31)वें पद से शुरू होने पर (30) तक का योग घटाएँ।
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किसी समांतर श्रेढ़ी में (a=5) है और (16)वें पद से (30)वें पद तक का योग (1395) है। (d) ज्ञात कीजिए।
In an AP, (a=5), and the sum from the (16)th term to the (30)th term is (1395). Find (d).
#find d
#middle sum
#ap
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
Putting \(S_{30}-S_{15}=1395\) gives (d=4). Convert the middle sum into a difference of partial sums.
Step 2
Why this answer is correct
The correct answer is C. (4). Putting \(S_{30}-S_{15}=1395\) gives (d=4). Convert the middle sum into a difference of partial sums.
Step 3
Exam Tip
\(S_{30}-S_{15}=1395\) रखने पर (d=4) मिलता है। बीच के योग को आंशिक योगों के अंतर में बदलें।
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किसी समांतर श्रेढ़ी का (14)वाँ पद (52) और (31)वाँ पद (120) है। पहले (40) पदों का योग ज्ञात कीजिए।
The (14)th term of an AP is (52), and the (31)st term is (120). Find the sum of the first (40) terms.
#two terms
#find sum
#ap
A (3000)
B (3040)
C (3080)
D (3120)
Explanation opens after your attempt
Step 1
Concept
The two terms give (d=4) and (a=0), so \(S_{40}=3120\). Finding the common difference from distant terms is the first step.
Step 2
Why this answer is correct
The correct answer is D. (3120). The two terms give (d=4) and (a=0), so \(S_{40}=3120\). Finding the common difference from distant terms is the first step.
Step 3
Exam Tip
दो पदों से (d=4) और (a=0) मिलते हैं, इसलिए \(S_{40}=3120\) है। दूर के पदों से सार्व अंतर निकालना पहला कदम है।
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यदि (S_n=n(4n+3)), तो (21)वें पद से (35)वें पद तक का योग ज्ञात कीजिए।
If (S_n=n(4n+3)), find the sum from the (21)st term to the (35)th term.
#given sn
#range sum
#hard
A (3255)
B (3285)
C (3315)
D (3345)
Explanation opens after your attempt
Step 1
Concept
The required sum is \(S_{35}-S_{20}=3345\). When starting from the (21)st term, subtract the sum up to (20).
Step 2
Why this answer is correct
The correct answer is D. (3345). The required sum is \(S_{35}-S_{20}=3345\). When starting from the (21)st term, subtract the sum up to (20).
Step 3
Exam Tip
आवश्यक योग \(S_{35}-S_{20}=3345\) है। (21)वें पद से शुरू होने पर (20) तक का योग घटाएँ।
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किसी समांतर श्रेढ़ी का (8)वाँ पद (37) और (22)वाँ पद (107) है। पहले (30) पदों का योग ज्ञात कीजिए।
The (8)th term of an AP is (37), and the (22)nd term is (107). Find the sum of the first (30) terms.
#given terms
#find sum
#ap
A (2190)
B (2235)
C (2280)
D (2325)
Explanation opens after your attempt
Step 1
Concept
From the two terms, (d=5) and (a=2), so \(S_{30}=2235\). First find (a,d), then apply the sum formula.
Step 2
Why this answer is correct
The correct answer is B. (2235). From the two terms, (d=5) and (a=2), so \(S_{30}=2235\). First find (a,d), then apply the sum formula.
Step 3
Exam Tip
दो पदों से (d=5) और (a=2) मिलते हैं, इसलिए \(S_{30}=2235\) है। पहले (a,d) निकालकर योग सूत्र लगाएँ।
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यदि \(S_n=4n^2+n\), तो (31)वें पद से (45)वें पद तक का योग ज्ञात कीजिए।
If \(S_n=4n^2+n\), find the sum from the (31)st term to the (45)th term.
#given sn
#range sum
#hard
A (4455)
B (4485)
C (4515)
D (4545)
Explanation opens after your attempt
Step 1
Concept
The required sum is \(S_{45}-S_{30}=4515\). With given \(S_n\), find the range sum directly by subtraction.
Step 2
Why this answer is correct
The correct answer is C. (4515). The required sum is \(S_{45}-S_{30}=4515\). With given \(S_n\), find the range sum directly by subtraction.
Step 3
Exam Tip
आवश्यक योग \(S_{45}-S_{30}=4515\) है। दिए गए \(S_n\) में range sum सीधे घटाव से निकालें।
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यदि \(S_n=5n^2-2n\), तो (26)वें पद से (40)वें पद तक का योग ज्ञात कीजिए।
If \(S_n=5n^2-2n\), find the sum from the (26)th term to the (40)th term.
#given sn
#range sum
#ap
A (4770)
B (4800)
C (4815)
D (4845)
Explanation opens after your attempt
Step 1
Concept
The required sum is \(S_{40}-S_{25}=4845\). When starting from the (26)th term, subtract the sum up to (25).
Step 2
Why this answer is correct
The correct answer is D. (4845). The required sum is \(S_{40}-S_{25}=4845\). When starting from the (26)th term, subtract the sum up to (25).
Step 3
Exam Tip
आवश्यक योग \(S_{40}-S_{25}=4845\) है। (26)वें पद से शुरू होने पर (25) तक का योग घटाएँ।
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किसी समांतर श्रेढ़ी में (a=3) है और (11)वें पद से (20)वें पद तक का योग (465) है। (d) ज्ञात कीजिए।
In an AP, (a=3), and the sum from the (11)th term to the (20)th term is (465). Find (d).
#find d
#middle sum
#ap
A (2)
B (4)
C (3)
D (5)
Explanation opens after your attempt
Step 1
Concept
Putting \(S_{20}-S_{10}=465\) gives (d=3). Convert the middle sum into a difference of partial sums.
Step 2
Why this answer is correct
The correct answer is C. (3). Putting \(S_{20}-S_{10}=465\) gives (d=3). Convert the middle sum into a difference of partial sums.
Step 3
Exam Tip
\(S_{20}-S_{10}=465\) रखने पर (d=3) मिलता है। बीच के योग को partial sums के अंतर में बदलें।
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किसी समांतर श्रेढ़ी का (12)वाँ पद (41) और (25)वाँ पद (80) है। पहले (50) पदों का योग ज्ञात कीजिए।
The (12)th term of an AP is (41), and the (25)th term is (80). Find the sum of the first (50) terms.
#two terms
#find sum
#ap
A (3975)
B (4025)
C (4125)
D (4075)
Explanation opens after your attempt
Step 1
Concept
The two terms give (d=3) and (a=8), so \(S_{50}=4075\). Finding the common difference from distant terms is the first step.
Step 2
Why this answer is correct
The correct answer is D. (4075). The two terms give (d=3) and (a=8), so \(S_{50}=4075\). Finding the common difference from distant terms is the first step.
Step 3
Exam Tip
दो पदों से (d=3) और (a=8) मिलता है, इसलिए \(S_{50}=4075\)। दूर के पदों से सार्व अंतर निकालना पहला कदम है।
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यदि (S_n=n(5n-2)), तो (16)वें पद से (25)वें पद तक का योग ज्ञात कीजिए।
If (S_n=n(5n-2)), find the sum from the (16)th term to the (25)th term.
#given sn
#range sum
#hard
A (1920)
B (1950)
C (2010)
D (1980)
Explanation opens after your attempt
Step 1
Concept
The required sum is \(S_{25}-S_{15}=1980\). When starting from the (16)th term, subtract the sum up to (15).
Step 2
Why this answer is correct
The correct answer is D. (1980). The required sum is \(S_{25}-S_{15}=1980\). When starting from the (16)th term, subtract the sum up to (15).
Step 3
Exam Tip
आवश्यक योग \(S_{25}-S_{15}=1980\) है। (16)वें पद से शुरू होने पर (15) तक का योग घटाएँ।
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किसी समांतर श्रेढ़ी का (5)वाँ पद (22) और (15)वाँ पद (62) है। पहले (20) पदों का योग ज्ञात कीजिए।
The (5)th term of an AP is (22), and the (15)th term is (62). Find the sum of the first (20) terms.
#given terms
#find sum
#ap
A (840)
B (880)
C (920)
D (960)
Explanation opens after your attempt
Step 1
Concept
From the two terms, (d=4) and (a=6), so \(S_{20}=880\). First find (a,d), then apply the sum formula.
Step 2
Why this answer is correct
The correct answer is B. (880). From the two terms, (d=4) and (a=6), so \(S_{20}=880\). First find (a,d), then apply the sum formula.
Step 3
Exam Tip
दो पदों से (d=4) और (a=6) मिलते हैं, इसलिए \(S_{20}=880\)। पहले (a,d) निकालकर योग सूत्र लगाएँ।
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यदि किसी समांतर श्रेढ़ी में \(S_{12}=420\) और \(S_6=150\), तो (7)वें पद से (12)वें पद तक का योग क्या होगा?
If in an AP \(S_{12}=420\) and \(S_6=150\), what is the sum from the (7)th term to the (12)th term?
#partial sum difference
#ap
A (270)
B (260)
C (280)
D (290)
Explanation opens after your attempt
Step 1
Concept
The required sum is \(S_{12}-S_6=270\). The sum of consecutive terms is quickly found by subtracting partial sums.
Step 2
Why this answer is correct
The correct answer is A. (270). The required sum is \(S_{12}-S_6=270\). The sum of consecutive terms is quickly found by subtracting partial sums.
Step 3
Exam Tip
आवश्यक योग \(S_{12}-S_6=270\) है। लगातार पदों का योग partial sums के अंतर से तुरंत मिलता है।
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किसी समांतर श्रेढ़ी में \(S_8=180\) और \(S_{16}=680\) है। (17)वें पद से (24)वें पद तक का योग ज्ञात कीजिए।
In an AP, \(S_8=180\) and \(S_{16}=680\). Find the sum from the (17)th term to the (24)th term.
#two partial sums
#range sum
#ap
A (760)
B (780)
C (800)
D (820)
Explanation opens after your attempt
Step 1
Concept
The given sums give (a=5), (d=5), and \(S_{24}-S_{16}=820\). First determine the AP from the two partial sums.
Step 2
Why this answer is correct
The correct answer is D. (820). The given sums give (a=5), (d=5), and \(S_{24}-S_{16}=820\). First determine the AP from the two partial sums.
Step 3
Exam Tip
दिए गए योगों से (a=5), (d=5) मिलता है और \(S_{24}-S_{16}=820\)। दो partial sums से पहले श्रेढ़ी निर्धारित करें।
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यदि \(S_n=3n^2+4n\), तो (21)वें पद से (30)वें पद तक का योग ज्ञात कीजिए।
If \(S_n=3n^2+4n\), find the sum from the (21)st term to the (30)th term.
#given sn
#range sum
#ap
A (1510)
B (1525)
C (1540)
D (1555)
Explanation opens after your attempt
Step 1
Concept
The required sum is \(S_{30}-S_{20}=1540\). If the range starts at (21), subtract the sum up to (20).
Step 2
Why this answer is correct
The correct answer is C. (1540). The required sum is \(S_{30}-S_{20}=1540\). If the range starts at (21), subtract the sum up to (20).
Step 3
Exam Tip
आवश्यक योग \(S_{30}-S_{20}=1540\) है। सीमा (21) से शुरू हो तो (20) तक का योग घटाएँ।
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समांतर श्रेढ़ी \(50,47,44,\ldots\) में (6)वें पद से (20)वें पद तक का योग क्या है?
In the AP \(50,47,44,\ldots\), what is the sum from the (6)th term to the (20)th term?
#decreasing ap
#middle terms
#partial sum
A (180)
B (195)
C (210)
D (225)
Explanation opens after your attempt
Step 1
Concept
The required sum is \(S_{20}-S_5=210\). The same partial-sum method works for a decreasing AP.
Step 2
Why this answer is correct
The correct answer is C. (210). The required sum is \(S_{20}-S_5=210\). The same partial-sum method works for a decreasing AP.
Step 3
Exam Tip
आवश्यक योग \(S_{20}-S_5=210\) है। घटती श्रेढ़ी में भी आंशिक योग का वही तरीका लागू होता है।
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समांतर श्रेढ़ी \(5,9,13,\ldots\) में (13)वें पद से (30)वें पद तक का योग क्या होगा?
In the AP \(5,9,13,\ldots\), what is the sum from the (13)th term to the (30)th term?
#middle terms
#partial sum
#ap
A (1548)
B (1566)
C (1584)
D (1602)
Explanation opens after your attempt
Step 1
Concept
The required sum is \(S_{30}-S_{12}=1566\). To find a middle block sum, subtract the previous partial sum from the larger sum.
Step 2
Why this answer is correct
The correct answer is B. (1566). The required sum is \(S_{30}-S_{12}=1566\). To find a middle block sum, subtract the previous partial sum from the larger sum.
Step 3
Exam Tip
मांगा गया योग \(S_{30}-S_{12}=1566\) है। बीच के पदों का योग निकालने के लिए बड़े योग से पहले वाला योग घटाएँ।
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समान्तर श्रेणी \(128,119,110,\ldots\) में (30) से बड़ा अंतिम पद कौन-सा है?
In the AP \(128,119,110,\ldots\), which is the last term greater than (30)?
#ap decreasing-ap greater-than nth-term
A (32)
B (34)
C (38)
D (29)
Explanation opens after your attempt
Step 1
Concept
(d=-9) and the terms go \(128,119,110,\ldots,38,29\). The last term greater than (30) is (38).
Step 2
Why this answer is correct
The correct answer is C. (38). (d=-9) and the terms go \(128,119,110,\ldots,38,29\). The last term greater than (30) is (38).
Step 3
Exam Tip
(d=-9) है और पद \(128,119,110,\ldots,38,29\) आते हैं। (30) से बड़ा अंतिम पद (38) है।
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समान्तर श्रेणी \(90,83,76,\ldots\) में (20) से बड़ा अंतिम पद कौन-सा है?
In the AP \(90,83,76,\ldots\), which is the last term greater than (20)?
#ap
#decreasing-ap
#greater-than
#nth-term
A (20)
B (21)
C (24)
D (27)
Explanation opens after your attempt
Step 1
Concept
(d=-7) and the terms go \(90,83,76,\ldots,27,20\). The last term greater than (20) is (27).
Step 2
Why this answer is correct
The correct answer is D. (27). (d=-7) and the terms go \(90,83,76,\ldots,27,20\). The last term greater than (20) is (27).
Step 3
Exam Tip
(d=-7) है और पद \(90,83,76,\ldots,27,20\) आते हैं। (20) से बड़ा अंतिम पद (27) है।
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समान्तर श्रेणी \(64,58,52,\ldots\) में (10) से बड़ा अंतिम पद कौन-सा है?
In the AP \(64,58,52,\ldots\), which is the last term greater than (10)?
#ap
#decreasing-ap
#greater-than
#nth-term
A (10)
B (12)
C (16)
D (22)
Explanation opens after your attempt
Step 1
Concept
The terms \(64,58,52,\ldots\) have (d=-6). The last term greater than (10) is (16) because the next term is (10).
Step 2
Why this answer is correct
The correct answer is C. (16). The terms \(64,58,52,\ldots\) have (d=-6). The last term greater than (10) is (16) because the next term is (10).
Step 3
Exam Tip
पद \(64,58,52,\ldots\) में (d=-6) है। (10) से बड़ा अंतिम पद (16) है क्योंकि अगला पद (10) है।
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(200) से कम (9) के धनात्मक गुणजों में अंतिम पद क्या है?
What is the last term among the positive multiples of (9) less than (200)?
#ap
#multiples
#less-than
#nth-term
A (189)
B (196)
C (198)
D (199)
Explanation opens after your attempt
Step 1
Concept
In \(9,18,27,\ldots\), (9n<200), so the greatest (n=22) and the term is (198). For multiples, take the largest integer below the limit.
Step 2
Why this answer is correct
The correct answer is C. (198). In \(9,18,27,\ldots\), (9n<200), so the greatest (n=22) and the term is (198). For multiples, take the largest integer below the limit.
Step 3
Exam Tip
\(9,18,27,\ldots\) में (9n<200), इसलिए सबसे बड़ा (n=22) और पद (198) है। गुणजों में सीमा से कम सबसे बड़ा पूर्णांक लें।
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