If the first term of an arithmetic progression is (8), the last term is (62), and there are (10) terms, what is the sum?

(350)

The governing concept is the sum of a finite arithmetic progression. When the first term a, last term l, and number of terms n are known, the efficient formula is Sₙ = n(a + l) ÷ 2. Here a = 8, l = 62, and n = 10. Substitution gives S₁₀ = 10(8 + 62) ÷ 2 = 10 × 70 ÷ 2 = 350. Thus option C is correct. There is no need to find the common difference because the first and last terms are already supplied. Options A, B, and D result from an incorrect average, an arithmetic slip, or using the wrong number of terms.

This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the sum of the first $n$ terms of an AP.