Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 31-40 of 650 questions.
A. \(\sqrt{n+1}\)
नया कर्ण (\sqrt{\(\sqrt{n}\)2+12}=\sqrt{n+1}) होता है। यह वर्गमूल सर्पिल का नियम है। / The new hypotenuse is (\sqrt{\(\sqrt{n}\)2+12}=\sqrt{n+1}). This is the rule of the square root spiral.
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What is the purpose of adding a (1) unit perpendicular in a square root spiral?
A. अगला वर्गमूल कर्ण बनानाTo make the next square root as hypotenuse
(1) इकाई लंब जोड़ने से नया समकोण त्रिभुज बनता है। उसका कर्ण अगला वर्गमूल देता है। / Adding a (1) unit perpendicular forms a new right triangle. Its hypotenuse gives the next square root.
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In a square root spiral, length \(\sqrt{2}\) is obtained from a right triangle with which two sides?
A. (1) इकाई और (1) इकाई(1) unit and (1) unit
(1) और (1) इकाई भुजाओं से कर्ण \(\sqrt{2}\) मिलता है। यह सर्पिल का पहला मुख्य चरण है। / Sides (1) and (1) units give hypotenuse \(\sqrt{2}\). This is the first main step of the spiral.
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In a square root spiral, which two sides form the right angle to make \(\sqrt{3}\)?
A. \(\sqrt{2}\) और (1)\(\sqrt{2}\) and (1)
\(\sqrt{2}\) पिछला कर्ण है और (1) इकाई नई लंब है। इनसे नया कर्ण \(\sqrt{3}\) बनता है। / \(\sqrt{2}\) is the previous hypotenuse and (1) unit is the new perpendicular. Together they form new hypotenuse \(\sqrt{3}\).
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After making \(\sqrt{4}\) in a square root spiral, which next irrational length can be obtained?
A. \(\sqrt{5}\)
\(\sqrt{4}=2\) परिमेय है। अगला कर्ण \(\sqrt{5}\) होगा, जो अपरिमेय है। / \(\sqrt{4}=2\) is rational. The next hypotenuse is \(\sqrt{5}\), which is irrational.
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In a square root spiral, a length like \(\sqrt{25}\) gives which type of number?
A. पूर्ण संख्याWhole number
\(\sqrt{25}=5\) होता है। पूर्ण वर्गों के वर्गमूल पूर्ण संख्या देते हैं। / \(\sqrt{25}=5\). Square roots of perfect squares give whole numbers.
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In a square root spiral, which hypotenuse will be formed after \(\sqrt{12}\)?
C. \(\sqrt{13}\)
नया कर्ण \(\sqrt{12+1}=\sqrt{13}\) होता है। क्रम में अगला वर्गमूल लें। / The new hypotenuse is \(\sqrt{12+1}=\sqrt{13}\). Take the next square root in sequence.
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B. \(\sqrt{17}\)
\(\sqrt{17}\) के साथ (1) इकाई लंब से \(\sqrt{18}\) बनता है। पिछली संख्या हमेशा (1) कम होती है। / With \(\sqrt{17}\) and a (1) unit perpendicular, \(\sqrt{18}\) is formed. The previous number is always (1) less.
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B. \(\sqrt{20}\) का कर्णHypotenuse of \(\sqrt{20}\)
जिस वर्गमूल को संख्या रेखा पर रखना है, उसी कर्ण की लंबाई कंपास में ली जाती है। / The hypotenuse length of the required square root is taken in the compass to place it on the number line.
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Which statement is incorrect for a square root spiral?
D. हर कर्ण हमेशा पूर्ण संख्या होता हैEvery hypotenuse is always a whole number
\(\sqrt{2},\sqrt{3},\sqrt{5}\) जैसे कई कर्ण पूर्ण संख्या नहीं होते। इसलिए यह कथन गलत है। / Many hypotenuses like \(\sqrt{2},\sqrt{3},\sqrt{5}\) are not whole numbers. So this statement is incorrect.
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