Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 21-30 of 650 questions.
In a square root spiral, \(\sqrt{5}\) is an example of which type of number?
B. अपरिमेय संख्याIrrational number
\(\sqrt{5}\) पूर्ण वर्ग का वर्गमूल नहीं है। इसलिए यह अपरिमेय संख्या है। / \(\sqrt{5}\) is not the square root of a perfect square. Therefore it is irrational.
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In a square root spiral, the length \(\sqrt{16}\) will be equal to which number?
C. (4)
\(\sqrt{16}=4\) होता है। पूर्ण वर्गों के वर्गमूल परिमेय और पूर्ण संख्या होते हैं। / \(\sqrt{16}=4\). Square roots of perfect squares are rational and whole numbers.
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To make \(\sqrt{11}\) in a square root spiral, what should be the previous hypotenuse length?
B. \(\sqrt{10}\)
\(\sqrt{10}\) के साथ (1) इकाई लंब जोड़ने पर \(\sqrt{11}\) बनता है। क्रमिक निर्माण याद रखें। / Adding a (1) unit perpendicular to \(\sqrt{10}\) forms \(\sqrt{11}\). Remember the stepwise construction.
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A. कंपासCompass
कंपास से कर्ण की लंबाई लेकर संख्या रेखा पर चाप लगाया जाता है। यही ज्यामितीय निर्माण है। / With a compass, the hypotenuse length is taken and an arc is drawn on the number line. This is the geometric construction.
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What is the reason for \(\sqrt{2}\) becoming \(\sqrt{3}\) in a square root spiral?
A. (\(\sqrt{2}\)2+12=3)
पाइथागोरस प्रमेय से नया कर्ण \(\sqrt{2+1}=\sqrt{3}\) बनता है। \(\sqrt{2}+1\) को \(\sqrt{3}\) न मानें। / By Pythagoras theorem, the new hypotenuse becomes \(\sqrt{2+1}=\sqrt{3}\). Do not treat \(\sqrt{2}+1\) as \(\sqrt{3}\).
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Which calculation is used when \(\sqrt{3}\) becomes \(\sqrt{4}\) in a square root spiral?
A. (\(\sqrt{3}\)2+12=4)
\(\sqrt{3}\) और (1) इकाई से नया कर्ण \(\sqrt{4}\) मिलता है। सही गणना वर्गों के योग से होती है। / With \(\sqrt{3}\) and (1) unit, the new hypotenuse is \(\sqrt{4}\). The correct calculation uses sum of squares.
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The lines formed in a square root spiral gradually look like which shape?
A. सर्पिलSpiral
लगातार बने समकोण त्रिभुज मुड़ते हुए सर्पिल जैसी आकृति बनाते हैं। इसलिए इसे वर्गमूल सर्पिल कहते हैं। / Successive right triangles turn around and make a spiral-like shape. Hence it is called a square root spiral.
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In a square root spiral, the length \(\sqrt{1}\) is equal to what?
B. (1)
\(\sqrt{1}=1\) होता है। यही प्रारंभिक (1) इकाई रेखाखंड है। / \(\sqrt{1}=1\). This is the initial (1) unit line segment.
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Just before making \(\sqrt{13}\) in a square root spiral, which hypotenuse should be present?
B. \(\sqrt{12}\)
\(\sqrt{12}\) में (1) इकाई लंब जोड़ने पर नया कर्ण \(\sqrt{13}\) बनता है। पिछला कर्ण एक कम संख्या का होता है। / Adding a (1) unit perpendicular to \(\sqrt{12}\) forms \(\sqrt{13}\). The previous hypotenuse has one less number.
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In a square root spiral, what will be the next hypotenuse after \(\sqrt{14}\)?
C. \(\sqrt{15}\)
हर नए चरण में संख्या (1) बढ़ती है। इसलिए \(\sqrt{14}\) के बाद \(\sqrt{15}\) आता है। / At each new step, the number increases by (1). Therefore \(\sqrt{15}\) comes after \(\sqrt{14}\).
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