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What is the reason for (\sqrt{2}) becoming (\sqrt{3}) in a square root spiral?वर्गमूल सर्पिल में (\sqrt{2}) से (\sqrt{3}) बनने का कारण कौन-सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ((\sqrt{2})^2+1^2=3)((\sqrt{2})^2+1^2=3)
By Pythagoras theorem, the new hypotenuse becomes (\sqrt{2+1}=\sqrt{3}). Do not treat (\sqrt{2}+1) as (\sqrt{3}).पाइथागोरस प्रमेय से नया कर्ण (\sqrt{2+1}=\sqrt{3}) बनता है। (\sqrt{2}+1) को (\sqrt{3}) न मानें।
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