\(\sqrt{2}\) लंबाई वाले कर्ण के सिरे पर (1) इकाई लंब खींचकर अगला कर्ण कितना बनेगा?

If a perpendicular of (1) unit is drawn at the end of the hypotenuse of length \(\sqrt{2}\), what will be the next hypotenuse?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. \(\sqrt{3}\)

Explanation

Simple Explanation

नया कर्ण (\sqrt{\(\sqrt{2}\)2+12}=\sqrt{3}) होगा। हर बार (1) इकाई लंब जुड़ता है। / The new hypotenuse is (\sqrt{\(\sqrt{2}\)2+12}=\sqrt{3}). Each time a (1) unit perpendicular is added.

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Mathematics Answer, Explanation and Revision Hints

\(\sqrt{2}\) लंबाई वाले कर्ण के सिरे पर (1) इकाई लंब खींचकर अगला कर्ण कितना बनेगा? / If a perpendicular of (1) unit is drawn at the end of the hypotenuse of length \(\sqrt{2}\), what will be the next hypotenuse?

Correct Answer: B. \(\sqrt{3}\). Explanation: नया कर्ण (\sqrt{\(\sqrt{2}\)2+12}=\sqrt{3}) होगा। हर बार (1) इकाई लंब जुड़ता है। / The new hypotenuse is (\sqrt{\(\sqrt{2}\)2+12}=\sqrt{3}). Each time a (1) unit perpendicular is added.