वर्गमूल सर्पिल में (1) इकाई आधार और (1) इकाई लंब से बने पहले समकोण त्रिभुज का कर्ण कितना होता है?

In a square root spiral, what is the hypotenuse of the first right triangle made with base (1) unit and perpendicular (1) unit?

Author: Muft Shiksha Editorial Team Published: Updated:
Explanation opens after your attempt
Correct Answer

B. \(\sqrt{2}\)

Step 1

Concept

By Pythagoras theorem, the hypotenuse is \(\sqrt{1^2+1^2}=\sqrt{2}\). Remember the first hypotenuse.

Step 2

Why this answer is correct

The correct answer is B. \(\sqrt{2}\). By Pythagoras theorem, the hypotenuse is \(\sqrt{1^2+1^2}=\sqrt{2}\). Remember the first hypotenuse.

Step 3

Exam Tip

पाइथागोरस प्रमेय से कर्ण \(\sqrt{1^2+1^2}=\sqrt{2}\) होता है। पहला कर्ण याद रखें।

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Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में (1) इकाई आधार और (1) इकाई लंब से बने पहले समकोण त्रिभुज का कर्ण कितना होता है? / In a square root spiral, what is the hypotenuse of the first right triangle made with base (1) unit and perpendicular (1) unit?

Correct Answer: B. \(\sqrt{2}\). Explanation: पाइथागोरस प्रमेय से कर्ण \(\sqrt{1^2+1^2}=\sqrt{2}\) होता है। पहला कर्ण याद रखें। / By Pythagoras theorem, the hypotenuse is \(\sqrt{1^2+1^2}=\sqrt{2}\). Remember the first hypotenuse.

Which concept should I revise for this Mathematics MCQ?

By Pythagoras theorem, the hypotenuse is \(\sqrt{1^2+1^2}=\sqrt{2}\). Remember the first hypotenuse.

What exam hint can help solve this Mathematics question?

पाइथागोरस प्रमेय से कर्ण \(\sqrt{1^2+1^2}=\sqrt{2}\) होता है। पहला कर्ण याद रखें।