वर्गमूल सर्पिल में (1) इकाई आधार और (1) इकाई लंब से बने पहले समकोण त्रिभुज का कर्ण कितना होता है?
In a square root spiral, what is the hypotenuse of the first right triangle made with base (1) unit and perpendicular (1) unit?
Explanation opens after your attempt
B. \(\sqrt{2}\)
Concept
By Pythagoras theorem, the hypotenuse is \(\sqrt{1^2+1^2}=\sqrt{2}\). Remember the first hypotenuse.
Why this answer is correct
The correct answer is B. \(\sqrt{2}\). By Pythagoras theorem, the hypotenuse is \(\sqrt{1^2+1^2}=\sqrt{2}\). Remember the first hypotenuse.
Exam Tip
पाइथागोरस प्रमेय से कर्ण \(\sqrt{1^2+1^2}=\sqrt{2}\) होता है। पहला कर्ण याद रखें।
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