वर्गमूल सर्पिल में \(\sqrt{3}\) बनाने के लिए कौन-सी दो भुजाएँ समकोण बनाती हैं?
In a square root spiral, which two sides form the right angle to make \(\sqrt{3}\)?
Explanation opens after your attempt
Correct Answer
A. \(\sqrt{2}\) और (1)\(\sqrt{2}\) and (1)
Concept
\(\sqrt{2}\) is the previous hypotenuse and (1) unit is the new perpendicular. Together they form new hypotenuse \(\sqrt{3}\).
Why this answer is correct
The correct answer is A. \(\sqrt{2}\) और (1) / \(\sqrt{2}\) and (1). \(\sqrt{2}\) is the previous hypotenuse and (1) unit is the new perpendicular. Together they form new hypotenuse \(\sqrt{3}\).
Exam Tip
\(\sqrt{2}\) पिछला कर्ण है और (1) इकाई नई लंब है। इनसे नया कर्ण \(\sqrt{3}\) बनता है।
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