वर्गमूल सर्पिल में किसी चरण पर पिछला कर्ण \(\sqrt{n}\) हो, तो (1) इकाई लंब जोड़ने पर नया कर्ण क्या होगा?
If the previous hypotenuse at a step in a square root spiral is \(\sqrt{n}\), what is the new hypotenuse after adding a (1) unit perpendicular?
Explanation opens after your attempt
Correct Answer
A. \(\sqrt{n+1}\)
Concept
The new hypotenuse is (\sqrt{\(\sqrt{n}\)2+12}=\sqrt{n+1}). This is the rule of the square root spiral.
Why this answer is correct
The correct answer is A. \(\sqrt{n+1}\). The new hypotenuse is (\sqrt{\(\sqrt{n}\)2+12}=\sqrt{n+1}). This is the rule of the square root spiral.
Exam Tip
नया कर्ण (\sqrt{\(\sqrt{n}\)2+12}=\sqrt{n+1}) होता है। यह वर्गमूल सर्पिल का नियम है।
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