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2 results found for "three multiples" in all classes.

\((U={1,2,3,\ldots,90}), (A={x:x\) 2 से विभाज्य है\(}), (B={x:x\) 3 से विभाज्य है\(}) और (C={x:x\) 5 से विभाज्य है}) हैं। \((n(A\cap B\cap C)) कितना है\)?

\((U={1,2,3,\ldots,90}), (A={x:x\) is divisible by \(2}), (B={x:x\) is divisible by \(3}), and (C={x:x\) is divisible by \(5}). What is (n(A\cap B\cap C))\)?

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Correct Answer

B. (3)

Step 1

Concept

To be in all three sets, a number must be divisible by (30), namely (30,60,90). Hence the count is (3).

Step 2

Why this answer is correct

The correct answer is B. (3). To be in all three sets, a number must be divisible by (30), namely (30,60,90). Hence the count is (3).

Step 3

Exam Tip

तीनों में आने के लिए संख्या (30) से विभाज्य होगी, यानी (30,60,90)। इसलिए संख्या (3) है।

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\((U={1,2,3,\ldots,60}), (A={x:x\) is divisible by \(2}), (B={x:x\) is divisible by \(3}) और (C={x:x\) is divisible by 5}) हैं। \((n(A\cap B\cap C)) कितना है\)?

\((U={1,2,3,\ldots,60}), (A={x:x\) is divisible by \(2}), (B={x:x\) is divisible by \(3}), and (C={x:x\) is divisible by \(5}). What is (n(A\cap B\cap C))\)?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

To be in all three sets, a number must be divisible by (30), namely (30,60). Hence the count is (2).

Step 2

Why this answer is correct

The correct answer is B. (2). To be in all three sets, a number must be divisible by (30), namely (30,60). Hence the count is (2).

Step 3

Exam Tip

तीनों में आने के लिए संख्या (30) से विभाज्य होगी, यानी (30,60)। इसलिए संख्या (2) है।

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