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What is the HCF of the three numbers (2^4\times 3^2\times 5), (2^3\times 3^3\times 7), and (2^5\times 3\times 5\times 7)?

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Answer and explanation

Correct answer: (2^3\times 3)

Step 1: HCF contains only the prime factors common to all three numbers. Step 2: The smallest exponent of (2) is (3) and of (3) is (1). (5) and (7) are not common to all. Hence the answer is (2^3\times 3). Step 3: For three numbers, first identify prime factors common to all.

Related tags

Hcf Of Three NumbersPrime FactorisationHard

Frequently asked questions

What is the correct answer to this question?

(2^3\times 3)

Why is this the correct answer?

Step 1: HCF contains only the prime factors common to all three numbers. Step 2: The smallest exponent of (2) is (3) and of (3) is (1). (5) and (7) are not common to all. Hence the answer is (2^3\times 3). Step 3: For three numbers, first identify prime factors common to all.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.

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