( (x+5)2 ) का विस्तार क्या है?
What is the expansion of ( (x+5)2 )?
#algebraic identities
#square expansion
#binomial
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A \(x^2+10x+25\)
B \(x^2+5x+25\)
C \(x^2+25\)
D \(x^2-10x+25\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+10x+25\)
Step 1
Concept
Using identity ( (a+b)2 =a-2 +2ab+b-2 ) gives the answer. Exam tip: do not forget the middle term (2ab).
Step 2
Why this answer is correct
The correct answer is A. \(x^2+10x+25\). Using identity ( (a+b)2 =a-2 +2ab+b-2 ) gives the answer. Exam tip: do not forget the middle term (2ab).
Step 3
Exam Tip
पहचान ( (a+b)2 =a-2 +2ab+b-2 ) लगाने पर उत्तर मिलता है। परीक्षा में बीच का पद (2ab) भूलें नहीं।
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पहचान ( (a-b)2 ) का सही विस्तार कौन-सा है?
Which is the correct expansion of the identity ( (a-b)2 )?
#algebraic identities
#minus square
#expansion
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A \(a^2+2ab+b^2\) / योग का वर्ग
B \(a^2-b^2\) / वर्गों का अंतर
C \(a^2-2ab+b^2\) / सही विस्तार
D \(a^2-ab+b^2\) / मध्य पद अधूरा
Explanation opens after your attempt
Correct Answer
C. \(a^2-2ab+b^2\) / सही विस्तार
Step 1
Concept
In ( (a-b)2 ), the middle term is (-2ab). Exam tip: check the negative sign carefully.
Step 2
Why this answer is correct
The correct answer is C. \(a^2-2ab+b^2\) / सही विस्तार. In ( (a-b)2 ), the middle term is (-2ab). Exam tip: check the negative sign carefully.
Step 3
Exam Tip
( (a-b)2 ) में मध्य पद (-2ab) होता है। परीक्षा में ऋण चिह्न ध्यान से देखें।
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( (y-4)2 ) का सही विस्तार चुनिए।
Choose the correct expansion of ( (y-4)2 ).
#algebraic identities
#minus square
#expansion
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A \(y^2-4y+16\)
B \(y^2-8y+16\)
C \(y^2+8y+16\)
D \(y^2-16\)
Explanation opens after your attempt
Correct Answer
B. \(y^2-8y+16\)
Step 1
Concept
By ( (a-b)2 =a-2 -2ab+b-2 ) the middle term is negative. Exam tip: note that \(2\times y\times4=8y\).
Step 2
Why this answer is correct
The correct answer is B. \(y^2-8y+16\). By ( (a-b)2 =a-2 -2ab+b-2 ) the middle term is negative. Exam tip: note that \(2\times y\times4=8y\).
Step 3
Exam Tip
( (a-b)2 =a-2 -2ab+b-2 ) से बीच का पद ऋणात्मक होता है। परीक्षा में \(2\times y\times4=8y\) ध्यान रखें।
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\(36-x^2\) का सही गुणनखंडन क्या है?
What is the correct factorisation of \(36-x^2\)?
#difference of squares
#factorisation
#36 minus x square
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A ( (x+6)(x-6) ) / क्रम उल्टा
B ( (6+x)(6-x) ) / सही गुणनखंड
C ( (36+x)(36-x) ) / वर्गमूल गलत
D ( (6-x)2 ) / पूर्ण वर्ग नहीं
Explanation opens after your attempt
Correct Answer
B. ( (6+x)(6-x) ) / सही गुणनखंड
Step 1
Concept
\(36-x^2=6^2-x^2\). Exam tip: identify both square roots in difference of squares.
Step 2
Why this answer is correct
The correct answer is B. ( (6+x)(6-x) ) / सही गुणनखंड. \(36-x^2=6^2-x^2\). Exam tip: identify both square roots in difference of squares.
Step 3
Exam Tip
\(36-x^2=6^2-x^2\) है। परीक्षा में वर्गों के अंतर में दोनों वर्गमूल पहचानें।
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( (p+7)(p-7) ) किसके बराबर है?
What is ( (p+7)(p-7) ) equal to?
#difference of squares
#product identity
#algebra
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A \(p^2+49\)
B \(p^2+14p+49\)
C \(p^2-49\)
D \(p^2-14p+49\)
Explanation opens after your attempt
Correct Answer
C. \(p^2-49\)
Step 1
Concept
This is the form ( (a+b)(a-b)=a-2 -b-2 ). Exam tip: identify difference of squares in opposite-sign factors.
Step 2
Why this answer is correct
The correct answer is C. \(p^2-49\). This is the form ( (a+b)(a-b)=a-2 -b-2 ). Exam tip: identify difference of squares in opposite-sign factors.
Step 3
Exam Tip
यह ( (a+b)(a-b)=a-2 -b-2 ) का रूप है। परीक्षा में विपरीत चिन्ह वाले पदों में अंतर वर्ग पहचानें।
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( (x+4)(x+6) ) में (x) का गुणांक क्या होगा?
What will be the coefficient of (x) in ( (x+4)(x+6) )?
#product identity
#coefficient
#x plus numbers
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A (10) / स्थिर पदों का योग
B (24) / स्थिर पदों का गुणन
C (4) / पहला स्थिर पद
D (6) / दूसरा स्थिर पद
Explanation opens after your attempt
Correct Answer
A. (10) / स्थिर पदों का योग
Step 1
Concept
( (x+4)(x+6)=x-2 +10x+24 ). Exam tip: the coefficient of (x) comes from the sum of constants.
Step 2
Why this answer is correct
The correct answer is A. (10) / स्थिर पदों का योग. ( (x+4)(x+6)=x-2 +10x+24 ). Exam tip: the coefficient of (x) comes from the sum of constants.
Step 3
Exam Tip
( (x+4)(x+6)=x-2 +10x+24 ) होता है। परीक्षा में (x) का गुणांक स्थिर पदों के योग से मिलता है।
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( (m+2)2 ) में बीच का पद कौन सा है?
What is the middle term in ( (m+2)2 )?
#middle term
#binomial square
#easy algebra
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A (2m)
B \(m^2\)
C (4)
D (4m)
Explanation opens after your attempt
Step 1
Concept
The middle term is (2ab) so \(2\times m\times2=4m\). Exam tip: distinguish squares from the middle term.
Step 2
Why this answer is correct
The correct answer is D. (4m). The middle term is (2ab) so \(2\times m\times2=4m\). Exam tip: distinguish squares from the middle term.
Step 3
Exam Tip
बीच का पद (2ab) होता है इसलिए \(2\times m\times2=4m\)। परीक्षा में वर्ग और बीच का पद अलग पहचानें।
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\(49^2\) को ( (50-1)2 ) से निकालने पर मान क्या होगा?
Using ( (50-1)2 ), what is the value of \(49^2\)?
#mental math
#49 square
#square identity
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A (2501)
B (2500)
C (2400)
D (2401)
Explanation opens after your attempt
Step 1
Concept
\(49^2=2500-100+1=2401\). Exam tip: subtract (2ab) in the square of a difference.
Step 2
Why this answer is correct
The correct answer is D. (2401). \(49^2=2500-100+1=2401\). Exam tip: subtract (2ab) in the square of a difference.
Step 3
Exam Tip
\(49^2=2500-100+1=2401\) होता है। परीक्षा में घटाव वाले वर्ग में (2ab) घटाएँ।
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( (3a+b)2 ) का विस्तार क्या होगा?
What will be the expansion of ( (3a+b)2 )?
#binomial square
#algebraic expansion
#identity
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A \(9a^2+6ab+b^2\)
B \(3a^2+6ab+b^2\)
C \(9a^2+b^2\)
D \(9a^2-6ab+b^2\)
Explanation opens after your attempt
Correct Answer
A. \(9a^2+6ab+b^2\)
Step 1
Concept
The square of the first term is \(9a^2\) and the middle term is (6ab). Exam tip: write the square of (3a) as \(9a^2\).
Step 2
Why this answer is correct
The correct answer is A. \(9a^2+6ab+b^2\). The square of the first term is \(9a^2\) and the middle term is (6ab). Exam tip: write the square of (3a) as \(9a^2\).
Step 3
Exam Tip
पहले पद का वर्ग \(9a^2\) और बीच का पद (6ab) है। परीक्षा में (3a) का वर्ग \(9a^2\) लिखें।
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( (2m+3)2 ) में मध्य पद कौन-सा है?
What is the middle term in ( (2m+3)2 )?
#middle term
#binomial square
#2m plus 3
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A (6m) / आधा पद
B (12m) / सही मध्य पद
C \(4m^2\) / पहला वर्ग
D (9) / अंतिम वर्ग
Explanation opens after your attempt
Correct Answer
B. (12m) / सही मध्य पद
Step 1
Concept
The middle term is \(2\cdot2m\cdot3=12m\). Exam tip: multiply both terms and then multiply by (2).
Step 2
Why this answer is correct
The correct answer is B. (12m) / सही मध्य पद. The middle term is \(2\cdot2m\cdot3=12m\). Exam tip: multiply both terms and then multiply by (2).
Step 3
Exam Tip
मध्य पद \(2\cdot2m\cdot3=12m\) है। परीक्षा में दोनों पदों को गुणा करके (2) से गुणा करें।
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( (2x-3)2 ) का सही रूप चुनिए।
Choose the correct form of ( (2x-3)2 ).
#minus square
#binomial identity
#expansion
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A \(4x^2+12x+9\)
B \(4x^2-12x+9\)
C \(2x^2-6x+9\)
D \(4x^2-9\)
Explanation opens after your attempt
Correct Answer
B. \(4x^2-12x+9\)
Step 1
Concept
In ( (a-b)2 ) the middle term is ( -2ab ). Exam tip: remember \(2\times2x\times3=12x\).
Step 2
Why this answer is correct
The correct answer is B. \(4x^2-12x+9\). In ( (a-b)2 ) the middle term is ( -2ab ). Exam tip: remember \(2\times2x\times3=12x\).
Step 3
Exam Tip
( (a-b)2 ) में बीच का पद ( -2ab ) होता है। परीक्षा में \(2\times2x\times3=12x\) याद रखें।
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\( 51^2 \) को ( (50+1)2 ) से निकालने पर मान क्या है?
What is the value of \( 51^2 \) using ( (50+1)2 )?
#numeric identity
#square calculation
#mental math
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A (2501)
B (2600)
C (2601)
D (2500)
Explanation opens after your attempt
Step 1
Concept
( (50+1)2 =2500+100+1=2601 ). Exam tip: identities make numerical squares faster.
Step 2
Why this answer is correct
The correct answer is C. (2601). ( (50+1)2 =2500+100+1=2601 ). Exam tip: identities make numerical squares faster.
Step 3
Exam Tip
( (50+1)2 =2500+100+1=2601 )। परीक्षा में संख्यात्मक वर्ग में पहचान से गणना तेज होती है।
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\( 49^2 \) को ( (50-1)2 ) से निकालिए।
Find \( 49^2 \) using ( (50-1)2 ).
#numeric square
#minus identity
#calculation
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A (2401)
B (2499)
C (2501)
D (2301)
Explanation opens after your attempt
Step 1
Concept
( (50-1)2 =2500-100+1=2401 ). Exam tip: the middle term is subtracted in ( (a-b)2 ).
Step 2
Why this answer is correct
The correct answer is A. (2401). ( (50-1)2 =2500-100+1=2401 ). Exam tip: the middle term is subtracted in ( (a-b)2 ).
Step 3
Exam Tip
( (50-1)2 =2500-100+1=2401 )। परीक्षा में ( (a-b)2 ) में बीच का पद घटता है।
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\( 103^2 \) का मान पहचान से क्या होगा?
What is the value of \( 103^2 \) using an identity?
#square calculation
#numeric identity
#algebra
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A (10609)
B (10600)
C (10900)
D (10690)
Explanation opens after your attempt
Correct Answer
A. (10609)
Step 1
Concept
(103=100+3) so ( (100+3)2 =10609 ). Exam tip: split the number near an easy square.
Step 2
Why this answer is correct
The correct answer is A. (10609). (103=100+3) so ( (100+3)2 =10609 ). Exam tip: split the number near an easy square.
Step 3
Exam Tip
(103=100+3) इसलिए ( (100+3)2 =10609 )। परीक्षा में संख्या को पास के आसान वर्ग में तोड़ें।
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\( 98^2 \) को ( (100-2)2 ) से निकालने पर उत्तर क्या है?
What is the answer for \( 98^2 \) using ( (100-2)2 )?
#numeric square
#algebraic identity
#mental calculation
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A (9804)
B (9604)
C (9404)
D (10004)
Explanation opens after your attempt
Step 1
Concept
( (100-2)2 =10000-400+4=9604 ). Exam tip: keep the subtracted middle term correct.
Step 2
Why this answer is correct
The correct answer is B. (9604). ( (100-2)2 =10000-400+4=9604 ). Exam tip: keep the subtracted middle term correct.
Step 3
Exam Tip
( (100-2)2 =10000-400+4=9604 )। परीक्षा में घटाने वाले बीच के पद को सही रखें।
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( (x+8)2 -x-2 ) को सरल कीजिए।
Simplify ( (x+8)2 -x-2 ).
#simplification
#square identity
#like terms
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A (8x+64)
B (16x+8)
C (16x+64)
D \(x^2+64\)
Explanation opens after your attempt
Correct Answer
C. (16x+64)
Step 1
Concept
( (x+8)2 =x-2 +16x+64 ) and then \(x^2\) cancels. Exam tip: do not forget to cancel like terms.
Step 2
Why this answer is correct
The correct answer is C. (16x+64). ( (x+8)2 =x-2 +16x+64 ) and then \(x^2\) cancels. Exam tip: do not forget to cancel like terms.
Step 3
Exam Tip
( (x+8)2 =x-2 +16x+64 ) से \(x^2\) घटता है। परीक्षा में समान पदों को काटना न भूलें।
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( (a+6)2 -(a-6)2 ) का सरल रूप क्या है?
What is the simplified form of ( (a+6)2 -(a-6)2 )?
#difference of squares
#simplification
#algebra
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A (12a)
B (24a)
C (36a)
D \(a^2+36\)
Explanation opens after your attempt
Step 1
Concept
On expansion \(a^2+12a+36-a^2+12a-36=24a\). Exam tip: apply the minus sign to the whole bracket.
Step 2
Why this answer is correct
The correct answer is B. (24a). On expansion \(a^2+12a+36-a^2+12a-36=24a\). Exam tip: apply the minus sign to the whole bracket.
Step 3
Exam Tip
विस्तार करने पर \(a^2+12a+36-a^2+12a-36=24a\) मिलता है। परीक्षा में ऋण चिन्ह पूरे कोष्ठक पर लागू करें।
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( (r+9)(r-9) ) का गुणनफल क्या है?
What is the product of ( (r+9)(r-9) )?
#product identity
#difference of squares
#binomial
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A \(r^2+81\)
B \(r^2-18r+81\)
C \(r^2-81\)
D \(r^2+18r+81\)
Explanation opens after your attempt
Correct Answer
C. \(r^2-81\)
Step 1
Concept
This is the \(a^2-b^2\) form. Exam tip: remember \(9^2=81\).
Step 2
Why this answer is correct
The correct answer is C. \(r^2-81\). This is the \(a^2-b^2\) form. Exam tip: remember \(9^2=81\).
Step 3
Exam Tip
यह \(a^2-b^2\) वाला रूप है। परीक्षा में \(9^2=81\) ध्यान रखें।
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\( 72\times68 \) को पहचान से निकालिए।
Find \( 72\times68 \) using an identity.
#difference of squares
#numeric product
#identity
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A (4896)
B (4900)
C (4800)
D (4796)
Explanation opens after your attempt
Step 1
Concept
(72\times68=(70+2)(70-2)=702 -22 =4896). Exam tip: choose the nearby common number.
Step 2
Why this answer is correct
The correct answer is A. (4896). (72\times68=(70+2)(70-2)=702 -22 =4896). Exam tip: choose the nearby common number.
Step 3
Exam Tip
(72\times68=(70+2)(70-2)=702 -22 =4896)। परीक्षा में पास की समान संख्या चुनें।
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\( 64^2-36^2 \) का मान क्या है?
What is the value of \( 64^2-36^2 \)?
#difference of squares
#numeric value
#identity
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A (1800)
B (2800)
C (3000)
D (2000)
Explanation opens after your attempt
Step 1
Concept
Using (a-2 -b-2 =(a+b)(a-b)), we get \(100\times28=2800\). Exam tip: convert difference of squares into a product.
Step 2
Why this answer is correct
The correct answer is B. (2800). Using (a-2 -b-2 =(a+b)(a-b)), we get \(100\times28=2800\). Exam tip: convert difference of squares into a product.
Step 3
Exam Tip
(a-2 -b-2 =(a+b)(a-b)) से \(100\times28=2800\)। परीक्षा में अंतर वर्ग को गुणनफल में बदलें।
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\( x^2+12x+36 \) किसका वर्ग है?
\( x^2+12x+36 \) is the square of what?
#perfect square
#factorization
#algebra
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A ( (x+12)2 )
B ( (x-6)2 )
C ( (x+6)2 )
D ( (x-12)2 )
Explanation opens after your attempt
Correct Answer
C. ( (x+6)2 )
Step 1
Concept
It is \(x^2+2\times x\times6+6^2\). Exam tip: use the square root of the last term to identify the bracket.
Step 2
Why this answer is correct
The correct answer is C. ( (x+6)2 ). It is \(x^2+2\times x\times6+6^2\). Exam tip: use the square root of the last term to identify the bracket.
Step 3
Exam Tip
यह \(x^2+2\times x\times6+6^2\) है। परीक्षा में अंतिम पद के वर्गमूल से कोष्ठक पहचानें।
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\( t^2-14t+49 \) किसके बराबर है?
What is \( t^2-14t+49 \) equal to?
#perfect square
#minus square
#factorization
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A ( (t+7)2 )
B ( (t-7)2 )
C ( (t-14)2 )
D ( (t+49)2 )
Explanation opens after your attempt
Correct Answer
B. ( (t-7)2 )
Step 1
Concept
It is \(t^2-2\times t\times7+7^2\). Exam tip: choose ( (a-b)2 ) when the middle term is negative.
Step 2
Why this answer is correct
The correct answer is B. ( (t-7)2 ). It is \(t^2-2\times t\times7+7^2\). Exam tip: choose ( (a-b)2 ) when the middle term is negative.
Step 3
Exam Tip
यह \(t^2-2\times t\times7+7^2\) है। परीक्षा में बीच का ऋण चिन्ह देखकर ( (a-b)2 ) चुनें।
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\( x^2-64 \) का गुणनखंड रूप क्या है?
What is the factor form of \( x^2-64 \)?
#factorization
#difference of squares
#algebraic identities
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A ( (x+8)2 )
B ( (x-8)2 )
C ( (x+64)(x-1) )
D ( (x+8)(x-8) )
Explanation opens after your attempt
Correct Answer
D. ( (x+8)(x-8) )
Step 1
Concept
Since \(64=8^2\), (x-2 -64=(x+8)(x-8)). Exam tip: identify difference of squares quickly.
Step 2
Why this answer is correct
The correct answer is D. ( (x+8)(x-8) ). Since \(64=8^2\), (x-2 -64=(x+8)(x-8)). Exam tip: identify difference of squares quickly.
Step 3
Exam Tip
\(64=8^2\) इसलिए (x-2 -64=(x+8)(x-8))। परीक्षा में अंतर वर्ग तुरंत पहचानें।
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\( 4x^2-25 \) का गुणनखंड क्या है?
What are the factors of \( 4x^2-25 \)?
#difference of squares
#factorization
#identity
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A ( (2x+5)(2x-5) )
B ( (4x+5)(x-5) )
C ( (2x-5)2 )
D ( (x+5)(x-5) )
Explanation opens after your attempt
Correct Answer
A. ( (2x+5)(2x-5) )
Step 1
Concept
(4x-2 =(2x)2 ) and \(25=5^2\). Exam tip: write both terms as squares.
Step 2
Why this answer is correct
The correct answer is A. ( (2x+5)(2x-5) ). (4x-2 =(2x)2 ) and \(25=5^2\). Exam tip: write both terms as squares.
Step 3
Exam Tip
(4x-2 =(2x)2 ) और \(25=5^2\) है। परीक्षा में दोनों पदों को वर्ग के रूप में लिखें।
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( (x+3)(x-4) ) का सही विस्तार कौन सा है?
Which is the correct expansion of ( (x+3)(x-4) )?
#product identity
#signed terms
#expansion
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A \(x^2+x-12\)
B \(x^2-x-12\)
C \(x^2+7x-12\)
D \(x^2-12\)
Explanation opens after your attempt
Correct Answer
B. \(x^2-x-12\)
Step 1
Concept
(3+(-4)=-1) and \(3\times(-4)=-12\). Exam tip: be careful while adding negative numbers.
Step 2
Why this answer is correct
The correct answer is B. \(x^2-x-12\). (3+(-4)=-1) and \(3\times(-4)=-12\). Exam tip: be careful while adding negative numbers.
Step 3
Exam Tip
(3+(-4)=-1) और \(3\times(-4)=-12\)। परीक्षा में ऋण संख्या जोड़ते समय सावधान रहें।
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( (x-6)(x-2) ) का विस्तार क्या होगा?
What will be the expansion of ( (x-6)(x-2) )?
#binomial product
#negative terms
#expansion
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A \(x^2-8x+12\)
B \(x^2+8x+12\)
C \(x^2-4x-12\)
D \(x^2-12x+8\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-8x+12\)
Step 1
Concept
((-6)+(-2)=-8) and ((-6)(-2)=12). Exam tip: product of two negative terms is positive.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-8x+12\). ((-6)+(-2)=-8) and ((-6)(-2)=12). Exam tip: product of two negative terms is positive.
Step 3
Exam Tip
((-6)+(-2)=-8) और ((-6)(-2)=12)। परीक्षा में दो ऋण पदों का गुणन धनात्मक होता है।
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( (z+1)(z+9) ) में (z) का गुणांक क्या है?
What is the coefficient of (z) in ( (z+1)(z+9) )?
#coefficient
#product identity
#algebra
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A (9)
B (1)
C (10)
D (90)
Explanation opens after your attempt
Step 1
Concept
( (z+1)(z+9)=z-2 +10z+9 ). Exam tip: the coefficient of (z) comes from the sum of the constants.
Step 2
Why this answer is correct
The correct answer is C. (10). ( (z+1)(z+9)=z-2 +10z+9 ). Exam tip: the coefficient of (z) comes from the sum of the constants.
Step 3
Exam Tip
( (z+1)(z+9)=z-2 +10z+9 ) होता है। परीक्षा में (z) का गुणांक दोनों स्थिर पदों के योग से मिलता है।
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( (x+y+z)2 ) में (2xy) के साथ कौन से और मिश्र पद आते हैं?
In ( (x+y+z)2 ), which other mixed terms come with (2xy)?
#three term identity
#mixed terms
#algebra
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A (2xz) और (2yz) / (2xz) and (2yz)
B \(x^2\) और \(y^2\) / \(x^2\) and \(y^2\)
C \(z^2\) और (xy) / \(z^2\) and (xy)
D (xyz) और (x+y) / (xyz) and (x+y)
Explanation opens after your attempt
Correct Answer
A. (2xz) और (2yz) / (2xz) and (2yz)
Step 1
Concept
In the square of three terms, mixed terms are (2xy), (2yz), and (2zx). Exam tip: include all pairs.
Step 2
Why this answer is correct
The correct answer is A. (2xz) और (2yz) / (2xz) and (2yz). In the square of three terms, mixed terms are (2xy), (2yz), and (2zx). Exam tip: include all pairs.
Step 3
Exam Tip
तीन पदों के वर्ग में मिश्र पद (2xy), (2yz), और (2zx) होते हैं। परीक्षा में सभी जोड़ों को शामिल करें।
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( (a+b+c)2 ) का सही विस्तार कौन सा है?
Which is the correct expansion of ( (a+b+c)2 )?
#three term square
#algebraic identity
#expansion
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A \(a^2+b^2+c^2+2ab+2bc+2ca\)
B \(a^2+b^2+c^2+abc\)
C \(a^2+b^2+c^2+ab+bc+ca\)
D \(a^2-b^2+c^2\)
Explanation opens after your attempt
Correct Answer
A. \(a^2+b^2+c^2+2ab+2bc+2ca\)
Step 1
Concept
Each pair gives a double mixed term in three terms. Exam tip: do not miss (2ab), (2bc), and (2ca).
Step 2
Why this answer is correct
The correct answer is A. \(a^2+b^2+c^2+2ab+2bc+2ca\). Each pair gives a double mixed term in three terms. Exam tip: do not miss (2ab), (2bc), and (2ca).
Step 3
Exam Tip
तीन पदों में प्रत्येक जोड़े का दुगुना मिश्र पद आता है। परीक्षा में (2ab), (2bc), और (2ca) न छोड़ें।
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( (x+1)2 ) और \(x^2+1\) में क्या अंतर है?
What is the difference between ( (x+1)2 ) and \(x^2+1\)?
#middle term
#common mistake
#binomial square
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A (x)
B (2x)
C (1)
D \(x^2\)
Explanation opens after your attempt
Step 1
Concept
( (x+1)2 =x-2 +2x+1 ), so the difference is (2x). Exam tip: do not forget the middle term while expanding.
Step 2
Why this answer is correct
The correct answer is B. (2x). ( (x+1)2 =x-2 +2x+1 ), so the difference is (2x). Exam tip: do not forget the middle term while expanding.
Step 3
Exam Tip
( (x+1)2 =x-2 +2x+1 ) है इसलिए अंतर (2x) है। परीक्षा में वर्ग खोलते समय बीच का पद न भूलें।
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( (5x+2)2 ) में स्थिर पद क्या है?
What is the constant term in ( (5x+2)2 )?
#constant term
#square expansion
#algebra
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A \(25x^2\)
B (20x)
C (4)
D (10x)
Explanation opens after your attempt
Step 1
Concept
The constant term is \(2^2=4\). Exam tip: a constant term has no (x).
Step 2
Why this answer is correct
The correct answer is C. (4). The constant term is \(2^2=4\). Exam tip: a constant term has no (x).
Step 3
Exam Tip
स्थिर पद \(2^2=4\) होता है। परीक्षा में स्थिर पद वह होता है जिसमें (x) न हो।
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( (4p-1)2 ) में (p) वाला पद कौन सा है?
Which term contains (p) in ( (4p-1)2 )?
#middle term
#negative sign
#binomial square
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A (8p)
B (-8p)
C \(16p^2\)
D (1)
Explanation opens after your attempt
Step 1
Concept
The middle term is \(-2\times4p\times1=-8p\). Exam tip: the sign is very important in a subtraction square.
Step 2
Why this answer is correct
The correct answer is B. (-8p). The middle term is \(-2\times4p\times1=-8p\). Exam tip: the sign is very important in a subtraction square.
Step 3
Exam Tip
बीच का पद \(-2\times4p\times1=-8p\) है। परीक्षा में घटाव वाले वर्ग में चिन्ह बहुत महत्वपूर्ण है।
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\( 1002^2 \) निकालने के लिए कौन सा रूप सबसे उपयोगी है?
Which form is most useful to find \( 1002^2 \)?
#numeric identity
#square method
#easy calculation
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A ( (1000+2)2 )
B ( (1000-2)2 )
C ( (100+2)2 )
D ( (10+2)2 )
Explanation opens after your attempt
Correct Answer
A. ( (1000+2)2 )
Step 1
Concept
Writing (1002) as (1000+2) is easy. Exam tip: connect a large number to a nearby simple number.
Step 2
Why this answer is correct
The correct answer is A. ( (1000+2)2 ). Writing (1002) as (1000+2) is easy. Exam tip: connect a large number to a nearby simple number.
Step 3
Exam Tip
(1002) को (1000+2) लिखना आसान है। परीक्षा में बड़ी संख्या को निकट सरल संख्या से जोड़ें।
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\( 999^2 \) निकालने के लिए कौन सा रूप सही है?
Which form is correct to find \( 999^2 \)?
#numeric square
#minus square
#identity
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A ( (900+99)2 )
B ( (1000-1)2 )
C ( (1000+1)2 )
D ( (99+9)2 )
Explanation opens after your attempt
Correct Answer
B. ( (1000-1)2 )
Step 1
Concept
Write (999) as (1000-1) and use ( (a-b)2 ). Exam tip: choosing the nearest simple number is faster.
Step 2
Why this answer is correct
The correct answer is B. ( (1000-1)2 ). Write (999) as (1000-1) and use ( (a-b)2 ). Exam tip: choosing the nearest simple number is faster.
Step 3
Exam Tip
(999) को (1000-1) लिखकर ( (a-b)2 ) लगाएँ। परीक्षा में निकटतम सरल संख्या चुनना तेज तरीका है।
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( (u+v)(u-v) ) में कौन सा पद नहीं आता?
Which term does not appear in ( (u+v)(u-v) )?
#difference of squares
#cancel terms
#identity
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A \(u^2\)
B \(-v^2\)
C (uv)
D \(u^2-v^2\)
Explanation opens after your attempt
Step 1
Concept
The middle (uv) terms cancel. Exam tip: mixed terms do not remain in opposite-sign products.
Step 2
Why this answer is correct
The correct answer is C. (uv). The middle (uv) terms cancel. Exam tip: mixed terms do not remain in opposite-sign products.
Step 3
Exam Tip
मध्य के (uv) पद कट जाते हैं। परीक्षा में विपरीत चिन्ह वाले गुणन में मिश्र पद नहीं बचता।
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( (q+10)2 ) में \(q^2\) और (100) के अलावा कौन सा पद आएगा?
In ( (q+10)2 ), which term comes besides \(q^2\) and (100)?
#middle term
#square identity
#algebra
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A (10q)
B (20q)
C (100q)
D (q)
Explanation opens after your attempt
Step 1
Concept
The middle term is \(2\times q\times10=20q\). Exam tip: remember to multiply by two.
Step 2
Why this answer is correct
The correct answer is B. (20q). The middle term is \(2\times q\times10=20q\). Exam tip: remember to multiply by two.
Step 3
Exam Tip
बीच का पद \(2\times q\times10=20q\) है। परीक्षा में दो गुना गुणन करना याद रखें।
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( (n-11)2 ) में अंतिम पद क्या होगा?
What will be the last term in ( (n-11)2 )?
#last term
#minus square
#algebraic identity
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A (11n)
B (-121)
C (121)
D (-22n)
Explanation opens after your attempt
Step 1
Concept
The last term \(11^2=121\) is always positive. Exam tip: the square term remains positive.
Step 2
Why this answer is correct
The correct answer is C. (121). The last term \(11^2=121\) is always positive. Exam tip: the square term remains positive.
Step 3
Exam Tip
अंतिम पद \(11^2=121\) हमेशा धनात्मक होता है। परीक्षा में वर्ग का चिन्ह धनात्मक रहता है।
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( (2a+3b)2 ) में मिश्र पद क्या है?
What is the mixed term in ( (2a+3b)2 )?
#mixed term
#binomial square
#coefficients
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A (5ab)
B (6ab)
C (12ab)
D \(9b^2\)
Explanation opens after your attempt
Step 1
Concept
The mixed term is \(2\times2a\times3b=12ab\). Exam tip: multiply the coefficients too.
Step 2
Why this answer is correct
The correct answer is C. (12ab). The mixed term is \(2\times2a\times3b=12ab\). Exam tip: multiply the coefficients too.
Step 3
Exam Tip
मिश्र पद \(2\times2a\times3b=12ab\) है। परीक्षा में गुणांक भी साथ गुणा करें।
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( (3x-2y)2 ) का विस्तार क्या है?
What is the expansion of ( (3x-2y)2 )?
#binomial square
#two variables
#expansion
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A \(9x^2-12xy+4y^2\)
B \(9x^2+12xy+4y^2\)
C \(3x^2-12xy+2y^2\)
D \(9x^2-4y^2\)
Explanation opens after your attempt
Correct Answer
A. \(9x^2-12xy+4y^2\)
Step 1
Concept
In ( (a-b)2 ) the mixed term is negative. Exam tip: write ((3x)2 =9x-2 ) and ((2y)2 =4y-2 ).
Step 2
Why this answer is correct
The correct answer is A. \(9x^2-12xy+4y^2\). In ( (a-b)2 ) the mixed term is negative. Exam tip: write ((3x)2 =9x-2 ) and ((2y)2 =4y-2 ).
Step 3
Exam Tip
( (a-b)2 ) में मिश्र पद ऋणात्मक होता है। परीक्षा में ((3x)2 =9x-2 ) और ((2y)2 =4y-2 ) लिखें।
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( (5m+4n)(5m-4n) ) का मान क्या है?
What is the value of ( (5m+4n)(5m-4n) )?
#difference of squares
#two variables
#product
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A \(25m^2+16n^2\)
B \(25m^2-16n^2\)
C (10m-8n)
D \(25m^2-40mn+16n^2\)
Explanation opens after your attempt
Correct Answer
B. \(25m^2-16n^2\)
Step 1
Concept
This is a direct use of \(a^2-b^2\). Exam tip: use ((5m)2 =25m-2 ) and ((4n)2 =16n-2 ).
Step 2
Why this answer is correct
The correct answer is B. \(25m^2-16n^2\). This is a direct use of \(a^2-b^2\). Exam tip: use ((5m)2 =25m-2 ) and ((4n)2 =16n-2 ).
Step 3
Exam Tip
यह \(a^2-b^2\) का सीधा प्रयोग है। परीक्षा में ((5m)2 =25m-2 ) और ((4n)2 =16n-2 ) करें।
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\( x^2+18x+81 \) का वर्ग रूप कौन सा है?
Which square form represents \( x^2+18x+81 \)?
#perfect square
#recognition
#algebraic identity
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A ( (x+9)2 )
B ( (x-9)2 )
C ( (x+18)2 )
D ( (x+81)2 )
Explanation opens after your attempt
Correct Answer
A. ( (x+9)2 )
Step 1
Concept
\(81=9^2\) and the middle term \(18x=2\times x\times9\). Exam tip: identify the number from the last term.
Step 2
Why this answer is correct
The correct answer is A. ( (x+9)2 ). \(81=9^2\) and the middle term \(18x=2\times x\times9\). Exam tip: identify the number from the last term.
Step 3
Exam Tip
\(81=9^2\) और बीच का पद \(18x=2\times x\times9\) है। परीक्षा में अंतिम पद से संख्या पहचानें।
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\( k^2-20k+100 \) किसका वर्ग है?
\( k^2-20k+100 \) is the square of what?
#perfect square
#minus identity
#factorization
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A ( (k+20)2 )
B ( (k-10)2 )
C ( (k+10)2 )
D ( (k-100)2 )
Explanation opens after your attempt
Correct Answer
B. ( (k-10)2 )
Step 1
Concept
\(100=10^2\) and the middle term is \(-20k=-2\times k\times10\). Exam tip: identify the negative middle term.
Step 2
Why this answer is correct
The correct answer is B. ( (k-10)2 ). \(100=10^2\) and the middle term is \(-20k=-2\times k\times10\). Exam tip: identify the negative middle term.
Step 3
Exam Tip
\(100=10^2\) और बीच का पद \(-20k=-2\times k\times10\) है। परीक्षा में ऋणात्मक बीच का पद पहचानें।
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\( 37^2-27^2 \) का मान क्या है?
What is the value of \( 37^2-27^2 \)?
#numeric difference
#square identity
#calculation
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A (540)
B (600)
C (640)
D (720)
Explanation opens after your attempt
Step 1
Concept
(372 -272 =(37+27)(37-27)=64\times10=640). Exam tip: difference of squares makes multiplication easy.
Step 2
Why this answer is correct
The correct answer is C. (640). (372 -272 =(37+27)(37-27)=64\times10=640). Exam tip: difference of squares makes multiplication easy.
Step 3
Exam Tip
(372 -272 =(37+27)(37-27)=64\times10=640)। परीक्षा में अंतर वर्ग से गुणा आसान होता है।
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\( 45\times55 \) को किस पहचान से जल्दी निकाला जा सकता है?
Which identity can quickly find \( 45\times55 \)?
#numeric product
#difference of squares
#identity choice
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A ( (a+b)2 )
B ( (a-b)2 )
C ( (a+b)(a-b)=a-2 -b-2 )
D ( (a+b+c)2 )
Explanation opens after your attempt
Correct Answer
C. ( (a+b)(a-b)=a-2 -b-2 )
Step 1
Concept
(45\times55=(50-5)(50+5)). Exam tip: use difference of squares for numbers around the same centre.
Step 2
Why this answer is correct
The correct answer is C. ( (a+b)(a-b)=a-2 -b-2 ). (45\times55=(50-5)(50+5)). Exam tip: use difference of squares for numbers around the same centre.
Step 3
Exam Tip
(45\times55=(50-5)(50+5)) है। परीक्षा में समान केंद्र वाली संख्याएँ अंतर वर्ग से करें।
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( (a+2b+c)2 ) में \(4b^2\) किससे आता है?
In ( (a+2b+c)2 ), where does \(4b^2\) come from?
#three term square
#coefficient square
#identity
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A \(a^2\) से / From \(a^2\)
B ((2b)2 ) से / From ((2b)2 )
C \(c^2\) से / From \(c^2\)
D (2ac) से / From (2ac)
Explanation opens after your attempt
Correct Answer
B. ((2b)2 ) से / From ((2b)2 )
Step 1
Concept
The square of (2b) is ((2b)2 =4b-2 ). Exam tip: square the coefficient too.
Step 2
Why this answer is correct
The correct answer is B. ((2b)2 ) से / From ((2b)2 ). The square of (2b) is ((2b)2 =4b-2 ). Exam tip: square the coefficient too.
Step 3
Exam Tip
(2b) का वर्ग ((2b)2 =4b-2 ) होता है। परीक्षा में गुणांक का भी वर्ग करें।
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( (x+y+2)2 ) में स्थिर पद क्या होगा?
What will be the constant term in ( (x+y+2)2 )?
#constant term
#three term square
#algebra
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A (2)
B (4)
C (2x)
D (4xy)
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Step 1
Concept
The constant term is \(2^2=4\). Exam tip: the term containing only a number is called the constant term.
Step 2
Why this answer is correct
The correct answer is B. (4). The constant term is \(2^2=4\). Exam tip: the term containing only a number is called the constant term.
Step 3
Exam Tip
स्थिर पद \(2^2=4\) है। परीक्षा में केवल संख्या वाले पद को स्थिर पद कहते हैं।
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( (x-3)(x+3)+9 ) को सरल कीजिए।
Simplify ( (x-3)(x+3)+9 ).
#simplification
#difference of squares
#algebra
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A \(x^2\)
B \(x^2-9\)
C \(x^2+9\)
D \(x^2+18\)
Explanation opens after your attempt
Correct Answer
A. \(x^2\)
Step 1
Concept
( (x-3)(x+3)=x-2 -9 ) and then (+9) gives \(x^2\). Exam tip: identify the product first.
Step 2
Why this answer is correct
The correct answer is A. \(x^2\). ( (x-3)(x+3)=x-2 -9 ) and then (+9) gives \(x^2\). Exam tip: identify the product first.
Step 3
Exam Tip
( (x-3)(x+3)=x-2 -9 ) और फिर (+9) से \(x^2\) मिलता है। परीक्षा में पहले गुणनफल पहचानें।
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( (2x+1)2 -(2x-1)2 ) का मान क्या है?
What is the value of ( (2x+1)2 -(2x-1)2 )?
#difference of squares
#identity shortcut
#simplification
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A (2x)
B (4x)
C (8x)
D (16x)
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Step 1
Concept
This is (4ab) where (a=2x) and (b=1). Exam tip: calculate \(4\times2x\times1=8x\).
Step 2
Why this answer is correct
The correct answer is C. (8x). This is (4ab) where (a=2x) and (b=1). Exam tip: calculate \(4\times2x\times1=8x\).
Step 3
Exam Tip
यह (4ab) है जहाँ (a=2x) और (b=1)। परीक्षा में \(4\times2x\times1=8x\) करें।
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( (x+7)(x+7) ) को पहचान के रूप में कैसे लिखेंगे?
How will you write ( (x+7)(x+7) ) as an identity form?
#square form
#binomial
#identity recognition
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A ( (x+7)2 )
B ( (x-7)2 )
C \(x^2-49\)
D ( (x+7)(x-7) )
Explanation opens after your attempt
Correct Answer
A. ( (x+7)2 )
Step 1
Concept
The product of two identical factors is a square. Exam tip: treat ( (x+7)(x+7) ) as ( (x+7)2 ).
Step 2
Why this answer is correct
The correct answer is A. ( (x+7)2 ). The product of two identical factors is a square. Exam tip: treat ( (x+7)(x+7) ) as ( (x+7)2 ).
Step 3
Exam Tip
समान दो गुणनखंडों का गुणन वर्ग होता है। परीक्षा में ( (x+7)(x+7) ) को ( (x+7)2 ) मानें।
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( (a-b)2 ) और \(a^2-b^2\) में मुख्य अंतर क्या है?
What is the main difference between ( (a-b)2 ) and \(a^2-b^2\)?
#common mistake
#minus square
#difference of squares
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A दोनों हमेशा समान हैं / Both are always same
B ( (a-b)2 ) में (-2ab) पद होता है पर \(a^2-b^2\) में नहीं / ( (a-b)2 ) has (-2ab) term but \(a^2-b^2\) does not
C \(a^2-b^2\) में (+2ab) होता है / \(a^2-b^2\) has (+2ab)
D दोनों में कोई वर्ग पद नहीं होता / Neither has square terms
Explanation opens after your attempt
Correct Answer
B. ( (a-b)2 ) में (-2ab) पद होता है पर \(a^2-b^2\) में नहीं / ( (a-b)2 ) has (-2ab) term but \(a^2-b^2\) does not
Step 1
Concept
( (a-b)2 =a-2 -2ab+b-2 ) while (a-2 -b-2 =(a+b)(a-b)). Exam tip: keep square of bracket and difference of squares separate.
Step 2
Why this answer is correct
The correct answer is B. ( (a-b)2 ) में (-2ab) पद होता है पर \(a^2-b^2\) में नहीं / ( (a-b)2 ) has (-2ab) term but \(a^2-b^2\) does not. ( (a-b)2 =a-2 -2ab+b-2 ) while (a-2 -b-2 =(a+b)(a-b)). Exam tip: keep square of bracket and difference of squares separate.
Step 3
Exam Tip
( (a-b)2 =a-2 -2ab+b-2 ) जबकि (a-2 -b-2 =(a+b)(a-b)) है। परीक्षा में कोष्ठक के वर्ग और अंतर वर्ग को अलग रखें।
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