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What will be the last term in ( (n-11)^2 )?
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Answer and explanation
Correct answer: \(121\)
Using the identity \((a-b)^2=a^2-2ab+b^2\), we get \((n-11)^2=n^2-22n+121\). Therefore, the last term is \(121\). \(-22n\) is the middle term; the last term is \(11^2\), which is positive. Exam tip: in \((a-b)^2\), the last term is always \(b^2\).
Frequently asked questions
What is the correct answer to this question?
\(121\)
Why is this the correct answer?
Using the identity \((a-b)^2=a^2-2ab+b^2\), we get \((n-11)^2=n^2-22n+121\). Therefore, the last term is \(121\). \(-22n\) is the middle term; the last term is \(11^2\), which is positive. Exam tip: in \((a-b)^2\), the last term is always \(b^2\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Exploring Algebraic Identities. Topic: Algebraic identities.
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