What is the correct factorisation of (36-x^2)?
Answer and explanation
Correct answer: \((6+x)(6-x)\)
This is a difference of squares: \(36-x^2=6^2-x^2\). Using \(a^2-b^2=(a+b)(a-b)\), we get \((6+x)(6-x)\). Option A expands to \(x^2-36\), which is the negative of the given expression. Exam tip: first identify the square roots of both terms, then write one sum factor and one difference factor.
Frequently asked questions
What is the correct answer to this question?
\((6+x)(6-x)\)
Why is this the correct answer?
This is a difference of squares: \(36-x^2=6^2-x^2\). Using \(a^2-b^2=(a+b)(a-b)\), we get \((6+x)(6-x)\). Option A expands to \(x^2-36\), which is the negative of the given expression. Exam tip: first identify the square roots of both terms, then write one sum factor and one difference factor.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Exploring Algebraic Identities. Topic: Algebraic identities.
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