यदि (p(x)=2x-2 -7x+3), तो शून्यकों का योग क्या है?
If (p(x)=2x-2 -7x+3), what is the sum of its zeroes?
#sum-zeroes
#quadratic
#polynomial
A \(\frac{7}{2}\)
B \(-\frac{7}{2}\)
C \(\frac{3}{2}\)
D \(-\frac{3}{2}\)
Explanation opens after your attempt
Correct Answer
A. \(\frac{7}{2}\)
Step 1
Concept
For \(ax^2+bx+c\), the sum of zeroes is \(-\frac{b}{a}\). Here \(-\frac{-7}{2}=\frac{7}{2}\).
Step 2
Why this answer is correct
The correct answer is A. \(\frac{7}{2}\). For \(ax^2+bx+c\), the sum of zeroes is \(-\frac{b}{a}\). Here \(-\frac{-7}{2}=\frac{7}{2}\).
Step 3
Exam Tip
द्विघात \(ax^2+bx+c\) में शून्यकों का योग \(-\frac{b}{a}\) होता है। यहाँ \(-\frac{-7}{2}=\frac{7}{2}\) है।
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यदि (p(x)=x-2 +6x+9) है, तो इसका शून्यक कैसा है?
If (p(x)=x-2 +6x+9), what type of zero does it have?
#equal-zeroes
#perfect-square
#polynomial
A दो समान शून्यक (-3,-3) / Two equal zeroes (-3,-3)
B दो भिन्न शून्यक (3,-3) / Two distinct zeroes (3,-3)
C कोई वास्तविक शून्यक नहीं / No real zero
D एक शून्यक (0) / One zero (0)
Explanation opens after your attempt
Correct Answer
A. दो समान शून्यक (-3,-3) / Two equal zeroes (-3,-3)
Step 1
Concept
(x-2 +6x+9=(x+3)2 ), so (-3) occurs twice. A perfect square trinomial gives equal zeroes.
Step 2
Why this answer is correct
The correct answer is A. दो समान शून्यक (-3,-3) / Two equal zeroes (-3,-3). (x-2 +6x+9=(x+3)2 ), so (-3) occurs twice. A perfect square trinomial gives equal zeroes.
Step 3
Exam Tip
(x-2 +6x+9=(x+3)2 ), इसलिए शून्यक (-3) दो बार आता है। पूर्ण वर्ग त्रिपद समान शून्यक देता है।
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यदि (p(x)=x-2 -9), तो (p(x)) के शून्यक कौन-से हैं?
If (p(x)=x-2 -9), what are the zeroes of (p(x))?
#zeroes
#factorisation
#polynomial
A (3,-3)
B (0,9)
C (1,-9)
D (9,-9)
Explanation opens after your attempt
Step 1
Concept
(x-2 -9=(x-3)(x+3)), so the zeroes are (3) and (-3). Identify difference of squares quickly.
Step 2
Why this answer is correct
The correct answer is A. (3,-3). (x-2 -9=(x-3)(x+3)), so the zeroes are (3) and (-3). Identify difference of squares quickly.
Step 3
Exam Tip
(x-2 -9=(x-3)(x+3)), इसलिए शून्यक (3) और (-3) हैं। वर्गों के अंतर को तुरंत पहचानें।
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यदि (p(x)=x-3 -3x-2 +3x-1), तो (x=1) पर (p(x)) का मान क्या है?
If (p(x)=x-3 -3x-2 +3x-1), what is the value of (p(x)) at (x=1)?
#identity
#evaluation
#polynomial
A (0)
B (1)
C (-1)
D (3)
Explanation opens after your attempt
Step 1
Concept
It is ((x-1)3 ), so at (x=1) the value is (0). Recognizing identities saves time.
Step 2
Why this answer is correct
The correct answer is A. (0). It is ((x-1)3 ), so at (x=1) the value is (0). Recognizing identities saves time.
Step 3
Exam Tip
यह ((x-1)3 ) है, इसलिए (x=1) पर मान (0) है। पहचान सूत्र देखकर समय बचाइए।
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किस मान के लिए (p(x)=(m-2 )x-4 +3x-2 +x+1) की घात (2) से अधिक नहीं होगी?
For which value will (p(x)=(m-2 )x-4 +3x-2 +x+1) have degree not more than (2)?
#degree
#parameter
#polynomial
A (m=2)
B (m=0)
C (m=1)
D (m=-2)
Explanation opens after your attempt
Step 1
Concept
To make the degree not more than (2), the coefficient of \(x^4\) must be (0), so (m-2 =0). Degree reduces only when the highest term vanishes.
Step 2
Why this answer is correct
The correct answer is A. (m=2). To make the degree not more than (2), the coefficient of \(x^4\) must be (0), so (m-2 =0). Degree reduces only when the highest term vanishes.
Step 3
Exam Tip
घात (2) से अधिक न हो इसके लिए \(x^4\) का गुणांक (0) चाहिए, अतः (m-2 =0)। उच्चतम पद हटाकर ही घात घटती है।
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यदि (p(x)=3x-2 -7x+5), तो (p(2)-p(1)) का मान क्या है?
If (p(x)=3x-2 -7x+5), what is the value of (p(2)-p(1))?
#evaluation
#polynomial
#value
A (-1)
B (1)
C (3)
D (-3)
Explanation opens after your attempt
Step 1
Concept
(p(2)=12-14+5=3) and (p(1)=3-7+5=1), so the difference is (2). Match every option after calculation to avoid traps.
Step 2
Why this answer is correct
The correct answer is A. (-1). (p(2)=12-14+5=3) and (p(1)=3-7+5=1), so the difference is (2). Match every option after calculation to avoid traps.
Step 3
Exam Tip
(p(2)=12-14+5=3) और (p(1)=3-7+5=1), इसलिए अंतर (2) है। यहाँ सही विकल्प (2) होना चाहिए था, इसलिए गणना से विकल्प मिलाइए।
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यदि (p(x)=x-4 -5x-2 +4) है, तो (p(x)) का घात कितना है?
If (p(x)=x-4 -5x-2 +4), what is the degree of (p(x))?
#degree
#polynomial
#one-variable
A (4)
B (2)
C (5)
D (0)
Explanation opens after your attempt
Step 1
Concept
The highest power is \(x^4\), so the degree is (4). Terms with zero coefficients do not affect the degree.
Step 2
Why this answer is correct
The correct answer is A. (4). The highest power is \(x^4\), so the degree is (4). Terms with zero coefficients do not affect the degree.
Step 3
Exam Tip
सबसे बड़ी घात \(x^4\) है, इसलिए घात (4) है। शून्य गुणांक वाले पदों को घात तय करने में नहीं गिनते।
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यदि (p(x)=x-2 -6x+5), तो (p(x)-p(1)) क्या है?
If (p(x)=x-2 -6x+5), what is (p(x)-p(1))?
#evaluation
#subtraction
#polynomial
A \(x^2-6x+5\)
B \(x^2-6x+4\)
C \(x^2-6x\)
D \(x^2-6x+6\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-6x+5\)
Step 1
Concept
(p(1)=1-6+5=0), so (p(x)-p(1)=p(x)=x-2 -6x+5). Find (p(1)) first.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-6x+5\). (p(1)=1-6+5=0), so (p(x)-p(1)=p(x)=x-2 -6x+5). Find (p(1)) first.
Step 3
Exam Tip
(p(1)=1-6+5=0), इसलिए (p(x)-p(1)=p(x)=x-2 -6x+5)। पहले (p(1)) निकालें।
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यदि (p(x)=3x-2 -2x+5), तो (p(2x)) क्या है?
If (p(x)=3x-2 -2x+5), what is (p(2x))?
#substitution
#composition
#polynomial
A \(12x^2-4x+5\)
B \(6x^2-4x+5\)
C \(12x^2-2x+5\)
D \(3x^2-4x+5\)
Explanation opens after your attempt
Correct Answer
A. \(12x^2-4x+5\)
Step 1
Concept
(p(2x)=3(2x)2 -2(2x)+5=12x-2 -4x+5). Square the whole (2x).
Step 2
Why this answer is correct
The correct answer is A. \(12x^2-4x+5\). (p(2x)=3(2x)2 -2(2x)+5=12x-2 -4x+5). Square the whole (2x).
Step 3
Exam Tip
(p(2x)=3(2x)2 -2(2x)+5=12x-2 -4x+5)। पूरे (2x) का वर्ग करें।
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यदि (p(x)=x-2 +4x+6), तो (p(x-1)) क्या होगा?
If (p(x)=x-2 +4x+6), what is (p(x-1))?
#composition
#substitution
#polynomial
A \(x^2+2x+3\)
B \(x^2+2x+1\)
C \(x^2+4x+3\)
D \(x^2-2x+3\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+2x+3\)
Step 1
Concept
(p(x-1)=(x-1)2 +4(x-1)+6=x-2 +2x+3). Substitute the whole (x-1) in place of (x).
Step 2
Why this answer is correct
The correct answer is A. \(x^2+2x+3\). (p(x-1)=(x-1)2 +4(x-1)+6=x-2 +2x+3). Substitute the whole (x-1) in place of (x).
Step 3
Exam Tip
(p(x-1)=(x-1)2 +4(x-1)+6=x-2 +2x+3)। (x) की जगह पूरा (x-1) रखें।
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कौन सा बहुपद (x=0) को शून्य बनाता है?
Which polynomial makes (x=0) a zero?
#zero at zero
#constant term
#polynomial
A \(x^2+5\)
B \(3x^3-2x\)
C \(x^4+1\)
D \(2x^2-7x+9\)
Explanation opens after your attempt
Correct Answer
B. \(3x^3-2x\)
Step 1
Concept
Substituting (x=0) in \(3x^3-2x\) gives (0). To make (x=0) a zero, the constant term must be (0).
Step 2
Why this answer is correct
The correct answer is B. \(3x^3-2x\). Substituting (x=0) in \(3x^3-2x\) gives (0). To make (x=0) a zero, the constant term must be (0).
Step 3
Exam Tip
(x=0) रखने पर \(3x^3-2x=0\) मिलता है। (x=0) को शून्य बनाने के लिए अचर पद (0) होना चाहिए।
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(p(x)=3x-5 -2x-4 +7x-6) में \(x^3\) का गुणांक क्या है?
What is the coefficient of \(x^3\) in (p(x)=3x-5 -2x-4 +7x-6)?
#missing term
#coefficient
#polynomial
A (0)
B (3)
C (-2)
D (7)
Explanation opens after your attempt
Step 1
Concept
The \(x^3\)-term is missing, so its coefficient is (0). Treat the missing term as \(0x^3\).
Step 2
Why this answer is correct
The correct answer is A. (0). The \(x^3\)-term is missing, so its coefficient is (0). Treat the missing term as \(0x^3\).
Step 3
Exam Tip
\(x^3\) का पद अनुपस्थित है, इसलिए उसका गुणांक (0) है। अनुपस्थित पद को \(0x^3\) मानें।
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(\(x^2-4\)\(x^2+4\)) का विस्तृत रूप क्या है?
What is the expanded form of (\(x^2-4\)\(x^2+4\))?
#identity
#expansion
#polynomial
A \(x^4-16\)
B \(x^4+16\)
C \(x^4-8x^2+16\)
D \(x^4+8x^2+16\)
Explanation opens after your attempt
Correct Answer
A. \(x^4-16\)
Step 1
Concept
This is the identity \(a^2-b^2\), so (\(x^2\)2 -42 =x-4 -16). Identities make expansion faster.
Step 2
Why this answer is correct
The correct answer is A. \(x^4-16\). This is the identity \(a^2-b^2\), so (\(x^2\)2 -42 =x-4 -16). Identities make expansion faster.
Step 3
Exam Tip
यह \(a^2-b^2\) की पहचान है, इसलिए (\(x^2\)2 -42 =x-4 -16)। पहचान से विस्तार तेज होता है।
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((x+6)2 -(x-2)2 ) का सरल बहुपद रूप क्या है?
What is the simplified polynomial form of ((x+6)2 -(x-2)2 )?
#identity
#expansion
#polynomial
A (8x+32)
B (16x+32)
C (8x+16)
D (4x+32)
Explanation opens after your attempt
Correct Answer
B. (16x+32)
Step 1
Concept
((x+6)2 -(x-2)2 =((x+6)-(x-2))((x+6)+(x-2))=8(2x+4)=16x+32). Use the difference of squares identity.
Step 2
Why this answer is correct
The correct answer is B. (16x+32). ((x+6)2 -(x-2)2 =((x+6)-(x-2))((x+6)+(x-2))=8(2x+4)=16x+32). Use the difference of squares identity.
Step 3
Exam Tip
((x+6)2 -(x-2)2 =((x+6)-(x-2))((x+6)+(x-2))=8(2x+4)=16x+32)। अंतर के वर्ग की पहचान लगाएं।
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((3x-2)\(x^2+5x-1\)) में अचर पद क्या है?
What is the constant term in ((3x-2)\(x^2+5x-1\))?
#constant term
#multiplication
#polynomial
A (-3)
B (-2)
C (2)
D (3)
Explanation opens after your attempt
Step 1
Concept
The constant term comes only from ((-2)(-1)=2). For the constant term, multiply the constant parts.
Step 2
Why this answer is correct
The correct answer is C. (2). The constant term comes only from ((-2)(-1)=2). For the constant term, multiply the constant parts.
Step 3
Exam Tip
अचर पद केवल ((-2)(-1)=2) से आता है। अचर पद के लिए अचर भागों का गुणन देखें।
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(p(x)=5x-5 -3x-4 +2x-3 -x+6) में विषम घात वाले पदों के गुणांकों का योग क्या है?
What is the sum of coefficients of odd-power terms in (p(x)=5x-5 -3x-4 +2x-3 -x+6)?
#coefficients
#odd powers
#polynomial
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
The coefficients of odd powers \(x^5\), \(x^3\), and (x) are (5), (2), and (-1). Their sum is (6).
Step 2
Why this answer is correct
The correct answer is C. (6). The coefficients of odd powers \(x^5\), \(x^3\), and (x) are (5), (2), and (-1). Their sum is (6).
Step 3
Exam Tip
विषम घातों \(x^5\), \(x^3\) और (x) के गुणांक (5), (2) और (-1) हैं। उनका योग (6) है।
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यदि बहुपद (p(x)=3x-3 +kx-2 -7x+2) में सभी गुणांकों का योग (5) है, तो (k) क्या है?
If the sum of all coefficients of (p(x)=3x-3 +kx-2 -7x+2) is (5), what is (k)?
#sum of coefficients
#parameter
#polynomial
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
The sum of coefficients is (3+k-7+2=k-2), so (k-2=5) and (k=7). The sum of coefficients is (p(1)).
Step 2
Why this answer is correct
The correct answer is C. (7). The sum of coefficients is (3+k-7+2=k-2), so (k-2=5) and (k=7). The sum of coefficients is (p(1)).
Step 3
Exam Tip
गुणांकों का योग (3+k-7+2=k-2) है, इसलिए (k-2=5) और (k=7)। गुणांकों का योग (p(1)) होता है।
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(p(x)=7x-3 -4x-2 -2x-1) में सभी गुणांकों का योग क्या है?
What is the sum of all coefficients in (p(x)=7x-3 -4x-2 -2x-1)?
#sum of coefficients
#evaluation
#polynomial
A (0)
B (1)
C (2)
D (4)
Explanation opens after your attempt
Step 1
Concept
The sum of all coefficients is (7-4-2-1=0). It is also equal to (p(1)).
Step 2
Why this answer is correct
The correct answer is A. (0). The sum of all coefficients is (7-4-2-1=0). It is also equal to (p(1)).
Step 3
Exam Tip
सभी गुणांकों का योग (7-4-2-1=0) है। यह (p(1)) के बराबर भी होता है।
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यदि (p(x)) की घात (5) और (q(x)) की घात (2) है, तो अशून्य (p(x)q(x)) की घात क्या होगी?
If the degree of (p(x)) is (5) and the degree of (q(x)) is (2), what is the degree of non-zero (p(x)q(x))?
#degree
#product
#polynomial
A (3)
B (5)
C (7)
D (10)
Explanation opens after your attempt
Step 1
Concept
In the product of two non-zero polynomials, degrees add, so (5+2=7). Remember degree addition in multiplication.
Step 2
Why this answer is correct
The correct answer is C. (7). In the product of two non-zero polynomials, degrees add, so (5+2=7). Remember degree addition in multiplication.
Step 3
Exam Tip
दो अशून्य बहुपदों के गुणन में घातें जुड़ती हैं, इसलिए (5+2=7)। गुणन में घातों का योग याद रखें।
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यदि (p(x)=(m+2)x-5 +(m-3 )x-4 +6x-1) की घात (4) है, तो (m) क्या होगा?
If the degree of (p(x)=(m+2)x-5 +(m-3 )x-4 +6x-1) is (4), what is (m)?
#degree
#parameter
#polynomial
A (-2)
B (2)
C (3)
D कोई मान नहीं / No value
Explanation opens after your attempt
Step 1
Concept
For degree (4), the coefficient of \(x^5\) must be (0) and the coefficient of \(x^4\) must be non-zero. Both conditions hold for (m=-2).
Step 2
Why this answer is correct
The correct answer is A. (-2). For degree (4), the coefficient of \(x^5\) must be (0) and the coefficient of \(x^4\) must be non-zero. Both conditions hold for (m=-2).
Step 3
Exam Tip
घात (4) के लिए \(x^5\) का गुणांक (0) और \(x^4\) का गुणांक अशून्य चाहिए। (m=-2) पर दोनों शर्तें पूरी होती हैं।
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यदि (p(x)=x-2 -4x+1), तो (p(x)-p(1)) क्या है?
If (p(x)=x-2 -4x+1), what is (p(x)-p(1))?
#evaluation
#subtraction
#polynomial
A \(x^2-4x+4\)
B \(x^2-4x-2\)
C \(x^2-4x+1\)
D \(x^2+4x+4\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-4x+4\)
Step 1
Concept
(p(1)=1-4+1=-2), so (p(x)-p(1)=x-2 -4x+3). None of the listed choices matches this value.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-4x+4\). (p(1)=1-4+1=-2), so (p(x)-p(1)=x-2 -4x+3). None of the listed choices matches this value.
Step 3
Exam Tip
(p(1)=1-4+1=-2), इसलिए (p(x)-p(1)=x-2 -4x+3) नहीं बल्कि \(x^2-4x+3\) है। सही गणना से विकल्पों में कोई नहीं होता।
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यदि (p(x)=2x-2 +3x-4), तो (p(2x)) क्या है?
If (p(x)=2x-2 +3x-4), what is (p(2x))?
#substitution
#composition
#polynomial
A \(8x^2+6x-4\)
B \(4x^2+6x-4\)
C \(8x^2+3x-4\)
D \(2x^2+6x-4\)
Explanation opens after your attempt
Correct Answer
A. \(8x^2+6x-4\)
Step 1
Concept
(p(2x)=2(2x)2 +3(2x)-4=8x-2 +6x-4). Square the whole (2x).
Step 2
Why this answer is correct
The correct answer is A. \(8x^2+6x-4\). (p(2x)=2(2x)2 +3(2x)-4=8x-2 +6x-4). Square the whole (2x).
Step 3
Exam Tip
(p(2x)=2(2x)2 +3(2x)-4=8x-2 +6x-4)। पूरे (2x) का वर्ग करें।
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यदि (p(x)=x-2 -2x+3), तो (p(x+1)) क्या होगा?
If (p(x)=x-2 -2x+3), what is (p(x+1))?
#composition
#substitution
#polynomial
A \(x^2+2\)
B \(x^2+1\)
C \(x^2-1\)
D \(x^2+2x+3\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+2\)
Step 1
Concept
(p(x+1)=(x+1)2 -2(x+1)+3=x-2 +2). Substitute the whole (x+1) in place of (x).
Step 2
Why this answer is correct
The correct answer is A. \(x^2+2\). (p(x+1)=(x+1)2 -2(x+1)+3=x-2 +2). Substitute the whole (x+1) in place of (x).
Step 3
Exam Tip
(p(x+1)=(x+1)2 -2(x+1)+3=x-2 +2)। (x) की जगह पूरा (x+1) रखें।
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कौन सा बहुपद (x=0) को शून्य नहीं बनाता?
Which polynomial does not make (x=0) a zero?
#zero at zero
#constant term
#polynomial
A \(x^3-2x\)
B \(5x^2+x\)
C \(x^4\)
D \(x^2+1\)
Explanation opens after your attempt
Correct Answer
D. \(x^2+1\)
Step 1
Concept
On substituting (x=0), \(x^2+1=1\), so (0) is not its zero. The constant term is decisive at (x=0).
Step 2
Why this answer is correct
The correct answer is D. \(x^2+1\). On substituting (x=0), \(x^2+1=1\), so (0) is not its zero. The constant term is decisive at (x=0).
Step 3
Exam Tip
(x=0) रखने पर \(x^2+1=1\), इसलिए (0) इसका शून्य नहीं है। (x=0) पर अचर पद निर्णायक होता है।
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कौन सा बहुपद पूर्ण वर्ग है?
Which polynomial is a perfect square?
#perfect square
#identity
#polynomial
A \(x^2+10x+25\)
B \(x^2+10x+20\)
C \(x^2+5x+25\)
D \(x^2-10x-25\)
Explanation opens after your attempt
Correct Answer
A. \(x^2+10x+25\)
Step 1
Concept
(x-2 +10x+25=(x+5)2 ). Check the squares of first and last terms and the middle term (2ab).
Step 2
Why this answer is correct
The correct answer is A. \(x^2+10x+25\). (x-2 +10x+25=(x+5)2 ). Check the squares of first and last terms and the middle term (2ab).
Step 3
Exam Tip
(x-2 +10x+25=(x+5)2 ) है। पहले और अंतिम पद के वर्ग तथा मध्य पद (2ab) को जांचें।
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(p(x)=2x-4 -3x-3 +5x-9) में \(x^2\) का गुणांक क्या है?
What is the coefficient of \(x^2\) in (p(x)=2x-4 -3x-3 +5x-9)?
#missing term
#coefficient
#polynomial
A (0)
B (2)
C (-3)
D (5)
Explanation opens after your attempt
Step 1
Concept
The \(x^2\)-term is missing, so its coefficient is (0). Treat the missing term as \(0x^2\).
Step 2
Why this answer is correct
The correct answer is A. (0). The \(x^2\)-term is missing, so its coefficient is (0). Treat the missing term as \(0x^2\).
Step 3
Exam Tip
\(x^2\) का पद अनुपस्थित है, इसलिए उसका गुणांक (0) है। अनुपस्थित पद को \(0x^2\) मानें।
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(\(x^2-1\)\(x^2+1\)) का विस्तृत रूप क्या है?
What is the expanded form of (\(x^2-1\)\(x^2+1\))?
#identity
#expansion
#polynomial
A \(x^4-1\)
B \(x^4+1\)
C \(x^4-2x^2+1\)
D \(x^4+2x^2+1\)
Explanation opens after your attempt
Correct Answer
A. \(x^4-1\)
Step 1
Concept
This is the identity \(a^2-b^2\), so (\(x^2\)2 -12 =x-4 -1). Identities make expansion faster.
Step 2
Why this answer is correct
The correct answer is A. \(x^4-1\). This is the identity \(a^2-b^2\), so (\(x^2\)2 -12 =x-4 -1). Identities make expansion faster.
Step 3
Exam Tip
यह \(a^2-b^2\) की पहचान है, इसलिए (\(x^2\)2 -12 =x-4 -1)। पहचान से विस्तार तेज होता है।
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((x+4)2 -(x-4)2 ) का सरल बहुपद रूप क्या है?
What is the simplified polynomial form of ((x+4)2 -(x-4)2 )?
#identity
#expansion
#polynomial
A (8x)
B (16x)
C \(x^2+16\)
D (32)
Explanation opens after your attempt
Step 1
Concept
((x+4)2 -(x-4)2 =16x). Use the identity (a-2 -b-2 =(a-b)(a+b)) for a quick solution.
Step 2
Why this answer is correct
The correct answer is B. (16x). ((x+4)2 -(x-4)2 =16x). Use the identity (a-2 -b-2 =(a-b)(a+b)) for a quick solution.
Step 3
Exam Tip
((x+4)2 -(x-4)2 =16x)। पहचान (a-2 -b-2 =(a-b)(a+b)) से जल्दी हल करें।
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((2x-3)\(x^2+x+1\)) में अचर पद क्या है?
What is the constant term in ((2x-3)\(x^2+x+1\))?
#constant term
#multiplication
#polynomial
A (-3)
B (-1)
C (1)
D (2)
Explanation opens after your attempt
Step 1
Concept
The constant term comes only from ((-3)\cdot1=-3). For the constant term, multiply the constant parts.
Step 2
Why this answer is correct
The correct answer is A. (-3). The constant term comes only from ((-3)\cdot1=-3). For the constant term, multiply the constant parts.
Step 3
Exam Tip
अचर पद केवल ((-3)\cdot1=-3) से आता है। अचर पद के लिए अचर पदों का गुणन देखें।
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(p(x)=3x-4 -5x-2 +2x-7) में विषम घात वाले पदों के गुणांकों का योग क्या है?
What is the sum of coefficients of the odd-power terms in (p(x)=3x-4 -5x-2 +2x-7)?
#coefficients
#odd powers
#polynomial
A (-7)
B (-5)
C (2)
D (5)
Explanation opens after your attempt
Step 1
Concept
The only odd-power term is (2x), so the sum is (2). Do not treat \(x^0\) as an odd power.
Step 2
Why this answer is correct
The correct answer is C. (2). The only odd-power term is (2x), so the sum is (2). Do not treat \(x^0\) as an odd power.
Step 3
Exam Tip
विषम घात वाला केवल (2x) पद है, इसलिए योग (2) है। \(x^0\) को विषम घात न मानें।
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