For which value will (p(x)=(m-2)x^4+3x^2+x+1) have degree not more than (2)?किस मान के लिए (p(x)=(m-2)x^4+3x^2+x+1) की घात (2) से अधिक नहीं होगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (m=2)(m=2)
To make the degree not more than (2), the coefficient of (x^4) must be (0), so (m-2=0). Degree reduces only when the highest term vanishes.घात (2) से अधिक न हो इसके लिए (x^4) का गुणांक (0) चाहिए, अतः (m-2=0)। उच्चतम पद हटाकर ही घात घटती है।
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