calculation se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.
41 questions tagged with calculation.
In (2x+3y=18), if (y=4), what is (x)?
A. (x=3)
(2x+12=18), इसलिए (2x=6) और (x=3)। पहले गुणा करके स्थिर पद अलग करें। / (2x+12=18), so (2x=6) and (x=3). Multiply first and then separate the constant term.
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What is the value of \(4^0+5^2\)?
B. (26)
यहाँ \(4^0=1\) और \(5^2=25\) है। इसलिए (1+25=26) है। / Here \(4^0=1\) and \(5^2=25\). Therefore (1+25=26).
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What is the value of \(9^0+3^2\)?
B. (10)
यहाँ \(9^0=1\) और \(3^2=9\) है। इसलिए (1+9=10) है। / Here \(9^0=1\) and \(3^2=9\). Therefore (1+9=10).
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What is the discriminant (D) of \(3x^2-11x+2=0\)?
A. (97)
यहां (D=(-11)2-4(3)(2)=97) है। परीक्षा में (a,b,c) सही पहचानकर (D) निकालें। / Here (D=(-11)2-4(3)(2)=97). In exams, identify (a,b,c) correctly while finding (D).
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Using the quadratic formula setup, what is the value of (D) for \(5x^2-10x-3=0\)?
A. (160)
यहां (D=(-10)2-4(5)(-3)=160) है। परीक्षा में ऋणात्मक (c) के कारण दूसरा पद जुड़ता है। / Here (D=(-10)2-4(5)(-3)=160). In exams, a negative (c) makes the second term add.
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What is the discriminant (D) of \(2x^2-7x+1=0\)?
A. (41)
यहां (D=(-7)2-4(2)(1)=41) है। परीक्षा में (D) निकालते समय (a,b,c) सही पहचानें। / Here (D=(-7)2-4(2)(1)=41). In exams, identify (a,b,c) correctly while finding (D).
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Using the quadratic formula setup, what is the value of (D) for \(3x^2-6x-2=0\)?
A. (60)
यहां (D=(-6)2-4(3)(-2)=60) है। परीक्षा में ऋणात्मक (c) के कारण दूसरा पद जुड़ता है। / Here (D=(-6)2-4(3)(-2)=60). In exams, a negative (c) makes the second term add.
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What is the discriminant (D) of \(4x^2-8x-1=0\)?
A. (80)
यहां (D=(-8)2-4(4)(-1)=80) है। परीक्षा में ऋणात्मक (c) से (D) बढ़ जाता है। / Here (D=(-8)2-4(4)(-1)=80). In exams, a negative (c) increases (D).
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Using the quadratic formula setup, what is the value of (D) for \(2x^2-4x-3=0\)?
A. (40)
यहां (D=(-4)2-4(2)(-3)=40) है। परीक्षा में ऋणात्मक (c) के कारण जोड़ बनता है। / Here (D=(-4)2-4(2)(-3)=40). In exams, a negative (c) makes the term add.
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What will be the discriminant (D) of \(x^2+2x+1=0\)?
A. (0)
यहां (D=22-4(1)(1)=0) है। परीक्षा में (D=0) से समान मूल मिलते हैं। / Here (D=22-4(1)(1)=0). In exams, (D=0) gives equal roots.
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What will be the discriminant (D) of \(x^2-2x+1=0\)?
A. (0)
यहां (D=(-2)2-4(1)(1)=0) है। परीक्षा में (b) का चिन्ह लगाकर वर्ग करें। / Here (D=(-2)2-4(1)(1)=0). In exams, square (b) with its sign.
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What is the discriminant (D) of \(x^2-4x+4=0\)?
A. (0)
यहां (a=1), (b=-4), (c=4), इसलिए (D=(-4)2-4(1)(4)=0)। परीक्षा में संकेत सहित (b) रखें। / Here (a=1), (b=-4), (c=4), so (D=(-4)2-4(1)(4)=0). In exams, use (b) with its sign.
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If \(\alpha\) and \(\beta\) are roots of \(6x^2+5x-4=0\), what is \(\alpha\beta\)?
A. -\(\frac{2}{3}\)
मूलों का गुणनफल \(\frac{c}{a}=\frac{-4}{6}=-\frac{2}{3}\) होता है। (c) का चिन्ह न भूलें। / The product of roots is \(\frac{c}{a}=\frac{-4}{6}=-\frac{2}{3}\). Do not forget the sign of (c).
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If \(\alpha\) and \(\beta\) are roots of \(4x^2-20x+7=0\), what is \(\alpha+\beta\)?
A. (5)
मूलों का योग \(-\frac{b}{a}=-\frac{-20}{4}=5\) है। सूत्र में (b) का चिन्ह सही रखें। / The sum of roots is \(-\frac{b}{a}=-\frac{-20}{4}=5\). Keep the sign of (b) correct in the formula.
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If \(\alpha\) and \(\beta\) are roots of \(5x^2+3x-2=0\), what is \(\alpha\beta\)?
A. -\(\frac{2}{5}\)
मूलों का गुणनफल \(\frac{c}{a}=\frac{-2}{5}\) होता है। (c) का चिन्ह न भूलें। / The product of roots is \(\frac{c}{a}=\frac{-2}{5}\). Do not forget the sign of (c).
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If \(\alpha\) and \(\beta\) are roots of \(3x^2-12x+5=0\), what is \(\alpha+\beta\)?
A. (4)
मूलों का योग \(-\frac{b}{a}=-\frac{-12}{3}=4\) है। सूत्र में (b) का चिन्ह सही रखें। / The sum of roots is \(-\frac{b}{a}=-\frac{-12}{3}=4\). Keep the sign of (b) correct in the formula.
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If \(\alpha\) and \(\beta\) are roots of \(4x^2+4x-3=0\), what is \(\alpha\beta\)?
A. -\(\frac{3}{4}\)
मूलों का गुणनफल \(\frac{c}{a}=\frac{-3}{4}\) होता है। (c) का चिन्ह न भूलें। / The product of roots is \(\frac{c}{a}=\frac{-3}{4}\). Do not forget the sign of (c).
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If \(\alpha\) and \(\beta\) are roots of \(2x^2-6x+1=0\), what is \(\alpha+\beta\)?
A. (3)
मूलों का योग \(-\frac{b}{a}=-\frac{-6}{2}=3\) है। सूत्र में (b) का चिन्ह सही रखें। / The sum of roots is \(-\frac{b}{a}=-\frac{-6}{2}=3\). Keep the sign of (b) correct in the formula.
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What is the discriminant (D) of \(x^2+4x+4=0\)?
B. (0)
यहां \(D=b^2-4ac=16-16=0\) है। इसलिए दोनों मूल बराबर होंगे। / Here \(D=b^2-4ac=16-16=0\). Therefore the two roots will be equal.
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What is the value of discriminant (D) for \(x^2-4x+4=0\)?
B. (0)
यहां \(D=b^2-4ac=16-16=0\) है। इसलिए इसके मूल बराबर होंगे। / Here \(D=b^2-4ac=16-16=0\). Therefore its roots will be equal.
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Which option gives the correct simplified form of \(\sqrt{50}+3\sqrt{8}-\sqrt{18}\)?
A. \(8\sqrt{2}\)
\(\sqrt{50}=5\sqrt{2}\), \(3\sqrt{8}=6\sqrt{2}\) और \(\sqrt{18}=3\sqrt{2}\) है। इसलिए मान \(8\sqrt{2}\) है। / \(\sqrt{50}=5\sqrt{2}\), \(3\sqrt{8}=6\sqrt{2}\) and \(\sqrt{18}=3\sqrt{2}\). Hence the value is \(8\sqrt{2}\).
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Which option is the value of \(\sqrt{0.49}+\frac{1}{\sqrt{25}}\)?
A. (0.9)
\(\sqrt{0.49}=0.7\) और \(\frac{1}{\sqrt{25}}=\frac{1}{5}=0.2\) है। योग (0.9) है। / \(\sqrt{0.49}=0.7\) and \(\frac{1}{\sqrt{25}}=\frac{1}{5}=0.2\). The sum is (0.9).
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Which option is the value of \(\sqrt{0.36}+\sqrt{0.49}\)?
A. (1.3)
\(\sqrt{0.36}=0.6\) और \(\sqrt{0.49}=0.7\) है। योग (1.3) है जो परिमेय है। / \(\sqrt{0.36}=0.6\) and \(\sqrt{0.49}=0.7\). The sum is (1.3), which is rational.
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Which option is the value of (\(\sqrt{3}+\sqrt{12}\)2)?
A. (27)
\(\sqrt{12}=2\sqrt{3}\) इसलिए कोष्ठक \(3\sqrt{3}\) बनता है। उसका वर्ग (27) है। / \(\sqrt{12}=2\sqrt{3}\), so the bracket becomes \(3\sqrt{3}\). Its square is (27).
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Which option is the value of \(\sqrt{0.64}+\sqrt{0.09}\)?
A. (1.1)
\(\sqrt{0.64}=0.8\) और \(\sqrt{0.09}=0.3\) है। योग (1.1) है। / \(\sqrt{0.64}=0.8\) and \(\sqrt{0.09}=0.3\). The sum is (1.1).
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Which option is the value of \(\sqrt{0.81}\)?
A. (0.9)
\(0.9\times0.9=0.81\) इसलिए \(\sqrt{0.81}=0.9\)। यह सांत दशमलव है। / Since \(0.9\times0.9=0.81\), \(\sqrt{0.81}=0.9\). It is a terminating decimal.
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Which option is the value of \(\sqrt{0.25}+\sqrt{0.04}\)?
A. (0.7)
\(\sqrt{0.25}=0.5\) और \(\sqrt{0.04}=0.2\) है। योग (0.7) है जो परिमेय है। / \(\sqrt{0.25}=0.5\) and \(\sqrt{0.04}=0.2\). The sum is (0.7), which is rational.
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Which option is the value of \(\sqrt{0.16}\)?
A. (0.4)
\(0.4\times0.4=0.16\) इसलिए \(\sqrt{0.16}=0.4\)। यह परिमेय संख्या है। / Since \(0.4\times0.4=0.16\), \(\sqrt{0.16}=0.4\). This is a rational number.
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Which option is the value of \(\sqrt{\frac{49}{64}}\)?
A. \(\frac{7}{8}\)
\(\sqrt{\frac{49}{64}}=\frac{\sqrt{49}}{\sqrt{64}}=\frac{7}{8}\) है। यह परिमेय संख्या है। / \(\sqrt{\frac{49}{64}}=\frac{\sqrt{49}}{\sqrt{64}}=\frac{7}{8}\). This is a rational number.
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If \(x=\sqrt{19}\), what is \(x^2\)?
A. (19)
(\(\sqrt{19}\)2=19) होता है। वर्ग करने पर वर्गमूल हट जाती है। / (\(\sqrt{19}\)2=19). Squaring removes the square root.
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