Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 251-260 of 600 questions.
If (q(t)=0) in a quadratic equation (q(x)=0), what is (t) called?
A. मूलRoot
(q(t)=0) का अर्थ है कि (x=t) रखने पर समीकरण सत्य है। इसलिए (t) उस समीकरण का मूल है। / (q(t)=0) means the equation is true when (x=t). Therefore (t) is a root of the equation.
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Is (x=5) a root of \(x^2-10x+25=0\)?
A. हाँYes
(x=5) रखने पर (25-50+25=0) मिलता है। इसलिए (5) इसका मूल है। / Putting (x=5) gives (25-50+25=0). Therefore (5) is its root.
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Is (x=-3) a root of \(2x^2+7x+3=0\)?
A. हाँYes
(x=-3) रखने पर (18-21+3=0) मिलता है। ऋणात्मक मूल रखते समय चिन्हों को ध्यान से देखें। / Putting (x=-3) gives (18-21+3=0). Watch the signs carefully when substituting a negative root.
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What are the roots of \(x^2-14x+45=0\)?
A. (5) और (9)(5) and (9)
(x-2-14x+45=(x-5)(x-9)) है। इसलिए मूल (5) और (9) हैं। / (x-2-14x+45=(x-5)(x-9)). Therefore the roots are (5) and (9).
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What are the roots of \(4x^2-17x+4=0\)?
A. (4) और \(\frac{1}{4}\)(4) and \(\frac{1}{4}\)
(4x-2-17x+4=(4x-1)(x-4)) है। इसलिए मूल \(\frac{1}{4}\) और (4) हैं। / (4x-2-17x+4=(4x-1)(x-4)). Therefore the roots are \(\frac{1}{4}\) and (4).
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What are the roots of \(5x^2+16x+3=0\)?
A. (-3) और \(-\frac{1}{5}\)(-3) and \(-\frac{1}{5}\)
(5x-2+16x+3=(5x+1)(x+3)) है। इसलिए मूल \(-\frac{1}{5}\) और (-3) हैं। / (5x-2+16x+3=(5x+1)(x+3)). Therefore the roots are \(-\frac{1}{5}\) and (-3).
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Which equation has roots (3) and (-8)?
A. \(x^2+5x-24=0\)
मूल (3) और (-8) होने पर ((x-3)(x+8)=0) होगा। खोलने पर \(x^2+5x-24=0\) मिलता है। / With roots (3) and (-8), we get ((x-3)(x+8)=0). Expanding gives \(x^2+5x-24=0\).
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If (4) is a root of \(x^2+kx-32=0\), what is the value of (k)?
A. (4)
(x=4) रखने पर (16+4k-32=0) इसलिए (k=4) है। पैरामीटर के लिए दिए गए मूल को सीधे रखें। / Putting (x=4) gives (16+4k-32=0), so (k=4). Substitute the given root directly for a parameter.
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What is the sum of roots of \(6x^2-13x+5=0\)?
A. \(\frac{13}{6}\)
मूलों का योग \(-\frac{b}{a}\) होता है। यहां (a=6) और (b=-13) हैं इसलिए योग \(\frac{13}{6}\) है। / The sum of roots is \(-\frac{b}{a}\). Here (a=6) and (b=-13), so the sum is \(\frac{13}{6}\).
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What is the product of roots of \(7x^2+4x-9=0\)?
A. -\(\frac{9}{7}\)
मूलों का गुणनफल \(\frac{c}{a}\) होता है। यहां \(\frac{-9}{7}=-\frac{9}{7}\) सही है। / The product of roots is \(\frac{c}{a}\). Here \(\frac{-9}{7}=-\frac{9}{7}\) is correct.
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