Question 1 / 11
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Time 06:25
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यदि \(a_1=3\), \(a_2=5\) और \(a_n=a_{n-1}+2a_{n-2}\) है तो \(a_5\) क्या होगा?
If \(a_1=3\), \(a_2=5\), and \(a_n=a_{n-1}+2a_{n-2}\), what is \(a_5\)?
Explanation opens after your attempt
Step 1
Concept
The terms are (3,5,11,21,43), so \(a_5=43\). The correct option should include (43).
Step 2
Why this answer is correct
The correct answer is C. (31). The terms are (3,5,11,21,43), so \(a_5=43\). The correct option should include (43).
Step 3
Exam Tip
पद (3,5,11,21,43) नहीं बल्कि \(a_5=43\) होता है। सही विकल्प में (43) होना चाहिए।
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यदि \(a_1=3\), \(a_2=5\) और \(a_n=a_{n-1}+2a_{n-2}\) है तो \(a_4\) क्या होगा?
If \(a_1=3\), \(a_2=5\), and \(a_n=a_{n-1}+2a_{n-2}\), what is \(a_4\)?
Explanation opens after your attempt
Step 1
Concept
\(a_3=5+2\times3=11\) and \(a_4=11+2\times5=21\). Exam tip: write positions while using two-term rules.
Step 2
Why this answer is correct
The correct answer is C. (21). \(a_3=5+2\times3=11\) and \(a_4=11+2\times5=21\). Exam tip: write positions while using two-term rules.
Step 3
Exam Tip
\(a_3=5+2\times3=11\) और \(a_4=11+2\times5=21\) है। दो-पद नियम में क्रमांक साथ लिखें।
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यदि \(a_1=6\) और \(a_{n+1}=a_n+2a_1+n\) है तो \(a_3\) क्या होगा?
If \(a_1=6\) and \(a_{n+1}=a_n+2a_1+n\), what is \(a_3\)?
Explanation opens after your attempt
Step 1
Concept
\(a_2=6+12+1=19\) and \(a_3=19+12+2=33\). The correct option should be (33).
Step 2
Why this answer is correct
The correct answer is B. (31). \(a_2=6+12+1=19\) and \(a_3=19+12+2=33\). The correct option should be (33).
Step 3
Exam Tip
\(a_2=6+12+1=19\) और \(a_3=19+12+2=33\) नहीं बल्कि (33) है। सही विकल्प (33) होना चाहिए।
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यदि \(a_1=6\) और \(a_{n+1}=a_n+2a_1+n\) है तो \(a_2\) क्या होगा?
If \(a_1=6\) and \(a_{n+1}=a_n+2a_1+n\), what is \(a_2\)?
Explanation opens after your attempt
Step 1
Concept
\(a_2=6+2\times6+1=19\). Exam tip: \(a_1\) stays fixed while (n) changes.
Step 2
Why this answer is correct
The correct answer is B. (19). \(a_2=6+2\times6+1=19\). Exam tip: \(a_1\) stays fixed while (n) changes.
Step 3
Exam Tip
\(a_2=6+2\times6+1=19\) है। \(a_1\) स्थिर रहता है और (n) बदलता है।
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यदि \(a_1=2\), \(a_2=4\) और \(a_n=a_{n-1}+a_{n-2}+n\) है तो \(a_4\) क्या होगा?
If \(a_1=2\), \(a_2=4\), and \(a_n=a_{n-1}+a_{n-2}+n\), what is \(a_4\)?
Explanation opens after your attempt
Step 1
Concept
\(a_3=4+2+3=9\) and \(a_4=9+4+4=17\). The correct option should include (17).
Step 2
Why this answer is correct
The correct answer is C. (14). \(a_3=4+2+3=9\) and \(a_4=9+4+4=17\). The correct option should include (17).
Step 3
Exam Tip
\(a_3=4+2+3=9\) और \(a_4=9+4+4=17\) है। सही विकल्प में (17) होना चाहिए।
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यदि \(a_1=2\), \(a_2=4\) और \(a_n=a_{n-1}+a_{n-2}+n\) है तो \(a_3\) क्या होगा?
If \(a_1=2\), \(a_2=4\), and \(a_n=a_{n-1}+a_{n-2}+n\), what is \(a_3\)?
Explanation opens after your attempt
Step 1
Concept
\(a_3=4+2+3=9\). Exam tip: add the current (n) along with the previous two terms.
Step 2
Why this answer is correct
The correct answer is C. (9). \(a_3=4+2+3=9\). Exam tip: add the current (n) along with the previous two terms.
Step 3
Exam Tip
\(a_3=4+2+3=9\) है। इस नियम में पिछले दो पदों के साथ वर्तमान (n) भी जोड़ें।
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यदि \(a_1=9\) और \(a_{n+1}=a_n+7\) है तो कौन सा पद (51) है?
If \(a_1=9\) and \(a_{n+1}=a_n+7\), which term is (51)?
Explanation opens after your attempt
Correct Answer
B. (7)वाँ/(7)th
Step 1
Concept
The terms are (9,16,23,30,37,44,51), so (51) is the seventh term. Exam tip: write terms with their positions.
Step 2
Why this answer is correct
The correct answer is B. (7)वाँ / (7)th. The terms are (9,16,23,30,37,44,51), so (51) is the seventh term. Exam tip: write terms with their positions.
Step 3
Exam Tip
पद (9,16,23,30,37,44,51) हैं इसलिए (51) सातवाँ पद है। पदों को क्रमांक के साथ लिखें।
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यदि \(a_1=4\) और \(a_{n+1}=2a_n+1\) है तो \(a_4-a_2\) का मान क्या होगा?
If \(a_1=4\) and \(a_{n+1}=2a_n+1\), what is the value of \(a_4-a_2\)?
Explanation opens after your attempt
Step 1
Concept
The terms are (4,9,19,39), so \(a_4-a_2=39-9=30\). Exam tip: find both terms first and then subtract.
Step 2
Why this answer is correct
The correct answer is B. (30). The terms are (4,9,19,39), so \(a_4-a_2=39-9=30\). Exam tip: find both terms first and then subtract.
Step 3
Exam Tip
पद (4,9,19,39) हैं इसलिए \(a_4-a_2=39-9=30\) है। पहले दोनों पद निकालें फिर घटाएँ।
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यदि \(a_1=3\), \(a_2=6\) और \(a_n=a_{n-1}+a_{n-2}+2\) है तो \(a_5\) क्या होगा?
If \(a_1=3\), \(a_2=6\), and \(a_n=a_{n-1}+a_{n-2}+2\), what is \(a_5\)?
Explanation opens after your attempt
Step 1
Concept
The terms are (3,6,11,19,32), so \(a_5=32\). The correct option should include (32).
Step 2
Why this answer is correct
The correct answer is B. (27). The terms are (3,6,11,19,32), so \(a_5=32\). The correct option should include (32).
Step 3
Exam Tip
पद (3,6,11,19,32) नहीं बल्कि \(a_5=32\) है। सही विकल्प में (32) होना चाहिए।
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यदि \(a_1=3\), \(a_2=6\) और \(a_n=a_{n-1}+a_{n-2}+2\) है तो \(a_4\) क्या होगा?
If \(a_1=3\), \(a_2=6\), and \(a_n=a_{n-1}+a_{n-2}+2\), what is \(a_4\)?
Explanation opens after your attempt
Step 1
Concept
\(a_3=6+3+2=11\) and \(a_4=11+6+2=19\). Exam tip: add the extra (2) at each step.
Step 2
Why this answer is correct
The correct answer is C. (19). \(a_3=6+3+2=11\) and \(a_4=11+6+2=19\). Exam tip: add the extra (2) at each step.
Step 3
Exam Tip
\(a_3=6+3+2=11\) और \(a_4=11+6+2=19\) है। अतिरिक्त (2) हर चरण में जोड़ें।
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यदि \(a_1=6\), \(a_2=10\) और \(a_n=2a_{n-1}+a_{n-2}-n\) है तो \(a_3\) क्या होगा?
If \(a_1=6\), \(a_2=10\), and \(a_n=2a_{n-1}+a_{n-2}-n\), what is \(a_3\)?
Explanation opens after your attempt
Step 1
Concept
\(a_3=2\times10+6-3=23\). Exam tip: subtract the current (n) in this two-term rule.
Step 2
Why this answer is correct
The correct answer is B. (23). \(a_3=2\times10+6-3=23\). Exam tip: subtract the current (n) in this two-term rule.
Step 3
Exam Tip
\(a_3=2\times10+6-3=23\) है। दो-पद नियम में वर्तमान (n) भी घटाएँ।
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