Question 1 / 10
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Time 05:50
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यदि \(a_1=1\), \(a_2=4\) और \(a_n=a_{n-1}+2a_{n-2}\) है तो \(a_5\) क्या होगा?
If \(a_1=1\), \(a_2=4\), and \(a_n=a_{n-1}+2a_{n-2}\), what is \(a_5\)?
Explanation opens after your attempt
Step 1
Concept
The terms are (1,4,6,14,26), so \(a_5=26\). Exam tip: multiply the second previous term by (2).
Step 2
Why this answer is correct
The correct answer is C. (26). The terms are (1,4,6,14,26), so \(a_5=26\). Exam tip: multiply the second previous term by (2).
Step 3
Exam Tip
पद (1,4,6,14,26) हैं इसलिए \(a_5=26\) है। पिछले दो पदों में दूसरे पिछले पद को (2) से गुणा करें।
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यदि \(a_1=2\), \(a_2=6\) और \(a_n=a_{n-1}+3a_{n-2}\) है तो \(a_4\) क्या होगा?
If \(a_1=2\), \(a_2=6\), and \(a_n=a_{n-1}+3a_{n-2}\), what is \(a_4\)?
Explanation opens after your attempt
Step 1
Concept
\(a_3=6+3\times2=12\) and \(a_4=12+3\times6=30\). Therefore the correct value is (30).
Step 2
Why this answer is correct
The correct answer is D. (32). \(a_3=6+3\times2=12\) and \(a_4=12+3\times6=30\). Therefore the correct value is (30).
Step 3
Exam Tip
\(a_3=6+3\times2=12\) और \(a_4=12+3\times6=30\) है। इसलिए सही मान (30) है।
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यदि \(a_1=2\), \(a_2=6\) और \(a_n=a_{n-1}+3a_{n-2}\) है तो \(a_3\) क्या होगा?
If \(a_1=2\), \(a_2=6\), and \(a_n=a_{n-1}+3a_{n-2}\), what is \(a_3\)?
Explanation opens after your attempt
Step 1
Concept
\(a_3=6+3\times2=12\). Exam tip: multiply \(a_{n-2}\) by (3) in this two-term rule.
Step 2
Why this answer is correct
The correct answer is B. (12). \(a_3=6+3\times2=12\). Exam tip: multiply \(a_{n-2}\) by (3) in this two-term rule.
Step 3
Exam Tip
\(a_3=6+3\times2=12\) है। दो-पद नियम में \(a_{n-2}\) को (3) से गुणा करें।
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यदि \(a_1=2\) और \(a_{n+1}=a_n+2a_1\) है तो \(a_4\) क्या होगा?
If \(a_1=2\) and \(a_{n+1}=a_n+2a_1\), what is \(a_4\)?
Explanation opens after your attempt
Step 1
Concept
Here \(2a_1=4\) is added each time, so the terms are (2,6,10,14). Exam tip: \(a_1\) stays constant.
Step 2
Why this answer is correct
The correct answer is C. (14). Here \(2a_1=4\) is added each time, so the terms are (2,6,10,14). Exam tip: \(a_1\) stays constant.
Step 3
Exam Tip
यहाँ \(2a_1=4\) हर बार जुड़ता है इसलिए पद (2,6,10,14) हैं। \(a_1\) स्थिर रहता है।
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यदि \(a_1=6\) और \(a_{n+1}=a_n+a_1+n\) है तो \(a_3\) क्या होगा?
If \(a_1=6\) and \(a_{n+1}=a_n+a_1+n\), what is \(a_3\)?
Explanation opens after your attempt
Step 1
Concept
\(a_2=6+6+1=13\) and \(a_3=13+6+2=21\). Exam tip: \(a_1\) is fixed while (n) changes.
Step 2
Why this answer is correct
The correct answer is C. (21). \(a_2=6+6+1=13\) and \(a_3=13+6+2=21\). Exam tip: \(a_1\) is fixed while (n) changes.
Step 3
Exam Tip
\(a_2=6+6+1=13\) और \(a_3=13+6+2=21\) है। \(a_1\) स्थिर और (n) बदलता है।
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यदि \(a_1=12\) और \(a_{n+1}=a_n+6\) है तो कौन सा पद (42) है?
If \(a_1=12\) and \(a_{n+1}=a_n+6\), which term is (42)?
Explanation opens after your attempt
Correct Answer
B. (6)वाँ/(6)th
Step 1
Concept
The terms are (12,18,24,30,36,42), so (42) is the sixth term. Exam tip: write terms with their positions.
Step 2
Why this answer is correct
The correct answer is B. (6)वाँ / (6)th. The terms are (12,18,24,30,36,42), so (42) is the sixth term. Exam tip: write terms with their positions.
Step 3
Exam Tip
पद (12,18,24,30,36,42) हैं इसलिए (42) छठा पद है। पदों को क्रमांक के साथ लिखें।
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यदि \(a_1=3\) और \(a_{n+1}=2a_n+2\) है तो \(a_4-a_2\) का मान क्या होगा?
If \(a_1=3\) and \(a_{n+1}=2a_n+2\), what is the value of \(a_4-a_2\)?
Explanation opens after your attempt
Step 1
Concept
The terms are (3,8,18,38), so \(a_4-a_2=30\). The correct difference should be (30).
Step 2
Why this answer is correct
The correct answer is C. (24). The terms are (3,8,18,38), so \(a_4-a_2=30\). The correct difference should be (30).
Step 3
Exam Tip
पद (3,8,18,38) हैं इसलिए \(a_4-a_2=38-8=30\) है। सही अंतर (30) होना चाहिए।
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यदि \(a_1=3\) और \(a_{n+1}=2a_n+2\) है तो \(a_3-a_2\) का मान क्या होगा?
If \(a_1=3\) and \(a_{n+1}=2a_n+2\), what is the value of \(a_3-a_2\)?
Explanation opens after your attempt
Step 1
Concept
The terms are (3,8,18), so \(a_3-a_2=18-8=10\). Exam tip: find both terms first and then subtract.
Step 2
Why this answer is correct
The correct answer is B. (10). The terms are (3,8,18), so \(a_3-a_2=18-8=10\). Exam tip: find both terms first and then subtract.
Step 3
Exam Tip
पद (3,8,18) हैं इसलिए \(a_3-a_2=18-8=10\) है। पहले दोनों पद निकालें फिर घटाएँ।
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यदि \(a_1=2\), \(a_2=5\) और \(a_n=a_{n-1}+a_{n-2}+1\) है तो \(a_5\) क्या होगा?
If \(a_1=2\), \(a_2=5\), and \(a_n=a_{n-1}+a_{n-2}+1\), what is \(a_5\)?
Explanation opens after your attempt
Step 1
Concept
The terms are (2,5,8,14,23), so \(a_5=23\). Include the extra (1) at each step.
Step 2
Why this answer is correct
The correct answer is C. (22). The terms are (2,5,8,14,23), so \(a_5=23\). Include the extra (1) at each step.
Step 3
Exam Tip
पद (2,5,8,14,23) नहीं बल्कि \(a_5=23\) है। जोड़ में अतिरिक्त (1) हर चरण शामिल करें।
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यदि \(a_1=2\), \(a_2=5\) और \(a_n=a_{n-1}+a_{n-2}+1\) है तो \(a_4\) क्या होगा?
If \(a_1=2\), \(a_2=5\), and \(a_n=a_{n-1}+a_{n-2}+1\), what is \(a_4\)?
Explanation opens after your attempt
Step 1
Concept
\(a_3=5+2+1=8\) and \(a_4=8+5+1=14\). Exam tip: add (1) along with the previous two terms.
Step 2
Why this answer is correct
The correct answer is D. (14). \(a_3=5+2+1=8\) and \(a_4=8+5+1=14\). Exam tip: add (1) along with the previous two terms.
Step 3
Exam Tip
\(a_3=5+2+1=8\) और \(a_4=8+5+1=14\) है। पिछले दो पदों के साथ (1) भी जोड़ें।
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