Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 251-260 of 550 questions.
What is the factorisation of (ax+ay+bx+by) by grouping?
A. ((a+b)(x+y))
पहले (a(x+y)+b(x+y)) लिखें। फिर समान ((x+y)) निकालकर ((a+b)(x+y)) मिलता है। / First write (a(x+y)+b(x+y)). Then take common ((x+y)) to get ((a+b)(x+y)).
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What are the correct factors of (px-py+qx-qy)?
B. ((p+q)(x-y))
समूह बनाने पर (p(x-y)+q(x-y)) मिलता है। इसलिए समान ((x-y)) निकालकर ((p+q)(x-y)) मिलेगा। / Grouping gives (p(x-y)+q(x-y)). Taking common ((x-y)) gives ((p+q)(x-y)).
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What is the complete factorisation of \(3a^2-12b^2\)?
C. (3(a-2b)(a+2b))
पहले (3) समान निकालें और \(a^2-4b^2\) को वर्गों के अंतर से तोड़ें। परीक्षा में समान गुणनखंड निकालने के बाद भी आगे जांचें। / First take (3) common and split \(a^2-4b^2\) by difference of squares. Exam tip: check further factorisation after taking common factor.
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Which is the correct factorisation of \(x^2+10x+25-y^2\)?
D. ((x+5-y)(x+5+y))
पहले (x-2+10x+25=(x+5)2) पहचानें। फिर वर्गों के अंतर से ((x+5-y)(x+5+y)) मिलेगा। / First identify (x-2+10x+25=(x+5)2). Then difference of squares gives ((x+5-y)(x+5+y)).
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\(4x^2-20xy+25y^2\) is the perfect square of what?
A. ((2x-5y)2)
(4x-2=(2x)2) और (25y-2=(5y)2) है। मध्य पद ऋण है इसलिए ((2x-5y)2) सही है। / (4x-2=(2x)2) and (25y-2=(5y)2). The middle term is negative so ((2x-5y)2) is correct.
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Which factorisation is correct for \(9a^2-16b^2+6a-8b\)?
B. ((3a-4b)(3a+4b+2))
समूह बनाकर ((3a-4b)(3a+4b)+2(3a-4b)) लिख सकते हैं। समान ((3a-4b)) निकालें। / By grouping write ((3a-4b)(3a+4b)+2(3a-4b)). Take common ((3a-4b)).
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Which common factor is present in the factorisations of \(x^2+7x+10\) and \(x^2+5x+6\)?
C. (x+2)
पहला ((x+5)(x+2)) और दूसरा ((x+2)(x+3)) है। इसलिए सामान्य गुणनखंड ((x+2)) है। / The first is ((x+5)(x+2)) and the second is ((x+2)(x+3)). So the common factor is ((x+2)).
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Which is the factorisation of \(2x^2+11x+15\)?
C. ((2x+3)(x+5))
((2x+5)(x+3)) से \(2x^2+11x+15\) नहीं बल्कि \(2x^2+11x+15\) ही मिलता है? गुणा जांचें और सही विकल्प ((2x+5)(x+3)) है। / Check multiplication carefully: ((2x+5)(x+3)=2x-2+11x+15). So the correct factorisation is ((2x+5)(x+3)).
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What are the correct factors of \(3x^2+10x+8\)?
A. ((3x+4)(x+2))
((3x+4)(x+2)=3x-2+6x+4x+8) है। मध्य पद (10x) बनता है। / ((3x+4)(x+2)=3x-2+6x+4x+8). The middle term becomes (10x).
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Choose the factorisation of \(6x^2+13x+6\).
B. ((2x+3)(3x+2))
((2x+3)(3x+2)) फैलाने पर \(6x^2+4x+9x+6\) मिलता है। मध्य पद (13x) है। / Expanding ((2x+3)(3x+2)) gives \(6x^2+4x+9x+6\). The middle term is (13x).
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