Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 171-180 of 600 questions.
If both roots of \(x^2+px+16=0\) are (-4) and (-4), what is the value of (p)?
A. (8)
मूलों का योग (-8) है और (-p=-8) होगा। इसलिए (p=8) है। / The sum of roots is (-8), and (-p=-8). Therefore (p=8).
Login to save your score, XP, coins and progress.
If \(x=\frac{3}{2}\) is a root of \(2x^2-5x+c=0\), what is the value of (c)?
A. (3)
\(x=\frac{3}{2}\) रखने पर \(\frac{9}{2}-\frac{15}{2}+c=0\) इसलिए (c=3) है। भिन्न मूल में हर पद अलग निकालें। / Putting \(x=\frac{3}{2}\) gives \(\frac{9}{2}-\frac{15}{2}+c=0\), so (c=3). For fractional roots calculate each term separately.
Login to save your score, XP, coins and progress.
What is the nature of roots of \(4x^2-12x+9=0\)?
A. बराबर वास्तविक मूलEqual real roots
यह (4x-2-12x+9=(2x-3)2) है। इसलिए दोनों मूल \(\frac{3}{2}\) और \(\frac{3}{2}\) बराबर हैं। / It is (4x-2-12x+9=(2x-3)2). Therefore both roots are \(\frac{3}{2}\) and \(\frac{3}{2}\), which are equal.
Login to save your score, XP, coins and progress.
If a quadratic equation has (a=1), (b=-10), and (c=25), what will be the roots?
A. (5) और (5)(5) and (5)
समीकरण \(x^2-10x+25=0\) है जो ((x-5)2=0) बनता है। इसलिए दोनों मूल (5) हैं। / The equation is \(x^2-10x+25=0\), which becomes ((x-5)2=0). Therefore both roots are (5).
Login to save your score, XP, coins and progress.
If the product of roots of a quadratic equation is (0), which statement is correct?
A. कम से कम एक मूल (0) हैAt least one root is (0)
यदि \(\alpha\beta=0\) है तो \(\alpha=0\) या \(\beta=0\) होगा। गुणनफल शून्य हो तो शून्य मूल जरूर देखें। / If \(\alpha\beta=0\), then \(\alpha=0\) or \(\beta=0\). If the product is zero, always check for a zero root.
Login to save your score, XP, coins and progress.
What are the roots of \(x^2-2x-15=0\)?
A. (5) और (-3)(5) and (-3)
(x-2-2x-15=(x-5)(x+3)) है। इसलिए मूल (5) और (-3) हैं। / (x-2-2x-15=(x-5)(x+3)). Therefore the roots are (5) and (-3).
Login to save your score, XP, coins and progress.
A. (11)
यहां \(\alpha+\beta=5\) और \(\alpha\beta=6\) है। इसलिए कुल (5+6=11) है। / Here \(\alpha+\beta=5\) and \(\alpha\beta=6\). Therefore the total is (5+6=11).
Login to save your score, XP, coins and progress.
If the sum of roots is (0) and product is (-16), which monic equation is formed?
A. \(x^2-16=0\)
मोनिक समीकरण (x-2-(0)x+(-16)=0) होगा। इसलिए \(x^2-16=0\) सही है। / The monic equation is (x-2-(0)x+(-16)=0). Therefore \(x^2-16=0\) is correct.
Login to save your score, XP, coins and progress.
What is the repeated root of \(9x^2-6x+1=0\)?
A. \(\frac{1}{3}\)
(9x-2-6x+1=(3x-1)2) है। इसलिए दोहराया मूल \(\frac{1}{3}\) है। / (9x-2-6x+1=(3x-1)2). Therefore the repeated root is \(\frac{1}{3}\).
Login to save your score, XP, coins and progress.
If (x=0) is a root of \(ax^2+bx+c=0\) and \(a\ne0\), what is true about (c)?
A. (c=0)
(x=0) रखने पर समीकरण (c=0) बनता है। इसलिए शून्य मूल के लिए अचर पद शून्य होता है। / Putting (x=0) makes the equation (c=0). Therefore the constant term is zero for a zero root.
Login to save your score, XP, coins and progress.
Use Google login or mobile OTP. Admin can block users and control login providers.