Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
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If (p(x)=(k-3)x-5+2x-3-x+9) has degree (3), what is (k)?
A. (3)
घात (3) होने के लिए \(x^5\) का गुणांक (0) होना चाहिए। इसलिए (k-3=0) और (k=3)। / For degree (3), the coefficient of \(x^5\) must be (0). Thus (k-3=0) and (k=3).
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If \(\alpha,\beta\) are zeroes of \(x^2-9x+20\), what is the value of (\(\alpha+2\)\(\beta+2\))?
A. (42)
\(\alpha+\beta=9\) और \(\alpha\beta=20\) हैं। (\(\alpha+2\)\(\beta+2\)=\alpha\beta+2\(\alpha+\beta\)+4=20+18+4=42)। / \(\alpha+\beta=9\) and \(\alpha\beta=20\). (\(\alpha+2\)\(\beta+2\)=\alpha\beta+2\(\alpha+\beta\)+4=20+18+4=42).
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If (p(x)=x-2-4x+1), what is the sum of reciprocals of its zeroes?
A. (4)
शून्यकों के व्युत्क्रमों का योग \(\frac{\alpha+\beta}{\alpha\beta}\) होता है। यहाँ \(\alpha+\beta=4\) और \(\alpha\beta=1\), इसलिए उत्तर (4) है। / The sum of reciprocals is \(\frac{\alpha+\beta}{\alpha\beta}\). Here \(\alpha+\beta=4\) and \(\alpha\beta=1\), so the answer is (4).
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A. \(x^2-4x+1\)
योग (4) और गुणनफल (1) है। अतः मोनिक बहुपद \(x^2-4x+1\) होगा। / The sum is (4) and the product is (1). Therefore the monic polynomial is \(x^2-4x+1\).
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If (p(x)=x-3-6x-2+12x-8), what is the zero of (p(x)) with its multiplicity?
A. (2) गुणनता (3)(2) with multiplicity (3)
यह (p(x)=(x-2)3) है, इसलिए (2) तीन बार शून्यक है। घन पूर्ण पहचान को पहचानना उपयोगी है। / This is (p(x)=(x-2)3), so (2) is a zero three times. Recognizing cube identities is useful.
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For (p(x)=3x-2-12x+15), what is the correct conclusion about real zeroes?
A. कोई वास्तविक शून्यक नहींNo real zeroes
(p(x)=3\(x^2-4x+5\)=3((x-2)2+1)), जो सदा धनात्मक है। इसलिए कोई वास्तविक शून्यक नहीं है। / (p(x)=3\(x^2-4x+5\)=3((x-2)2+1)), which is always positive. Hence there are no real zeroes.
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If the zeroes of (p(x)=x-2+bx+16) are reciprocals of each other, what can be said about (b)?
A. ऐसा संभव नहीं हैIt is not possible
परस्पर व्युत्क्रम शून्यकों का गुणनफल (1) होना चाहिए। यहाँ गुणनफल (16) है, इसलिए यह संभव नहीं है। / Reciprocal zeroes must have product (1). Here the product is (16), so it is not possible.
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If (p(x)=x-2-11x+30) and (q(x)=p(x-2)), what are the zeroes of (q(x))?
A. (7,8)
(p(x)) के शून्यक (5) और (6) हैं। (p(x-2)=0) के लिए (x-2=5) या (x-2=6), इसलिए शून्यक (7,8) हैं। / The zeroes of (p(x)) are (5) and (6). For (p(x-2)=0), (x-2=5) or (x-2=6), so the zeroes are (7,8).
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If (p(x)=x-2-3x-28), what is the distance between its zeroes?
A. (11)
(p(x)=(x-7)(x+4)), इसलिए शून्यक (7) और (-4) हैं। दूरी (|7-(-4)|=11) है। / (p(x)=(x-7)(x+4)), so the zeroes are (7) and (-4). The distance is (|7-(-4)|=11).
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If one zero of (p(x)=2x-2+mx+18) is (3), what is the other zero?
A. (3)
गुणनफल \(\frac{18}{2}=9\) है। एक शून्यक (3) है, इसलिए दूसरा (3) होगा। / The product is \(\frac{18}{2}=9\). Since one zero is (3), the other is (3).
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