कौन सा विकल्प \(\sqrt{162}\) का सरल रूप है?
Which option is the simplified form of \(\sqrt{162}\)?
Explanation opens after your attempt
Correct Answer
A. \(9\sqrt{2}\)
Step 1
Concept
\(\sqrt{162}=\sqrt{81\times2}=9\sqrt{2}\). Take the greatest perfect square inside the root.
Step 2
Why this answer is correct
The correct answer is A. \(9\sqrt{2}\). \(\sqrt{162}=\sqrt{81\times2}=9\sqrt{2}\). Take the greatest perfect square inside the root.
Step 3
Exam Tip
\(\sqrt{162}=\sqrt{81\times2}=9\sqrt{2}\) है। जड़ में सबसे बड़ा पूर्ण वर्ग लें।
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कौन सा विकल्प (\(2+\sqrt{3}\)2) का सही विस्तार है?
Which option is the correct expansion of (\(2+\sqrt{3}\)2)?
Explanation opens after your attempt
Correct Answer
A. \(7+4\sqrt{3}\)
Step 1
Concept
(\(2+\sqrt{3}\)2=4+4\sqrt{3}+3=7+4\sqrt{3}). Do not forget the middle term in the square formula.
Step 2
Why this answer is correct
The correct answer is A. \(7+4\sqrt{3}\). (\(2+\sqrt{3}\)2=4+4\sqrt{3}+3=7+4\sqrt{3}). Do not forget the middle term in the square formula.
Step 3
Exam Tip
(\(2+\sqrt{3}\)2=4+4\sqrt{3}+3=7+4\sqrt{3}) है। वर्ग सूत्र में बीच का पद न भूलें।
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कौन सा विकल्प (\(\sqrt{7}+1\)\(\sqrt{7}-1\)) का मान है?
Which option is the value of (\(\sqrt{7}+1\)\(\sqrt{7}-1\))?
Explanation opens after your attempt
Step 1
Concept
This is ((a+b)(a-b)=a-2-b-2). The value is (7-1=6).
Step 2
Why this answer is correct
The correct answer is A. (6). This is ((a+b)(a-b)=a-2-b-2). The value is (7-1=6).
Step 3
Exam Tip
यह ((a+b)(a-b)=a-2-b-2) है। मान (7-1=6) मिलेगा।
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कौन सा विकल्प (\sqrt{5}\(2+\sqrt{5}\)) का मान है?
Which option is the value of (\sqrt{5}\(2+\sqrt{5}\))?
Explanation opens after your attempt
Correct Answer
A. \(5+2\sqrt{5}\)
Step 1
Concept
Distributing gives \(2\sqrt{5}+5\). Keep rational and irrational parts separate.
Step 2
Why this answer is correct
The correct answer is A. \(5+2\sqrt{5}\). Distributing gives \(2\sqrt{5}+5\). Keep rational and irrational parts separate.
Step 3
Exam Tip
वितरण करने पर \(2\sqrt{5}+5\) मिलता है। पदों को परिमेय और अपरिमेय भाग में अलग रखें।
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यदि \(y=\sqrt{2}+\sqrt{32}\) है तो (y) का सरल रूप क्या है?
If \(y=\sqrt{2}+\sqrt{32}\), what is the simplified form of (y)?
Explanation opens after your attempt
Correct Answer
A. \(5\sqrt{2}\)
Step 1
Concept
\(\sqrt{32}=4\sqrt{2}\), so \(y=5\sqrt{2}\). Add like radical terms.
Step 2
Why this answer is correct
The correct answer is A. \(5\sqrt{2}\). \(\sqrt{32}=4\sqrt{2}\), so \(y=5\sqrt{2}\). Add like radical terms.
Step 3
Exam Tip
\(\sqrt{32}=4\sqrt{2}\) है इसलिए \(y=5\sqrt{2}\) होगा। समान जड़ वाले पदों को जोड़ें।
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कौन सा विकल्प \(\sqrt{3}\) और \(\sqrt{27}\) का गुणनफल बताता है?
Which option gives the product of \(\sqrt{3}\) and \(\sqrt{27}\)?
Explanation opens after your attempt
Step 1
Concept
\(\sqrt{3}\times\sqrt{27}=\sqrt{81}=9\). In multiplication multiply the numbers inside the roots.
Step 2
Why this answer is correct
The correct answer is A. (9). \(\sqrt{3}\times\sqrt{27}=\sqrt{81}=9\). In multiplication multiply the numbers inside the roots.
Step 3
Exam Tip
\(\sqrt{3}\times\sqrt{27}=\sqrt{81}=9\) है। गुणन में जड़ों के अंदर के संख्याओं को गुणा करें।
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कौन सा विकल्प \(\sqrt{128}\) का सरल रूप है?
Which option is the simplified form of \(\sqrt{128}\)?
Explanation opens after your attempt
Correct Answer
A. \(8\sqrt{2}\)
Step 1
Concept
\(\sqrt{128}=\sqrt{64\times2}=8\sqrt{2}\). Taking out the greatest perfect square is the better method.
Step 2
Why this answer is correct
The correct answer is A. \(8\sqrt{2}\). \(\sqrt{128}=\sqrt{64\times2}=8\sqrt{2}\). Taking out the greatest perfect square is the better method.
Step 3
Exam Tip
\(\sqrt{128}=\sqrt{64\times2}=8\sqrt{2}\) है। सबसे बड़ा पूर्ण वर्ग निकालना बेहतर तरीका है।
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कौन सा विकल्प \(\sqrt{3}\) और \(\sqrt{12}\) के बीच सही संबंध बताता है?
Which option gives the correct relation between \(\sqrt{3}\) and \(\sqrt{12}\)?
Explanation opens after your attempt
Correct Answer
A. \(\sqrt{12}=2\sqrt{3}\)
Step 1
Concept
\(\sqrt{12}=\sqrt{4\times3}=2\sqrt{3}\). Taking out the perfect square makes comparison easy.
Step 2
Why this answer is correct
The correct answer is A. \(\sqrt{12}=2\sqrt{3}\). \(\sqrt{12}=\sqrt{4\times3}=2\sqrt{3}\). Taking out the perfect square makes comparison easy.
Step 3
Exam Tip
\(\sqrt{12}=\sqrt{4\times3}=2\sqrt{3}\) है। पूर्ण वर्ग बाहर निकालने से तुलना आसान होती है।
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\(\sqrt{2}+\sqrt{8}+\sqrt{18}\) का सरल रूप क्या है?
What is the simplified form of \(\sqrt{2}+\sqrt{8}+\sqrt{18}\)?
Explanation opens after your attempt
Correct Answer
A. \(6\sqrt{2}\)
Step 1
Concept
\(\sqrt{8}=2\sqrt{2}\) and \(\sqrt{18}=3\sqrt{2}\). The total is \(6\sqrt{2}\).
Step 2
Why this answer is correct
The correct answer is A. \(6\sqrt{2}\). \(\sqrt{8}=2\sqrt{2}\) and \(\sqrt{18}=3\sqrt{2}\). The total is \(6\sqrt{2}\).
Step 3
Exam Tip
\(\sqrt{8}=2\sqrt{2}\) और \(\sqrt{18}=3\sqrt{2}\) है। कुल \(6\sqrt{2}\) मिलता है।
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कौन सा विकल्प \(\sqrt{75}-\sqrt{27}\) का सही मान है?
Which option is the correct value of \(\sqrt{75}-\sqrt{27}\)?
Explanation opens after your attempt
Correct Answer
A. \(2\sqrt{3}\)
Step 1
Concept
\(\sqrt{75}=5\sqrt{3}\) and \(\sqrt{27}=3\sqrt{3}\). The difference is \(2\sqrt{3}\).
Step 2
Why this answer is correct
The correct answer is A. \(2\sqrt{3}\). \(\sqrt{75}=5\sqrt{3}\) and \(\sqrt{27}=3\sqrt{3}\). The difference is \(2\sqrt{3}\).
Step 3
Exam Tip
\(\sqrt{75}=5\sqrt{3}\) और \(\sqrt{27}=3\sqrt{3}\) है। अंतर \(2\sqrt{3}\) मिलेगा।
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यदि \(a=\sqrt{20}\) है तो (a) का सरल रूप क्या है?
If \(a=\sqrt{20}\), what is the simplified form of (a)?
Explanation opens after your attempt
Correct Answer
A. \(2\sqrt{5}\)
Step 1
Concept
\(\sqrt{20}=\sqrt{4\times5}=2\sqrt{5}\). Look for a perfect square factor inside the root.
Step 2
Why this answer is correct
The correct answer is A. \(2\sqrt{5}\). \(\sqrt{20}=\sqrt{4\times5}=2\sqrt{5}\). Look for a perfect square factor inside the root.
Step 3
Exam Tip
\(\sqrt{20}=\sqrt{4\times5}=2\sqrt{5}\) होता है। जड़ में पूर्ण वर्ग गुणनखंड खोजें।
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कौन सा विकल्प \(3\sqrt{2}\times2\sqrt{2}\) का मान है?
Which option is the value of \(3\sqrt{2}\times2\sqrt{2}\)?
Explanation opens after your attempt
Step 1
Concept
\(3\sqrt{2}\times2\sqrt{2}=6\times2=12\). Multiplying same roots can give a rational result.
Step 2
Why this answer is correct
The correct answer is A. (12). \(3\sqrt{2}\times2\sqrt{2}=6\times2=12\). Multiplying same roots can give a rational result.
Step 3
Exam Tip
\(3\sqrt{2}\times2\sqrt{2}=6\times2=12\) है। समान जड़ का गुणन परिमेय परिणाम दे सकता है।
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कौन सा विकल्प \(7\sqrt{3}+2\sqrt{3}\) का सही सरल रूप है?
Which option is the correct simplified form of \(7\sqrt{3}+2\sqrt{3}\)?
Explanation opens after your attempt
Correct Answer
A. \(9\sqrt{3}\)
Step 1
Concept
The coefficients of like radical terms are added. So \(7\sqrt{3}+2\sqrt{3}=9\sqrt{3}\).
Step 2
Why this answer is correct
The correct answer is A. \(9\sqrt{3}\). The coefficients of like radical terms are added. So \(7\sqrt{3}+2\sqrt{3}=9\sqrt{3}\).
Step 3
Exam Tip
समान जड़ वाले पदों के गुणांक जुड़ते हैं। इसलिए \(7\sqrt{3}+2\sqrt{3}=9\sqrt{3}\) है।
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कौन सा विकल्प \(\sqrt{242}\) का सरल रूप है?
Which option is the simplified form of \(\sqrt{242}\)?
Explanation opens after your attempt
Correct Answer
A. \(11\sqrt{2}\)
Step 1
Concept
\(\sqrt{242}=\sqrt{121\times2}=11\sqrt{2}\). Identify the perfect square factor inside the root.
Step 2
Why this answer is correct
The correct answer is A. \(11\sqrt{2}\). \(\sqrt{242}=\sqrt{121\times2}=11\sqrt{2}\). Identify the perfect square factor inside the root.
Step 3
Exam Tip
\(\sqrt{242}=\sqrt{121\times2}=11\sqrt{2}\) है। जड़ में पूर्ण वर्ग गुणनखंड पहचानें।
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\(\sqrt{3}+\sqrt{75}\) का सरल रूप क्या है?
What is the simplified form of \(\sqrt{3}+\sqrt{75}\)?
Explanation opens after your attempt
Correct Answer
A. \(6\sqrt{3}\)
Step 1
Concept
\(\sqrt{75}=5\sqrt{3}\), so the total is \(6\sqrt{3}\). Only like radical terms add directly.
Step 2
Why this answer is correct
The correct answer is A. \(6\sqrt{3}\). \(\sqrt{75}=5\sqrt{3}\), so the total is \(6\sqrt{3}\). Only like radical terms add directly.
Step 3
Exam Tip
\(\sqrt{75}=5\sqrt{3}\) इसलिए कुल \(6\sqrt{3}\) है। समान जड़ वाले पद ही सीधे जुड़ते हैं।
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\(\sqrt{2}+\sqrt{18}\) का सरल रूप क्या है?
What is the simplified form of \(\sqrt{2}+\sqrt{18}\)?
Explanation opens after your attempt
Correct Answer
A. \(4\sqrt{2}\)
Step 1
Concept
\(\sqrt{18}=3\sqrt{2}\) so the sum is \(4\sqrt{2}\). First simplify the root and then add.
Step 2
Why this answer is correct
The correct answer is A. \(4\sqrt{2}\). \(\sqrt{18}=3\sqrt{2}\) so the sum is \(4\sqrt{2}\). First simplify the root and then add.
Step 3
Exam Tip
\(\sqrt{18}=3\sqrt{2}\) इसलिए योग \(4\sqrt{2}\) है। पहले जड़ को सरल करें फिर जोड़ें।
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कौन सा विकल्प \(\sqrt{200}\) का सरल रूप है?
Which option is the simplified form of \(\sqrt{200}\)?
Explanation opens after your attempt
Correct Answer
A. \(10\sqrt{2}\)
Step 1
Concept
\(\sqrt{200}=\sqrt{100\times2}=10\sqrt{2}\). Taking out the greatest perfect square is a good method.
Step 2
Why this answer is correct
The correct answer is A. \(10\sqrt{2}\). \(\sqrt{200}=\sqrt{100\times2}=10\sqrt{2}\). Taking out the greatest perfect square is a good method.
Step 3
Exam Tip
\(\sqrt{200}=\sqrt{100\times2}=10\sqrt{2}\) है। सबसे बड़े पूर्ण वर्ग को बाहर निकालना अच्छा तरीका है।
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कौन सा विकल्प \(\sqrt{150}\) का सरल रूप है?
Which option is the simplified form of \(\sqrt{150}\)?
Explanation opens after your attempt
Correct Answer
A. \(5\sqrt{6}\)
Step 1
Concept
\(\sqrt{150}=\sqrt{25\times6}=5\sqrt{6}\). The perfect square factor inside the root is (25).
Step 2
Why this answer is correct
The correct answer is A. \(5\sqrt{6}\). \(\sqrt{150}=\sqrt{25\times6}=5\sqrt{6}\). The perfect square factor inside the root is (25).
Step 3
Exam Tip
\(\sqrt{150}=\sqrt{25\times6}=5\sqrt{6}\) है। जड़ में पूर्ण वर्ग गुणनखंड (25) है।
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\(\sqrt{98}-\sqrt{50}\) का मान क्या है?
What is the value of \(\sqrt{98}-\sqrt{50}\)?
Explanation opens after your attempt
Correct Answer
A. \(2\sqrt{2}\)
Step 1
Concept
\(\sqrt{98}=7\sqrt{2}\) and \(\sqrt{50}=5\sqrt{2}\). Their difference is \(2\sqrt{2}\).
Step 2
Why this answer is correct
The correct answer is A. \(2\sqrt{2}\). \(\sqrt{98}=7\sqrt{2}\) and \(\sqrt{50}=5\sqrt{2}\). Their difference is \(2\sqrt{2}\).
Step 3
Exam Tip
\(\sqrt{98}=7\sqrt{2}\) और \(\sqrt{50}=5\sqrt{2}\) है। अंतर \(2\sqrt{2}\) होगा।
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\(\sqrt{63}+\sqrt{28}\) का सरल रूप क्या है?
What is the simplified form of \(\sqrt{63}+\sqrt{28}\)?
Explanation opens after your attempt
Correct Answer
A. \(5\sqrt{7}\)
Step 1
Concept
\(\sqrt{63}=3\sqrt{7}\) and \(\sqrt{28}=2\sqrt{7}\). Adding like terms gives \(5\sqrt{7}\).
Step 2
Why this answer is correct
The correct answer is A. \(5\sqrt{7}\). \(\sqrt{63}=3\sqrt{7}\) and \(\sqrt{28}=2\sqrt{7}\). Adding like terms gives \(5\sqrt{7}\).
Step 3
Exam Tip
\(\sqrt{63}=3\sqrt{7}\) और \(\sqrt{28}=2\sqrt{7}\) है। समान पद जोड़ने पर \(5\sqrt{7}\) मिलता है।
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कौन सा विकल्प \(\sqrt{108}\) का सही सरल रूप है?
Which option is the correct simplified form of \(\sqrt{108}\)?
Explanation opens after your attempt
Correct Answer
A. \(6\sqrt{3}\)
Step 1
Concept
\(\sqrt{108}=\sqrt{36\times3}=6\sqrt{3}\). Taking out the perfect square simplifies the root.
Step 2
Why this answer is correct
The correct answer is A. \(6\sqrt{3}\). \(\sqrt{108}=\sqrt{36\times3}=6\sqrt{3}\). Taking out the perfect square simplifies the root.
Step 3
Exam Tip
\(\sqrt{108}=\sqrt{36\times3}=6\sqrt{3}\) है। पूर्ण वर्ग बाहर निकालने से जड़ सरल होती है।
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कौन सा विकल्प \(\sqrt{72}\) का सरल रूप है?
Which option is the simplified form of \(\sqrt{72}\)?
Explanation opens after your attempt
Correct Answer
A. \(6\sqrt{2}\)
Step 1
Concept
\(\sqrt{72}=\sqrt{36\times2}=6\sqrt{2}\). Find the large perfect square inside the root.
Step 2
Why this answer is correct
The correct answer is A. \(6\sqrt{2}\). \(\sqrt{72}=\sqrt{36\times2}=6\sqrt{2}\). Find the large perfect square inside the root.
Step 3
Exam Tip
\(\sqrt{72}=\sqrt{36\times2}=6\sqrt{2}\) है। जड़ के अंदर बड़ा पूर्ण वर्ग खोजें।
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कौन सा विकल्प \(\sqrt{80}\) का सही सरल रूप है?
Which option is the correct simplified form of \(\sqrt{80}\)?
Explanation opens after your attempt
Correct Answer
A. \(4\sqrt{5}\)
Step 1
Concept
\(\sqrt{80}=\sqrt{16\times5}=4\sqrt{5}\). Look for a perfect square factor inside the root.
Step 2
Why this answer is correct
The correct answer is A. \(4\sqrt{5}\). \(\sqrt{80}=\sqrt{16\times5}=4\sqrt{5}\). Look for a perfect square factor inside the root.
Step 3
Exam Tip
\(\sqrt{80}=\sqrt{16\times5}=4\sqrt{5}\) है। जड़ के अंदर पूर्ण वर्ग गुणनखंड खोजें।
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कौन सा विकल्प \(\sqrt{147}\) का सरल रूप है?
Which option is the simplified form of \(\sqrt{147}\)?
Explanation opens after your attempt
Correct Answer
A. \(7\sqrt{3}\)
Step 1
Concept
\(\sqrt{147}=\sqrt{49\times3}=7\sqrt{3}\). Take the large perfect square outside the root.
Step 2
Why this answer is correct
The correct answer is A. \(7\sqrt{3}\). \(\sqrt{147}=\sqrt{49\times3}=7\sqrt{3}\). Take the large perfect square outside the root.
Step 3
Exam Tip
\(\sqrt{147}=\sqrt{49\times3}=7\sqrt{3}\) है। बड़े पूर्ण वर्ग को जड़ से बाहर निकालें।
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कौन सा विकल्प \(\sqrt{28}\) का सरल रूप है?
Which option is the simplified form of \(\sqrt{28}\)?
Explanation opens after your attempt
Correct Answer
A. \(2\sqrt{7}\)
Step 1
Concept
\(\sqrt{28}=\sqrt{4\times7}=2\sqrt{7}\). The perfect square (4) comes outside.
Step 2
Why this answer is correct
The correct answer is A. \(2\sqrt{7}\). \(\sqrt{28}=\sqrt{4\times7}=2\sqrt{7}\). The perfect square (4) comes outside.
Step 3
Exam Tip
\(\sqrt{28}=\sqrt{4\times7}=2\sqrt{7}\) है। पूर्ण वर्ग (4) बाहर आता है।
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\(\sqrt{45}-\sqrt{20}\) का मान क्या है?
What is the value of \(\sqrt{45}-\sqrt{20}\)?
Explanation opens after your attempt
Correct Answer
A. \(\sqrt{5}\)
Step 1
Concept
\(\sqrt{45}=3\sqrt{5}\) and \(\sqrt{20}=2\sqrt{5}\). The difference is \(\sqrt{5}\).
Step 2
Why this answer is correct
The correct answer is A. \(\sqrt{5}\). \(\sqrt{45}=3\sqrt{5}\) and \(\sqrt{20}=2\sqrt{5}\). The difference is \(\sqrt{5}\).
Step 3
Exam Tip
\(\sqrt{45}=3\sqrt{5}\) और \(\sqrt{20}=2\sqrt{5}\) है। अंतर \(\sqrt{5}\) है।
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\(\sqrt{48}+\sqrt{12}\) का सरल रूप क्या है?
What is the simplified form of \(\sqrt{48}+\sqrt{12}\)?
Explanation opens after your attempt
Correct Answer
A. \(6\sqrt{3}\)
Step 1
Concept
\(\sqrt{48}=4\sqrt{3}\) and \(\sqrt{12}=2\sqrt{3}\). Adding like terms gives \(6\sqrt{3}\).
Step 2
Why this answer is correct
The correct answer is A. \(6\sqrt{3}\). \(\sqrt{48}=4\sqrt{3}\) and \(\sqrt{12}=2\sqrt{3}\). Adding like terms gives \(6\sqrt{3}\).
Step 3
Exam Tip
\(\sqrt{48}=4\sqrt{3}\) और \(\sqrt{12}=2\sqrt{3}\) है। समान पद जोड़ने पर \(6\sqrt{3}\) मिलता है।
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\(\sqrt{75}\) का सही सरल रूप कौन सा है?
Which is the correct simplified form of \(\sqrt{75}\)?
Explanation opens after your attempt
Correct Answer
A. \(5\sqrt{3}\)
Step 1
Concept
\(\sqrt{75}=\sqrt{25\times3}=5\sqrt{3}\). Take the perfect square factor (25) outside.
Step 2
Why this answer is correct
The correct answer is A. \(5\sqrt{3}\). \(\sqrt{75}=\sqrt{25\times3}=5\sqrt{3}\). Take the perfect square factor (25) outside.
Step 3
Exam Tip
\(\sqrt{75}=\sqrt{25\times3}=5\sqrt{3}\) है। पूर्ण वर्ग गुणनखंड (25) को बाहर निकालें।
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\(\sqrt{32}\) का सरल रूप क्या है?
What is the simplified form of \(\sqrt{32}\)?
Explanation opens after your attempt
Correct Answer
A. \(4\sqrt{2}\)
Step 1
Concept
\(\sqrt{32}=\sqrt{16\times2}=4\sqrt{2}\). Take out the greatest perfect square.
Step 2
Why this answer is correct
The correct answer is A. \(4\sqrt{2}\). \(\sqrt{32}=\sqrt{16\times2}=4\sqrt{2}\). Take out the greatest perfect square.
Step 3
Exam Tip
\(\sqrt{32}=\sqrt{16\times2}=4\sqrt{2}\) है। सबसे बड़ा पूर्ण वर्ग बाहर निकालें।
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\(\sqrt{98}\) को सरल करने पर क्या मिलेगा?
What do we get after simplifying \(\sqrt{98}\)?
Explanation opens after your attempt
Correct Answer
A. \(7\sqrt{2}\)
Step 1
Concept
\(\sqrt{98}=\sqrt{49\times2}=7\sqrt{2}\). Take the perfect square (49) outside the root.
Step 2
Why this answer is correct
The correct answer is A. \(7\sqrt{2}\). \(\sqrt{98}=\sqrt{49\times2}=7\sqrt{2}\). Take the perfect square (49) outside the root.
Step 3
Exam Tip
\(\sqrt{98}=\sqrt{49\times2}=7\sqrt{2}\) है। पूर्ण वर्ग (49) को जड़ से बाहर निकालें।
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