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Which of the following is the simplified form of \(\sqrt{28}\)?

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Answer and explanation

Correct answer: \(2\sqrt{7}\)

\(\sqrt{28}=\sqrt{4\times7}=\sqrt{4}\cdot\sqrt{7}=2\sqrt{7}\). The perfect square 4 is taken outside the radical, giving the principal (positive) square root. Option D is incorrect because the principal square root is non-negative, so \(-2\sqrt{7}\) is not the simplified value. Option C (\(\sqrt{14}\)) comes from a mistaken grouping and does not equal \(2\sqrt{7}\). Option B (\(4\sqrt{7}\)) would imply \(28=16\times7\), which is false. Exam tip: factor out the largest perfect-square factor to simplify radicals efficiently.

Related tags

SurdsSquare-RootSimplificationIrrational-NumbersReal-Numbers

Frequently asked questions

What is the correct answer to this question?

\(2\sqrt{7}\)

Why is this the correct answer?

\(\sqrt{28}=\sqrt{4\times7}=\sqrt{4}\cdot\sqrt{7}=2\sqrt{7}\). The perfect square 4 is taken outside the radical, giving the principal (positive) square root. Option D is incorrect because the principal square root is non-negative, so \(-2\sqrt{7}\) is not the simplified value. Option C (\(\sqrt{14}\)) comes from a mistaken grouping and does not equal \(2\sqrt{7}\). Option B (\(4\sqrt{7}\)) would imply \(28=16\times7\), which is false. Exam tip: factor out the largest perfect-square factor to simplify radicals efficiently.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Irrational numbers and real numbers.

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