कौन सा विकल्प \(\sqrt{6}\times\sqrt{10}\) की प्रकृति सही बताता है?
Which option correctly describes the nature of \(\sqrt{6}\times\sqrt{10}\)?
#irrational-product
#square-root
#classification
A अपरिमेय संख्या / Irrational number
B परिमेय संख्या / Rational number
C पूर्णांक / Integer
D सांत दशमलव / Terminating decimal
Explanation opens after your attempt
Correct Answer
A. अपरिमेय संख्या / Irrational number
Step 1
Concept
\(\sqrt{6}\times\sqrt{10}=\sqrt{60}=2\sqrt{15}\). Since (15) is not a perfect square the result is irrational.
Step 2
Why this answer is correct
The correct answer is A. अपरिमेय संख्या / Irrational number. \(\sqrt{6}\times\sqrt{10}=\sqrt{60}=2\sqrt{15}\). Since (15) is not a perfect square the result is irrational.
Step 3
Exam Tip
\(\sqrt{6}\times\sqrt{10}=\sqrt{60}=2\sqrt{15}\) है। (15) पूर्ण वर्ग नहीं है इसलिए परिणाम अपरिमेय है।
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यदि \(x=\sqrt{17}\) है तो \(x^2-5\) किस प्रकार की संख्या है?
If \(x=\sqrt{17}\), what type of number is \(x^2-5\)?
#square-root
#expression
#rational-result
A परिमेय संख्या / Rational number
B अपरिमेय संख्या / Irrational number
C अवास्तविक संख्या / Non real number
D अनावर्ती दशमलव / Non repeating decimal
Explanation opens after your attempt
Correct Answer
A. परिमेय संख्या / Rational number
Step 1
Concept
Here \(x^2=17\), so \(x^2-5=12\). This is a rational number.
Step 2
Why this answer is correct
The correct answer is A. परिमेय संख्या / Rational number. Here \(x^2=17\), so \(x^2-5=12\). This is a rational number.
Step 3
Exam Tip
\(x^2=17\) इसलिए \(x^2-5=12\) है। यह परिमेय संख्या है।
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कौन सा विकल्प \(\sqrt{180}\) का सरल रूप है?
Which option is the simplified form of \(\sqrt{180}\)?
#surds
#simplification
#square-root
A \(6\sqrt{5}\)
B \(18\sqrt{5}\)
C \(3\sqrt{20}\)
D \(5\sqrt{6}\)
Explanation opens after your attempt
Correct Answer
A. \(6\sqrt{5}\)
Step 1
Concept
\(\sqrt{180}=\sqrt{36\times5}=6\sqrt{5}\). Take out the greatest perfect square.
Step 2
Why this answer is correct
The correct answer is A. \(6\sqrt{5}\). \(\sqrt{180}=\sqrt{36\times5}=6\sqrt{5}\). Take out the greatest perfect square.
Step 3
Exam Tip
\(\sqrt{180}=\sqrt{36\times5}=6\sqrt{5}\) है। सबसे बड़ा पूर्ण वर्ग बाहर निकालें।
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कौन सा विकल्प \(\sqrt{300}\) का सरल रूप है?
Which option is the simplified form of \(\sqrt{300}\)?
#surds
#simplification
#square-root
A \(10\sqrt{3}\)
B \(30\sqrt{10}\)
C \(5\sqrt{12}\)
D \(3\sqrt{100}\)
Explanation opens after your attempt
Correct Answer
A. \(10\sqrt{3}\)
Step 1
Concept
\(\sqrt{300}=\sqrt{100\times3}=10\sqrt{3}\). Take out the greatest perfect square.
Step 2
Why this answer is correct
The correct answer is A. \(10\sqrt{3}\). \(\sqrt{300}=\sqrt{100\times3}=10\sqrt{3}\). Take out the greatest perfect square.
Step 3
Exam Tip
\(\sqrt{300}=\sqrt{100\times3}=10\sqrt{3}\) है। सबसे बड़ा पूर्ण वर्ग बाहर निकालें।
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कौन सा विकल्प \(\sqrt{50}\) और \(\sqrt{72}\) की तुलना सही करता है?
Which option correctly compares \(\sqrt{50}\) and \(\sqrt{72}\)?
#comparison
#square-root
#number-line
A \(\sqrt{72}>\sqrt{50}\)
B \(\sqrt{72}<\sqrt{50}\)
C \(\sqrt{72}=\sqrt{50}\)
D तुलना संभव नहीं / Comparison is not possible
Explanation opens after your attempt
Correct Answer
A. \(\sqrt{72}>\sqrt{50}\)
Step 1
Concept
For positive numbers a larger number inside the root gives a larger square root. Since (72>50), \(\sqrt{72}>\sqrt{50}\).
Step 2
Why this answer is correct
The correct answer is A. \(\sqrt{72}>\sqrt{50}\). For positive numbers a larger number inside the root gives a larger square root. Since (72>50), \(\sqrt{72}>\sqrt{50}\).
Step 3
Exam Tip
धनात्मक संख्याओं में अंदर की संख्या बड़ी हो तो वर्गमूल भी बड़ा होता है। (72>50) इसलिए \(\sqrt{72}>\sqrt{50}\)।
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कौन सा विकल्प \(\sqrt{2}\) के निकटतम दो पूर्णांकों को सही बताता है?
Which option correctly gives the two nearest integers between which \(\sqrt{2}\) lies?
#number-line
#square-root
#estimation
A (1) और (2) / (1) and (2)
B (2) और (3) / (2) and (3)
C (0) और (1) / (0) and (1)
D (3) और (4) / (3) and (4)
Explanation opens after your attempt
Correct Answer
A. (1) और (2) / (1) and (2)
Step 1
Concept
Since (1<2<4), \(1<\sqrt{2}<2\). Use squares to locate roots.
Step 2
Why this answer is correct
The correct answer is A. (1) और (2) / (1) and (2). Since (1<2<4), \(1<\sqrt{2}<2\). Use squares to locate roots.
Step 3
Exam Tip
क्योंकि (1<2<4) इसलिए \(1<\sqrt{2}<2\)। वर्गों से जड़ की स्थिति पहचानें।
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कौन सा विकल्प \(\sqrt{162}\) का सरल रूप है?
Which option is the simplified form of \(\sqrt{162}\)?
#surds
#simplification
#square-root
A \(9\sqrt{2}\)
B \(18\sqrt{2}\)
C \(3\sqrt{18}\)
D \(6\sqrt{3}\)
Explanation opens after your attempt
Correct Answer
A. \(9\sqrt{2}\)
Step 1
Concept
\(\sqrt{162}=\sqrt{81\times2}=9\sqrt{2}\). Take the greatest perfect square inside the root.
Step 2
Why this answer is correct
The correct answer is A. \(9\sqrt{2}\). \(\sqrt{162}=\sqrt{81\times2}=9\sqrt{2}\). Take the greatest perfect square inside the root.
Step 3
Exam Tip
\(\sqrt{162}=\sqrt{81\times2}=9\sqrt{2}\) है। जड़ में सबसे बड़ा पूर्ण वर्ग लें।
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किस विकल्प में केवल अपरिमेय संख्याएँ हैं?
Which option contains only irrational numbers?
#set-classification
#irrational-numbers
#square-root
A \(\sqrt{6}\), \(\sqrt{10}\), \(\sqrt{15}\)
B \(\sqrt{4}\), \(\sqrt{6}\), \(\sqrt{10}\)
C \(\frac{1}{2}\), \(\sqrt{10}\), \(\pi\)
D (0), \(\sqrt{6}\), \(\sqrt{15}\)
Explanation opens after your attempt
Correct Answer
A. \(\sqrt{6}\), \(\sqrt{10}\), \(\sqrt{15}\)
Step 1
Concept
In the first option none is the root of a perfect square. So all are irrational.
Step 2
Why this answer is correct
The correct answer is A. \(\sqrt{6}\), \(\sqrt{10}\), \(\sqrt{15}\). In the first option none is the root of a perfect square. So all are irrational.
Step 3
Exam Tip
पहले विकल्प में कोई भी संख्या पूर्ण वर्ग की जड़ नहीं है। इसलिए सभी अपरिमेय हैं।
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कौन सा विकल्प \(\sqrt{128}\) का सरल रूप है?
Which option is the simplified form of \(\sqrt{128}\)?
#surds
#simplification
#square-root
A \(8\sqrt{2}\)
B \(16\sqrt{2}\)
C \(4\sqrt{8}\)
D \(2\sqrt{32}\)
Explanation opens after your attempt
Correct Answer
A. \(8\sqrt{2}\)
Step 1
Concept
\(\sqrt{128}=\sqrt{64\times2}=8\sqrt{2}\). Taking out the greatest perfect square is the better method.
Step 2
Why this answer is correct
The correct answer is A. \(8\sqrt{2}\). \(\sqrt{128}=\sqrt{64\times2}=8\sqrt{2}\). Taking out the greatest perfect square is the better method.
Step 3
Exam Tip
\(\sqrt{128}=\sqrt{64\times2}=8\sqrt{2}\) है। सबसे बड़ा पूर्ण वर्ग निकालना बेहतर तरीका है।
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\(\frac{\sqrt{45}}{\sqrt{5}}\) का मान क्या है?
What is the value of \(\frac{\sqrt{45}}{\sqrt{5}}\)?
#division
#square-root
#rational-result
A (3)
B \(\sqrt{40}\)
C (9)
D \(\sqrt{9}\sqrt{5}\)
Explanation opens after your attempt
Step 1
Concept
\(\frac{\sqrt{45}}{\sqrt{5}}=\sqrt{9}=3\). In division of roots simplify the ratio inside.
Step 2
Why this answer is correct
The correct answer is A. (3). \(\frac{\sqrt{45}}{\sqrt{5}}=\sqrt{9}=3\). In division of roots simplify the ratio inside.
Step 3
Exam Tip
\(\frac{\sqrt{45}}{\sqrt{5}}=\sqrt{9}=3\) है। जड़ों की भाग में अंदर के अनुपात को सरल करें।
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कौन सा विकल्प \(\sqrt{3}\) और \(\sqrt{12}\) के बीच सही संबंध बताता है?
Which option gives the correct relation between \(\sqrt{3}\) and \(\sqrt{12}\)?
#surds
#comparison
#square-root
A \(\sqrt{12}=2\sqrt{3}\)
B \(\sqrt{12}=4\sqrt{3}\)
C \(\sqrt{12}=3\sqrt{2}\)
D \(\sqrt{12}=\sqrt{3}\)
Explanation opens after your attempt
Correct Answer
A. \(\sqrt{12}=2\sqrt{3}\)
Step 1
Concept
\(\sqrt{12}=\sqrt{4\times3}=2\sqrt{3}\). Taking out the perfect square makes comparison easy.
Step 2
Why this answer is correct
The correct answer is A. \(\sqrt{12}=2\sqrt{3}\). \(\sqrt{12}=\sqrt{4\times3}=2\sqrt{3}\). Taking out the perfect square makes comparison easy.
Step 3
Exam Tip
\(\sqrt{12}=\sqrt{4\times3}=2\sqrt{3}\) है। पूर्ण वर्ग बाहर निकालने से तुलना आसान होती है।
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यदि \(x=\sqrt{11}\) है तो \(x^2+1\) का मान किस प्रकार की संख्या है?
If \(x=\sqrt{11}\), what type of number is \(x^2+1\)?
#square-root
#expression
#rational-result
A परिमेय संख्या / Rational number
B अपरिमेय संख्या / Irrational number
C अवास्तविक संख्या / Non real number
D अनावर्ती दशमलव / Non repeating decimal
Explanation opens after your attempt
Correct Answer
A. परिमेय संख्या / Rational number
Step 1
Concept
Here \(x^2=11\), so \(x^2+1=12\). This is a rational number.
Step 2
Why this answer is correct
The correct answer is A. परिमेय संख्या / Rational number. Here \(x^2=11\), so \(x^2+1=12\). This is a rational number.
Step 3
Exam Tip
\(x^2=11\) इसलिए \(x^2+1=12\) है। यह परिमेय संख्या है।
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कौन सा विकल्प \(\sqrt{242}\) का सरल रूप है?
Which option is the simplified form of \(\sqrt{242}\)?
#surds
#simplification
#square-root
A \(11\sqrt{2}\)
B \(22\sqrt{2}\)
C \(2\sqrt{11}\)
D \(\sqrt{121}\)
Explanation opens after your attempt
Correct Answer
A. \(11\sqrt{2}\)
Step 1
Concept
\(\sqrt{242}=\sqrt{121\times2}=11\sqrt{2}\). Identify the perfect square factor inside the root.
Step 2
Why this answer is correct
The correct answer is A. \(11\sqrt{2}\). \(\sqrt{242}=\sqrt{121\times2}=11\sqrt{2}\). Identify the perfect square factor inside the root.
Step 3
Exam Tip
\(\sqrt{242}=\sqrt{121\times2}=11\sqrt{2}\) है। जड़ में पूर्ण वर्ग गुणनखंड पहचानें।
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कौन सा विकल्प \(\sqrt{200}\) का सरल रूप है?
Which option is the simplified form of \(\sqrt{200}\)?
#surds
#square-root
#simplification
A \(10\sqrt{2}\)
B \(20\sqrt{2}\)
C \(5\sqrt{8}\)
D \(2\sqrt{100}\)
Explanation opens after your attempt
Correct Answer
A. \(10\sqrt{2}\)
Step 1
Concept
\(\sqrt{200}=\sqrt{100\times2}=10\sqrt{2}\). Taking out the greatest perfect square is a good method.
Step 2
Why this answer is correct
The correct answer is A. \(10\sqrt{2}\). \(\sqrt{200}=\sqrt{100\times2}=10\sqrt{2}\). Taking out the greatest perfect square is a good method.
Step 3
Exam Tip
\(\sqrt{200}=\sqrt{100\times2}=10\sqrt{2}\) है। सबसे बड़े पूर्ण वर्ग को बाहर निकालना अच्छा तरीका है।
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कौन सा विकल्प \(\sqrt{150}\) का सरल रूप है?
Which option is the simplified form of \(\sqrt{150}\)?
#surds
#simplification
#square-root
A \(5\sqrt{6}\)
B \(15\sqrt{10}\)
C \(10\sqrt{15}\)
D \(3\sqrt{50}\)
Explanation opens after your attempt
Correct Answer
A. \(5\sqrt{6}\)
Step 1
Concept
\(\sqrt{150}=\sqrt{25\times6}=5\sqrt{6}\). The perfect square factor inside the root is (25).
Step 2
Why this answer is correct
The correct answer is A. \(5\sqrt{6}\). \(\sqrt{150}=\sqrt{25\times6}=5\sqrt{6}\). The perfect square factor inside the root is (25).
Step 3
Exam Tip
\(\sqrt{150}=\sqrt{25\times6}=5\sqrt{6}\) है। जड़ में पूर्ण वर्ग गुणनखंड (25) है।
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कौन सा विकल्प वास्तविक है लेकिन अपरिमेय है?
Which option is real but irrational?
#real-irrational
#classification
#square-root
A \(\sqrt{41}\)
B \(\frac{41}{1}\)
C (4.1)
D \(0.\overline{41}\)
Explanation opens after your attempt
Correct Answer
A. \(\sqrt{41}\)
Step 1
Concept
\(\sqrt{41}\) is real and (41) is not a perfect square. So it is irrational.
Step 2
Why this answer is correct
The correct answer is A. \(\sqrt{41}\). \(\sqrt{41}\) is real and (41) is not a perfect square. So it is irrational.
Step 3
Exam Tip
\(\sqrt{41}\) वास्तविक है और (41) पूर्ण वर्ग नहीं है। इसलिए यह अपरिमेय है।
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यदि \(x=\sqrt{19}\) है तो \(x^2\) क्या होगा?
If \(x=\sqrt{19}\), what is \(x^2\)?
#square-root
#square
#calculation
A (19)
B \(\sqrt{19}\)
C (38)
D (361)
Explanation opens after your attempt
Step 1
Concept
(\(\sqrt{19}\)2 =19). Squaring removes the square root.
Step 2
Why this answer is correct
The correct answer is A. (19). (\(\sqrt{19}\)2 =19). Squaring removes the square root.
Step 3
Exam Tip
(\(\sqrt{19}\)2 =19) होता है। वर्ग करने पर वर्गमूल हट जाती है।
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कौन सा विकल्प \(\sqrt{108}\) का सही सरल रूप है?
Which option is the correct simplified form of \(\sqrt{108}\)?
#surds
#square-root
#simplification
A \(6\sqrt{3}\)
B \(3\sqrt{6}\)
C \(9\sqrt{3}\)
D \(12\sqrt{3}\)
Explanation opens after your attempt
Correct Answer
A. \(6\sqrt{3}\)
Step 1
Concept
\(\sqrt{108}=\sqrt{36\times3}=6\sqrt{3}\). Taking out the perfect square simplifies the root.
Step 2
Why this answer is correct
The correct answer is A. \(6\sqrt{3}\). \(\sqrt{108}=\sqrt{36\times3}=6\sqrt{3}\). Taking out the perfect square simplifies the root.
Step 3
Exam Tip
\(\sqrt{108}=\sqrt{36\times3}=6\sqrt{3}\) है। पूर्ण वर्ग बाहर निकालने से जड़ सरल होती है।
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कौन सा विकल्प \(\sqrt{72}\) का सरल रूप है?
Which option is the simplified form of \(\sqrt{72}\)?
#surds
#simplification
#square-root
A \(6\sqrt{2}\)
B \(8\sqrt{2}\)
C \(3\sqrt{8}\)
D \(12\sqrt{2}\)
Explanation opens after your attempt
Correct Answer
A. \(6\sqrt{2}\)
Step 1
Concept
\(\sqrt{72}=\sqrt{36\times2}=6\sqrt{2}\). Find the large perfect square inside the root.
Step 2
Why this answer is correct
The correct answer is A. \(6\sqrt{2}\). \(\sqrt{72}=\sqrt{36\times2}=6\sqrt{2}\). Find the large perfect square inside the root.
Step 3
Exam Tip
\(\sqrt{72}=\sqrt{36\times2}=6\sqrt{2}\) है। जड़ के अंदर बड़ा पूर्ण वर्ग खोजें।
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\(\sqrt{43}\) के बारे में सही कथन कौन सा है?
Which statement is correct about \(\sqrt{43}\)?
#irrational-root
#square-root
#classification
A यह अपरिमेय है / It is irrational
B यह पूर्णांक है / It is an integer
C यह (7) के बराबर है / It is equal to (7)
D यह सांत दशमलव है / It is a terminating decimal
Explanation opens after your attempt
Correct Answer
A. यह अपरिमेय है / It is irrational
Step 1
Concept
(43) is not a perfect square so \(\sqrt{43}\) is irrational. Watch the root when the number is not a perfect square.
Step 2
Why this answer is correct
The correct answer is A. यह अपरिमेय है / It is irrational. (43) is not a perfect square so \(\sqrt{43}\) is irrational. Watch the root when the number is not a perfect square.
Step 3
Exam Tip
(43) पूर्ण वर्ग नहीं है इसलिए \(\sqrt{43}\) अपरिमेय है। पूर्ण वर्ग न होने पर जड़ पर ध्यान दें।
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\(\sqrt{144}\) का मान किस प्रकार की संख्या है?
What type of number is the value of \(\sqrt{144}\)?
#perfect-square
#square-root
#rational-number
A परिमेय संख्या / Rational number
B अपरिमेय संख्या / Irrational number
C अवास्तविक संख्या / Non real number
D ऋणात्मक संख्या / Negative number
Explanation opens after your attempt
Correct Answer
A. परिमेय संख्या / Rational number
Step 1
Concept
\(\sqrt{144}=12\) and (12) is rational. The square root of a perfect square is rational.
Step 2
Why this answer is correct
The correct answer is A. परिमेय संख्या / Rational number. \(\sqrt{144}=12\) and (12) is rational. The square root of a perfect square is rational.
Step 3
Exam Tip
\(\sqrt{144}=12\) है और (12) परिमेय है। पूर्ण वर्ग की वर्गमूल परिमेय होती है।
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कौन सी संख्या अपरिमेय है?
Which number is irrational?
#irrational-numbers
#square-root
#classification
A \(\sqrt{22}\)
B \(\frac{8}{3}\)
C (4.75)
D (-6)
Explanation opens after your attempt
Correct Answer
A. \(\sqrt{22}\)
Step 1
Concept
\(\sqrt{22}\) is irrational because (22) is not a perfect square. In exams first check perfect squares.
Step 2
Why this answer is correct
The correct answer is A. \(\sqrt{22}\). \(\sqrt{22}\) is irrational because (22) is not a perfect square. In exams first check perfect squares.
Step 3
Exam Tip
\(\sqrt{22}\) अपरिमेय है क्योंकि (22) पूर्ण वर्ग नहीं है। परीक्षा में पहले पूर्ण वर्गों की जाँच करें।
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कौन सा विकल्प \(\sqrt{80}\) का सही सरल रूप है?
Which option is the correct simplified form of \(\sqrt{80}\)?
#surds
#simplification
#square-root
A \(4\sqrt{5}\)
B \(8\sqrt{5}\)
C \(5\sqrt{4}\)
D \(2\sqrt{20}\)
Explanation opens after your attempt
Correct Answer
A. \(4\sqrt{5}\)
Step 1
Concept
\(\sqrt{80}=\sqrt{16\times5}=4\sqrt{5}\). Look for a perfect square factor inside the root.
Step 2
Why this answer is correct
The correct answer is A. \(4\sqrt{5}\). \(\sqrt{80}=\sqrt{16\times5}=4\sqrt{5}\). Look for a perfect square factor inside the root.
Step 3
Exam Tip
\(\sqrt{80}=\sqrt{16\times5}=4\sqrt{5}\) है। जड़ के अंदर पूर्ण वर्ग गुणनखंड खोजें।
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कौन सा निष्कर्ष सही है यदि \(\sqrt{k}=12\) है?
Which conclusion is correct if \(\sqrt{k}=12\)?
#perfect-square
#square-root
#reasoning
A (k=144) और (k) पूर्ण वर्ग है / (k=144) and (k) is a perfect square
B (k=24) और (k) अपरिमेय है / (k=24) and (k) is irrational
C (k=6) और (k) पूर्ण घन है / (k=6) and (k) is a perfect cube
D (k=12) और (k) अपरिमेय है / (k=12) and (k) is irrational
Explanation opens after your attempt
Correct Answer
A. (k=144) और (k) पूर्ण वर्ग है / (k=144) and (k) is a perfect square
Step 1
Concept
From \(\sqrt{k}=12\), \(k=12^2=144\). Therefore (k) is a perfect square.
Step 2
Why this answer is correct
The correct answer is A. (k=144) और (k) पूर्ण वर्ग है / (k=144) and (k) is a perfect square. From \(\sqrt{k}=12\), \(k=12^2=144\). Therefore (k) is a perfect square.
Step 3
Exam Tip
\(\sqrt{k}=12\) से \(k=12^2=144\) मिलता है। इसलिए (k) पूर्ण वर्ग है।
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कौन सा विकल्प \(\sqrt{147}\) का सरल रूप है?
Which option is the simplified form of \(\sqrt{147}\)?
#surds
#simplification
#square-root
A \(7\sqrt{3}\)
B \(3\sqrt{7}\)
C \(21\sqrt{3}\)
D \(\sqrt{49}\)
Explanation opens after your attempt
Correct Answer
A. \(7\sqrt{3}\)
Step 1
Concept
\(\sqrt{147}=\sqrt{49\times3}=7\sqrt{3}\). Take the large perfect square outside the root.
Step 2
Why this answer is correct
The correct answer is A. \(7\sqrt{3}\). \(\sqrt{147}=\sqrt{49\times3}=7\sqrt{3}\). Take the large perfect square outside the root.
Step 3
Exam Tip
\(\sqrt{147}=\sqrt{49\times3}=7\sqrt{3}\) है। बड़े पूर्ण वर्ग को जड़ से बाहर निकालें।
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कौन सा विकल्प \(\sqrt{28}\) का सरल रूप है?
Which option is the simplified form of \(\sqrt{28}\)?
#surds
#square-root
#simplification
A \(2\sqrt{7}\)
B \(7\sqrt{2}\)
C \(4\sqrt{7}\)
D \(\sqrt{14}\)
Explanation opens after your attempt
Correct Answer
A. \(2\sqrt{7}\)
Step 1
Concept
\(\sqrt{28}=\sqrt{4\times7}=2\sqrt{7}\). The perfect square (4) comes outside.
Step 2
Why this answer is correct
The correct answer is A. \(2\sqrt{7}\). \(\sqrt{28}=\sqrt{4\times7}=2\sqrt{7}\). The perfect square (4) comes outside.
Step 3
Exam Tip
\(\sqrt{28}=\sqrt{4\times7}=2\sqrt{7}\) है। पूर्ण वर्ग (4) बाहर आता है।
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\(\sqrt{\frac{16}{25}}\) का मान क्या है?
What is the value of \(\sqrt{\frac{16}{25}}\)?
#square-root
#fraction
#rational-numbers
A \(\frac{4}{5}\)
B \(\frac{16}{5}\)
C \(\frac{8}{25}\)
D \(\frac{2}{5}\)
Explanation opens after your attempt
Correct Answer
A. \(\frac{4}{5}\)
Step 1
Concept
\(\sqrt{\frac{16}{25}}=\frac{\sqrt{16}}{\sqrt{25}}=\frac{4}{5}\). This is a rational number.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{4}{5}\). \(\sqrt{\frac{16}{25}}=\frac{\sqrt{16}}{\sqrt{25}}=\frac{4}{5}\). This is a rational number.
Step 3
Exam Tip
\(\sqrt{\frac{16}{25}}=\frac{\sqrt{16}}{\sqrt{25}}=\frac{4}{5}\) है। यह परिमेय संख्या है।
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यदि \(x=\sqrt{13}\) है तो \(x^2\) का मान क्या है?
If \(x=\sqrt{13}\), what is the value of \(x^2\)?
#square-root
#square
#calculation
A (13)
B \(\sqrt{13}\)
C (169)
D (26)
Explanation opens after your attempt
Step 1
Concept
(\(\sqrt{13}\)2 =13). Squaring and taking the square root cancel each other.
Step 2
Why this answer is correct
The correct answer is A. (13). (\(\sqrt{13}\)2 =13). Squaring and taking the square root cancel each other.
Step 3
Exam Tip
(\(\sqrt{13}\)2 =13) होता है। वर्ग और वर्गमूल एक-दूसरे को समाप्त कर देते हैं।
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\(\sqrt{75}\) का सही सरल रूप कौन सा है?
Which is the correct simplified form of \(\sqrt{75}\)?
#surds
#square-root
#simplification
A \(5\sqrt{3}\)
B \(3\sqrt{5}\)
C \(25\sqrt{3}\)
D \(\sqrt{15}\)
Explanation opens after your attempt
Correct Answer
A. \(5\sqrt{3}\)
Step 1
Concept
\(\sqrt{75}=\sqrt{25\times3}=5\sqrt{3}\). Take the perfect square factor (25) outside.
Step 2
Why this answer is correct
The correct answer is A. \(5\sqrt{3}\). \(\sqrt{75}=\sqrt{25\times3}=5\sqrt{3}\). Take the perfect square factor (25) outside.
Step 3
Exam Tip
\(\sqrt{75}=\sqrt{25\times3}=5\sqrt{3}\) है। पूर्ण वर्ग गुणनखंड (25) को बाहर निकालें।
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\(\sqrt{32}\) का सरल रूप क्या है?
What is the simplified form of \(\sqrt{32}\)?
#surds
#simplification
#square-root
A \(4\sqrt{2}\)
B \(8\sqrt{2}\)
C \(2\sqrt{8}\)
D \(\sqrt{16}\)
Explanation opens after your attempt
Correct Answer
A. \(4\sqrt{2}\)
Step 1
Concept
\(\sqrt{32}=\sqrt{16\times2}=4\sqrt{2}\). Take out the greatest perfect square.
Step 2
Why this answer is correct
The correct answer is A. \(4\sqrt{2}\). \(\sqrt{32}=\sqrt{16\times2}=4\sqrt{2}\). Take out the greatest perfect square.
Step 3
Exam Tip
\(\sqrt{32}=\sqrt{16\times2}=4\sqrt{2}\) है। सबसे बड़ा पूर्ण वर्ग बाहर निकालें।
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