59 results found for "cosecant-cotangent" in all classes.
What is \(\frac{1}{\cosec x-\cot x}\) equal to?
C. \(\cosec x+\cot x\)
क्योंकि (\(\cosec x-\cot x\)\(\cosec x+\cot x\)=1)। इसलिए आवश्यक व्युत्क्रम \(\cosec x+\cot x\) है। / Since (\(\cosec x-\cot x\)\(\cosec x+\cot x\)=1). Hence the required reciprocal is \(\cosec x+\cot x\).
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If \(\cosec x+\cot x=4\), what is the value of \(\cot x\)?
B. \(\frac{15}{8}\)
\(\cosec x-\cot x=\frac{1}{4}\) होगा। घटाने पर \(2\cot x=4-\frac{1}{4}\), इसलिए \(\cot x=\frac{15}{8}\)। / \(\cosec x-\cot x=\frac{1}{4}\). Subtracting gives \(2\cot x=4-\frac{1}{4}\), so \(\cot x=\frac{15}{8}\).
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What is the simplified value of \(\frac{\cosec x}{\cot x}\)?
B. \(\sec x\)
\(\cosec x=\frac{1}{\sin x}\) और \(\cot x=\frac{\cos x}{\sin x}\) रखें। अनुपात \(\frac{1}{\cos x}=\sec x\) होगा। / Put \(\cosec x=\frac{1}{\sin x}\) and \(\cot x=\frac{\cos x}{\sin x}\). The ratio becomes \(\frac{1}{\cos x}=\sec x\).
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If \(\cosec x+\cot x=6\), what is the value of \(\cosec x-\cot x\)?
A. \(\frac{1}{6}\)
(\(\cosec x+\cot x\)\(\cosec x-\cot x\)=1) होता है। इसलिए आवश्यक मान \(\frac{1}{6}\) है। / The identity is (\(\cosec x+\cot x\)\(\cosec x-\cot x\)=1). Therefore, the required value is \(\frac{1}{6}\).
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If \(\cosec x-\cot x=\frac{1}{3}\), what is the value of \(\cosec x+\cot x\)?
B. (3)
क्योंकि (\(\cosec x-\cot x\)\(\cosec x+\cot x\)=1)। इसलिए \(\cosec x+\cot x=3\)। / Since (\(\cosec x-\cot x\)\(\cosec x+\cot x\)=1). Hence \(\cosec x+\cot x=3\).
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What is the simplified value of \(\frac{\cosec^2 x-1}{\cot^2 x}\)?
C. (1)
\(\cosec^2 x-1=\cot^2 x\) होता है। इसलिए अनुपात (1) है। / \(\cosec^2 x-1=\cot^2 x\). Hence the ratio is (1).
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If (x) is in the second quadrant and \(\cot x=-\frac{3}{4}\), what is the value of \(\cosec x\)?
A. \(\frac{5}{4}\)
\(\cosec^2 x=1+\cot^2 x\) से \(|\cosec x|=\frac{5}{4}\) मिलता है। दूसरे चतुर्थांश में \(\cosec x\) धनात्मक होता है। / From \(\cosec^2 x=1+\cot^2 x\), \(|\cosec x|=\frac{5}{4}\). In the second quadrant, \(\cosec x\) is positive.
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If \(\cot x=\frac{8}{15}\) and (x) is in the first quadrant, what is the value of \(\cosec x\)?
B. \(\frac{17}{15}\)
\(\cosec^2 x=1+\cot^2 x\) से \(\cosec x=\frac{17}{15}\) मिलता है। प्रथम चतुर्थांश में धनात्मक मान लें। / From \(\cosec^2 x=1+\cot^2 x\), \(\cosec x=\frac{17}{15}\). Take the positive value in the first quadrant.
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What is the value of \(\cosec^2 x-\cot^2 x\)?
B. (1)
क्योंकि \(\cosec^2 x=1+\cot^2 x\), अंतर (1) होगा। यह पहचान \(\sin^2 x+\cos^2 x=1\) से जुड़ी है। / Since \(\cosec^2 x=1+\cot^2 x\), the difference is (1). This identity is linked to \(\sin^2 x+\cos^2 x=1\).
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What is \(\cosec^2 \theta-1\) equal to?
B. \(\cot^2 \theta\)
\(\cosec^2 \theta=1+\cot^2 \theta\) से \(\cosec^2 \theta-1=\cot^2 \theta\) होता है। समान पहचान सूत्रों की जोड़ी बनाकर अभ्यास करें। / From \(\cosec^2 \theta=1+\cot^2 \theta\), \(\cosec^2 \theta-1=\cot^2 \theta\). Practice similar identities in pairs.
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What is the value of \(cosec^2 \theta-\cot^2 \theta\)?
A. (1)
\(cosec^2 \theta=1+\cot^2 \theta\) होता है। समान प्रकार के सूत्रों को साथ में याद करें। / \(cosec^2 \theta=1+\cot^2 \theta\). Remember similar identities together.
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Where is \(\cosec x\) not defined?
B. \(x=n\pi\)
\(\cosec x=\frac{1}{\sin x}\) है, इसलिए \(\sin x=0\) पर यह अपरिभाषित होता है। अतः \(x=n\pi\)। / Since \(\cosec x=\frac{1}{\sin x}\), it is undefined when \(\sin x=0\). Thus \(x=n\pi\).
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If \(\cosec \theta=\frac{5}{2}\) and \(\theta\) is in the first quadrant, what is \(\sin \theta\)?
C. \(\frac{2}{5}\)
\(\cosec \theta=\frac{1}{\sin \theta}\), इसलिए \(\sin \theta=\frac{2}{5}\) है। परीक्षा में cosecant और sine reciprocal हैं। / \( \cosec \theta=\frac{1}{\sin \theta}\), so \( \sin \theta=\frac{2}{5}\). In exams remember cosecant and sine are reciprocals.
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What is the simplified value of \(\frac{1}{1+\cos x}+\frac{1}{1-\cos x}\)?
C. \(2\cosec^2 x\)
हरों को मिलाने पर \(\frac{2}{1-\cos^2 x}\) मिलता है। यह \(\frac{2}{\sin^2 x}=2\cosec^2 x\) है। / Combining denominators gives \(\frac{2}{1-\cos^2 x}\). This is \(\frac{2}{\sin^2 x}=2\cosec^2 x\).
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How can \(\sec^2 x+\cosec^2 x\) be written in terms of \(\tan x\) and \(\cot x\)?
B. \(2+\tan^2 x+\cot^2 x\)
\(\sec^2 x=1+\tan^2 x\) और \(\cosec^2 x=1+\cot^2 x\) लगाएँ। योग \(2+\tan^2 x+\cot^2 x\) होगा। / Use \(\sec^2 x=1+\tan^2 x\) and \(\cosec^2 x=1+\cot^2 x\). The sum becomes \(2+\tan^2 x+\cot^2 x\).
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What is (\cosec\(\frac{\pi}{2}-x\)) equal to?
A. \(\sec x\)
(\sin\(\frac{\pi}{2}-x\)=\cos x), इसलिए (\cosec\(\frac{\pi}{2}-x\)=\frac{1}{\cos x}=\sec x)। व्युत्क्रम और पूरक पहचान साथ लगाएँ। / (\sin\(\frac{\pi}{2}-x\)=\cos x), so (\cosec\(\frac{\pi}{2}-x\)=\frac{1}{\cos x}=\sec x). Use reciprocal and cofunction identities together.
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What is (\sec\(\frac{\pi}{2}-x\)) equal to?
C. \(\cosec x\)
(\cos\(\frac{\pi}{2}-x\)=\sin x), इसलिए (\sec\(\frac{\pi}{2}-x\)=\frac{1}{\sin x}=\cosec x)। पूरक कोण में सहफलन बनता है। / (\cos\(\frac{\pi}{2}-x\)=\sin x), so (\sec\(\frac{\pi}{2}-x\)=\frac{1}{\sin x}=\cosec x). Complementary angles give cofunctions.
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If \(\cosec x=4\), what is the value of \(\sin x\)?
D. \(\frac{1}{4}\)
\(\cosec x=\frac{1}{\sin x}\) होता है। इसलिए \(\sin x=\frac{1}{4}\); हर व्युत्क्रम फलन को जोड़ी में याद करें। / \(\cosec x=\frac{1}{\sin x}\). Hence \(\sin x=\frac{1}{4}\); learn each reciprocal function as a pair.
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Where is \(\cosec x\) undefined?
B. \(\sin x=0\)
\(\cosec x=\frac{1}{\sin x}\) है, इसलिए \(\sin x=0\) पर यह अपरिभाषित होता है। व्युत्क्रम में नीचे वाला फलन शून्य नहीं होना चाहिए। / \(\cosec x=\frac{1}{\sin x}\), so it is undefined when \(\sin x=0\). In a reciprocal, the denominator function must not be zero.
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What is the range of \(\cosec x\)?
A. (\(-\infty,-1]\cup[1,\infty\))
\(\cosec x=\frac{1}{\sin x}\) है। इसलिए इसका परिसर (\(-\infty,-1]\cup[1,\infty\)) होता है। / \(\cosec x=\frac{1}{\sin x}\). Therefore, its range is (\(-\infty,-1]\cup[1,\infty\)).
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What is the period of the function \(\cosec x\)?
C. \(2\pi\)
\(\cosec x\) \(\sin x\) का व्युत्क्रम है और इसका काल \(2\pi\) है। व्युत्क्रम संबंध से काल पहचानें। / \(\cosec x\) is the reciprocal of \(\sin x\) and its period is \(2\pi\). Use reciprocal relation to identify the period.
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The function \(\cosec x\) is the reciprocal of which function?
B. \(\sin x\)
\(\cosec x=\frac{1}{\sin x}\) होता है। ध्यान रखें कि \(\cosec x\) का संबंध \(\sin x\) से है। / \(\cosec x=\frac{1}{\sin x}\). Remember that \(\cosec x\) is related to \(\sin x\).
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What is (\cosec\(2\pi-\theta\)) equal to?
A. -\(\cosec \theta\)
\(\cosec \theta\) \(\sin \theta\) का व्युत्क्रम है और चौथे चतुर्थांश में ऋणात्मक होता है। इसलिए मान \(-\cosec \theta\) है। / \(\cosec \theta\) is the reciprocal of \(\sin \theta\) and is negative in the fourth quadrant. Therefore the value is \(-\cosec \theta\).
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What is (\cosec\(\theta+2\pi\)) equal to?
C. \(\cosec \theta\)
\(\cosec \theta\) का काल \(2\pi\) है क्योंकि यह \(\sin \theta\) का व्युत्क्रम है। काल से उत्तर तुरंत मिलता है। / The period of \(\cosec \theta\) is \(2\pi\) because it is the reciprocal of \(\sin \theta\). The period gives the answer directly.
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What is (\cosec\left\(\frac{\pi}{2}+\theta\right\)) equal to?
B. \(\sec \theta\)
\(\cosec \theta\) का सह-फलन \(\sec \theta\) है और दूसरे चतुर्थांश में चिह्न धनात्मक रहता है। सह-फलन जोड़ों को याद रखें। / The cofunction of \(\cosec \theta\) is \(\sec \theta\), and the sign remains positive in the second quadrant. Remember cofunction pairs.
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What is (\sec\left\(\frac{\pi}{2}-\theta\right\)) equal to?
D. \(\cosec \theta\)
(\sec\left\(\frac{\pi}{2}-\theta\right\)=\cosec \theta) होता है। \(\sec \theta\) और \(\cosec \theta\) सह-फलन हैं। / (\sec\left\(\frac{\pi}{2}-\theta\right\)=\cosec \theta). \(\sec \theta\) and \(\cosec \theta\) are cofunctions.
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When is \(\cosec \theta\) undefined?
C. जब \(\sin \theta=0\)when \(\sin \theta=0\)
\(\cosec \theta=\frac{1}{\sin \theta}\) है इसलिए \(\sin \theta=0\) पर यह अपरिभाषित होता है। हर शून्य होने पर फलन नहीं बनता। / \(\cosec \theta=\frac{1}{\sin \theta}\), so it is undefined when \(\sin \theta=0\). A function is not defined when the denominator is zero.
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What is the range of \(\cosec \theta\)?
D. (\(-\infty,-1]\cup[1,\infty\))
\(\cosec \theta=\frac{1}{\sin \theta}\) होता है। इसका परिसर (\(-\infty,-1]\cup[1,\infty\)) है। / \(\cosec \theta=\frac{1}{\sin \theta}\). Its range is (\(-\infty,-1]\cup[1,\infty\)).
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What is (\cosec\(-\theta\)) equal to?
B. \(-\cosec \theta\)
\(\cosec \theta\) विषम फलन है इसलिए (\cosec\(-\theta\)=-\cosec \theta)। यह \(\sin \theta\) के व्युत्क्रम जैसा व्यवहार करता है। / \(\cosec \theta\) is an odd function, so (\cosec\(-\theta\)=-\cosec \theta). It behaves like the reciprocal of \(\sin \theta\).
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Which trigonometric function is the reciprocal of \(\sin \theta\)?
B. \(\cosec \theta\)
\(\cosec \theta=\frac{1}{\sin \theta}\) होता है। व्युत्क्रम संबंधों को जोड़ों में याद करें। / \(\cosec \theta=\frac{1}{\sin \theta}\). Remember reciprocal relations in pairs.
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If \(\cot x=3\), what is the value of \(\cosec^2 x\)?
B. (10)
\(\cosec^2 x=1+\cot^2 x\) होता है। इसलिए (1+9=10) है। / We know \(\cosec^2 x=1+\cot^2 x\). Hence (1+9=10).
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What is the value of \(\tan \theta \cdot \cot \theta\), when both are defined?
C. (1)
\(\cot \theta=\frac{1}{\tan \theta}\), इसलिए गुणनफल (1) है। परीक्षा में reciprocal formulas से समय बचता है। / \( \cot \theta=\frac{1}{\tan \theta}\), so the product is (1). In exams reciprocal formulas save time.
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If \(\cot \theta=\frac{12}{5}\) and \(\theta\) is in the first quadrant, what is \(\cos \theta\)?
B. \(\frac{12}{13}\)
\(\cot \theta=\frac{12}{5}\) में adjacent (12), opposite (5), hypotenuse (13) है। \(परीक्षा में (\cos \theta=\frac{\)adjacent}{hypotenuse}) लगाएं। \(/ In ( \cot \theta=\frac{12}{5}), adjacent is (12), opposite is (5), and hypotenuse is (13). In exams use ( \cos \theta=\frac{\)adjacent}{hypotenuse}).
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What is (\cot\left\(\frac{\pi}{2}-\theta\right\)) equal to?
D. \(\tan \theta\)
\(\frac{\pi}{2}-\theta\) पर cotangent का co-function tangent होता है। परीक्षा में reciprocal function pair याद रखें। / At \( \frac{\pi}{2}-\theta\), cotangent changes to the co-function tangent. In exams remember reciprocal function pairs.
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If \(\sin x-\cos x=\frac{1}{3}\), what is the value of \(\tan x+\cot x\)?
A. \(\frac{9}{4}\)
वर्ग करने पर \(1-2\sin x\cos x=\frac{1}{9}\) मिलता है। इसलिए \(\sin x\cos x=\frac{4}{9}\) और \(\tan x+\cot x=\frac{9}{4}\)। / Squaring gives \(1-2\sin x\cos x=\frac{1}{9}\). Thus \(\sin x\cos x=\frac{4}{9}\) and \(\tan x+\cot x=\frac{9}{4}\).
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If \(\sin x+\cos x=\frac{7}{5}\), what is the value of \(\tan x+\cot x\)?
B. \(\frac{25}{12}\)
वर्ग करने पर \(1+2\sin x\cos x=\frac{49}{25}\), इसलिए \(\sin x\cos x=\frac{12}{25}\)। अब \(\tan x+\cot x=\frac{1}{\sin x\cos x}=\frac{25}{12}\)। / Squaring gives \(1+2\sin x\cos x=\frac{49}{25}\), so \(\sin x\cos x=\frac{12}{25}\). Now \(\tan x+\cot x=\frac{1}{\sin x\cos x}=\frac{25}{12}\).
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If \(\cot x=\frac{3}{2}\), what is the value of \(\frac{\cot^2 x-1}{\cot^2 x+1}\)?
A. \(\frac{5}{13}\)
\(\cot^2 x=\frac{9}{4}\) रखकर सरल करें। मान \(\frac{\frac{9}{4}-1}{\frac{9}{4}+1}=\frac{5}{13}\) है। / Substitute \(\cot^2 x=\frac{9}{4}\) and simplify. The value is \(\frac{\frac{9}{4}-1}{\frac{9}{4}+1}=\frac{5}{13}\).
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What is the simplified value of (\sin-2 x\(1+\cot^2 x\))?
B. (1)
क्योंकि \(1+\cot^2 x=\cosec^2 x\)। इसलिए \(\sin^2 x\cosec^2 x=1\) होगा। / Since \(1+\cot^2 x=\cosec^2 x\). Therefore, \(\sin^2 x\cosec^2 x=1\).
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What is the simplified value of \(\frac{\tan x+\cot x}{\sec x\cosec x}\)?
A. (1)
\(\tan x+\cot x=\frac{1}{\sin x\cos x}\) और \(\sec x\cosec x=\frac{1}{\sin x\cos x}\) होता है। इसलिए अनुपात (1) है। / \(\tan x+\cot x=\frac{1}{\sin x\cos x}\) and \(\sec x\cosec x=\frac{1}{\sin x\cos x}\). Hence the ratio is (1).
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What is the simplified value of (\frac{\cos\(2\pi-x\)}{\sin\(\pi+x\)})?
B. -\(\cot x\)
(\cos\(2\pi-x\)=\cos x) और (\sin\(\pi+x\)=-\sin x) है। इसलिए मान \(-\cot x\) है। / (\cos\(2\pi-x\)=\cos x) and (\sin\(\pi+x\)=-\sin x). Hence the value is \(-\cot x\).
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What is (\tan\(\frac{3\pi}{2}+x\)) equal to?
C. -\(\cot x\)
\(\frac{3\pi}{2}+x\) पर \(\tan\) बदलकर \(\cot\) होता है और चिन्ह ऋणात्मक है। इसलिए (\tan\(\frac{3\pi}{2}+x\)=-\cot x)। / At \(\frac{3\pi}{2}+x\), \(\tan\) changes to \(\cot\) with a negative sign. Hence (\tan\(\frac{3\pi}{2}+x\)=-\cot x).
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What is \(\frac{1+\cos x}{\sin x}\) equal to?
C. \(\cot \frac{x}{2}\)
मानक अर्ध-कोण रूप \(\cot \frac{x}{2}=\frac{1+\cos x}{\sin x}\) है। \(\tan \frac{x}{2}\) और \(\cot \frac{x}{2}\) के रूप अलग रखें। / The standard half-angle form is \(\cot \frac{x}{2}=\frac{1+\cos x}{\sin x}\). Keep the forms of \(\tan \frac{x}{2}\) and \(\cot \frac{x}{2}\) separate.
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If \(\tan x+\cot x=5\), what is the value of \(\tan^2 x+\cot^2 x\)?
B. (23)
(\(\tan x+\cot x\)2=\tan-2 x+\cot-2 x+2) होता है। इसलिए मान (25-2=23) है। / (\(\tan x+\cot x\)2=\tan-2 x+\cot-2 x+2). Therefore, the value is (25-2=23).
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What is the simplified value of \(\frac{1+\tan^2 x}{1+\cot^2 x}\)?
A. \(\tan^2 x\)
ऊपर \(1+\tan^2 x=\sec^2 x\) और नीचे \(1+\cot^2 x=\cosec^2 x\) है। अनुपात \(\frac{\sec^2 x}{\cosec^2 x}=\tan^2 x\) होता है। / The numerator is \(1+\tan^2 x=\sec^2 x\) and the denominator is \(1+\cot^2 x=\cosec^2 x\). Their ratio is \(\frac{\sec^2 x}{\cosec^2 x}=\tan^2 x\).
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What is (\tan\(\frac{\pi}{2}+x\)) equal to?
A. \(-\cot x\)
\(\frac{\pi}{2}+x\) पर \(\tan\) बदलकर \(\cot\) होता है और चिन्ह ऋणात्मक होता है। इसलिए (\tan\(\frac{\pi}{2}+x\)=-\cot x)। / At \(\frac{\pi}{2}+x\), \(\tan\) changes to \(\cot\) with a negative sign. Hence (\tan\(\frac{\pi}{2}+x\)=-\cot x).
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If \(\cot x=\frac{5}{12}\) and (x) is in the first quadrant, what is the value of \(\cos x\)?
C. \(\frac{5}{13}\)
\(\cot x=\frac{5}{12}\) में आसन्न (5) और सामने (12) मानें। कर्ण (13) होगा, इसलिए \(\cos x=\frac{5}{13}\)। / For \(\cot x=\frac{5}{12}\), take adjacent as (5) and opposite as (12). The hypotenuse is (13), so \(\cos x=\frac{5}{13}\).
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If \(\cos x=\frac{8}{17}\) and (x) is in the first quadrant, what is the value of \(\cot x\)?
A. \(\frac{8}{15}\)
\(\sin x=\frac{15}{17}\) मिलता है और \(\cot x=\frac{\cos x}{\sin x}\) होता है। इसलिए \(\cot x=\frac{8}{15}\)। / \(\sin x=\frac{15}{17}\) and \(\cot x=\frac{\cos x}{\sin x}\). Therefore, \(\cot x=\frac{8}{15}\).
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Where is \(\cot x\) undefined?
B. \(\sin x=0\)
\(\cot x=\frac{\cos x}{\sin x}\) है, इसलिए \(\sin x=0\) पर यह अपरिभाषित होता है। हर को हमेशा ध्यान से देखें। / \(\cot x=\frac{\cos x}{\sin x}\), so it is undefined when \(\sin x=0\). Always check the denominator carefully.
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What is the period of the function \(\cot x\)?
A. \(\pi\)
\(\cot x\) हर \(\pi\) के बाद अपना मान दोहराता है। \(\tan x\) और \(\cot x\) दोनों का काल \(\pi\) है। / \(\cot x\) repeats its value after every \(\pi\). Both \(\tan x\) and \(\cot x\) have period \(\pi\).
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What is (\tan\(\frac{\pi}{2}-x\)) equal to?
B. \(\cot x\)
\(\frac{\pi}{2}\) के पूरक कोण में \(\tan x\) बदलकर \(\cot x\) हो जाता है। पूरक पहचान याद रखें। / For a complementary angle with \(\frac{\pi}{2}\), \(\tan x\) changes to \(\cot x\). Remember cofunction identities.
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How is \(\cot x\) written in terms of \(\sin x\) and \(\cos x\)?
B. \(\frac{\cos x}{\sin x}\)
\(\cot x=\frac{\cos x}{\sin x}\) होता है। \(\tan x\) और \(\cot x\) एक-दूसरे के व्युत्क्रम हैं। / \(\cot x=\frac{\cos x}{\sin x}\). \(\tan x\) and \(\cot x\) are reciprocals of each other.
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What is (\cot\(\theta+\pi\)) equal to?
A. \(\cot \theta\)
\(\cot \theta\) का काल \(\pi\) होता है। इसलिए (\cot\(\theta+\pi\)) का मान \(\cot \theta\) ही रहता है। / The period of \(\cot \theta\) is \(\pi\). Therefore (\cot\(\theta+\pi\)) remains \(\cot \theta\).
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What is (\cot\left\(\frac{\pi}{2}+\theta\right\)) equal to?
D. -\(\tan \theta\)
\(\cot \theta\) का सह-फलन \(\tan \theta\) है और दूसरे चतुर्थांश में चिह्न ऋणात्मक होता है। ऐसे प्रश्नों में पहले सह-फलन पहचानें। / The cofunction of \(\cot \theta\) is \(\tan \theta\), and the sign is negative in the second quadrant. In such questions, first identify the cofunction.
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What is (\tan\left\(\frac{\pi}{2}-\theta\right\)) equal to?
C. \(\cot \theta\)
(\tan\left\(\frac{\pi}{2}-\theta\right\)=\cot \theta) होता है। \(\tan \theta\) का सह-फलन \(\cot \theta\) है। / (\tan\left\(\frac{\pi}{2}-\theta\right\)=\cot \theta). The cofunction of \(\tan \theta\) is \(\cot \theta\).
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When is \(\cot \theta\) undefined?
D. जब \(\sin \theta=0\)when \(\sin \theta=0\)
\(\cot \theta=\frac{\cos \theta}{\sin \theta}\) है इसलिए \(\sin \theta=0\) पर यह अपरिभाषित होता है। भाग वाले फलनों में हर पहचानें। / \(\cot \theta=\frac{\cos \theta}{\sin \theta}\), so it is undefined when \(\sin \theta=0\). In quotient functions, identify the denominator.
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What is the range of \(\cot \theta\)?
A. (\(-\infty,\infty\))
\(\cot \theta\) सभी वास्तविक मान ले सकता है। \(\tan \theta\) और \(\cot \theta\) का परिसर समान है। / \(\cot \theta\) can take all real values. \(\tan \theta\) and \(\cot \theta\) have the same range.
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What is the fundamental period of \(\cot \theta\)?
A. \(\pi\)
\(\cot \theta\) का मूल काल \(\pi\) होता है। \(\tan \theta\) और \(\cot \theta\) का काल समान है। / The fundamental period of \(\cot \theta\) is \(\pi\). \(\tan \theta\) and \(\cot \theta\) have the same period.
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What is \(\cot \theta\) equal to?
D. \(\frac{\cos \theta}{\sin \theta}\)
\(\cot \theta=\frac{\cos \theta}{\sin \theta}\) होता है। \(\tan \theta\) और \(\cot \theta\) के संबंध उलटे होते हैं। / \(\cot \theta=\frac{\cos \theta}{\sin \theta}\). The relations of \(\tan \theta\) and \(\cot \theta\) are reciprocal.
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Which trigonometric function is the reciprocal of \(\tan \theta\)?
C. \(\cot \theta\)
\(\cot \theta=\frac{1}{\tan \theta}\) होता है। व्युत्क्रम फलनों को सूत्र रूप में लिखकर जाँचें। / \(\cot \theta=\frac{1}{\tan \theta}\). Check reciprocal functions by writing them as formulas.
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