cofunction-identities se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.
(\sin\(\frac{\pi}{2}-x\)=\cos x), so (\cosec\(\frac{\pi}{2}-x\)=\frac{1}{\cos x}=\sec x). Use reciprocal and cofunction identities together.
Step 2
Why this answer is correct
The correct answer is A. \(\sec x\). (\sin\(\frac{\pi}{2}-x\)=\cos x), so (\cosec\(\frac{\pi}{2}-x\)=\frac{1}{\cos x}=\sec x). Use reciprocal and cofunction identities together.
Step 3
Exam Tip
(\sin\(\frac{\pi}{2}-x\)=\cos x), इसलिए (\cosec\(\frac{\pi}{2}-x\)=\frac{1}{\cos x}=\sec x)। व्युत्क्रम और पूरक पहचान साथ लगाएँ।
(\cos\(\frac{\pi}{2}-x\)=\sin x), so (\sec\(\frac{\pi}{2}-x\)=\frac{1}{\sin x}=\cosec x). Complementary angles give cofunctions.
Step 2
Why this answer is correct
The correct answer is C. \(\cosec x\). (\cos\(\frac{\pi}{2}-x\)=\sin x), so (\sec\(\frac{\pi}{2}-x\)=\frac{1}{\sin x}=\cosec x). Complementary angles give cofunctions.
Step 3
Exam Tip
(\cos\(\frac{\pi}{2}-x\)=\sin x), इसलिए (\sec\(\frac{\pi}{2}-x\)=\frac{1}{\sin x}=\cosec x)। पूरक कोण में सहफलन बनता है।
At \(\frac{\pi}{2}+x\), \(\tan\) changes to \(\cot\) with a negative sign. Hence (\tan\(\frac{\pi}{2}+x\)=-\cot x).
Step 2
Why this answer is correct
The correct answer is A. \(-\cot x\). At \(\frac{\pi}{2}+x\), \(\tan\) changes to \(\cot\) with a negative sign. Hence (\tan\(\frac{\pi}{2}+x\)=-\cot x).
Step 3
Exam Tip
\(\frac{\pi}{2}+x\) पर \(\tan\) बदलकर \(\cot\) होता है और चिन्ह ऋणात्मक होता है। इसलिए (\tan\(\frac{\pi}{2}+x\)=-\cot x)।
In the form \(\frac{\pi}{2}+x\), \(\cos\) changes to \(\sin\) with a negative sign. Hence it becomes \(-\sin x\).
Step 2
Why this answer is correct
The correct answer is B. \(-\sin x\). In the form \(\frac{\pi}{2}+x\), \(\cos\) changes to \(\sin\) with a negative sign. Hence it becomes \(-\sin x\).
Step 3
Exam Tip
\(\frac{\pi}{2}+x\) वाले रूप में \(\cos\) बदलकर \(\sin\) होता है और चिन्ह ऋणात्मक होता है। इसलिए \(-\sin x\) मिलता है।
In the form \(\frac{\pi}{2}+x\), \(\sin\) changes to \(\cos\) and the sign remains positive. Hence the answer is \(\cos x\).
Step 2
Why this answer is correct
The correct answer is D. \(\cos x\). In the form \(\frac{\pi}{2}+x\), \(\sin\) changes to \(\cos\) and the sign remains positive. Hence the answer is \(\cos x\).
Step 3
Exam Tip
\(\frac{\pi}{2}+x\) वाले रूप में \(\sin\) बदलकर \(\cos\) होता है और चिन्ह धनात्मक रहता है। इसलिए उत्तर \(\cos x\) है।
For a complementary angle with \(\frac{\pi}{2}\), \(\tan x\) changes to \(\cot x\). Remember cofunction identities.
Step 2
Why this answer is correct
The correct answer is B. \(\cot x\). For a complementary angle with \(\frac{\pi}{2}\), \(\tan x\) changes to \(\cot x\). Remember cofunction identities.
Step 3
Exam Tip
\(\frac{\pi}{2}\) के पूरक कोण में \(\tan x\) बदलकर \(\cot x\) हो जाता है। पूरक पहचान याद रखें।
By the complementary angle identity, (\cos\(\frac{\pi}{2}-x\)=\sin x). In such questions, \(\sin x\) and \(\cos x\) interchange.
Step 2
Why this answer is correct
The correct answer is D. \(\sin x\). By the complementary angle identity, (\cos\(\frac{\pi}{2}-x\)=\sin x). In such questions, \(\sin x\) and \(\cos x\) interchange.
Step 3
Exam Tip
पूरक कोण पहचान से (\cos\(\frac{\pi}{2}-x\)=\sin x) होता है। ऐसे प्रश्नों में \(\sin x\) और \(\cos x\) आपस में बदलते हैं।
By the complementary angle identity, (\sin\(\frac{\pi}{2}-x\)=\cos x). With \(\frac{\pi}{2}\), the function changes.
Step 2
Why this answer is correct
The correct answer is C. \(\cos x\). By the complementary angle identity, (\sin\(\frac{\pi}{2}-x\)=\cos x). With \(\frac{\pi}{2}\), the function changes.
Step 3
Exam Tip
पूरक कोण पहचान से (\sin\(\frac{\pi}{2}-x\)=\cos x) होता है। \(\frac{\pi}{2}\) के साथ फलन बदलता है।
