For \(\frac{\pi}{2}+x\), sine changes to cosine and remains positive in the second quadrant. Hence the value is \(\cos x\).
Step 2
Why this answer is correct
The correct answer is C. \(\cos x\). For \(\frac{\pi}{2}+x\), sine changes to cosine and remains positive in the second quadrant. Hence the value is \(\cos x\).
Step 3
Exam Tip
\(\frac{\pi}{2}+x\) के लिए sine, cosine में बदलता है और दूसरे चतुर्थांश में धनात्मक रहता है। इसलिए मान \(\cos x\) है।
\(\cosec \theta\) is the reciprocal of \(\sin \theta\) and is negative in the fourth quadrant. Therefore the value is \(-\cosec \theta\).
Step 2
Why this answer is correct
The correct answer is A. -\(\cosec \theta\). \(\cosec \theta\) is the reciprocal of \(\sin \theta\) and is negative in the fourth quadrant. Therefore the value is \(-\cosec \theta\).
Step 3
Exam Tip
\(\cosec \theta\) \(\sin \theta\) का व्युत्क्रम है और चौथे चतुर्थांश में ऋणात्मक होता है। इसलिए मान \(-\cosec \theta\) है।
\(\sec \theta\) is the reciprocal of \(\cos \theta\) and remains positive in the fourth quadrant. So (\sec\(2\pi-\theta\)=\sec \theta).
Step 2
Why this answer is correct
The correct answer is D. \(\sec \theta\). \(\sec \theta\) is the reciprocal of \(\cos \theta\) and remains positive in the fourth quadrant. So (\sec\(2\pi-\theta\)=\sec \theta).
Step 3
Exam Tip
\(\sec \theta\) \(\cos \theta\) का व्युत्क्रम है और चौथे चतुर्थांश में धनात्मक रहता है। इसलिए (\sec\(2\pi-\theta\)=\sec \theta) है।
With \(\frac{3\pi}{2}\), \(\tan \theta\) changes to \(\cot \theta\), and the sign is negative in the fourth quadrant. Therefore the answer is \(-\cot \theta\).
Step 2
Why this answer is correct
The correct answer is A. -\(\cot \theta\). With \(\frac{3\pi}{2}\), \(\tan \theta\) changes to \(\cot \theta\), and the sign is negative in the fourth quadrant. Therefore the answer is \(-\cot \theta\).
Step 3
Exam Tip
\(\frac{3\pi}{2}\) के साथ \(\tan \theta\) \(\cot \theta\) में बदलता है और चौथे चतुर्थांश में चिह्न ऋणात्मक होता है। इसलिए उत्तर \(-\cot \theta\) है।
(\cos\left\(\frac{3\pi}{2}+\theta\right\)=\sin \theta). In the fourth quadrant, \(\cos \theta\) is taken as positive.
Step 2
Why this answer is correct
The correct answer is D. \(\sin \theta\). (\cos\left\(\frac{3\pi}{2}+\theta\right\)=\sin \theta). In the fourth quadrant, \(\cos \theta\) is taken as positive.
Step 3
Exam Tip
(\cos\left\(\frac{3\pi}{2}+\theta\right\)=\sin \theta) होता है। चौथे चतुर्थांश में \(\cos \theta\) धनात्मक माना जाता है।
(\sin\left\(\frac{3\pi}{2}+\theta\right\)=-\cos \theta). In a \(\frac{3\pi}{2}\) form, \(\sin \theta\) changes to its cofunction.
Step 2
Why this answer is correct
The correct answer is C. -\(\cos \theta\). (\sin\left\(\frac{3\pi}{2}+\theta\right\)=-\cos \theta). In a \(\frac{3\pi}{2}\) form, \(\sin \theta\) changes to its cofunction.
Step 3
Exam Tip
(\sin\left\(\frac{3\pi}{2}+\theta\right\)=-\cos \theta) होता है। \(\frac{3\pi}{2}\) वाले रूप में \(\sin \theta\) सह-फलन में बदलता है।
With \(\frac{3\pi}{2}\), \(\tan \theta\) changes to \(\cot \theta\). In the third quadrant, \(\tan \theta\) is positive.
Step 2
Why this answer is correct
The correct answer is B. \(\cot \theta\). With \(\frac{3\pi}{2}\), \(\tan \theta\) changes to \(\cot \theta\). In the third quadrant, \(\tan \theta\) is positive.
Step 3
Exam Tip
\(\frac{3\pi}{2}\) के साथ \(\tan \theta\) \(\cot \theta\) में बदलता है। तीसरे चतुर्थांश में \(\tan \theta\) धनात्मक होता है।
With \(\frac{3\pi}{2}\), \(\cos \theta\) changes to the cofunction \(\sin \theta\). In the third quadrant, \(\cos \theta\) is negative.
Step 2
Why this answer is correct
The correct answer is A. -\(\sin \theta\). With \(\frac{3\pi}{2}\), \(\cos \theta\) changes to the cofunction \(\sin \theta\). In the third quadrant, \(\cos \theta\) is negative.
Step 3
Exam Tip
\(\frac{3\pi}{2}\) के साथ \(\cos \theta\) सह-फलन \(\sin \theta\) में बदलता है। तीसरे चतुर्थांश में \(\cos \theta\) ऋणात्मक होता है।
With \(\frac{3\pi}{2}\), \(\sin \theta\) changes to a cofunction and the sign is negative in the third quadrant. So the answer is \(-\cos \theta\).
Step 2
Why this answer is correct
The correct answer is C. -\(\cos \theta\). With \(\frac{3\pi}{2}\), \(\sin \theta\) changes to a cofunction and the sign is negative in the third quadrant. So the answer is \(-\cos \theta\).
Step 3
Exam Tip
\(\frac{3\pi}{2}\) के साथ \(\sin \theta\) सह-फलन में बदलता है और तीसरे चतुर्थांश में चिह्न ऋणात्मक होता है। इसलिए उत्तर \(-\cos \theta\) है।
(\cos\left\(\frac{\pi}{2}+\theta\right\)=-\sin \theta). At \(\frac{\pi}{2}\), the function changes and the sign is decided by the quadrant.
Step 2
Why this answer is correct
The correct answer is B. -\(\sin \theta\). (\cos\left\(\frac{\pi}{2}+\theta\right\)=-\sin \theta). At \(\frac{\pi}{2}\), the function changes and the sign is decided by the quadrant.
Step 3
Exam Tip
(\cos\left\(\frac{\pi}{2}+\theta\right\)=-\sin \theta) होता है। \(\frac{\pi}{2}\) पर फलन बदलता है और चिह्न चतुर्थांश से तय होता है।
With \(\frac{\pi}{2}\), \(\sin \theta\) changes to its cofunction \(\cos \theta\). The sign remains positive in the second quadrant.
Step 2
Why this answer is correct
The correct answer is A. \(\cos \theta\). With \(\frac{\pi}{2}\), \(\sin \theta\) changes to its cofunction \(\cos \theta\). The sign remains positive in the second quadrant.
Step 3
Exam Tip
\(\frac{\pi}{2}\) के साथ \(\sin \theta\) सह-फलन \(\cos \theta\) में बदलता है। दूसरे चतुर्थांश में चिह्न धनात्मक रहता है।
The period of \(\tan \theta\) is \(\pi\), so (\tan\(\pi+\theta\)=\tan \theta). Knowing periods makes transformations easier.
Step 2
Why this answer is correct
The correct answer is C. \(\tan \theta\). The period of \(\tan \theta\) is \(\pi\), so (\tan\(\pi+\theta\)=\tan \theta). Knowing periods makes transformations easier.
Step 3
Exam Tip
\(\tan \theta\) का काल \(\pi\) है इसलिए (\tan\(\pi+\theta\)=\tan \theta)। काल याद रखने से रूपांतरण आसान होता है।
