cofunction se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.
12 questions tagged with cofunction.
What is (\cos\(\frac{3\pi}{2}-x\)) equal to?
C. -\(\sin x\)
\(\frac{3\pi}{2}-x\) तीसरे चतुर्थांश से जुड़ा है। \(\cos\) बदलकर \(\sin\) होता है और चिन्ह ऋणात्मक रहता है। / \(\frac{3\pi}{2}-x\) is related to the third quadrant. \(\cos\) changes to \(\sin\) with a negative sign.
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What is (\sin\(\frac{3\pi}{2}+x\)) equal to?
A. -\(\cos x\)
\(\frac{3\pi}{2}+x\) रूप में \(\sin\) बदलकर \(\cos\) होता है और चिन्ह ऋणात्मक होता है। इसलिए उत्तर \(-\cos x\) है। / In the form \(\frac{3\pi}{2}+x\), \(\sin\) changes to \(\cos\) with a negative sign. Hence the answer is \(-\cos x\).
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What is \(\cosec\left(\frac{\pi}{2}+\theta\right)\) equal to?
B. \(\sec \theta\)
\(\cosec \theta\) का सह-फलन \(\sec \theta\) है और दूसरे चतुर्थांश में चिह्न धनात्मक रहता है। सह-फलन जोड़ों को याद रखें। / The cofunction of \(\cosec \theta\) is \(\sec \theta\), and the sign remains positive in the second quadrant. Remember cofunction pairs.
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What is \(\sec\left(\frac{\pi}{2}+\theta\right)\) equal to?
A. -\(\cosec \theta\)
\(\sec \theta\) का सह-फलन \(\cosec \theta\) है और दूसरे चतुर्थांश में \(\sec \theta\) ऋणात्मक होता है। इसलिए मान \(-\cosec \theta\) है। / The cofunction of \(\sec \theta\) is \(\cosec \theta\), and \(\sec \theta\) is negative in the second quadrant. Hence the value is \(-\cosec \theta\).
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What is \(\cot\left(\frac{\pi}{2}+\theta\right)\) equal to?
D. -\(\tan \theta\)
\(\cot \theta\) का सह-फलन \(\tan \theta\) है और दूसरे चतुर्थांश में चिह्न ऋणात्मक होता है। ऐसे प्रश्नों में पहले सह-फलन पहचानें। / The cofunction of \(\cot \theta\) is \(\tan \theta\), and the sign is negative in the second quadrant. In such questions, first identify the cofunction.
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What is \(\tan\left(\frac{\pi}{2}+\theta\right)\) equal to?
C. -\(\cot \theta\)
\(\tan \theta\) का सह-फलन \(\cot \theta\) है और दूसरे चतुर्थांश में चिह्न ऋणात्मक होता है। इसलिए उत्तर \(-\cot \theta\) है। / The cofunction of \(\tan \theta\) is \(\cot \theta\), and the sign is negative in the second quadrant. Therefore the answer is \(-\cot \theta\).
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What is \(\cos\left(\frac{\pi}{2}+\theta\right)\) equal to?
B. -\(\sin \theta\)
\(\cos\left(\frac{\pi}{2}+\theta\right)=-\sin \theta\) होता है। \(\frac{\pi}{2}\) पर फलन बदलता है और चिह्न चतुर्थांश से तय होता है। / \(\cos\left(\frac{\pi}{2}+\theta\right)=-\sin \theta\). At \(\frac{\pi}{2}\), the function changes and the sign is decided by the quadrant.
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What is \(\sin\left(\frac{\pi}{2}+\theta\right)\) equal to?
A. \(\cos \theta\)
\(\frac{\pi}{2}\) के साथ \(\sin \theta\) सह-फलन \(\cos \theta\) में बदलता है। दूसरे चतुर्थांश में चिह्न धनात्मक रहता है। / With \(\frac{\pi}{2}\), \(\sin \theta\) changes to its cofunction \(\cos \theta\). The sign remains positive in the second quadrant.
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What is \(\sec\left(\frac{\pi}{2}-\theta\right)\) equal to?
D. \(\cosec \theta\)
\(\sec\left(\frac{\pi}{2}-\theta\right)=\cosec \theta\) होता है। \(\sec \theta\) और \(\cosec \theta\) सह-फलन हैं। / \(\sec\left(\frac{\pi}{2}-\theta\right)=\cosec \theta\). \(\sec \theta\) and \(\cosec \theta\) are cofunctions.
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What is \(\tan\left(\frac{\pi}{2}-\theta\right)\) equal to?
C. \(\cot \theta\)
\(\tan\left(\frac{\pi}{2}-\theta\right)=\cot \theta\) होता है। \(\tan \theta\) का सह-फलन \(\cot \theta\) है। / \(\tan\left(\frac{\pi}{2}-\theta\right)=\cot \theta\). The cofunction of \(\tan \theta\) is \(\cot \theta\).
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What is \(\cos\left(\frac{\pi}{2}-\theta\right)\) equal to?
B. \(\sin \theta\)
\(\cos\left(\frac{\pi}{2}-\theta\right)=\sin \theta\) होता है। सह-फलन संबंध में \(\sin \theta\) और \(\cos \theta\) आपस में बदलते हैं। / \(\cos\left(\frac{\pi}{2}-\theta\right)=\sin \theta\). In cofunction relations, \(\sin \theta\) and \(\cos \theta\) interchange.
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What is \(\sin\left(\frac{\pi}{2}-\theta\right)\) equal to?
A. \(\cos \theta\)
\(\sin\left(\frac{\pi}{2}-\theta\right)=\cos \theta\) सह-फलन संबंध है। \(\frac{\pi}{2}\) वाले रूपांतरण में फलन बदलता है। / \(\sin\left(\frac{\pi}{2}-\theta\right)=\cos \theta\) is a cofunction relation. In transformations with \(\frac{\pi}{2}\), the function changes.
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