Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 71-80 of 600 questions.
What is the domain of (f(x)=\sqrt{x+2})?
A. \(x\ge -2\)
वास्तविक वर्गमूल के लिए \(x+2\ge 0\) होना चाहिए। इसलिए डोमेन \(x\ge -2\) है। / For a real square root, \(x+2\ge 0\) is required. Hence the domain is \(x\ge -2\).
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What is the minimum value of (f(x)=\sqrt{x}+4)?
C. (4)
\(\sqrt{x}\ge 0\), इसलिए \(\sqrt{x}+4\ge 4\)। न्यूनतम मान (4) (x=0) पर मिलता है। / Since \(\sqrt{x}\ge 0\), \(\sqrt{x}+4\ge 4\). The minimum value (4) occurs at (x=0).
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From which point does the graph of (f(x)=\sqrt{x-1}) start?
B. ((1,0))
\(\sqrt{x-1}\) में (x-1=0) से (x=1) मिलता है। इसलिए ग्राफ ((1,0)) से शुरू होता है। / In \(\sqrt{x-1}\), (x-1=0) gives (x=1). So the graph starts from ((1,0)).
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Which point lies on the graph of (f(x)=\sqrt{x})?
A. ((4,2))
\(\sqrt{4}=2\), इसलिए ((4,2)) आलेख पर है। वर्गमूल फलन में (y) ऋणात्मक नहीं होता। / Since \(\sqrt{4}=2\), ((4,2)) lies on the graph. In the square root function, (y) is not negative.
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For which (x)-value is (f(x)=\frac{1}{x-2}) not defined?
C. (x=2)
हर (x-2) शून्य नहीं हो सकता। (x-2=0) से (x=2) मिलता है। / The denominator (x-2) cannot be zero. From (x-2=0), we get (x=2).
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What is the vertical asymptote of (f(x)=\frac{1}{x+1})?
B. (x=-1)
हर (x+1) शून्य होने पर फलन परिभाषित नहीं रहता। इसलिए (x=-1) ऊर्ध्व आसिम्प्टोट है। / When the denominator (x+1) becomes zero, the function is not defined. So (x=-1) is the vertical asymptote.
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What is the horizontal asymptote of (f(x)=\frac{1}{x}+2)?
C. (y=2)
\(\frac{1}{x}\) का मान बड़े (x) पर (0) के पास जाता है। इसलिए \(\frac{1}{x}+2\) का क्षैतिज आसिम्प्टोट (y=2) है। / The value of \(\frac{1}{x}\) approaches (0) for large (x). So the horizontal asymptote of \(\frac{1}{x}+2\) is (y=2).
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What is the slope of the line (y=2x+1)?
B. (2)
(y=mx+c) में (m) ढाल होता है। (y=2x+1) में ढाल (2) है। / In (y=mx+c), (m) is the slope. In (y=2x+1), the slope is (2).
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What is the (y)-intercept of the line (y=-3x+5)?
A. (5)
(y=mx+c) में (c) (y)-अक्ष प्रतिच्छेद होता है। यहां (c=5) है। / In (y=mx+c), (c) is the (y)-intercept. Here (c=5).
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What is the slope of the line (y=4)?
C. (0)
(y=4) एक क्षैतिज रेखा है। क्षैतिज रेखा की ढाल (0) होती है। / (y=4) is a horizontal line. The slope of a horizontal line is (0).
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